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NEET • CHEMISTRY • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

Classification of elements and periodicity in properties practice · Mixed difficulty

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91 Hard

91 of 407

Application +4 | -1

One mole of magnesium in the vapour state absorbed 1200

\mathrm{kJmo}{\mathrm{l}^{ - 1}}

of energy. If the first and second ionisation energies of Mg are 750 and 1450

\mathrm{kJmo}{\mathrm{l}^{ - 1}}

respectively, the final composition of the mixture is

View answer and explanation

Correct option: B

69\mathrm{\% M}{\mathrm{g}^ + } + 31\mathrm{\% M}{\mathrm{g}^{2 + }}

Option B (

69\% \mathrm{Mg}^+ + 31\% \mathrm{Mg}^{2+}

) is correct because it accurately calculates the percentage of Mg+ and Mg2+ ions formed based on the energy absorbed and the ionization energies.

92 Medium

92 of 407

Application +4 | -1

Assign the position of the element having outer electronic configuration

n s^2 n p^4

for

n=3

View answer and explanation

Correct option: A

Third period, 16th group

The correct answer is A (Third period, 16th group) because with

n=3

, the electronic configuration is

3s^2 3p^4

, indicating it's in the third period and group 16 (chalcogens).

93 Easy

93 of 407

Understanding +4 | -1

The dipositive ion can be formed by the atom with configuration

View answer and explanation

Correct option: D

n{s^2}

Option D (

n{s^2}

) is correct because an atom with this configuration can lose two electrons from the s-orbital to form a dipositive ion.

94 Medium

94 of 407

Analyzing +4 | -1

Which statement is wrong?

View answer and explanation

Correct option: C

Maximum electron affinity exists for

\mathrm{F}

Option C is wrong because maximum electron affinity exists for

\mathrm{Cl}

not

\mathrm{F}

due to its smaller size and strong interelectronic repulsions.

95 Medium

95 of 407

Analyzing +4 | -1

Which of the following does not represents the correct order of the property indicated?

View answer and explanation

Correct option: A

\mathrm{S}{\mathrm{c}^{3 + }} > C{\mathrm{r}^{3 + }} > F{\mathrm{e}^{3 + }} > M{\mathrm{n}^{3 + }} -

ionic radii

Option C is incorrect because the first ionization energy of Nitrogen is higher than Oxygen due to the stable half-filled p-orbital configuration of Nitrogen.

96 Easy

96 of 407

Analyzing +4 | -1

Which of the following sequence correctly represents the decreasing acidic nature of oxides?

View answer and explanation

Correct option: C

{\mathrm{N}_2}{\mathrm{O}_3} > \mathrm{C}{\mathrm{O}_2} > {\mathrm{B}_2}{\mathrm{O}_3} > \mathrm{BeO} > \mathrm{L}{\mathrm{i}_2}\mathrm{O}

Option C (

{\mathrm{N}_2}{\mathrm{O}_3} > \mathrm{C}{\mathrm{O}_2} > {\mathrm{B}_2}{\mathrm{O}_3} > \mathrm{BeO} > \mathrm{L}{\mathrm{i}_2}\mathrm{O}

) correctly represents the decreasing acidic nature of oxides because non-metal oxides are acidic, and metallic oxides are basic.

97 Hard

97 of 407

Analyzing +4 | -1

The correct order of ionic radius is

View answer and explanation

Correct option: D

{\mathrm{P}^{3 + }} > {\mathrm{P}^{5 + }}

Option D (

{\mathrm{P}^{3 + }} > {\mathrm{P}^{5 + }}

) is correct because a smaller positive charge results in a larger ionic radius due to reduced effective nuclear charge.

98 Medium

98 of 407

Remembering +4 | -1

The atomic radius of Ag is closest to

View answer and explanation

Correct option: B

Option B is correct because Au (Gold) has an atomic radius closest to that of Ag (Silver) due to the lanthanide contraction affecting the size of gold.

99 Easy

99 of 407

Understanding +4 | -1

Among the following most metallic element is

View answer and explanation

Correct option: C

Option C (K) is correct because Potassium (K) is an alkali metal and has the lowest ionization energy among the given options, making it the most metallic.

100 Easy

100 of 407

Analyzing +4 | -1

Which of the following have the same number of electrons in outermost shell?

View answer and explanation

Correct option: A

Elements with atomic number 30, 48, 80

Option A (Elements with atomic number 30, 48, 80) is correct because they all belong to group 12 and have 2 electrons in their outermost shell after filling the d-orbitals.

101 Easy

101 of 407

Remembering +4 | -1

Which element has the lowest electronegativity?

View answer and explanation

Correct option: A

Option A (Li) is correct because electronegativity generally decreases down and to the left on the periodic table, and Lithium is the furthest to the left among the options.

102 Easy

102 of 407

Remembering +4 | -1

The discovery of which of the following group of elements gave death blow to the Newland’s law of octaves?

View answer and explanation

Correct option: A

Inert gases

Option A (Inert gases) is correct because the discovery of inert gases added new elements, disrupting the octaves pattern.

103 Hard

103 of 407

Understanding +4 | -1

Arrange the elements

N,\,\,\,P,\,\,\,O

and

S

in the order of increasing non-metallic nature.

View answer and explanation

Correct option: B

P < S < N < O

Option B (

P < S < N < O

) is correct because non-metallic character increases across a period and decreases down a group.

104 Easy

104 of 407

Application +4 | -1

The amount of energy released when

10^6

atoms of iodine in vapour state are converted to

\mathrm{I}^{-}

ions is

4.9 \times 10^{-13} \mathrm{~J}

. What is the electron affinity of iodine in

\mathrm{eV}

per atom?

View answer and explanation

Correct option: D

-3.06

Option D (-3.06) is correct because the electron affinity is calculated by dividing the total energy released by the number of atoms and converting the units to eV.

105 Medium

105 of 407

Understanding +4 | -1

Which of the following ion is the smallest ion?

View answer and explanation

Correct option: B

O_2^ +

Option B (

O_2^+

) is correct because removing an electron from a molecule reduces electron-electron repulsion and increases the effective nuclear charge, leading to a smaller size.

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106 Medium

106 of 407

Understanding +4 | -1

The following ion is colourless in aqueous solution

View answer and explanation

Correct option: D

All the above

The correct answer is D (All the above) because

Ca^{2+}

Sc^{3+}

, and

Zn^{2+}

are all colorless in aqueous solution due to having no d-d transitions.

107 Easy

107 of 407

Analyzing +4 | -1

The electronic configuration of the atom having maximum difference in first and second ionisation energies is

View answer and explanation

Correct option: A

1{s^2},2{s^2},2{p^6},3{s^1}

Option A (

1{s^2},2{s^2},2{p^6},3{s^1}

) is correct because the removal of the single 3s electron results in a stable noble gas configuration, leading to a large jump in ionization energy.

108 Medium

108 of 407

Understanding +4 | -1

The tendency towards formation of coloured ions is the maximum in:

View answer and explanation

Correct option: B

d-block elements

The correct answer is B (d-block elements) because d-block elements have unpaired d-electrons which allow for d-d transitions, leading to the formation of colored ions.

109 Easy

109 of 407

Application +4 | -1

An element ‘x’occurs in short period having configuration

n{s^2}n{p^1}

. The formula and nature of its oxide is

View answer and explanation

Correct option: C

{x_2}{o_3}

Amphoteric

Option C (

{x_2}{o_3}

Amphoteric) is correct because the element 'x' belongs to group 13 (ns²np¹) and its oxide is amphoteric.

110 Easy

110 of 407

Understanding +4 | -1

Mendeleef’s Periodic Table is upset by the fact that

View answer and explanation

Correct option: A

Many elements has several isotopes

Option A is correct because the existence of isotopes with varying neutron numbers disrupts the strict ordering based on atomic weight that Mendeleev initially used.

111 Medium

111 of 407

Remembering +4 | -1

The electron affinity of for the inert gases is

View answer and explanation

Correct option: A

Zero

Option A (Zero) is correct because inert gases have a stable electronic configuration and do not tend to accept electrons, resulting in zero electron affinity.

112 Medium

112 of 407

Remembering +4 | -1

The electronegativity order of

O

F

Cl

and

Br

is:

View answer and explanation

Correct option: A

\mathrm{F} > O > Cl > Br

Option A (

\mathrm{F} > O > Cl > Br

) is correct because it represents the correct order of electronegativity for the given elements.

113 Medium

113 of 407

Remembering +4 | -1

Electron affinity is measured in

View answer and explanation

Correct option: D

Both 2 and 3

Option D (Both 2 and 3) is correct because electron affinity is an energy change, and energy is commonly measured in both

K\,cal\,mo{l^{ - 1}}

and

kJ\,mo{l^{ - 1}}

114 Easy

114 of 407

Remembering +4 | -1

Atomic radii of

F

and

Ne

{A^0}

, are given by

View answer and explanation

Correct option: B

0.72, 1.60

Option B (0.72, 1.60) is correct because atomic radii decrease across a period, and noble gases have larger van der Waals radii.

115 Medium

115 of 407

Remembering +4 | -1

The elements with atomic numbers 9, 17, 35, 53, 85 are all

View answer and explanation

Correct option: A

Halogens

Option A (Halogens) is correct because elements with atomic numbers 9 (Fluorine), 17 (Chlorine), 35 (Bromine), 53 (Iodine), and 85 (Astatine) are all halogens.

116 Medium

116 of 407

Remembering +4 | -1

Atomic number of element Ununnillium is

View answer and explanation

Correct option: B

110

Option B (110) is correct because Ununnillium is the IUPAC name for the element with atomic number 110.

117 Medium

117 of 407

Understanding +4 | -1

Which of the atomic number pairs represents elements of s-block?

View answer and explanation

Correct option: D

3,12

Option D (3,12) is correct because element with atomic number 3 (Lithium) has electronic configuration

1s^22s^1

and element with atomic number 12 (Magnesium) has electronic configuration

1s^22s^22p^63s^2

, both having their last electron in s-orbital.

118 Easy

118 of 407

Application +4 | -1

The electro negativity of

\mathrm{H}, \mathrm{X}

and

\mathrm{O}

are

2.1,0.8

and

3.5

respectively on Pauling scale. The nature of compound

\mathrm{HOX}

is:

View answer and explanation

Correct option: B

Basic

Option B (Basic) is correct because the electronegativity difference between M' and O is smaller than between H and O, indicating a higher tendency for M'-O bond to break, releasing OH- ions.

119 Easy

119 of 407

Remembering +4 | -1

The element which occupies peak of Lother Meyer curve is

View answer and explanation

Correct option: C

K

Option C (

K

) is correct because alkali metals like Potassium (K) occupy the peaks in the Lothar Meyer curve.

120 Easy

120 of 407

Understanding +4 | -1

Which pair has both members from the same period of Periodic Table?

View answer and explanation

Correct option: D

Na, Cl

Option D (Na, Cl) is correct because both Sodium (Na) and Chlorine (Cl) are in the same period (Period 3) of the Periodic Table.

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