NEET UG CHEMISTRY MCQ: Equilibrium

1 Hard

1 of 1

Understanding +4 | -1

For a sparingly soluble salt

{A}_{{p}} {B}_{{q}},

the relationship of its solubility product

\left(L_{{S}}\right)

with its solubility

(S)

View answer and explanation

Correct option: A

L_{{S}}=S^{p+q} \cdot p^p \cdot q^q

Option A is correct because the solubility product is related to solubility by the equation

L_{{S}}=S^{p+q} \cdot p^p \cdot q^q

for a sparingly soluble salt

{A}_{{p}} {B}_{{q}}

More Questions from Equilibrium

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Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}