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NEET • CHEMISTRY • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

General principles and processes of isolation of elements practice · Hard

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31 Hard
Remembering +4 | -1
The methods chiefly used for the extraction of lead and tin from their ores are respectively
View answer and explanation
Correct option: A
Self reduction and carbon reduction
Option A is correct because lead is extracted from its sulfide ore (PbS) by self-reduction, while tin is extracted from its oxide ore (SnO2SnO_2) by carbon reduction.
Solution approach
  1. Correct Answer + Core Reason: Self reduction and carbon reduction. Lead is extracted by self-reduction, and tin is extracted by carbon reduction.

    Step-by-Step Solution:

    Step 1: Lead Extraction: Lead is extracted from its sulfide ore (PbS) through a self-reduction process, where the ore is partially oxidized to PbO and SO2SO_2, and then the PbO reacts with remaining PbS to form Pb and SO2SO_2.

    Step 2: Tin Extraction: Tin is extracted from its oxide ore (SnO2SnO_2) by reduction with carbon at high temperatures.

    Step 3: Conclusion: Lead is extracted by self-reduction, and tin is extracted by carbon reduction.

    Why other options are wrong:
    - Option B: Tin is not extracted by electrolytic reduction.
    - Option C: Lead is extracted by self-reduction, not carbon reduction.
    - Option D: Cyanide process is used for gold and silver, not lead or tin.

    Key Concepts:
    - Metal Extraction
    - Self-Reduction
    - Carbon Reduction

    Memory Aids:
    - Remember that lead undergoes self-reduction and tin uses carbon reduction.

    Quick Tips:
    - Know the different methods used for extracting various metals.
32 Hard
Analyzing +4 | -1
Assertion: According to ellingam diagram FeO\mathrm{FeO} can be easily reduced than Cu2O\mathrm{Cu}_2 \mathrm{O} by carbon.

Reason: ΔG∘\Delta \mathrm{G}^{\circ} of FeO\mathrm{FeO} is −300 kJ-300 \mathrm{~kJ} where as that of Cu2O\mathrm{Cu}_2 \mathrm{O} is −450 kJ-450 \mathrm{~kJ}.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because both the assertion and the reason are false. Ellingham diagrams show that the ΔG∘\Delta G^\circ for the formation of FeO is less negative than that of Cu2OCu_2O, meaning Cu2OCu_2O is easier to reduce than FeO by carbon. Also, the given ΔG∘\Delta G^\circ values are incorrect.
Solution approach
  1. Correct Answer + Core Reason: If both Assertion & Reason are false. The assertion is incorrect because Cu2OCu_2O is easier to reduce than FeOFeO by carbon. The reason is also incorrect because the ΔG∘\Delta G^\circ values are wrong.

    Step-by-Step Solution:

    Step 1: Understand Ellingham Diagrams: Ellingham diagrams plot the Gibbs free energy of formation (ΔG∘\Delta G^\circ) of metal oxides as a function of temperature. A more negative ΔG∘\Delta G^\circ indicates greater thermodynamic stability.

    Step 2: Analyze the Assertion: The assertion states that FeOFeO can be more easily reduced than Cu2OCu_2O by carbon. This is incorrect. In an Ellingham diagram, the metal oxide with a less negative (higher) ΔG∘\Delta G^\circ at a given temperature is easier to reduce by carbon.

    Step 3: Analyze the Reason: The reason provides ΔG∘\Delta G^\circ values for FeOFeO and Cu2OCu_2O. The values given are incorrect based on typical Ellingham diagrams. Cu2OCu_2O has a more negative ΔG∘\Delta G^\circ than FeOFeO.

    Step 4: Conclusion: Both the assertion and the reason are false.

    Why other options are wrong:
    - Option A: This is incorrect because both the assertion and the reason are false.
    - Option B: This is incorrect because both the assertion and the reason are false.
    - Option C: This is incorrect because both the assertion and the reason are false.
    - Option D: This is correct because both the assertion and the reason are false.

    Key Concepts:
    - Ellingham Diagrams
    - Gibbs Free Energy of Formation
    - Reduction Potential

    Memory Aids:
    - Remember that in Ellingham diagrams, a lower line indicates a more stable oxide and a more difficult reduction.

    Quick Tips:
    - When comparing the reducibility of metal oxides, refer to Ellingham diagrams.
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