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NEET • CHEMISTRY • HYDROCARBONS

Hydrocarbons practice · Mixed difficulty

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Showing 61-90 of 229 questions
61 Hard
61 of 229
Remembering +4 | -1
Which of the following is carcinogenic hydrocarbon
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because 1,2-Benzanthracene, 1,2-Benzpyrene, and 3-Methylcholanthrene are all known carcinogenic hydrocarbons.
62 Medium
62 of 229
Analyzing +4 | -1
One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of 44 u. The alkene is
View answer and explanation
Correct option: C
2-butene
Option C (2-butene) is correct because ozonolysis of 2-butene yields two moles of acetaldehyde (molecular mass 44 u).
63 Medium
63 of 229
Remembering +4 | -1
Which of the following fuel cause the least pollution?
View answer and explanation
Correct option: D
LPG
Option D (LPG) is correct because LPG (Liquefied Petroleum Gas) generally produces less pollution compared to petrol, CNG, and kerosene when burned.
64 Easy
64 of 229
Analyzing +4 | -1
Correct statement about 1,3-dibutene
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Correct option: D
All of the above
Option D (All of the above) is correct because 1,3-dibutene has conjugated double bonds, reacts with HBr, and can form a polymer.
65 Hard
65 of 229
Understanding +4 | -1
Which of the following statement(s) is/are correct regarding rotation around internuclear axis of C−C\mathrm{C}-\mathrm{C} bond?

I. Rotation produces rotamers.

II. Magnitude of torsional strain depends upon the angle of rotation about C−C\mathrm{C}-\mathrm{C} bond.

III. Repulsive interaction between adjacent bond is termed as torsional strain.

IV. Ethane has only four conformational isomers.
Choose the correct option.
View answer and explanation
Correct option: B
I, II and III
Option B (I, II and III) is correct because rotation around the internuclear axis of a C-C bond produces rotamers, the magnitude of torsional strain depends on the angle of rotation, and repulsive interactions between adjacent bonds are termed torsional strain.
66 Easy
66 of 229
Application +4 | -1
Hydration of but-2-ene gives
View answer and explanation
Correct option: A
CH3CH2C∣OHHCH3C{H_3}C{H_2}\mathop C\limits_{\mathop |\limits_{OH} } HC{H_3}
Option A (CH3CH2C∣OHHCH3C{H_3}C{H_2}\mathop C\limits_{\mathop |\limits_{OH} } HC{H_3}) is correct because hydration of but-2-ene in the presence of an acid catalyst follows Markovnikov's rule, leading to the formation of butan-2-ol.
67 Easy
67 of 229
Remembering +4 | -1
The number of carbon atoms in hydrocarbons of kerosene is in the range of:
View answer and explanation
Correct option: B
C12−C16{\mathrm{C}_{12}}-{\mathrm{C}_{16}}
Option B (C12−C16{\mathrm{C}_{12}}-{\mathrm{C}_{16}}) is correct because kerosene typically contains hydrocarbons with carbon chain lengths ranging from C12 to C16.
68 Easy
68 of 229
Analyzing +4 | -1
Assertion (A) Friedel-Crafts reaction benzene with n-propyl chloride onheating produce isopropyl benzene

Reason (R) Benzene undergoes electrophilic substitution easily.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are true but Reason is not the correct explanation of Assertion) is correct because while both statements are true, the ease of electrophilic substitution doesn't directly explain why n-propyl chloride rearranges to isopropyl chloride.
69 Hard
69 of 229
Application +4 | -1
Heat of hydrogenation of cyclohexene (one  C=C  bond)(\mathrm{one}\,\,C = C\,\,\mathrm{bond}) is −28.4  k.cal.mol−1- 28.4\,\,k.cal.mo{l^{ - 1}}. Hence,heat of hydrogenation of benzene (three  C=C  bonds)(\mathrm{three}\,\,C = C\,\,\mathrm{bonds}) should be
View answer and explanation
Correct option: A
−85.2  k.cal.mol−1- 85.2\,\,k.cal.mo{l^{ - 1}}
Option A is correct because the addition of HBr to 3-phenylpropene follows Markownikoff's rule, and also considers the stability of the carbocation intermediate. The more stable carbocation is benzylic and secondary, leading to the major product.
70 Easy
70 of 229
Remembering +4 | -1
Position of double bond in alkenes is identified by
View answer and explanation
Correct option: A
Ozonolysis
Option A (Ozonolysis) is correct because ozonolysis cleaves the double bond and the products formed can be used to determine the position of the double bond.
71 Easy
71 of 229
Understanding +4 | -1
CaC2+H2O→A→H2SO4HgSO4B,Ca{C_2} + {H_2}O \to A\xrightarrow[{{H_2}S{O_4}}]{{HgS{O_4}}}B, Identify AA and BB
View answer and explanation
Correct option: A
C2H2  and  CH3CHO{C_2}{H_2}\,\,and\,\,C{H_3}CHO
Option A (C2H2  and  CH3CHO{C_2}{H_2}\,\,and\,\,C{H_3}CHO) is correct because calcium carbide reacts with water to form ethyne, which then undergoes hydration to form ethanal.
72 Medium
72 of 229
Application +4 | -1
The number of possible isomers of alkane with formula C6H14{\mathrm{C}_6}{\mathrm{H}_{14}} is:
View answer and explanation
Correct option: D
5
Option D (5) is correct because there are five structural isomers of the alkane with the formula C6H14.
73 Hard
73 of 229
Analyzing +4 | -1
Which will give cyclooctyne when treated with base?
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Correct option: C
1,1-dibromocyclooctane
Option C is correct because 1,1-dibromocyclooctane can undergo two successive dehydrohalogenation reactions in the presence of a strong base to form cyclooctyne. The geminal dibromide is necessary for the elimination to form the cyclic alkyne.
74 Easy
74 of 229
Remembering +4 | -1
The treatment of calcium carbides with water gives
View answer and explanation
Correct option: B
acetylene
Option B (acetylene) is correct because calcium carbide (CaC2CaC_2) reacts with water to produce acetylene (C2H2C_2H_2).
75 Medium
75 of 229
Understanding +4 | -1
By heating tetraethyl ammonium hydroxide, the product formed are:
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because heating tetraethyl ammonium hydroxide results in Hofmann elimination, producing ethene, triethylamine, and water.
76 Easy
76 of 229
Understanding +4 | -1
Hydration of ethyne to ethanol takes place through the formation of
View answer and explanation
Correct option: B
CH2=CHOHC{H_2} = CHOH
Option B (CH2=CHOHC{H_2} = CHOH) is correct because the hydration of ethyne initially forms vinyl alcohol (CH2=CHOHC{H_2} = CHOH), which then tautomerizes to acetaldehyde.
77 Easy
77 of 229
Application +4 | -1
CH3−C≡CH\mathrm{C}{\mathrm{H}_3}-\mathrm{C} \equiv \mathrm{CH} reacts with HCIHCI to give:
View answer and explanation
Correct option: A
2,2-dichloropropane
Option A (2,2-dichloropropane) is correct because the addition of HCl to propyne follows Markovnikov's rule, leading to the formation of 2-chloropropene, which then reacts with another molecule of HCl to give 2,2-dichloropropane.
78 Medium
78 of 229
Understanding +4 | -1
Which of the following will not give white ppt with ammoniacal silver nitrate
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Correct option: B
2 - butyne
Option B (2 - butyne) is correct because terminal alkynes (alkynes with a hydrogen atom attached to the sp-hybridized carbon) react with ammoniacal silver nitrate to form a white precipitate, while internal alkynes do not.
79 Medium
79 of 229
Analyzing +4 | -1
Which of the following will not produce ethane
View answer and explanation
Correct option: B
reduction of CH3COCH3C{H_3}COC{H_3} with HI/P4HI/{P_4}
Option B (Reduction of CH3COCH3\mathrm{C}{\mathrm{H}_3}\mathrm{COC}{\mathrm{H}_3} with HI and red P) is correct because the reduction of acetone with HI and red P yields propane, not ethane.
80 Hard
80 of 229
Understanding +4 | -1
S-I: Alkynes are more reactive than alkenes towards catalytic hydrogenation
S-II: Alkynes are less reactive towards electrophilic reaction than alkenes.
View answer and explanation
Correct option: A
S-I &\& S-II are true
Option A (S-I & S-II are true) is correct because alkynes are more reactive than alkenes towards catalytic hydrogenation, but less reactive towards electrophilic reactions.
81 Hard
81 of 229
Understanding +4 | -1
The reactants involved in general combustion equation for any alkane is represented as
View answer and explanation
Correct option: D
CnH2n+2+(3n+12)O2{C}_n {H}_{2 n+2}+\left(\frac{3 n+1}{2}\right) {O}_2
Option D (CnH2n+2+(3n+12)O2{C}_n {H}_{2 n+2}+(\frac{3 n+1}{2}) {O}_2) is correct because it represents the balanced general combustion equation for any alkane, where the coefficients are correctly balanced to ensure the conservation of mass.
82 Easy
82 of 229
Understanding +4 | -1
Which of the following is unsymmetrical alkene?
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because 1-butene, 2-hexene, and 1-pentene all have different groups attached to the carbon atoms of the double bond, making them unsymmetrical.
83 Medium
83 of 229
Remembering +4 | -1
When two halogen atoms are attached to two adjacent carbon atoms, the dihaloalkane is called :
View answer and explanation
Correct option: C
Alkylene dihalide
Option C (Alkylene dihalide) is correct because alkylene dihalides have two halogen atoms attached to two adjacent carbon atoms.
84 Hard
84 of 229
Remembering +4 | -1
Angle strain in cyclopropane is
View answer and explanation
Correct option: A
24∘44′24^\circ 44'
Option A (24∘44′24^\circ 44') is correct because cyclopropane is a three-membered ring with bond angles of 60°, leading to a significant angle strain compared to the ideal tetrahedral angle of 109.5°.
85 Easy
85 of 229
Analyzing +4 | -1
A hydrocarbon Xadds on one mole of hydrogen to give another hydrocarbon and decolourised bromine water. X react with KMnO4\mathrm{KMn}{\mathrm{O}_4} in presence of acid to give two mole of the same carboxylic acid. The structure of X is:
View answer and explanation
Correct option: B
CH3CH2CH=CHCH2CH3\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{CH} = \mathrm{CHC}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_3}
Option B (CH3CH2CH=CHCH2CH3\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{CH} = \mathrm{CHC}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_3}) is correct because it adds one mole of hydrogen and gives two moles of the same carboxylic acid upon reaction with KMnO4\mathrm{KMn}{\mathrm{O}_4}.
86 Medium
86 of 229
Understanding +4 | -1
The relative rates of reaction of alkene with Br2/CH3OHB{r_2}/C{H_3}OH are in order
View answer and explanation
Correct option: A
ethene < 1 – butene < trans but–2-ene
Option A (ethene < 1 – butene < trans but–2-ene) is correct because the rate of reaction with Br2/CH3OHBr_2/CH_3OH increases with increasing alkyl substitution on the alkene.
87 Easy
87 of 229
Understanding +4 | -1
Alkyl halides have higher boiling points than alkanes (having same number of carbon atoms) because of
View answer and explanation
Correct option: A
dipole – dipole interaction
Option A (dipole – dipole interaction) is correct because alkyl halides are polar molecules due to the electronegativity difference between the halogen and carbon atoms, leading to dipole-dipole interactions.
88 Medium
88 of 229
Application +4 | -1
Major product of the given reaction is CH3CH=CH2C{H_3}CH = C{H_2}
View answer and explanation
Correct option: B
CH3CH(OH)CH2(OH)C{H_3}CH\left( {OH} \right)C{H_2}\left( {OH} \right)
Option B (CH3CH(OH)CH2(OH)C{H_3}CH(OH)C{H_2}(OH)) is correct because the reaction of propene with KMnO4KMnO_4 results in syn-dihydroxylation of the double bond, forming a vicinal diol.
89 Medium
89 of 229
Analyzing +4 | -1
Which of the following compounds are not arranged on order of decreasing reactivity towards electrophilic substitution?
View answer and explanation
Correct option: D
Benzoic acid> phenol>nn- propyl benzene
Option D (Benzoic acid> phenol>nn- propyl benzene) is correct because it incorrectly orders the reactivity; electron-donating groups increase reactivity, while electron-withdrawing groups decrease it.
90 Medium
90 of 229
Application +4 | -1
In the following reaction, the product ‘ RR’ is
CaC2→H2OP→tubeHot, ironQ→CH3ClRCa{C_2}\xrightarrow{{{H_2}O}}P\xrightarrow[{\mathrm{tube}}]{{\mathrm{Hot,}\,\mathrm{iron}}}Q\xrightarrow{{C{H_3}Cl}}R
View answer and explanation
Correct option: C
toluene
Benzoic acid is the correct answer because toluene (formed by Friedel-Crafts alkylation of benzene) is oxidized by KMnO4KMn{O_4} to form benzoic acid.
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