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NEET • CHEMISTRY • CHEMICAL KINETICS

Chemical kinetics practice · Mixed difficulty

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61 Medium
61 of 207
Analyzing +4 | -1
Which statement is not correct?
View answer and explanation
Correct option: B
For exothermic reactions, heat of reaction is more than energy of activation
Option B (For exothermic reactions, heat of reaction is more than energy of activation) is correct because for exothermic reactions, the heat of reaction is negative, and its magnitude is typically less than the activation energy.
62 Medium
62 of 207
Analyzing +4 | -1
The data for the reaction, A+B→C\mathrm{ }A + B \to C
Ex                      [A]0                  [B]0                  Initial  rate1                            0.012                0.035                              0.102                          0.024                  0.070                              0.803                          0.024                    0.035                          0.104                          0.012                  0.070                          0.80\begin{array}{l} Ex\;\;\;\;\;\;\;\;\;\;\;{\left[ A \right]_0}\;\;\;\;\;\;\;\;\;{\left[ B \right]_0}\;\;\;\;\;\;\;\;\;Initial\;\mathrm{ }rate\\ \begin{array}{llllllllllllllllllll} {1\;\;\;\;\;\;\;\;\;\;\;\;\;\;0.012\;\;\;\;\;\;\;\;0.035\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;0.10}\\ {2\;\;\;\;\;\;\;\;\;\;\;\;\;0.024\;\;\;\;\;\;\;\;\;0.070\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;0.80}\\ {3\;\;\;\;\;\;\;\;\;\;\;\;\;0.024\;\;\;\;\;\;\;\;\;\;0.035\;\;\;\;\;\;\;\;\;\;\;\;\;0.10}\\ {4\;\;\;\;\;\;\;\;\;\;\;\;\;0.012\;\;\;\;\;\;\;\;\;0.070\;\;\;\;\;\;\;\;\;\;\;\;\;0.80} \end{array} \end{array}
The rate law corresponds to the above data is
View answer and explanation
Correct option: A
rate=k[B]3rate = k{\left[ B \right]^3}
Option A (rate=k[B]3rate = k{\left[ B \right]^3}) is correct because the rate is only dependent on the concentration of B, and the order with respect to B is 3.
63 Easy
63 of 207
Understanding +4 | -1
Slope and intercepts of the plots log10  K  vs  1T\mathrm{ }lo{g_{10}}\;K\;\mathrm{vs}\;\frac{1}{T} are given respectively by :
View answer and explanation
Correct option: C
−ΔH∘2.303  R,ΔS∘2.303  R\frac{{ - \Delta {H^ \circ }}}{{2.303\;R}},\frac{{\Delta {S^ \circ }}}{{2.303\;R}}
Option C is correct because the slope and intercept of the plot log₁₀K vs 1/T are given by -ΔH°/(2.303R) and ΔS°/(2.303R) respectively, according to the van't Hoff equation.
64 Easy
64 of 207
Understanding +4 | -1
In a reaction, the threshold energy is equal to:
View answer and explanation
Correct option: A
Activation energy + normal energy of reactants
Option A (Activation energy + normal energy of reactants) is correct because threshold energy is the sum of the activation energy (the extra energy needed for the reaction) and the initial energy possessed by the reactants.
65 Hard
65 of 207
Analyzing +4 | -1
In the given first-order sequential reactions A→K1B→K2C→K3D,\mathrm{A}\xrightarrow{K_1} \mathrm{B} \xrightarrow{K_2} \mathrm{C} \xrightarrow{K_3} \mathrm{D}, what is the ratio of number of atoms of A\mathrm{A} to the number of atoms of B\text{B} after long time interval starting with pure A?\text{A}? (K1=ln⁡21200 and K2=ln⁡230)\left(K_1=\frac{\ln 2}{1200} \text{ and }K_2=\frac{\ln 2}{30}\right)
View answer and explanation
Correct option: D
40
Option D (40) is correct because after a long time, all of A will convert to D through B and C, and the ratio of A to B will depend on the rate constants K1 and K2.
66 Medium
66 of 207
Understanding +4 | -1
Which of the following quantities changes on addition of a catalyst during a chemical reaction ?
View answer and explanation
Correct option: B
Activation energy
Option B (Activation energy) is correct because a catalyst lowers the activation energy of a reaction, thus speeding it up.
67 Easy
67 of 207
Understanding +4 | -1
The efficiency of an enzyme in catalyzing a reaction is due to its capacity
View answer and explanation
Correct option: D
To lower the activation energy of the reaction
Option D (To lower the activation energy of the reaction) is correct because enzymes act as catalysts by reducing the activation energy required for a reaction to proceed, thus increasing the reaction rate.
68 Hard
68 of 207
Application +4 | -1
From the following data, the activation energy for the reaction (cal/mol):

H2+I2→2HI{\mathrm{H}_2} + {\mathrm{I}_2} \to 2\mathrm{HI}

T,K            1T,K−1            log⁡10K769          1.3×10−3                2.9667          1.5×10−3                1.1\begin{array}{l} T,K\;\;\;\;\;\;1T,{K^{ - 1}}\;\;\;\;\;\;{\log _{10}}K\\ 769\;\;\;\;\;1.3 \times {10^{ - 3}}\;\;\;\;\;\;\;\;2.9\\ 667\;\;\;\;\;1.5 \times {10^{ - 3}}\;\;\;\;\;\;\;\;1.1 \end{array}
View answer and explanation
Correct option: A
4×1044 \times {10^4}
Option A (4×1044 \times {10^4}) is correct because it is the activation energy calculated using the Arrhenius equation with the given data.
69 Easy
69 of 207
Analyzing +4 | -1
For a certain reaction a plot of [c0−c]c\frac{{\left[ {{c_0} - c} \right]}}{c} against time tt, yields a straight line. c0  and  c{{c_0}\;and\;c} are concentrations of reactant at t=0  and  t=tt = 0\;and\;t = t respectively. The rate of reaction is:
View answer and explanation
Correct option: D
2
Option D (2) is correct because the given plot indicates a second-order reaction.
70 Hard
70 of 207
Analyzing +4 | -1
For the reaction aA+bB→P,r=K[A]a⋅[B]b,{aA}+{bB} \rightarrow {P}, r=K[{A}]^a \cdot [{B}]^b, if the concentration of A{A} is doubled, then the rate is doubled. If the concentration of B{B} is doubled, then the rate becomes four times. The correct relation is
View answer and explanation
Correct option: C
2⋅d[A]dt=d[B]dt2 \cdot \frac{{d}[{A}]}{{d} t}=\frac{{d}[{B}]}{{d} t}
The correct answer is C (2⋅d[A]dt=d[B]dt2 \cdot \frac{{d}[{A}]}{{d} t}=\frac{{d}[{B}]}{{d} t}) because the rate law indicates that A is first order and B is second order, meaning for every two moles of A consumed, one mole of B is consumed.
71 Medium
71 of 207
Understanding +4 | -1
Which plots will give the value of activation energy?
View answer and explanation
Correct option: D
ln⁡  K  vs.  1T\ln \;K\;\mathrm{ }vs.\;\frac{1}{T}
Option D (ln⁡  K    vs.  1T\ln \;K\;\mathrm{ }\;vs.\;\frac{1}{T}) is correct because the slope of this plot is related to the activation energy according to the Arrhenius equation.
72 Easy
72 of 207
Application +4 | -1
For a reaction A→products,A \to products, rate law is -−d[A]dt=K[A]0.- \frac{{d\left[ A \right]}}{{dt}} = K{\left[ A \right]_0}. The concentration of A left after time tt when t=1Kt = \frac{1}{K} is:
View answer and explanation
Correct option: A
[A]0e\frac{{{{\left[ A \right]}_0}}}{e}
Option A ([A]0e\frac{{{{\left[ A \right]}_0}}}{e}) is correct because it is derived from integrating the given rate law and substituting the given time.
73 Easy
73 of 207
Application +4 | -1
In a reaction 2A→products2A \to products; the concentration of A decreases from 0.5  mol  litre−1  to  0.4  mol  litre−10.5\;\mathrm{mol}\;\mathrm{litr}{\mathrm{e}^{ - 1}}\;to\;0.4\;\mathrm{mol}\;\mathrm{litr}{\mathrm{e}^{ - 1}} in 10 minute. The rate of reaction during this interval is:
View answer and explanation
Correct option: B
0.005  M  min⁡−10.005\;M\;{\min ^{ - 1}}
Option B (0.005  M  min⁡−10.005\;M\;{\min ^{ - 1}}) is correct because the rate of the reaction is half the rate of disappearance of A, considering the stoichiometry.
74 Hard
74 of 207
Application +4 | -1
The slope of Arrhenius plot (ln⁡ k v/s1T)\left( {\ln \,k\,\mathrm{v/s}\frac{1}{T}} \right) of first order reaction is −5×103K.- 5 \times {10^3}K. The value of Ea{E_a} of the reaction is.
Choose the correct option for your answer.
[Given R=8.314JK−1mol−1R = 8.314\mathrm{ J}{\mathrm{K}^{ - 1}}\mathrm{ mo}{\mathrm{l}^{ - 1}}]
View answer and explanation
Correct option: C
41.5 KJ mol−141.5\,\mathrm{KJ}\,\mathrm{mo}{\mathrm{l}^{ - 1}}
Option C (41.5 KJ mol−141.5\,\mathrm{KJ}\,\mathrm{mo}{\mathrm{l}^{ - 1}}) is correct because it is calculated using the Arrhenius equation and the given slope.
75 Medium
75 of 207
Application +4 | -1
N2(g)+3H2(g)  ⇋  2NH3(g)+22  kcal{\mathrm{N}_2}\left( \mathrm{g} \right) + 3{\mathrm{H}_2}\left( \mathrm{g} \right)\;\leftrightharpoons\;2\mathrm{N}{\mathrm{H}_3}\left( \mathrm{g} \right) + 22\;\mathrm{kcal}.

The activation energy for the forward reaction is 50  kcal.50\mathrm{ }\;kcal. What is the activation energy for the backward reaction?
View answer and explanation
Correct option: D
+72  kcal+ 72\mathrm{ }\;kcal
Option D (+72  kcal+ 72\mathrm{ }\;kcal) is correct because the activation energy for the backward reaction is the sum of the activation energy for the forward reaction and the enthalpy change of the reaction.
76 Hard
76 of 207
Application +4 | -1
For a fist order reaction, the concentration changes from 0.8  to  0.4  in  15  min.0.8\mathrm{ }\;to\;\mathrm{ }0.4\mathrm{ }\;in\mathrm{ }\;15\;\mathrm{ }min.. The time taken for the concentration to change from 0.1  M  to  0.025  M  is0.1\mathrm{ }\;M\;\mathrm{ }to\;\mathrm{ }0.025\mathrm{ }\;M\;\mathrm{ }is
View answer and explanation
Correct option: A
30 Min
Option A (30 Min) is correct because the time required for the concentration to halve is constant for a first-order reaction, and 0.1 M to 0.025 M represents two half-lives.
77 Hard
77 of 207
Analyzing +4 | -1
Consider the two hypothetical reactions given below:

I aA→a A \rightarrow Products, k=x mol−1 L min−1k=x \mathrm{~mol}^{-1} \mathrm{~L} \mathrm{~min}^{-1}
II bB→b B \rightarrow Products, k=y min−1k=y \mathrm{~min}^{-1}

The half-lives of both the reactions are the same, equal to 1hr1 \mathrm{hr} when molar concentration of the reactant is 1.0M1.0 \mathrm{M} in each case. If these reactions are started at the same time taking 1M1 \mathrm{M} of the reactant in each case, the ratio [A]/[B][A]/[B] after 3hr3 \mathrm{hr} will be:
View answer and explanation
Correct option: D
2
The correct answer is D (2) because the ratio [A]/[B] after 3 hours can be calculated based on the rate laws and half-lives of the two reactions.
78 Easy
78 of 207
Analyzing +4 | -1
The rate constant K1{K_1} of a reaction is found to be double that of rate constant K2{K_2} of another reaction. The relationship between corresponding activation energies of the two reactions at same temperature (E1  and  E2)({E_1}\;and\;{E_2}) can be represented as:
View answer and explanation
Correct option: D
None of these
Option B (E1<E2{E_1} < {E_2}) is correct because a higher rate constant (K1K_1) implies a lower activation energy (E1E_1) at the same temperature, according to the Arrhenius equation.
79 Easy
79 of 207
Understanding +4 | -1
The decomposition of N2O5{N_2}{O_5} occur as 2N2O5 →  4NO2+O2,2{N_2}{O_5}\, \to \,\,4N{O_2} + {O_2}, and follows Ist order kinetics, hance
View answer and explanation
Correct option: C
t1/2∝a0{t_{1/2}} \propto {a^0}
Option C (t1/2∝a0{t_{1/2}} \propto {a^0}) is correct because the half-life of a first-order reaction is independent of the initial concentration, hence proportional to a0.
80 Hard
80 of 207
Understanding +4 | -1
Choose correct option based on following statements. Here T stands for true statement and F for false statement.

(i) Molecularity is defined as the number of reacting species taking part in a complex reaction,

(ii) Molecularity helps in understanding the mechanism of reaction.

(iii) Reactions with the molecularity three are very rare and slow to proceed.

(iv) Complex reactions involving more than three molecules take place in more than one step.
View answer and explanation
Correct option: D
FTTT
Option D (FTTT) is correct because statement (i) is false, while statements (ii), (iii), and (iv) are true regarding molecularity and reaction mechanisms.
81 Easy
81 of 207
Application +4 | -1
The rate constant of a first order reaction is 4×10−3  sec⁡−1.4 \times {10^{ - 3\;}}{\sec ^{ - 1}}. At a reactant concentration of 0.02  M0.02\;M, the rate of reaction would be:
View answer and explanation
Correct option: A
8×10−5  M  sec⁡−18 \times {10^{ - 5}}\;M\;{\sec ^{ - 1}}
Option A (8×10−5  M  sec⁡−18 \times {10^{ - 5}}\;M\;{\sec ^{ - 1}}) is correct because for a first-order reaction, rate = k[A].
82 Easy
82 of 207
Understanding +4 | -1
Which of the following statements are correct?

1. Order of a reaction can be known from experimental result and not from the stoichiometry of reaction

2. Overall molecularity of a reaction may be determined in a manner similar to overall order of reaction

3. Overall order of reaction,

Am+Bn→ABx  is  (m+n){A^m} + {B^n} \to A{B_x}\;is\;\left( {m + n} \right)

4. Molecularity of a reaction refers to

(i) Molecularity of each of the elementary steps (slow steps) in a multistep reaction

(ii) Molecularity of that particular step in a single step reaction

Select the correct answer by using the codes given below
View answer and explanation
Correct option: D
1, 2 and 4
Option A (1, 3 and 4) is incorrect. The correct answer includes statements 1 and 4, which are about reaction order and molecularity, but statement 3 is incorrect regarding the overall order of a reaction.
83 Easy
83 of 207
Analyzing +4 | -1
For a certain reaction involving a single reactant, it is found that C0TC_0 \sqrt{T} is constant, where C0C_0 is the initial concentration of the reactant and TT is the half-life. What is the order of the reaction?
View answer and explanation
Correct option: D
3
Option D (3) is correct because the given relationship C0TC_0 \sqrt{T} = constant implies that the half-life is inversely proportional to the square of the initial concentration, which is characteristic of a third-order reaction.
84 Easy
84 of 207
Application +4 | -1
For a chemical reaction X→PX \to P, the rate of reaction doubles when the concentration of X is increased 4 times. The order of reaction with respect to X is
View answer and explanation
Correct option: A
12\frac{1}{2}
Option A (12\frac{1}{2}) is correct because the rate is proportional to the square root of the concentration.
85 Hard
85 of 207
Analyzing +4 | -1
Select the correct statements out of I, II and III for zero order reaction.

(I) Quantity of the products formed is directly proportional to time.

(II) Larger the initial concentration of the reactant, greater the half-life period.

(III) If 50%50 \% reaction takes place in 100 min,75%100 \mathrm{~min}, 75 \% reaction takes place in 150 min150 \mathrm{~min}.
View answer and explanation
Correct option: D
(I), (II) and (III)
Option D ((I), (II) and (III)) is correct because all three statements are true for a zero-order reaction.
86 Easy
86 of 207
Remembering +4 | -1
With increase in temperature, rate of reaction
View answer and explanation
Correct option: A
increases
The correct answer is A (increases) because increasing the temperature generally increases the rate of a reaction due to increased molecular kinetic energy and more frequent collisions with sufficient energy.
87 Medium
87 of 207
Analyzing +4 | -1
For a reaction between A and B, the initial rate of reaction is measured for various initial concentrations A and B. the data provided are

            [A]           [B]              Initialreactionrate1       0.20M     0.30M      5×10−52     0.20M    0.10M      5×10−53     0.40M    0.05M      1×10−5\begin{array}{l} \,\,\,\,\,\,\,\,\,\,\,\,\left[ A \right]\,\,\,\,\,\,\,\,\,\,\,\left[ B \right]\;\;\;\;\;\;\;Initial\mathrm{ }reaction\mathrm{ }rate\\ 1\,\,\,\,\,\,\,0.20M\,\,\,\,\,0.30M\,\,\,\,\,\,5 \times {10^{ - 5}}\\ 2\,\,\,\,\,0.20\mathrm{ }M\,\,\,\,0.10\mathrm{ }M\,\,\,\,\,\,5 \times {10^{ - 5}}\\ 3\,\,\,\,\,0.40\mathrm{ }M\,\,\,\,0.05\mathrm{ }M\,\,\,\,\,\,1 \times {10^{ - 5}} \end{array}

The overall order of the reaction is
View answer and explanation
Correct option: A
One
Option A (One) is correct because the rate is independent of [B] and proportional to [A], making the overall order 1.
88 Easy
88 of 207
Analyzing +4 | -1
Which of the following statement is not correct for the reaction: 4A+B→2C+2D4A + B \to 2C + 2D
View answer and explanation
Correct option: A
The rate of disappearance of &lsquo;B&rsquo; is twice the rate of appearance of &lsquo;C&rsquo;
Option A (The rate of disappearance of &lsquo;B&rsquo; is twice the rate of appearance of &lsquo;C&rsquo;) is correct because the stoichiometry of the reaction dictates that the rate of disappearance of B is half the rate of appearance of C.
89 Medium
89 of 207
Application +4 | -1
The rate of the reaction A→productsA \to products, at the initial concentration of 3.24×10−2  M3.24 \times {10^{ - 2}}\;M is nine times its rate at another initial concentration of 1.2×10−3  M1.2 \times {10^{ - 3}}\;M. The order of the reaction is
View answer and explanation
Correct option: D
23\frac{2}{3}
Option D (2/3) is correct because the order of the reaction is calculated using the rate law and given data.
90 Hard
90 of 207
Analyzing +4 | -1
For a gaseous reaction A(g)→Products (order=n),\mathrm{A}(\mathrm{g}) \rightarrow \text{Products (order} = n), the rate may be expressed as

(i) −dPAdt=K1⋅PAn-\frac{\mathrm{d} P_{\mathrm{A}}}{\mathrm{d} t}=K_1 \cdot P_{\mathrm{A}}^n

(ii) −1VdnAdt=K2⋅CAn-\frac{1}{V} \frac{\mathrm{d} n_{\mathrm{A}}}{\mathrm{d} t}=K_2 \cdot C_{\mathrm{A}}^n

The rate constants, K1K_1 and K2K_2 are related as (PA\left(P_{\mathrm{A}}\right. and CAC_{\mathrm{A}} are the partial pressures and molar concentration of A\text{A} at time 'tt', respectively)
View answer and explanation
Correct option: D
K2=K1⋅(RT)n−1K_2=K_1 \cdot(R T)^{n-1}
Option D (K2=K1⋅(RT)n−1K_2=K_1 \cdot(R T)^{n-1}) is correct because it correctly relates the rate constants K1K_1 and K2K_2 based on the ideal gas law and the order of the reaction.
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