When one of the following hydrocarbons is burnt in excess of oxygen, the volume of ${\rm{C}}{{\rm{O}}_2}$ evolved is just double to that of hydrocarbon taken. The hydrocarbon is:

JEE CHEMISTRY MCQ: HYDROCARBONS

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When one of the following hydrocarbons is burnt in excess of oxygen, the volume of

\mathrm{C}{\mathrm{O}_2}

evolved is just double to that of hydrocarbon taken. The hydrocarbon is:

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Correct option: B

{\mathrm{C}_2}{\mathrm{H}_6}

The correct answer is C2H6 because when it burns in excess oxygen, the volume of CO2 evolved is double that of the hydrocarbon taken, as shown in the balanced equation.

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\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

\sigma

-bonds presents in Fischer-Tropsch process is used in the manufacture of: