Carbon cannot be used in the reduction of ${\rm{A}}{{\rm{l}}_2}{{\rm{O}}_3}$ because

The enthalpy of formation of ${\rm{A}}{{\rm{l}}_2}{{\rm{O}}_3}$ is too high

The enthalpy of formation of ${\rm{C}}{{\rm{O}}_2}$ is more than that of ${\rm{A}}{{\rm{l}}_2}{{\rm{O}}_3}$

Pure carbon is not easily available

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{SiC}}{{\rm{l}}_2}$ undergoes hydrolysis but ${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_2}{\rm{CC}}{{\rm{l}}_2}$ does not why?

Only 3p orbital is involved in C

${\rm{Si}} - {\rm{Cl}}$ bond is more polar than ${\rm{C}} - {\rm{Cl}}$ bond

Carbon reacts with ${conc.{{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}}$ to give :

${\rm{C}}{{\rm{O}}_2},{\rm{S}}{{\rm{O}}_2},{{\rm{H}}_2}{\rm{O}}$

${\rm{S}}{{\rm{O}}_2},{{\rm{H}}_2}{\rm{O}},{\rm{CO}}$

${\rm{CO}},{{\rm{H}}_2}{\rm{O}}$

${\rm{C}}{{\rm{O}}_2},{{\rm{H}}_2}{\rm{O}}$

${\rm{S}}{{\rm{i}}_2}{\rm{O}}_7^{6 - }$

${\rm{S}}{{\rm{i}}_2}{\rm{O}}_6^{7 - }$

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NEET • CHEMISTRY • 14 TH GROUP ELEMENTS (P-BLOCK)

14 th group elements (p-block) practice · Medium

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1 Medium

1 of 88

Understanding +4 | -1

Carbon cannot be used in the reduction of

\mathrm{A}{\mathrm{l}_2}{\mathrm{O}_3}

because

View answer and explanation

Correct option: D

The enthalpy of formation of

\mathrm{A}{\mathrm{l}_2}{\mathrm{O}_3}

is too high

Option D is correct because the enthalpy of formation of

Al_2O_3

is extremely high, making it thermodynamically unfavorable to reduce with carbon.

2 Medium

2 of 88

Remembering +4 | -1

Thermodynamically, the most stable allotrope of carbon is

View answer and explanation

Correct option: D

Graphite

Option D (Graphite) is correct because graphite is the thermodynamically most stable allotrope of carbon under standard conditions.

3 Medium

3 of 88

Analyzing +4 | -1

Assertion (A): In silicates like

\mathrm{SiO}_2, \mathrm{Si}

, is

\mathrm{sp}^3

hybridised.

Reason (R):

\mathrm{SiO}_2

is a linear molecule.

View answer and explanation

Correct option: C

(A) is true but (R) is false

Option C ((A) is true but (R) is false) is correct because Si in SiO2 is sp3 hybridized, but SiO2 is not a linear molecule; it has a network structure.

4 Medium

4 of 88

Understanding +4 | -1

Pure CO can be obtained from:

View answer and explanation

Correct option: B

Nickel tetracarbonyl

Option B (Nickel tetracarbonyl) is correct because nickel tetracarbonyl decomposes at high temperatures to give pure CO and Ni.

5 Medium

5 of 88

Analyzing +4 | -1

Which of the following has the minimum heat of dissociation?

View answer and explanation

Correct option: D

[{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}\mathrm{N} \to \mathrm{B}{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}]

Option D

[{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}\mathrm{N} \to \mathrm{B}{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}]

has the minimum heat of dissociation because the steric hindrance is maximum in this case, weakening the bond.

6 Medium

6 of 88

Remembering +4 | -1

Carborundum is obtained when silica is heated at high temperature with

View answer and explanation

Correct option: A

Carbon

Option A (Carbon) is correct because carborundum (silicon carbide, SiC) is produced by heating silica (SiO2) with carbon at high temperatures.

7 Medium

7 of 88

Remembering +4 | -1

The different layers in graphite are held together by

View answer and explanation

Correct option: D

Van\;\mathrm{der}Waals'\;forces

Option D (

Van der Waals' forces

) is correct because the layers in graphite are held together by weak Van der Waals' forces.

8 Medium

8 of 88

Remembering +4 | -1

The chemical formula of sindhur is

View answer and explanation

Correct option: B

\mathrm{P}{\mathrm{b}_3}{\mathrm{O}_4}

Option B (

\mathrm{P}{\mathrm{b}_3}{\mathrm{O}_4}

) is correct because sindhur, also known as red lead, has the chemical formula

\mathrm{P}{\mathrm{b}_3}{\mathrm{O}_4}

9 Medium

9 of 88

Analyzing +4 | -1

Statement-1:

B

and

C

form their stable halides as

B X_3

and

CX_4

, while

Tl

and

Pb

produce their stable halides as

Tl

and

PbX_2

.

Statement-2: Both

PbX_4

and

TlX_3

are strong oxidizing agent.

View answer and explanation

Correct option: B

Statement-1 is true, statement-2 is true and statement-2 is NOT the correct explanation for statement-1.

Option B is correct because both statements are true, but statement 2 is not the correct explanation for statement 1. The inert pair effect explains the stability of TlX and PbX2.

10 Medium

10 of 88

Understanding +4 | -1

Tin (II) fluoride (anhydrous) can be obtained by :

View answer and explanation

Correct option: C

Dissolving SnO in HF

The correct answer is C (Dissolving SnO in HF) because tin(II) fluoride is formed by the reaction of tin(II) oxide with hydrofluoric acid.

11 Medium

11 of 88

Understanding +4 | -1

Lead (IV) oxide is obtained by :

View answer and explanation

Correct option: D

Heating

\mathrm{P}{\mathrm{b}_3}{\mathrm{O}_4}

with

\mathrm{conc}\mathrm{.HN}{\mathrm{O}_3}

Option D (Heating

\mathrm{P}{\mathrm{b}_3}{\mathrm{O}_4}

with

\mathrm{conc}\mathrm{.HN}{\mathrm{O}_3}

) is correct because this reaction selectively dissolves PbO, leaving behind PbO2.

12 Medium

12 of 88

Understanding +4 | -1

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{SiC}{\mathrm{l}_2}

undergoes hydrolysis but

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{CC}{\mathrm{l}_2}

does not why?

View answer and explanation

Correct option: A

Low lying d-orbitals present in Si but not in C

Option A is correct because silicon has low-lying d-orbitals that can accept electron pairs from water during hydrolysis, while carbon does not.

13 Medium

13 of 88

Understanding +4 | -1

Zn on heating with barium carbonate gives :

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because Zn reacts with barium carbonate upon heating to produce BaO, ZnO, and CO.

14 Medium

14 of 88

Understanding +4 | -1

Activation of charcoal:

View answer and explanation

Correct option: B

Increases the adsorbing power of the charcoal

The correct answer is B (Increases the adsorbing power of the charcoal) because activation of charcoal involves increasing its surface area and porosity, thereby enhancing its ability to adsorb substances.

15 Medium

15 of 88

Remembering +4 | -1

The carbon of microphones used in public address systems is :

View answer and explanation

Correct option: A

Graphite

The correct answer is A (Graphite) because graphite is a form of carbon commonly used in microphones due to its electrical conductivity and layered structure.

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16 Medium

16 of 88

Remembering +4 | -1

Which is used for the manufacture of optical instruments?

View answer and explanation

Correct option: C

Flint glass

Option C (Flint glass) is correct because flint glass has a high refractive index and is used in optical instruments.

17 Medium

17 of 88

Remembering +4 | -1

Water softner is

View answer and explanation

Correct option: C

Both (a) And (b)

The correct answer is B (Zeolite) because zeolites are commonly used as water softeners.

18 Medium

18 of 88

Remembering +4 | -1

Which of the following is a three dimensional silicate?

View answer and explanation

Correct option: C

Zeolite

The correct answer is C (Zeolite) because zeolites have a three-dimensional network structure.

19 Medium

19 of 88

Analyzing +4 | -1

Assertion: Silicones are hydrophobic in nature.

Reason:

Si-O-Si

linkages are moisture sensitive.

View answer and explanation

Correct option: C

If the Assertion is correct but Reason is incorrect.

Option C is correct because silicones are hydrophobic, but the

Si-O-Si

linkages are not moisture sensitive; they are actually quite stable.

20 Medium

20 of 88

Analyzing +4 | -1

A tetravalent element forms monoxide and dioxide with oxygen. When air is passed over heated element (1273 K), producer gas is obtained. Monoxide of the element is a powerful reducing agent and reduces ferric oxide to iron. Identify the element.

View answer and explanation

Correct option: B

Carbon

Option B (Carbon) is correct because carbon forms monoxide (CO) and dioxide (CO2), producer gas is made with carbon, and carbon monoxide is a reducing agent that reduces ferric oxide to iron.

21 Medium

21 of 88

Analyzing +4 | -1

The compound

\left(\mathrm{SiH}_3\right)_3 \mathrm{~N}

is expected to be

View answer and explanation

Correct option: B

planar and less basic than

\left(\mathrm{CH}_3\right)_3 \mathrm{~N}

Option B is correct because in

(SiH_3)_3N

, the

p\pi - d\pi

back bonding between N and Si makes it planar and less basic than

(CH_3)_3N

22 Medium

22 of 88

Remembering +4 | -1

Which of the following compounds is used in cosmetic surgery.

View answer and explanation

Correct option: C

Silicones

Option C (Silicones) is correct because silicones are polymers containing silicon-oxygen bonds and are used in various cosmetic and surgical procedures due to their biocompatibility and flexibility.

23 Medium

23 of 88

Remembering +4 | -1

In the sale of diamonds the unit of weight is carat. One carat is equal to:

View answer and explanation

Correct option: A

100 mg

Option D (200 mg) is correct because one carat, the unit of weight for diamonds, is equal to 200 milligrams.

24 Medium

24 of 88

Understanding +4 | -1

Carbon reacts with

{conc.{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}}

to give :

View answer and explanation

Correct option: A

\mathrm{C}{\mathrm{O}_2},\mathrm{S}{\mathrm{O}_2},{\mathrm{H}_2}\mathrm{O}

Option A (

\mathrm{C}{\mathrm{O}_2},\mathrm{S}{\mathrm{O}_2},{\mathrm{H}_2}\mathrm{O}

) is correct because carbon reacts with concentrated sulfuric acid to produce carbon dioxide, sulfur dioxide, and water.

25 Medium

25 of 88

Analyzing +4 | -1

(A): The hardness of silica is less than that of diamond.

(R): In silica, each silicon atom in surrounded by two oxygen atoms where as in diamond each carbon atom is surrounded by 4 carbon atoms.

View answer and explanation

Correct option: C

(A) is true but (R) is false

Option C is correct because the assertion is true (silica is less hard than diamond), but the reason is false. In silica, each silicon atom is surrounded by four oxygen atoms, and each oxygen atom is surrounded by two silicon atoms, forming a three-dimensional network. In diamond, each carbon atom is surrounded by four carbon atoms.

26 Medium

26 of 88

Remembering +4 | -1

If a person is injured by the shot of a gun and all the pellets could not be removed, it may cause poisoning by:

View answer and explanation

Correct option: B

Option B (Pb) is correct because lead poisoning (plumbism) can occur if lead pellets remain in the body.

27 Medium

27 of 88

Understanding +4 | -1

Correct order among following

View answer and explanation

Correct option: C

Melting point

:C > Si > Ge > Pb > Sn

Option C is correct because melting point generally decreases down the group, but Sn has a lower melting point than Pb due to its metallic structure.

28 Medium

28 of 88

Remembering +4 | -1

Pyrosilicate ion is:

View answer and explanation

Correct option: C

\mathrm{S}{\mathrm{i}_2}\mathrm{O}_7^{6 - }

The correct answer is C (

\mathrm{S}{\mathrm{i}_2}\mathrm{O}_7^{6 - }

) because this is the formula for the pyrosilicate ion.

29 Medium

29 of 88

Understanding +4 | -1

Which of the following species is not stable?

View answer and explanation

Correct option: D

{[SiC{l_6}]^{2 - }}

Option D (

{[SiC{l_6}]^{2 - }}

) is correct because silicon cannot expand its coordination number beyond 4 due to the absence of available d-orbitals, making

{[SiC{l_6}]^{2 - }}

unstable.

30 Medium

30 of 88

Understanding +4 | -1

The correct order of decreasing ionic nature of lead dihalides is :

View answer and explanation

Correct option: A

\mathrm{Pb}{\mathrm{F}_2} > \mathrm{PbC}{\mathrm{l}_2} > \mathrm{PbB}{\mathrm{r}_2} > \mathrm{Pb}{\mathrm{I}_2}

Option A (

\mathrm{Pb}{\mathrm{F}_2} > \mathrm{PbC}{\mathrm{l}_2} > \mathrm{PbB}{\mathrm{r}_2} > \mathrm{Pb}{\mathrm{I}_2}

) is correct because ionic character decreases with increasing size of the halide ion due to increasing covalent character (Fajan's rule).

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