Skip to main content
Back to Equilibrium

Your Progress

0 / 408 Answered
0
Correct
0
Incorrect
0%
Accuracy
NEET • CHEMISTRY • Equilibrium

Equilibrium practice · Mixed difficulty

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

The practice player uses single-correct-answer MCQs. Chapter quizzes help you review a topic; they are not full-length NEET mock papers.

Take a chapter quiz →
Showing 391-408 of 408 questions
391 Easy
391 of 408
Understanding +4 | -1
Theory’s ‘active mass’ indicates that the rate of chemical reaction is directly proportional to the
View answer and explanation
Correct option: D
Concentration of reactants
Option D (Concentration of reactants) is correct because the rate of a chemical reaction is directly proportional to the active masses, which are effectively the concentrations, of the reactants.
392 Hard
392 of 408
Application +4 | -1
1 mole of NO2\mathrm{NO}_2 and 2 moles of CO\mathrm{CO} are enclosed in a one litre vessel to attain the following equilibrium NO2+CO⇋NO+CO2\mathrm{NO}_2+\mathrm{CO} \leftrightharpoons \mathrm{NO}+\mathrm{CO}_2. It was estimated that at the equilibrium, 25%25 \% of initial amount of CO\mathrm{CO} is consumed. The equilibrium constant Kp\mathrm{K}_{\mathrm{p}} is
View answer and explanation
Correct option: D
45717
Option A (8.58.5) is correct because it is calculated by determining the moles of each species at equilibrium based on the percentage of SO2\mathrm{S}{\mathrm{O}_2} used up.
393 Medium
393 of 408
Understanding +4 | -1
The solution of AgCl\mathrm{AgCl} is unsaturated if:
View answer and explanation
Correct option: A
[Ag+][Cl−]<Ksp\left[ {\mathrm{A}{\mathrm{g}^ + }} \right]\left[ {\mathrm{C}{\mathrm{l}^ - }} \right] < {K_{sp}}
Option A (Ag+[Cl−]<Ksp{\mathrm{A}{\mathrm{g}^ + }} \left[ {\mathrm{C}{\mathrm{l}^ - }} \right] < {K_{sp}}) is correct because an unsaturated solution exists when the ion product is less than the solubility product.
394 Easy
394 of 408
Understanding +4 | -1
In the case of gaseous homogeneous reaction, the concentrations of the reactants may be given by:
View answer and explanation
Correct option: C
nVRT\frac{n}{V}RT
Option B (PRT\frac{P}{{RT}}) is incorrect. Option B (PRT\frac{P}{{RT}}) is correct because, for a gaseous homogeneous reaction, concentration can be expressed as pressure divided by RT using the ideal gas law.
395 Hard
395 of 408
Analyzing +4 | -1
K1,K2K_1, K_2 and K3K_3 are the equilibrium constants of the following reactions (I), (II) and (III) respectively:

(I) N2+2O2⇌2NO2{N}_2+2 {O}_2 \rightleftharpoons 2 {NO}_2

(II) 2NO2⇌N2+2O22 {NO}_2 \rightleftharpoons {N}_2+2 {O}_2

(III) NO2⇌12 N2+O2{NO}_2 \rightleftharpoons \frac{1}{2} {~N}_2+{O}_2

The correct relation from the following is
View answer and explanation
Correct option: B
K1=1K2=1(K3)2K_1=\frac{1}{K_2}=\frac{1}{\left(K_3\right)^2}
Option B (K1=1K2=1(K3)2K_1=\frac{1}{K_2}=\frac{1}{\left(K_3\right)^2}) is correct because it accurately reflects the relationships between the equilibrium constants for the given reactions based on reversing and scaling the reactions.
396 Medium
396 of 408
Understanding +4 | -1
The correct relation for hydrolysis constant of NH4CN\mathrm{N}{\mathrm{H}_4}\mathrm{CN} is:
View answer and explanation
Correct option: B
KwKa×Kb\frac{{{K_w}}}{{{K_a} \times {K_b}}}
Option B (KwKa×Kb)\frac{{{K_w}}}{{{K_a} \times {K_b}}}) is correct because NH4CN\mathrm{N}{\mathrm{H}_4}\mathrm{CN} is a salt of a weak acid and a weak base, and the hydrolysis constant is given by this formula.
397 Easy
397 of 408
Application +4 | -1
An aqueous solution of 0.1  M  NH4Cl0.1\;M\;\mathrm{N}{\mathrm{H}_4}\mathrm{Cl} will have a pHpH closer to:
View answer and explanation
Correct option: D
5.15.1
Option D (5.15.1) is correct because NH4Cl\mathrm{N}{\mathrm{H}_4}\mathrm{Cl} is a salt of a weak base and a strong acid, making the solution acidic with a pHpH less than 7.
398 Easy
398 of 408
Understanding +4 | -1
The hydroxide having the lowest value of Ksp{K_{sp}} at 25∘C25^\circ C is:
View answer and explanation
Correct option: D
Be(OH)2\mathrm{Be}{\left( {\mathrm{OH}} \right)_2}
Option D (Be(OH)2\mathrm{Be}{\left( {\mathrm{OH}} \right)_2}) is correct because beryllium hydroxide has the smallest ionic radius and highest charge density among the given options, leading to the lowest solubility product.
399 Easy
399 of 408
Analyzing +4 | -1
Among BMe3,BF3,BCl3  and  B2H6\mathrm{BM}{\mathrm{e}_3},\mathrm{B}{\mathrm{F}_3},\mathrm{BC}{\mathrm{l}_3}\;\mathrm{and}\;{\mathrm{B}_2}{\mathrm{H}_6} which one will be the best Lewis acid?
View answer and explanation
Correct option: A
BCl3\mathrm{BC}{\mathrm{l}_3}
Option A (BCl3\mathrm{BC}{\mathrm{l}_3}) is correct because the back bonding is least effective due to the large size of Cl atom, making it the strongest Lewis acid among the given options.
400 Hard
400 of 408
Analyzing +4 | -1
For the equilibrium

A(g)+2 B( g)⇌AB2( g)\mathrm{A}(\mathrm{g})+2 \mathrm{~B}(\mathrm{~g}) \rightleftharpoons \mathrm{AB}_2(\mathrm{~g})

the value of equilibrium constant at 300k300 \mathrm{k} is 3×10−3 mole−2 L23 \times 10^{-3} \mathrm{~mole}^{-2} \mathrm{~L}^2 and value of equilibrium constant at 500k500 \mathrm{k} is 5×10−5 mol−2 L25 \times 10^{-5} \mathrm{~mol}^{-2} \mathrm{~L}^2.

What is the sign of enthalpy change for this reaction
View answer and explanation
Correct option: B
Negative
Option B (Negative) is correct. Since the equilibrium constant decreases as temperature increases, the reaction is exothermic, indicating a negative enthalpy change.
401 Medium
401 of 408
Remembering +4 | -1
Which of the following is a strong acid?
View answer and explanation
Correct option: A
HClO4\mathrm{HCl}{\mathrm{O}_4}
Option A (HClO4\mathrm{HCl}{\mathrm{O}_4}) is correct because perchloric acid is one of the strongest known acids, readily donating its proton in solution.
402 Medium
402 of 408
Analyzing +4 | -1
For the following three reactions I, II and III, equilibrium constants are given
I. CO(g)+H2O(g)⇋CO2(g)+H2(g);K1\mathrm{CO}\left( \mathrm{g} \right) + {\mathrm{H}_2}\mathrm{O}\left( \mathrm{g} \right)\leftrightharpoons\mathrm{C}{\mathrm{O}_2}\left( \mathrm{g} \right) + {\mathrm{H}_2}\left( \mathrm{g} \right);{K_1}
II.&nbsp;CH4(g)+H2O(g)⇋CO(g)+3H2(g);K2\mathrm{C}{\mathrm{H}_4}\left( \mathrm{g} \right) + {\mathrm{H}_2}\mathrm{O}\left( \mathrm{g} \right)\leftrightharpoons\mathrm{CO}\left( \mathrm{g} \right) + 3{\mathrm{H}_2}\left( \mathrm{g} \right);{K_2}
III.&nbsp;CH4(g)+2H2O(g)⇋CO2(g)+4H2(g);K3\mathrm{C}{\mathrm{H}_4}\left( \mathrm{g} \right) + 2{\mathrm{H}_2}\mathrm{O}\left( \mathrm{g} \right)\leftrightharpoons\mathrm{C}{\mathrm{O}_2}\left( \mathrm{g} \right) + 4{\mathrm{H}_2}\left( \mathrm{g} \right);{K_3}
Which of the following relations is correct?
&nbsp;
View answer and explanation
Correct option: C
K3=K1K2{K_3} = {K_1}{K_2}
Option C (K₃ = K₁K₂) is correct because reaction III can be obtained by adding reactions I and II. When reactions are added, their equilibrium constants are multiplied.
403 Hard
403 of 408
Application +4 | -1
What is PH{P^H} of 0.02 M solution of ammonium chloride at 25oC    (Kb  of  NH3=1.8×10−5){25^\mathrm{o}}C\,\,\,\,\left( {{K_b}\,\,\mathrm{ of }\,\,N{H_3} = 1.8 \times {{10}^{ - 5}}} \right)
View answer and explanation
Correct option: A
5.477
Option A (5.477) is correct because it is the pH calculated using the hydrolysis constant and concentration of the ammonium chloride solution.
404 Medium
404 of 408
Application +4 | -1
Consider the reaction, CH3COOH+C2H5OH    ⇋    CH3COOC2H5+H2O.C{H_3}COOH\mathrm{ } + \mathrm{ }{C_2}{H_5}OH\;\;\leftrightharpoons\;\;C{H_3}COO{C_2}{H_5} + \mathrm{ }{H_2}O. One mole each of CH3COOHC{H_3}COOH and C2H5OH{C_2}{H_5}OH are heated in the presence of little concentrated H2SO4.{H_2}S{O_4}. On equilibrium:
View answer and explanation
Correct option: D
2/32/3 mole of ethyl acetate is formed
Option D (2/32/3 mole of ethyl acetate is formed) is correct because it is calculated using the equilibrium constant and initial moles of reactants.
405 Medium
405 of 408
Analyzing +4 | -1
Which of the following is the best conductor of electricity?
View answer and explanation
Correct option: D
1M   H2SO41M\,\,\,{H_2}S{O_4}
Option D (1M   H2SO41M \,\,\,{H_2}S{O_4}) is the best conductor because it is a strong acid that dissociates completely into ions in solution, leading to higher conductivity.
406 Easy
406 of 408
Application +4 | -1
A decimolar solution of ammonium hydroxide is ionised to the extent of 1.3%1.3\%. If log⁡1.3\log 1.3. If log⁡1.3=0.11\log 1.3 = 0.11 what is the pHpH of the solution?
View answer and explanation
Correct option: A
11.1111.11
Option A (11.11) is correct because the pOH is calculated from the ionization extent, and then the pH is found using the relationship pH + pOH = 14.
407 Hard
407 of 408
Analyzing +4 | -1
The concentration of CH3COO−{CH}_3 {COO}^{-} ion in a solution prepared by adding 0.1 mole of CH3COOAg(s){CH}_3 {COOAg}(\mathrm{s}) in 1 L of 0.1 M−HCl0.1 \mathrm{~M}-{HCl} solution is [Given: Ka(CH3COOH)=10−5;Ksp(AgCl)=10−10;Ksp(CH3COOAg)=10−8]\left[\text{Given: }K_{\mathrm{a}}\left({CH}_3 {COOH}\right)=10^{-5} ; K_{\mathrm{sp}}({AgCl})=10^{-10} ; K_{\mathrm{sp}}\left({CH}_3 {COOAg}\right)=10^{-8}\right]
View answer and explanation
Correct option: B
10−2M10^{-2} \mathrm{M}
Option B (10−2M10^{-2} \mathrm{M}) is correct because the concentration of CH3COO- is determined by the solubility of CH3COOAg in the presence of HCl, which suppresses the acetate ion concentration.
408 Hard
408 of 408
Application +4 | -1
1 mole of N2O4(g){\mathrm{N}_2}{\mathrm{O}_4}\left( \mathrm{g} \right) at 300 K is kept in a closed container under 1 atm. It is heated to 600 K when 20% by mass ofN2O4(g){\mathrm{N}_2}{\mathrm{O}_4}\left( \mathrm{g} \right) decomposes to NO2(g)\mathrm{N}{\mathrm{O}_2}\left( \mathrm{g} \right). The resultant pressure is
View answer and explanation
Correct option: B
2.4 atm
Option B (2.4 atm) is correct because it represents the resultant pressure calculated considering the decomposition of N2O4 and the temperature change.
Revision notes and key takeaways

Review Equilibrium in your textbook or class notes, then use this set to check your understanding.

Showing 391-408 of 408 questions
0 /408
0✓ 0✗
0% Accuracy
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.