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NEET • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Mixed difficulty

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Showing 241-248 of 248 questions

241 Easy

241 of 248

Remembering +4 | -1

Ordinary oxygen contains:

View answer and explanation

Correct option: C

\mathrm{A\;mixture\;of\;}{\mathrm{O}^{16}},\mathrm{\;}{\mathrm{O}^{17}}\mathrm{\;and\;}{\mathrm{O}^{18}}\mathrm{\;isotopes}

Option C (

\mathrm{A\;mixture\;of\;}{\mathrm{O}^{16}},\mathrm{\;}{\mathrm{O}^{17}}\mathrm{\;and\;}{\mathrm{O}^{18}}\mathrm{\;isotopes}

) is correct because ordinary oxygen exists as a mixture of its stable isotopes: O-16, O-17, and O-18.

242 Hard

242 of 248

Understanding +4 | -1

Sulphur trioxide can be obtained by which of the following reaction:

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Correct option: D

F{e_2}{\left( {S{O_4}} \right)_3}\xrightarrow[{}]{\Delta }

Option D (

F{e_2}{\left( {S{O_4}} \right)_3}\xrightarrow[{}]{\Delta }

) is correct because the thermal decomposition of

F{e_2}{\left( {S{O_4}} \right)_3}

produces

Fe_2O_3

and

SO_3

243 Medium

243 of 248

Application +4 | -1

In the reaction,

\mathrm{MnO}_4^ - \mathrm{\;} + \mathrm{\;}{\mathrm{I}^ - }\;\mathop \to \limits^{A\mathrm{lkaline\;solution}} \;\left[ X \right];\,\,\left[ X \right]\;\mathrm{is}:

View answer and explanation

Correct option: A

\mathrm{IO}_3^ -

Option A (

\mathrm{IO}_3^ -

) is correct because in alkaline solution, permanganate ions oxidize iodide ions to iodate ions.

244 Medium

244 of 248

Application +4 | -1

Xe{O_3},\;Xe\;

is:

View answer and explanation

Correct option: A

s{p^3} -

hybridized

Option A (

sp^3

- hybridized) is correct because Xe in

XeO_3

has three sigma bonds and one lone pair, leading to

sp^3

hybridization.

245 Medium

245 of 248

Analyzing +4 | -1

Which of the following oxoacids of phosphorus has strongest reducing property

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Correct option: B

{H_3}P{O_2}

Option B is correct because

{H_3}P{O_2}

has the strongest reducing property due to the presence of two P-H bonds, which can easily donate hydrogen atoms.

246 Medium

246 of 248

Analyzing +4 | -1

Which are true statements among the following?(1)

\mathrm{P}{\mathrm{H}_5}\mathrm{ and BiC}{\mathrm{l}_5}

does not exist (2)

p\pi - d\pi

bonds are present in

\mathrm{S}{\mathrm{O}_2}

(3) Electrons travel with speed of light (4)

\mathrm{Se}{\mathrm{F}_4}\,\mathrm{and C}{\mathrm{H}_4}

has same shape (5)

\mathrm{I}_3^ +

has bent geometry

View answer and explanation

Correct option: B

1,\mathrm{ }2,\mathrm{ }5

Option B is correct.

PH_5

and

BiCl_5

do not exist due to the inability of P and Bi to form 5 bonds.

SO_2

has

p\pi - d\pi

bonds.

I_3^+

has a bent geometry.

247 Hard

247 of 248

Analyzing +4 | -1

Assertion : When a metal is treated with conc.

{HNO}_3

it generally yields a nitrate,

{NO}_2

and

{H}_2 {O}

.

Reason : Conc.

{HNO}_3

reacts with metal and first produces a metal nitrate and nascent hydrogen. The nascent hydrogen then further reduces

{HNO}_3

{NO}_2

View answer and explanation

Correct option: A

Assertion is correct, reason is correct; reason is a correct explanation for assertion.

Option A is correct because both the assertion and the reason are correct, and the reason correctly explains the assertion. Concentrated

{HNO}_3

reacts with metals to form metal nitrates,

{NO}_2

, and

{H}_2{O}

248 Medium

248 of 248

Understanding +4 | -1

Formic acid on reaction with concentrated

{H_2}S{O_4}

at 373 K gives

View answer and explanation

Correct option: D

Option D (CO) is correct because formic acid (

HCOOH

) when reacted with concentrated

{H_2}S{O_4}

undergoes dehydration to produce carbon monoxide (CO).

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