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JEE • PHYSICS • WORK-ENERGY-POWER

Work-energy-power practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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301 Medium
301 of 496
Understanding +4 | -1
The area under the displacement-force curve gives
View answer and explanation
Correct option: D
Work done
Option D (Work done) is correct because the area under the force-displacement curve represents the work done.
302 Medium
302 of 496
Application +4 | -1
If the kinetic energy of a body is increased 2 times, its momentum will
View answer and explanation
Correct option: D
increase 2\sqrt 2 times
Option D (increase 2\sqrt 2 times) is correct because momentum is proportional to the square root of kinetic energy, so doubling the kinetic energy increases momentum by a factor of 2\sqrt 2.
303 Medium
303 of 496
Application +4 | -1
A force acts on a 2 kg object, so that its position is given as a function of time as x=3t2+5x = 3{t^2} + 5. What is the work done by this force in first 5 seconds?
View answer and explanation
Correct option: B
900 J
Option B (900 J) is correct because the work done is equal to the change in kinetic energy, which can be calculated from the velocity at t=0 and t=5 seconds.
304 Medium
304 of 496
Application +4 | -1
A neutron moving with velocity v collides with a stationary α\alpha-particle.The velocity of the neutron after the collision is
View answer and explanation
Correct option: A
−3v5- \frac{{3v}}{5}
Option A (−3v5- \frac{{3v}}{5}) is correct because it is calculated by applying the conservation of momentum and kinetic energy in an elastic collision between the neutron and the alpha particle.
305 Medium
305 of 496
Application +4 | -1
A body thrown vertically up with certain velocity. The power due to gravitational force is maximum
View answer and explanation
Correct option: C
Just before striking ground
Option C (Just before striking ground) is correct because the power due to gravitational force is maximum when the velocity is maximum, which occurs just before impact.
306 Medium
306 of 496
Application +4 | -1
A uniform rope of mass 1 kg1 \mathrm{~kg} and length 1 m1 \mathrm{~m} is lying on the ground. One end of the rope is pulled up by a worker with the constant velocity of 1 m/s1 \mathrm{~m} / \mathrm{s}. The average power supplied by the worker in pulling the entire rope just off the ground such that the rope becomes vertical is (take g=10 m/s2g=10 \mathrm{~m} / \mathrm{s}^2 )
View answer and explanation
Correct option: A
5.5 W5.5 \mathrm{~W}
Option A (5.5 W5.5 \mathrm{~W}) is correct because it is the average power calculated by considering both the potential energy increase and the kinetic energy of the rope as it's lifted.
307 Medium
307 of 496
Application +4 | -1
A particle of mass MM is moving in a circle of fixed radius RR in such a way that its centripetal acceleration at time tt is given by n2Rt2n^2 R t^2 where nn is a constant. The power delivered to the particle by the force acting on it, is
View answer and explanation
Correct option: B
Mn2R2tM n^2 R^2 t
Option B (Mn2R2tM n^2 R^2 t) is correct because the power delivered is the product of the tangential force and the tangential velocity, which results in Mn2R2tM n^2 R^2 t.
308 Medium
308 of 496
Application +4 | -1
A motor boat is going in a river with velocity V⃗=4i^−2j^+k^ ms−1\vec V = 4\hat i - 2\hat j + \hat k\,m{s^{ - 1}}. If the resisting force due to stream is F→=(5i^−10j^+6k^)N\overrightarrow F = \left( {5\hat i - 10\hat j + 6\hat k} \right)N, then the power of motor boat is
View answer and explanation
Correct option: C
46 w
The correct answer is C (46 w) because the power is the dot product of the force and velocity vectors.
309 Medium
309 of 496
Application +4 | -1
A body of mass 0.1 kg moving with a velocity of 10 m/s hits a spring (fixed at the other end) of force constant 1000 N/m and comes to rest after compressing the spring. The compression of the spring is
View answer and explanation
Correct option: B
0.1 m0.1\,m
Option B (0.1 m) is correct because the kinetic energy of the mass is converted into the potential energy of the spring.
310 Medium
310 of 496
Application +4 | -1
A body of mass 1 gm1 \,{gm} is released down an inclined plane describes a circle of radius 10 cm10 {~cm} in the vertical plane on reaching the bottom. The minimum height of that inclined plane is
View answer and explanation
Correct option: B
25 cm25 {~cm}
Option B (25 cm) is correct because it is the minimum height required for the mass to complete the vertical circle, calculated using energy conservation principles.
311 Medium
311 of 496
Application +4 | -1
A block of mass 1.0 kg1.0 \mathrm{~kg} moving on a horizontal surface with speed 2 m/s2 \mathrm{~m} / \mathrm{s} enters a rough surface. The retarding force (Fr)\left(F_r\right) on the block is given by

Fr={−kx;10 m<x<100 m0;x<10 m and x>100 mF_r=\left\{\begin{array}{l} -\frac{k}{x} ; 10 \mathrm{~m} < x < 100 \mathrm{~m} \\ 0 ; x < 10 \mathrm{~m} \text { and } x > 100 \mathrm{~m} \end{array}\right.

where k=0.5 Jk=0.5 \mathrm{~J}. The kinetic energy of the block at x=100 mx=100 \mathrm{~m} is
View answer and explanation
Correct option: C
0.85 J0.85 \mathrm{~J}
Option C (0.85 J0.85 \mathrm{~J}) is correct because it is the final kinetic energy calculated using the work-energy theorem, considering the retarding force.
312 Medium
312 of 496
Understanding +4 | -1
Work done by the gravitational force on a body of mass &lsquo;m&rsquo; moving on a smooth horizontal surface through a distance &lsquo;s&rsquo; is.
View answer and explanation
Correct option: C
0
Option C is correct because the gravitational force acts vertically downwards, while the displacement is horizontal, resulting in zero work done.
313 Medium
313 of 496
Understanding +4 | -1
Kinetic energy of any moving particle is
View answer and explanation
Correct option: A
Scalar, positive
Option A is correct because kinetic energy is a scalar quantity and is always positive or zero, never negative.
314 Medium
314 of 496
Analyzing +4 | -1
The kinetic energy of particle continuously increase with time
a. The resultant force on the particle must parallel to velocity at all instants
b. The resultant force on the particle at an angle less than 90∘90^{\circ} all the time
c. Its height above the ground level continuously decrease
d. The magnitude of its linear momentum is increasing continuously
View answer and explanation
Correct option: D
b, d are correct
Option D is correct because if the kinetic energy of a particle continuously increases, the resultant force must have a component along the velocity (angle less than 90 degrees), and the magnitude of its linear momentum increases continuously.
315 Medium
315 of 496
Application +4 | -1
A stone of mass 1 kg tied to a light inextensible string of length L=103L = \frac{{10}}{3} is whirling in a circular path of radius L in vertical plane. If the ratio of the maximum tension to the minimum tension in the string is 4. What is the speed of stone at the highest point of the circle? (Taking g=10ms−2\mathrm{g} = 10\mathrm{m}{\mathrm{s}^{ - 2}})
View answer and explanation
Correct option: A
10 ms−1\mathrm{m}{\mathrm{s}^{ - 1}}
Option A (10 ms−1\mathrm{m}{\mathrm{s}^{ - 1}}) is correct because it is the speed of the stone at the highest point, calculated using the tension ratio and circular motion principles.
316 Medium
316 of 496
Analyzing +4 | -1
A stream of particles α\alpha-particles encounters a stationary unknown nucleus in a cloud chamber. After a collision, the two nuclei are scattered in mutually perpendicular directions. If some kinetic energy is lost in the collision, the unknown nucleus must be
View answer and explanation
Correct option: D
a nucleus heavier than an α\alpha-particle
Option D is correct because if kinetic energy is lost and the particles scatter perpendicularly, the unknown nucleus must be heavier than the alpha particle to conserve momentum.
317 Medium
317 of 496
Analyzing +4 | -1
Statement I: The maximum speed at which a car can turn on level curve of radius 40 m40 \mathrm{~m}, is 11 m/s;μ=0.311 \mathrm{~m} / \mathrm{s} ; \mu=0.3.

Statement II: v=μRg⇒μ=v2Rg=11×1140×10=0.3v=\sqrt{\mu \mathrm{Rg}} \Rightarrow \mu=\frac{\mathrm{v}^2}{\mathrm{Rg}}=\frac{11 \times 11}{40 \times 10}=0.3.
View answer and explanation
Correct option: A
If both Statement - I and Statement - II are true, and Statement - II is the correct explanation of Statement - I
Option A is correct. Statement I is true because the maximum speed is calculated using the formula v = √(μRg), and Statement II correctly explains how the coefficient of friction is derived from this formula.
318 Medium
318 of 496
Application +4 | -1
What average power is generated by a 90.0 kg90.0 \mathrm{~kg} mountain climber who climbs a summit of height 600 m600 \mathrm{~m} in 90.0 min90.0 \mathrm{~min} ?
View answer and explanation
Correct option: A
100 W100 \mathrm{~W}
Option A (100 W100 \mathrm{~W}) is correct because it is calculated by dividing the potential energy gained by the climber by the time taken.
319 Medium
319 of 496
Understanding +4 | -1
When a body falls freely under gravity, then the work done by the gravity is:
View answer and explanation
Correct option: A
Positive
Option A (Positive) is correct because the force of gravity and the displacement of the body are in the same direction, resulting in positive work done.
320 Medium
320 of 496
Application +4 | -1
A stone is moved in a horizontal circle of radius 4 m4 \mathrm{~m} by means of a string at the height of 20 m20 \mathrm{~m} above the ground. The string breaks and the particles fliesoff horizontally, striking the ground 10 m10 \mathrm{~m} away. The centripetal acceleration during circular motion is given by
View answer and explanation
Correct option: A
6.25 ms−26.25 \mathrm{~ms}^{-2}
Option A (6.25 ms−26.25 \mathrm{~ms}^{-2}) is correct because it is the centripetal acceleration calculated using the stone's velocity and the radius of the circular path.
321 Medium
321 of 496
Analyzing +4 | -1
Assertion (A): Collision between two fundamental particles is elastic
Reason (R): Fundamental particles lose their shape in collision
View answer and explanation
Correct option: C
If Assertion is true but Reason is false
Option C (If Assertion is true but Reason is false) is correct because collisions between fundamental particles are elastic, but they do not lose their shape.
322 Medium
322 of 496
Application +4 | -1
The velocity vector of a sphere after it hits a vertical wall which is parallel to j^\hat{j} is (−i^+3j^)(-\hat{i}+3 \hat{j}) on a smooth horizontal surface. The coefficient of restitution between ball and wall is (1/2). Find the velocity vector of sphere immediately before collision.
View answer and explanation
Correct option: D
2i^+3j^2 \hat{i}+3 \hat{j}
Option D (2i^+3j^2 \hat{i}+3 \hat{j}) is correct because the component of velocity parallel to the wall remains unchanged, and the perpendicular component is reversed and scaled by the coefficient of restitution.
323 Medium
323 of 496
Understanding +4 | -1
You lift a suitcase from the floor and keep it on table. The work done by you on the suitcase does not depend on
a. The path taken by the suitcase
b. The time taken by you in doing so
c. The weight of the suitcase
d. Your weight
View answer and explanation
Correct option: A
a, b &\& d are correct
Option A (a, b & d) is correct because work done by you on the suitcase depends on the weight of the suitcase and the height it is lifted, but not on the path taken, the time taken, or your weight.
324 Medium
324 of 496
Application +4 | -1
A boy of mass 1 kg moves from point A(2m,3m,4m) to B(3m,2m,5m). During motion of body, a force F⃗=(2N)i^−(4N)j^\mathbf{\vec F} = \left( {2\mathrm{N}} \right)\hat i - \left( {4\mathrm{N}} \right)\hat j acts on it. The work done by the force on the particle displacement is
View answer and explanation
Correct option: D
None of these
None of these is correct. The work done is calculated by taking the dot product of the force and displacement vectors, resulting in -2 J.
325 Medium
325 of 496
Application +4 | -1
By burning 1 g1 \mathrm{~g} of coal, the energy produced is 2kcal2 \mathrm{kcal}. Then for 1kWh1 \mathrm{kWh}, the quantity of coal so required will be nearly
View answer and explanation
Correct option: C
37 kg\frac{3}{7} \mathrm{~kg}
Option B (K2\frac{K}{2}) is correct because the kinetic energy is inversely proportional to the moment of inertia when angular momentum is conserved.
326 Medium
326 of 496
Analyzing +4 | -1
Assertion: No work is done by a force on an object when the point of application of the force does not move.
Reason: A small block of mass mm is kept on a rough inclined surface of inclination aa fixed in an elevator. The elevator goes up with a uniform velocity uu and the block does not slide on the wedge. Then the work done by the force of friction on the block in time tt will be mgutsin⁡2αmgut \sin ^2 \alpha.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion) is correct. The assertion is true, and the reason is also true, but the reason does not explain the assertion.
327 Medium
327 of 496
Analyzing +4 | -1
The potential energy function for the force between two atoms in a diatomic molecule is approximately given by U(x)ax12  −bx6U\left( x \right)\frac{a}{{{x^{12}}}}\; - \frac{b}{{{x^6}}} ,where a and b are constants and x is the distance between the atoms , If the dissociation energy of the molecule is D=[U(x=∞)−Uat  equilibrium],DD = \left[ {U\left( {x = \infty } \right) - {U_{\mathrm{at\,\,equilibrium}}}} \right],D is
View answer and explanation
Correct option: C
b24a\frac{{{b^2}}}{{4a}}
Option C (b24a\frac{{{b^2}}}{{4a}}) is correct because it is the correct expression for the dissociation energy D calculated from the potential energy function.
328 Medium
328 of 496
Application +4 | -1
Two balls of same mass are projected one vertically upwards and the other at angle 60∘60^{\circ} with the vertical. The ratio of their potential energy at the highest point is
View answer and explanation
Correct option: C
4:14: 1
Option C (4:14: 1) is correct because the ratio of potential energies at the highest point depends on the square of the sine of the angle with the horizontal.
329 Medium
329 of 496
Analyzing +4 | -1
Assertion(A): A spring of force constant kk is cut into two pieces having lengths in the ratio 1:21: 2. The force constant of series combination of the two parts is 3k/23 k / 2.

Reason(R): The spring connected in series are represented by k=k1+k2k=k_1+k_2.
View answer and explanation
Correct option: D
Both Assertion and Reason are incorrect.
Option D (Both Assertion and Reason are incorrect) is correct because the force constant is inversely proportional to length, and springs in series combine reciprocally, not additively.
330 Medium
330 of 496
Understanding +4 | -1
A particle is moving on a circular path with constant speed, then its acceleration will be
View answer and explanation
Correct option: C
Internal radial acceleration
Option C (Internal radial acceleration) is correct because a particle moving in a circle with constant speed experiences centripetal acceleration directed towards the center.
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