JEE CHEMISTRY MCQ: HYDROCARBONS

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What would be the main product when propene reacts with

HBr

presence of Benzoyl peroxide

View answer and explanation

Correct option: B

C{H_3} - C{H_2} - C{H_2}Br

Option B (

C{H_3} - C{H_2} - C{H_2}Br

) is correct because in the presence of benzoyl peroxide, HBr adds to propene via anti-Markovnikov's rule, resulting in the bromine atom attaching to the less substituted carbon.

More Questions from HYDROCARBONS

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\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

\sigma

-bonds presents in Fischer-Tropsch process is used in the manufacture of: