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NEET • CHEMISTRY • 14 TH GROUP ELEMENTS (P-BLOCK)

14 th group elements (p-block) practice · Easy

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Showing 1-30 of 74 questions
1 Easy
1 of 74
Understanding +4 | -1
It is because of inability of electrons of the valance shell to participate in bonding that
View answer and explanation
Correct option: D
Sn+2S{n^{ + 2}} is reducing while Pb+4P{b^{ + 4}} is oxidising
Option D (Sn+2S{n^{ + 2}} is reducing while Pb+4P{b^{ + 4}} is oxidising) is correct because of the inert pair effect, Sn+2S{n^{ + 2}} readily oxidizes to Sn+4S{n^{ + 4}} (reducing agent), while Pb+4P{b^{ + 4}} readily reduces to Pb+2P{b^{ + 2}} (oxidizing agent).
2 Easy
2 of 74
Understanding +4 | -1
(A): Silicones are used in surgical cosmetic plants.

(R): Silicones are biocompatible.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A is correct because silicones are biocompatible, which is why they are used in surgical cosmetic implants.
3 Easy
3 of 74
Remembering +4 | -1
Buckminster fullerene is
View answer and explanation
Correct option: B
C-60
Option B (C-60) is correct because Buckminsterfullerene is a specific allotrope of carbon containing 60 carbon atoms arranged in a spherical structure.
4 Easy
4 of 74
Remembering +4 | -1
Which form of carbon has a two-dimensional sheet-like structure?
View answer and explanation
Correct option: D
Graphite
Option D (Graphite) is correct because graphite has a layered structure consisting of two-dimensional sheets of carbon atoms.
5 Easy
5 of 74
Remembering +4 | -1
Diamond and graphite are:
View answer and explanation
Correct option: C
allotropes
Option C (allotropes) is correct because diamond and graphite are different structural forms of the same element (carbon).
6 Easy
6 of 74
Understanding +4 | -1
Calorific value of producer gas is low because of
View answer and explanation
Correct option: A
High per cent of N2{\mathrm{N}_2}
Option A (High per cent of N2{\mathrm{N}_2}) is correct because nitrogen is non-combustible and dilutes the combustible gases, lowering the calorific value.
7 Easy
7 of 74
Understanding +4 | -1
Which property is common in diamond and graphite?
View answer and explanation
Correct option: B
Relative atomic weight
The correct answer is B (Relative atomic weight) because both diamond and graphite are allotropes of carbon, and therefore have the same relative atomic weight.
8 Easy
8 of 74
Application +4 | -1
What is the average atomic mass of silicon, if it occurs naturally in 3 isotopes Si28,Si29,Si30\mathrm{Si}^{28}, \mathrm{Si}^{29}, \mathrm{Si}^{30} with the abundance of 92.2%,4.7%92.2 \%, 4.7 \% and 3.1%3.1 \% respectively?
View answer and explanation
Correct option: B
28.1 amu28.1 \mathrm{~amu}
Option B (28.1 amu) is correct because the average atomic mass is calculated by summing the product of each isotope's mass and its abundance.
9 Easy
9 of 74
Remembering +4 | -1
The bond energy for catenation next to carbon is :
View answer and explanation
Correct option: C
Si
The correct answer is C (Si) because silicon exhibits the strongest catenation after carbon due to its ability to form stable Si-Si bonds.
10 Easy
10 of 74
Analyzing +4 | -1
Select the incorrect statement :

a. The common oxidation states exhibited by group 14 elements are +4 and +3 .

b. Carbon and Silicon mostly show +4 oxidation state.

c. Group 14 oxides in higher oxidation states of elements are generally less acidic than those in lower oxidation state.
View answer and explanation
Correct option: D
a and c
Option D (a and c) is correct because group 14 elements commonly exhibit +4 and +2 oxidation states, not +3, and oxides in higher oxidation states are generally more acidic.
11 Easy
11 of 74
Remembering +4 | -1
Producer gas, a fuel and also a source of nitrogen is obtained by:
View answer and explanation
Correct option: B
Restricted supply of air through a bed of incandescent coke
Option B (Restricted supply of air through a bed of incandescent coke) is correct because producer gas is made by passing air over hot coke, which is primarily carbon, under controlled conditions.
12 Easy
12 of 74
Understanding +4 | -1
The tendency for catenation in the group – 14 elements is in the order
View answer and explanation
Correct option: D
C>>>Si>Ge≈Sn>>>Pb\mathrm{C > > > Si > Ge} \approx \mathrm{Sn > > > Pb}
Option D (C>>>Si>Ge≈Sn>>>Pb\mathrm{C > > > Si > Ge} \approx \mathrm{Sn > > > Pb}) is correct because the catenation tendency decreases down the group due to decreasing bond strength, with carbon having the highest tendency.
13 Easy
13 of 74
Remembering +4 | -1
The hybridisation of carbon in diamond, graphite and fullerenes are respectively.
View answer and explanation
Correct option: A
Sp3,SP2,SP2S{p^3},S{P^2},S{P^2}
Option A (Sp3,SP2,SP2S{p^3},S{P^2},S{P^2}) is correct because diamond is sp3sp^3 hybridized, while graphite and fullerenes are sp2sp^2 hybridized.
14 Easy
14 of 74
Understanding +4 | -1
SiF4\mathrm{Si}{\mathrm{F}_4} gets hydrolysed giving
View answer and explanation
Correct option: D
H2SiF6{\mathrm{H}_2}\mathrm{Si}{\mathrm{F}_6}
Option D (H2SiF6{\mathrm{H}_2}\mathrm{Si}{\mathrm{F}_6}) is correct because SiF4\mathrm{Si}{\mathrm{F}_4} hydrolyzes to form silicic acid and hydrofluorosilicic acid (H2SiF6{\mathrm{H}_2}\mathrm{Si}{\mathrm{F}_6}).
15 Easy
15 of 74
Understanding +4 | -1
Which of the following is not correct for the allotropic forms of carbon
View answer and explanation
Correct option: D
In diamond each carbon atom undergoes SP3S{P^3} hybridisation and is paramagnetic.
The correct answer is D (In diamond each carbon atom undergoes SP3S{P^3} hybridisation and is paramagnetic) because diamond is diamagnetic, not paramagnetic, due to the absence of unpaired electrons.
16 Easy
16 of 74
Understanding +4 | -1
The catenation tendency of C, Si  and  Ge C,{\mkern 1mu} Si\,\,\mathrm{and}\,\,Ge{\mkern 1mu} is in the order, Ge<Si<C.Ge < Si < C. The energies in (KJ/mol) of C−C, Si−Si  and  Ge−GeC - C,{\mkern 1mu} Si - Si\,\,\mathrm{and}\,\,Ge - Ge respectively.
View answer and explanation
Correct option: D
348, 180, 167
Option D (348, 180, 167) is correct because the bond energies correlate with the catenation tendency, with C-C having the highest bond energy and Ge-Ge having the lowest among the given elements.
17 Easy
17 of 74
Understanding +4 | -1
The core of a non-luminous Bunsen burner flame is observed to be yellow in colour. This is because of:
View answer and explanation
Correct option: C
Incomplete combustion
Option C is correct because the yellow color in the core of a non-luminous Bunsen burner flame indicates incomplete combustion of the fuel.
18 Easy
18 of 74
Analyzing +4 | -1
Salt solution → dil HCl\xrightarrow{\text { dil } \mathrm{HCl}} white ppt;
Salt solution →KI\xrightarrow{\mathrm{KI}} yellow ppt;
The salt contains.
View answer and explanation
Correct option: D
Pb2+\mathrm{Pb}^{2+}
Option D (Pb2+\mathrm{Pb}^{2+}) is correct because lead ions form a white precipitate with dilute HCl (PbCl2) and a yellow precipitate with KI (PbI2).
19 Easy
19 of 74
Understanding +4 | -1
Animal charcoal is used for decolourisation of sugar because:
View answer and explanation
Correct option: D
It adsorbs coloured material
The correct answer is D (It adsorbs coloured material) because animal charcoal has a large surface area and adsorbs impurities, including colored substances.
20 Easy
20 of 74
Analyzing +4 | -1
Assertion (A): Tin exhibits +2 and +4 oxidation states only and not +3 oxidation state.

Reason (R): Inert pair effect of electrons in the ss-orbital is responsible.
View answer and explanation
Correct option: B
Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is not the correct explanation of A\mathbf{A}.
Option B (Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is not the correct explanation of A\mathbf{A}) is correct because while both statements are true, the inert pair effect doesn't fully explain why +3 is not observed.
21 Easy
21 of 74
Understanding +4 | -1
CCl4CC{l_4} does not show hydrolysis but SiCl4SiC{l_4} is readily hydrolyzed because
View answer and explanation
Correct option: C
Carbon cannot expand its octet, but silicon can expand
Option C is correct because silicon can expand its octet due to the availability of d-orbitals, while carbon cannot.
22 Easy
22 of 74
Remembering +4 | -1
Which is not used as pigment in paints?
View answer and explanation
Correct option: A
Lead dioxide
Option A (Lead dioxide) is correct because lead dioxide (PbO2) is primarily used as an oxidizing agent and in batteries, not as a pigment in paints.
23 Easy
23 of 74
Analyzing +4 | -1
Assertion (A) : Diamond is insulator and graphite is conducting.

Reason (R): C-atom is sp3s p^3 hybridised in both.
View answer and explanation
Correct option: C
A\mathbf{A} is true but R\mathbf{R} is false.
Option C is correct because diamond is an insulator and graphite is conducting, but the reason is false as carbon is sp3sp^3 hybridized in diamond and sp2sp^2 hybridized in graphite.
24 Easy
24 of 74
Analyzing +4 | -1
Which of the following is not isostructural with SiF4Si{F_4} ?
View answer and explanation
Correct option: A
SF4S{F_4}
Option A (SF4S{F_4}) is correct because it has a see-saw shape due to the presence of a lone pair, while the others are tetrahedral.
25 Easy
25 of 74
Remembering +4 | -1
Graphite is used in nuclear reactors:
View answer and explanation
Correct option: C
As moderator
Option C (As moderator) is correct because graphite is used as a moderator in nuclear reactors to slow down neutrons.
26 Easy
26 of 74
Remembering +4 | -1
The basic structural unit is silicates is
View answer and explanation
Correct option: C
SiO4\mathrm{Si}{\mathrm{O}_4} tetrahedron
The correct answer is C (SiO4\mathrm{Si}{\mathrm{O}_4} tetrahedron) because this is the fundamental building block of silicate structures.
27 Easy
27 of 74
Remembering +4 | -1
Graphite is made by heating coke with silica for many hours in a :
View answer and explanation
Correct option: D
High electric arc furnace
Option D (High electric arc furnace) is correct because graphite is produced by heating coke with silica at very high temperatures in an electric arc furnace.
28 Easy
28 of 74
Understanding +4 | -1
The correct order of catenation is
View answer and explanation
Correct option: C
C>Si>Ge≈SnC > Si > Ge \approx Sn
Option C (C>Si>Ge≈SnC > Si > Ge \approx Sn) is correct because the catenation tendency decreases as you move down Group 14, with carbon having the highest tendency and germanium and tin having similar tendencies.
29 Easy
29 of 74
Analyzing +4 | -1
Which of the following is correct:
View answer and explanation
Correct option: D
Boric acid is considered as a weak acid
Option D is correct because boric acid acts as a Lewis acid and is considered a weak acid.
30 Easy
30 of 74
Remembering +4 | -1
The main constituents of coal gas are:
View answer and explanation
Correct option: A
CH4+CO+H2\mathrm{C}{\mathrm{H}_4} + \mathrm{CO} + {\mathrm{H}_2}
Option A (CH4+CO+H2\mathrm{C}{\mathrm{H}_4} + \mathrm{CO} + {\mathrm{H}_2}) is correct because coal gas primarily consists of methane (CH4), carbon monoxide (CO), and hydrogen (H2).
Revision notes and key takeaways

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Key Takeaways

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