Identify the correct order of solubility of ${\rm{N}}{{\rm{a}}_2}{\rm{S}},{\rm{CuS}}$ and ${\rm{ZnS}}$ in aqueous medium:

${\rm{N}}{{\rm{a}}_2}{\rm{S}} > ZnS > CuS$

${\rm{CuS}} > ZnS > N{{\rm{a}}_2}{\rm{S}}$

${\rm{ZnS}} > N{{\rm{a}}_2}{\rm{S}} > CuS$

${\rm{N}}{{\rm{a}}_2}{\rm{S}} > CuS > ZnS$

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NEET • CHEMISTRY • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

Classification of elements and periodicity in properties practice · Mixed difficulty

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121 Hard

121 of 407

Understanding +4 | -1

Which of the following orders of ionic radius is correctly represented?

View answer and explanation

Correct option: A

\mathrm{H}^{-} > \mathrm{H} > \mathrm{H}^{+}

Option A (

\mathrm{H}^{-} > \mathrm{H} > \mathrm{H}^{+}

) is correct because adding electrons increases the ionic radius, while removing electrons decreases it.

122 Easy

122 of 407

Analyzing +4 | -1

Which one of the following statement is false?

View answer and explanation

Correct option: A

The electron affinity of chlorine is less than that of fluorine.

Option A (The electron affinity of chlorine is less than that of fluorine) is correct because chlorine has a higher electron affinity than fluorine due to smaller size and higher interelectronic repulsion in fluorine.

123 Medium

123 of 407

Analyzing +4 | -1

Given below are two statements:
Statement I: The pentavalent oxide of group-15 element,

{E_2}{O_5}

, is less acidic than trivalent oxide,

{E_2}{O_3}

, of the same element.
Statement II: The acidic character of trivalent oxide of group 15 elements,

{E_2}{O_3}

, decreases down the group.
In light of the above statements, choose most appropriate answer from the options given below:

View answer and explanation

Correct option: D

Statement I false, but Statement II is true

Option D (Statement I false, but Statement II is true) is correct because the pentavalent oxide is more acidic than the trivalent oxide, and the acidic character of trivalent oxides decreases down the group.

124 Medium

124 of 407

Understanding +4 | -1

Elements of group 1 and group VI in the periodic table have one thing common. That is with the increasing atomic number, the:

View answer and explanation

Correct option: C

Atomic radius increases

Option C (Atomic radius increases) is correct because, within a group, atomic radius generally increases with increasing atomic number due to the addition of electron shells.

125 Easy

125 of 407

Remembering +4 | -1

Which of the following element has less electro negativity

View answer and explanation

Correct option: B

Option B (S) is correct because electronegativity decreases down a group in the periodic table, and sulfur (S) is below oxygen (O) in Group 16.

126 Medium

126 of 407

Analyzing +4 | -1

Which of the following halides is most acidic?

View answer and explanation

Correct option: B

\mathrm{PC}{\mathrm{l}_3}

Option B (PCl3) is the most acidic because the central atom (P) has the highest oxidation state and electronegativity among the given options, leading to a greater polarization of the P-Cl bond and easier release of H+ ions upon hydrolysis.

127 Easy

127 of 407

Remembering +4 | -1

Neutral oxide among the following is

View answer and explanation

Correct option: C

CO

Option C (

CO

) is correct because carbon monoxide (CO) does not react with either acids or bases, making it a neutral oxide.

128 Easy

128 of 407

Application +4 | -1

The ratio of radius of 2nd and 3rd Bohr orbit is

View answer and explanation

Correct option: D

0.172916667

Option C (

{N}_2, {CO}, {CN}^{-}, {O}_2^{+2}

) is correct because all species have the same number of electrons (14).

129 Medium

129 of 407

Understanding +4 | -1

The correct order of decreasing first ionisation energy is

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Correct option: B

C\mathrm{ } > \mathrm{ }Be\mathrm{ } > \mathrm{ }B\mathrm{ } > \mathrm{ }Li

Option D (Acid and base) is correct because ZnO reacts with a base (Na2O) to form a salt, acting as an acid, and reacts with an acid (CO2) to form a salt, acting as a base.

130 Medium

130 of 407

Understanding +4 | -1

Which of the following oxides is most basic?

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Correct option: A

\mathrm{N}{\mathrm{a}_2}\mathrm{O}

Option A (Na₂O) is the most basic oxide because oxides of Group 1 elements are strongly basic.

131 Easy

131 of 407

Understanding +4 | -1

Born Haber cycle is used to determine:

View answer and explanation

Correct option: D

Either of them

Option D (Either of them) is correct because the Born-Haber cycle relates lattice energy, electron affinity, ionization energy, and other thermodynamic quantities, allowing for the determination of any one of them if the others are known.

132 Easy

132 of 407

Remembering +4 | -1

Which of the following set of elements follows dobereiner law of triads

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Correct option: B

Li, Na, K

Option B is correct. The Dobereiner's law of triads states that the atomic mass of the middle element is approximately the arithmetic mean of the atomic masses of the other two elements. Li, Na, and K follow this law.

133 Easy

133 of 407

Analyzing +4 | -1

In which of the following arrangements the order is not correct according to property indicated against it?

View answer and explanation

Correct option: B

Increasing

I{E_1}\mathrm{\;}:\mathrm{B} < C < N < O

Option B (Increasing

I{E_1}\mathrm{\;}:\mathrm{B} < C < N < O

) is correct because the first ionization energy of Oxygen is less than Nitrogen due to the extra stability of half-filled p-orbitals in Nitrogen.

134 Easy

134 of 407

Application +4 | -1

Maximum number of orbitals in

3^{\text {rd }}

excited state of

L i^{+2}=x

. Electronegativity (Pauling scale) of most electronegative element

=y

. Then find value of

\left(\frac{x}{y}\right)

View answer and explanation

Correct option: A

Option A (4) is correct because the value of x is 16 and the electronegativity of fluorine is 4, so x/y = 16/4 = 4.

135 Easy

135 of 407

Remembering +4 | -1

The only non-metal which is liquid at ordinary temperature is

View answer and explanation

Correct option: B

B{r_2}

Option B (

B{r_2}

) is correct because Bromine (

B{r_2}

) is the only non-metal that exists as a liquid at room temperature.

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136 Medium

136 of 407

Understanding +4 | -1

Which of the following obeys triad law :

View answer and explanation

Correct option: D

Both (1) and (3)

The correct answer is D (Both (1) and (3)) because both Li, Na, K and Be, Mg, Ca follow Dobereiner's Triad law.

137 Easy

137 of 407

Understanding +4 | -1

Generally, the first ionisation energy increases along a period. But there are some exceptions. One which is not an exception is

View answer and explanation

Correct option: B

Na and Mg

Option A (Na and Mg) is correct because the general trend of increasing ionization energy is followed between Na and Mg, while other pairs have exceptions due to electronic configurations.

138 Easy

138 of 407

Application +4 | -1

Find the element having outer electronic configuration

(n-1) d^2 n s^2

for

n=4

View answer and explanation

Correct option: C

Titanium

Option C (Titanium) is correct because Titanium (Ti) has an atomic number of 22, and its electronic configuration matches the given formula for n=4.

139 Easy

139 of 407

Analyzing +4 | -1

Which of the following species show maximum ionisation energy

View answer and explanation

Correct option: B

N{e^ + }

Option B (

N{e^ + }

) exhibits the maximum ionization energy because it has already lost one electron, resulting in a higher effective nuclear charge and making it more difficult to remove another electron.

140 Medium

140 of 407

Application +4 | -1

If each orbital can hold a maximum of 3 electrons,
number of elements in fourth period of periodic table
is :

View answer and explanation

Correct option: C

Option C (27) is correct because with each orbital holding 3 electrons, the filling order changes, leading to a different number of elements in the fourth period.

141 Medium

141 of 407

Remembering +4 | -1

Which oxide is amphoteric in nature?

View answer and explanation

Correct option: A

ZnO

Option A (ZnO) is correct because Zinc oxide can act as both an acid and a base.

142 Medium

142 of 407

Remembering +4 | -1

The compounds of the

s

-block elements, with the exception of lithium and beryllium are predominantly

View answer and explanation

Correct option: A

Ionic

Option A (Ionic) is correct because compounds of s-block elements (except Li and Be) are predominantly ionic due to their low ionization energies.

143 Easy

143 of 407

Remembering +4 | -1

Decreasing electro negativities of

F,Cl,Br

and I is

View answer and explanation

Correct option: B

F > Cl > Br > I

Option B (

F > Cl > Br > I

) is correct because electronegativity decreases down the halogen group.

144 Hard

144 of 407

Application +4 | -1

If the electronegativity difference between two atoms

A

and

B

is 2.0, then the percentage of covalent character in the molecule is

View answer and explanation

Correct option: A

54\%

Option A (

54\%

) is correct because the percentage of covalent character can be estimated using the Pauling equation, which relates electronegativity difference to ionic character, and then subtracting from 100%.

145 Easy

145 of 407

Understanding +4 | -1

The screening effect of d-electrons is:

View answer and explanation

Correct option: D

Less than p-electrons

Option D (Less than p-electrons) is correct because d-electrons have a more diffused shape and are less effective at shielding the nuclear charge compared to p-electrons.

146 Hard

146 of 407

Understanding +4 | -1

The elements X,Y,Z and T have the indicated electronic configuration. Starting with the innermost shell, which is the most metallic element?

View answer and explanation

Correct option: C

Z=2,8,8,1

Option C (Z=2,8,8,1) is correct because metallic character increases with the ease of losing electrons, and this configuration has only one valence electron, making it the most metallic.

147 Medium

147 of 407

Remembering +4 | -1

Mendeleev corrected the atomic mass of:

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because Mendeleev corrected the atomic masses of Beryllium, Indium, and Osmium to better fit them into his periodic table based on their properties.

148 Hard

148 of 407

Understanding +4 | -1

Identify the correct order of solubility of

\mathrm{N}{\mathrm{a}_2}\mathrm{S},\mathrm{CuS}

and

\mathrm{ZnS}

in aqueous medium:

View answer and explanation

Correct option: D

\mathrm{N}{\mathrm{a}_2}\mathrm{S} > ZnS > CuS

Option D (

\mathrm{N}{\mathrm{a}_2}\mathrm{S} > ZnS > CuS

) is correct because alkali metal sulfides are generally soluble, while transition metal sulfides are generally insoluble, with CuS being the least soluble due to its high lattice energy.

149 Medium

149 of 407

Remembering +4 | -1

Out of the four blocks in which periodic table is divided, helium belongs to which block?

View answer and explanation

Correct option: B

p

-block

Option B is correct. Helium (He) belongs to the p-block because its position is in group 18, even though it has an s² configuration.

150 Easy

150 of 407

Remembering +4 | -1

Which is the general outer electronic configuration of the coinage metals?

View answer and explanation

Correct option: B

\left( {n - 1} \right){d^{10}}n{s^1}

Option B is correct because coinage metals (Cu, Ag, Au) have a general outer electronic configuration of (n-1)d¹⁰ns¹ due to the stability of the fully filled d-orbital.

Revision notes and key takeaways

Review CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES in your textbook or class notes, then use this set to check your understanding.

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