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NEET • CHEMISTRY • CHEMICAL BONDING & MOLECULAR STRUCTURE

Chemical bonding & molecular structure practice · Mixed difficulty

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61 Medium
61 of 579
Understanding +4 | -1
Which species has lone pair on central atom?
View answer and explanation
Correct option: D
H2O{\mathrm{H}_2}\mathrm{O}
Option D (H2O{H_2}O) is correct because in water, the oxygen atom has two bonding pairs and two lone pairs of electrons.
62 Medium
62 of 579
Analyzing +4 | -1
Consider the following statements.

I. In F2F_2 molecule F−F   σ−bondF - F\,\,\,\sigma - {\text{bond}} is formed by axial overlapping of two p-orbitals.

II. In O2O_2 molecule one σ−bond\sigma - {\text{bond}} is formed by axial overlap of p-orbitals and one π−bond\pi - {\text{bond}} is formed by lateral overlap of p-orbitals.

III. In N2N_2 molecule one σ\sigma and two π−bonds,\pi - {\text{bonds,}} i.e., all the three bonds are formed by lateral overlap of p-orbitals.

Which of the above statements are incorrect?
View answer and explanation
Correct option: C
Only III
Option C (Only III) is correct because in N2 molecule, one sigma bond is formed by axial overlap, and two pi bonds are formed by lateral overlap of p-orbitals.
63 Hard
63 of 579
Application +4 | -1
The correct order of hybridization of the central atom in the following species NH3,[PtCl4]2−,PCl5\mathrm{N}{\mathrm{H}_3},{\left[ {\mathrm{PtC}{\mathrm{l}_4}} \right]^{2 - }},\mathrm{PC}{\mathrm{l}_5} and BCl3\mathrm{BC}{\mathrm{l}_3} is:
View answer and explanation
Correct option: B
sp3,dsp2,dsp3,sp2s{p^3},ds{p^2},ds{p^3},s{p^2}
Option B (sp3,dsp2,dsp3,sp2s{p^3},ds{p^2},ds{p^3},s{p^2}) is correct because it lists the correct hybridization for each species in the given order: NH3NH_3, [PtCl4]2−[PtCl_4]^{2-}, PCl5PCl_5, and BCl3BCl_3.
64 Easy
64 of 579
Understanding +4 | -1
In which of the following dative bond is not present
View answer and explanation
Correct option: D
N2H4{N_2}{H_4}
Option D (N2H4{N_2}{H_4}) is correct because in N2H4{N_2}{H_4} (hydrazine), the nitrogen atoms are connected by a single covalent bond and each nitrogen is also bonded to two hydrogen atoms through covalent bonds; there is no donation of electron pairs from one atom to another.
65 Easy
65 of 579
Understanding +4 | -1
In the formation of a molecule by an atom
View answer and explanation
Correct option: C
both attractive and repulsive forces operative
Option C (both attractive and repulsive forces operative) is correct because bond formation involves both attractive forces between the nuclei and electrons, and repulsive forces between the nuclei and between the electrons.
66 Medium
66 of 579
Analyzing +4 | -1
Which of the following set contains same bond angle around central atom?
View answer and explanation
Correct option: C
BF3,BCl3,BBr3{BF}_3, {BCl}_3, {BBr}_3
Option C (BF3,BCl3,BBr3{BF}_3, {BCl}_3, {BBr}_3) is correct because all three molecules have a trigonal planar geometry with bond angles of 120 degrees around the central boron atom.
67 Hard
67 of 579
Application +4 | -1
In case of H2O\mathrm{H}_2 \mathrm{O} molecule, the enthalpy needed to break the two O−H\mathrm{O}-\mathrm{H} bonds is not the same, i.e.

H2O(g)⟶H(g)+OH(g);ΔaH1S=502 kJ mol−1OH(g)⟶H(g)+O(g);ΔaH2S=427 kJ mol−1\begin{aligned} & \mathrm{H}_2 \mathrm{O}(\mathrm{g}) \longrightarrow \mathrm{H}(\mathrm{g})+\mathrm{OH(g}) ; \Delta_\mathrm{a} \mathrm{H}_1^{\mathrm{S}}=502 \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \mathrm{OH}(\mathrm{g}) \longrightarrow \mathrm{H}(\mathrm{g})+\mathrm{O}(\mathrm{g}) ; \Delta_\mathrm{a} \mathrm{H}_2^{\mathrm{S}}=427 \mathrm{~kJ} \mathrm{~mol}^{-1} \end{aligned}

What should be the mean bond enthalpy of O−H\mathrm{O}-\mathrm{H} bonds in case of H2O\mathrm{H}_2 \mathrm{O} molecule?
View answer and explanation
Correct option: C
464.5 kJ mol−1464.5 \mathrm{~kJ} \mathrm{~mol}^{-1}
Option C (464.5 kJ mol−1464.5 \mathrm{~kJ} \mathrm{~mol}^{-1}) is correct because the mean bond enthalpy is the average of the two O-H bond dissociation enthalpies.
68 Medium
68 of 579
Understanding +4 | -1
Which statement is wrong?
View answer and explanation
Correct option: D
d2sp2{d^2}s{p^2}-hybrid orbitals are directed towards the corners of a regular tetrahedron
Option D (d2sp2{d^2}s{p^2}-hybrid orbitals are directed towards the corners of a regular tetrahedron) is wrong because d2sp3{d^2}sp^3 hybrid orbitals are directed towards the corners of a regular octahedron, not a tetrahedron. A tetrahedron is formed by sp3sp^3 hybridization.
69 Hard
69 of 579
Analyzing +4 | -1
Among the following, the molecule expected to be stabilised by anion formation is C2, O2, NO, F2.{C_2},\,{O_2},\,NO,\,{F_2}.
View answer and explanation
Correct option: A
C2{C_2}
Option A (C2{C_2}) is correct because adding an electron to C2{C_2} increases its bond order, thus stabilizing it.
70 Easy
70 of 579
Analyzing +4 | -1
Among the following molecules which one have smallest bond angle
View answer and explanation
Correct option: D
H2Sc{H}_2 {Sc}
Option D (H2Sc{H}_2 {Sc}) is correct because Sc has a lower electronegativity than N, P, and O, leading to less repulsion between bond pairs and a smaller bond angle.
71 Easy
71 of 579
Analyzing +4 | -1
The number of species below that have two lone pairs of electrons in their central atom is.
SF4,   BF4−,   ClF3,   AsF3,   PCl5,   BrF5,   XeF4,   SF6S{F_4},\,\,\,BF_4^ - ,\,\,\,Cl{F_3},\,\,\,As{F_3},\,\,\,PC{l_5},\,\,\,Br{F_5},\,\,\,Xe{F_4},\,\,\,S{F_6}
View answer and explanation
Correct option: D
2
Option D (2) is correct because only XeF4XeF_4 and ClF3ClF_3 have two lone pairs on their central atoms.
72 Easy
72 of 579
Understanding +4 | -1
The bond strength in O2+,O2,O2−\mathrm{O}_2^ + ,{\mathrm{O}_2},\mathrm{O}_2^ - and O22−\mathrm{O}_2^{2 - } follows the order:
View answer and explanation
Correct option: B
O2+>O2>O2−>O22−\mathrm{O}_2^ + > {\mathrm{O}_2} > \mathrm{O}_2^ - > \mathrm{O}_2^{2 - }
Option B (O2+>O2>O2−>O22−\mathrm{O}_2^ + > {\mathrm{O}_2} > \mathrm{O}_2^ - > \mathrm{O}_2^{2 - }) is correct because bond strength increases with bond order, and the bond orders are O2+ (2.5), O2 (2), O2- (1.5), and O22- (1).
73 Hard
73 of 579
Understanding +4 | -1
Select which type of overlapping is responsible for π\pi-character in Si−N{Si}-{N} bond of H3SiNCO{H}_3 {SiNCO}
View answer and explanation
Correct option: C
3 dπ←2pπ3 {~d} \pi \leftarrow 2 {p} \pi
Option C (3 dπ←2pπ3 {~d} \pi \leftarrow 2 {p} \pi) is correct because silicon can utilize its vacant 3d orbitals to form a dπ-pπ bond with nitrogen.
74 Medium
74 of 579
Analyzing +4 | -1
The pair having similar geometry is:
View answer and explanation
Correct option: B
BF3,AlF3\mathrm{B}{\mathrm{F}_3},\mathrm{Al}{\mathrm{F}_3}
Option B is correct because both BF3\mathrm{B}{\mathrm{F}_3} and AlF3\mathrm{Al}{\mathrm{F}_3} have trigonal planar geometry.
75 Medium
75 of 579
Analyzing +4 | -1
In which of the following compound sp2s{p^2} hybridisation is absent?
View answer and explanation
Correct option: B
CH≡C−CH2−CH3\mathrm{CH} \equiv \mathrm{C} - \mathrm{C}{\mathrm{H}_2} - \mathrm{C}{\mathrm{H}_3}
Option B (CH≡C−CH2−CH3\mathrm{CH} \equiv \mathrm{C} - \mathrm{CH}_2 - \mathrm{CH}_3) is correct because the carbon atoms in the triple bond are sp hybridized, while the other carbon atoms are sp3sp^3 hybridized. Therefore, sp2sp^2 hybridization is absent.
76 Medium
76 of 579
Understanding +4 | -1
Dipole moment is shown by
View answer and explanation
Correct option: D
Both (a) and (c )
Option D (Both (a) and (c )) is correct because cis-1,2-dichloroethane and cis-1,2-dichloro-2-pentene have a net dipole moment due to the asymmetry in the molecule.
77 Hard
77 of 579
Analyzing +4 | -1
Given below are two statements:

Statement I: PF5\mathrm{PF}_5 and BrF5\mathrm{BrF}_5 both exhibit sp3d\mathrm{sp}^3 \mathrm{d} hybridisation.

Statement II: Both SF6\mathrm{SF}_6 and [Co(NH3)6]3+\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+} exhibit sp3d2\mathrm{sp}^3 \mathrm{d}^2 hybridisation.

In the light of the above statements, choose the correct answer from the options given below:
View answer and explanation
Correct option: C
Both Statement I and Statement II are false
Option C is correct because in PF5\mathrm{PF}_5, the hybridization is sp3dsp^3d, but in BrF5\mathrm{BrF}_5 it is sp3d2sp^3d^2. In SF6\mathrm{SF}_6, the hybridization is sp3d2sp^3d^2, but in [Co(NH3)6]3+\left[\mathrm{Co}(\mathrm{NH}_3)_6\right]^{3+} it is d2sp3d^2sp^3.
78 Medium
78 of 579
Remembering +4 | -1
The decreasing order of bond dissociation energies of C−C,C−H\mathrm{C}-\mathrm{C}, \mathrm{C}-\mathrm{H} and H−H\mathrm{H}-\mathrm{H} bonds in
View answer and explanation
Correct option: A
H−H>−C−H>−C−C−\mathrm{H}-\mathrm{H}>-\mathrm{C}-\mathrm{H}>-\mathrm{C}-\mathrm{C}-
Option A (H−H>−C−H>−C−C−\mathrm{H}-\mathrm{H}>-\mathrm{C}-\mathrm{H}>-\mathrm{C}-\mathrm{C}-) is correct because the H-H bond is the strongest, followed by C-H, and then C-C.
79 Hard
79 of 579
Analyzing +4 | -1
Among the following the molecule with the highest dipole moment is
View answer and explanation
Correct option: A
CH3Cl\mathrm{C}{\mathrm{H}_3}\mathrm{Cl}
Option A (CH3Cl\mathrm{C}{\mathrm{H}_3}\mathrm{Cl}) is correct because the C-Cl bond is highly polar, and there is only one such bond, leading to a significant net dipole moment. As more Cl atoms are added, the vector sum of the bond dipoles decreases the overall dipole moment.
80 Medium
80 of 579
Remembering +4 | -1
Which of the following is a polar molecule?
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Correct option: C
NH3\mathrm{NH}_3
Option C is correct because NH3 has a lone pair on the nitrogen atom, resulting in an asymmetrical distribution of electron density and thus a net dipole moment, making it a polar molecule.
81 Medium
81 of 579
Application +4 | -1
Which one of the following constitutes a group of the isoelectronic species?
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Correct option: B
NO+,C22−,CN−,N2\mathrm{N}{\mathrm{O}^ + },\mathrm{C}_2^{2 - },\mathrm{C}{\mathrm{N}^ - },{\mathrm{N}_2}
Option B (NO+,C22−,CN−,N2\mathrm{N}{\mathrm{O}^ + },\mathrm{C}_2^{2 - },\mathrm{C}{\mathrm{N}^ - },{\mathrm{N}_2}) is correct because all species in this group have 14 electrons.
82 Medium
82 of 579
Application +4 | -1
The value of electronegativity of atoms A and B are 1.20 and 4.0 respectively. The percentage of ionic character of A−B\mathrm{A}-\mathrm{B} bond is:
View answer and explanation
Correct option: D
72.24%72.24 \%
Option D (72.24 %) is correct because the percentage of ionic character can be estimated using the Pauling equation: % ionic character = (1 - exp(-0.25 * (ΔEN)2)) * 100, where ΔEN is the electronegativity difference.
83 Medium
83 of 579
Understanding +4 | -1
In allene structure, three carbon atoms are joined by:
View answer and explanation
Correct option: C
Two σ\mathrm{\sigma } and two π\mathrm{\pi } bonds
Option C (Two σ\mathrm{\sigma } and two π\mathrm{\pi } bonds) is correct because in allene (C=C=C), the central carbon has two sigma bonds and two pi bonds.
84 Medium
84 of 579
Analyzing +4 | -1
Some of the properties of the two species, NO3−\mathrm{NO}_3^ - and H3O+{\mathrm{H}_3}{\mathrm{O}^ + } are described below. Which one of them is correct?
View answer and explanation
Correct option: A
Dissimilar in hybridization for the central atom with different structure
Option D (Similar is hybridization for the central atom with different structure) is correct because NO3−\mathrm{NO}_3^ - is sp2sp^2 hybridized and trigonal planar, while H3O+{\mathrm{H}_3}{\mathrm{O}^ + } is sp3sp^3 hybridized and pyramidal.
85 Easy
85 of 579
Understanding +4 | -1
Which is expected to have linear structure?
View answer and explanation
Correct option: B
CO2\mathrm{C}{\mathrm{O}_2}
Option B (CO2\mathrm{C}{\mathrm{O}_2}) is correct because carbon dioxide has a linear structure due to the double bonds between carbon and each oxygen atom, resulting in a bond angle of 180 degrees.
86 Medium
86 of 579
Analyzing +4 | -1
Which does not use sp3s{p^3}-hybrid orbitals in its bonding?
View answer and explanation
Correct option: A
BeF3−\mathrm{BeF}_3^ -
Option A (BeF3−\mathrm{BeF}_3^ -) is correct because Be in BeF3−\mathrm{BeF}_3^ - is sp2sp^2 hybridized, while the others are sp3sp^3 hybridized.
87 Medium
87 of 579
Understanding +4 | -1
In which of the following crystals of ionic compounds would you expect maximum distance between the centres of cotions and anions
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Correct option: C
CsI
Option C (CsI) is correct because both Cs+ and I- are large ions, leading to a greater distance between their centers in the crystal lattice.
88 Easy
88 of 579
Analyzing +4 | -1
Which of the following pairs are isostructural?
View answer and explanation
Correct option: C
BrO3−,XeO3\mathrm{BrO}_3^ - ,\mathrm{Xe}{\mathrm{O}_3}
Option C (BrO3−,XeO3\mathrm{BrO}_3^ - ,\mathrm{Xe}{\mathrm{O}_3}) is correct because both have a pyramidal shape with the same number of lone pairs and bond pairs around the central atom.
89 Medium
89 of 579
Analyzing +4 | -1
Assertion : The O−O{O}-{O} bond length in H2O2{H}_2 {O}_2 is shorter than that of O2 F2{O}_2 {~F}_2.

Reason: H2O2{H}_2 {O}_2 is an ionic compound.
View answer and explanation
Correct option: D
If both the Assertion and Reason are incorrect.
Option D (If both the Assertion and Reason are incorrect) is correct because the O-O bond length in H2O2 is longer than that in O2F2, and H2O2 is a covalent compound, not ionic.
90 Medium
90 of 579
Remembering +4 | -1
Bond formed due to complete transfer of electron is
View answer and explanation
Correct option: D
Ionic bond
Option D (Ionic bond) is correct because an ionic bond is formed through the complete transfer of electrons from one atom to another, resulting in the formation of ions.
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