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JEE • PHYSICS • WORK-ENERGY-POWER

Work-energy-power practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 481-510 of 535 questions

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481 Medium
481 of 535
Application +4 | -1
A particle of mass m1\mathrm{m}_1 collides head-on with another stationary particle of mass m2(m2>m1)\mathrm{m}_2\left(\mathrm{m}_2 > \mathrm{m}_1\right). The collision is perfectly inelastic. The fraction of kinetic energy which is converted into heat in this collision is
View answer and explanation
Correct option: A
m2/(m1+m2)\mathrm{m}_2 /\left(\mathrm{m}_1+\mathrm{m}_2\right)
Option A (m2/(m1+m2)\mathrm{m}_2 /\left(\mathrm{m}_1+\mathrm{m}_2\right)) is correct because it represents the fraction of kinetic energy converted into heat during a perfectly inelastic collision, derived from conservation of momentum and energy loss calculations.
482 Medium
482 of 535
Application +4 | -1
A car is moving along a circular path of radius 500 m500 {~m} with a speed of 30 ms−130 {~ms}^{-1}. If at some instant, its speed increases at the rate of 2 ms−12 {~ms}^{-1}, then at that instant, the magnitude of resultant acceleration will be
View answer and explanation
Correct option: D
2.7 ms−22.7 {~ms}^{-2}
Option D (2.7 ms−22.7 {~ms}^{-2}) is correct because it is the magnitude of the resultant acceleration, calculated using both centripetal and tangential accelerations.
483 Medium
483 of 535
Application +4 | -1
A particle of mass mm collides head-on with another stationary particle of mass MM such that the second particle starts moving and the first particle comes to rest after the collision. Which of the following conditions is valid if the coefficient of restriction is ee?
View answer and explanation
Correct option: B
e=mM≤1e=\frac{m}{M} \leq 1
Option B (e=mM≤1e=\frac{m}{M} \leq 1) is correct because the coefficient of restitution is the ratio of velocities, which equals mM\frac{m}{M} and must be less than or equal to 1.
484 Medium
484 of 535
Understanding +4 | -1
Statement-I: A quick collision between two bodies is more violent than slow collision, even when initial and final velocities are identical.
Statement-II: The rate of change of momentum determines that the force is small or large.
View answer and explanation
Correct option: A
Statement-I &\& II are true.
Option A is correct because both statements are true. A quick collision involves a larger force due to a shorter impact time, and the rate of change of momentum directly determines the magnitude of the force.
485 Easy
485 of 535
Application +4 | -1
KE of a body is increased by 44 % what is the percent increase in the momentum?
View answer and explanation
Correct option: B
0.2
Option B (20%) is correct because a 44% increase in kinetic energy corresponds to a 20% increase in momentum, as derived from the relationship between kinetic energy and momentum.
486 Medium
486 of 535
Application +4 | -1
A long spring, when stretched by x cm has a potential energy U. On increasing the length of spring by stretching to nx cm, the potential energy stored in the spring will be
View answer and explanation
Correct option: C
n2U{n^2}U
Option C (n2U{n^2}U) is correct because the potential energy stored in a spring is proportional to the square of the extension.
487 Medium
487 of 535
Analyzing +4 | -1
Two bodies of mass M and m are moving with same kinetic energy. If they are stopped by same retarding force, then
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because all the given statements are correct based on the principles of work, energy, and momentum.
488 Medium
488 of 535
Understanding +4 | -1
The quantity that is not conserved in an inelastic collision is
View answer and explanation
Correct option: B
Kinetic energy
Option B (Kinetic energy) is correct because kinetic energy is not conserved in an inelastic collision, while momentum and total energy are always conserved.
489 Medium
489 of 535
Application +4 | -1
A person stands on a spring balance at the equator. By what percentage is the balance reading less than his true weight?
View answer and explanation
Correct option: A
0.35%0.35 \%
Option A (0.350.35 \\%) is correct because the percentage difference is calculated using the formula (ω2R/g\omega^2 R / g) * 100, accounting for the Earth's rotation.
490 Medium
490 of 535
Application +4 | -1
A block of mass 5 kg5 \mathrm{~kg} is moving along xx-axis under the action of a variable force F=10x NF=10 x \mathrm{~N}. The work done by the force in moving the block from x=4 mx=4 \mathrm{~m} to x=6 mx=6 \mathrm{~m} will be
View answer and explanation
Correct option: D
100 J100 \mathrm{~J}
Option D (100 J100 \mathrm{~J}) is correct because it is the work done calculated by integrating the force over the given displacement.
491 Medium
491 of 535
Application +4 | -1
A coin placed on a rotating turn table just slips if it is placed at a distance of 8 cm from the centre. If angular velocity of the turn table is doubled, it will just slip at a distance of
View answer and explanation
Correct option: B
2 cm
Option B (2 cm) is correct because when the angular velocity doubles, the radius at which the coin slips decreases by a factor of four.
492 Medium
492 of 535
Remembering +4 | -1
For motion under an external conservative force, which quantity is conserved?
View answer and explanation
Correct option: B
Mechanical energy
Option B (Gallium arsenide) is correct because Gallium arsenide is a semiconductor material commonly used in LEDs to produce visible light.
493 Medium
493 of 535
Application +4 | -1
Find out the power of an engine which can draw a train of ' 400 ' metric ton up the inclined plane of 1 in 98 at the rate 10 ms−110 \mathrm{~ms}^{-1}. The resistance due to friction acting on the train is ' 10 ' N\mathrm{N} per ton.
View answer and explanation
Correct option: C
440 KW
Option C (440 KW) is correct because the power is calculated considering both the inclined plane and the friction force.
494 Medium
494 of 535
Understanding +4 | -1
A body is falling freely under the action of gravity alone in vacuum. Which of the following quantities remain constant during the fall?
View answer and explanation
Correct option: C
Total mechanical energy
Option C (Total mechanical energy) is correct because in the absence of non-conservative forces, the total mechanical energy (potential + kinetic) remains constant.
495 Medium
495 of 535
Application +4 | -1
A uniform chain of length LL and mass MM is lying on a table and 14th\frac{1}{4}^{\text {th}} of its length is hanging vertically down over the edge of the table. If gg is acceleration due to gravity, the work required to pull the hanging part back on the table
View answer and explanation
Correct option: B
MgL32\frac{{MgL}}{32}
Option B (MgL32\frac{{MgL}}{{32}}) is correct because it represents the work required to lift the hanging part of the chain to the table level, calculated by considering the center of mass of the hanging part.
496 Medium
496 of 535
Analyzing +4 | -1
Assertion: The work done in moving a body over a closed loop is zero for every force in nature.
Reason: Work done depends on nature of force.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
Option B is correct because both the assertion (work done in a closed loop by conservative forces is zero) and the reason (work depends on the nature of the force) are true, but the reason doesn't explain the assertion.
497 Medium
497 of 535
Application +4 | -1
A force F⃗=3i^−2j^+4k^\vec{F}=3 \hat{i}-2 \hat{j}+4 \hat{k} displaces a body from a point A(8,−2,−3)A(8,-2,-3) to the point B(−2,0,6)B(-2,0,6). The work done is
View answer and explanation
Correct option: B
2 units
Option B (2 units) is correct because the work done is calculated by taking the dot product of the force vector and the displacement vector.
498 Medium
498 of 535
Analyzing +4 | -1
Assertion: when a spring is elongated work done by spring is negative but when it compressed work done by spring is positive.
Reason: Work done by spring is path dependent.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because both the assertion and the reason are false. Work done by a spring is negative when the spring is elongated *or* compressed from its equilibrium position, and work done by a spring is path-independent (conservative force).
499 Medium
499 of 535
Analyzing +4 | -1
Assertion: For an isolated system mechanical energy is conserved.
Reason: Kinetic frictional force is absent for isolated system.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because neither the assertion nor the reason is true for an isolated system; mechanical energy is not always conserved due to non-conservative forces, and kinetic friction can exist.
500 Medium
500 of 535
Application +4 | -1
A certain spring is found not to obey Hooke's law, it exerts a restoring force F(x)=−αx−βx2F(x)=-\alpha x-\beta x^2 if it is stretched or compressed, where α=48 N/m\alpha=48 \mathrm{~N} / \mathrm{m} and β=24 N/m2.\beta=24 \mathrm{~N} / \mathrm{m}^2. The mass of the spring is negligible. An object with mass 1 kg1 \mathrm{~kg} on a frictionless, horizontal surface is attached to the spring, pulled a distance 1 m1 \mathrm{~m} to the right to stretch the spring and released. The speed of the object when it is 0.5 m0.5 \mathrm{~m} to the right of the x=0x=0 equilibrium position is
View answer and explanation
Correct option: A
52 m/s5 \sqrt{2} \text{ m/s}
Option A (52 m/s5 \sqrt{2} \text{ m/s}) is correct because it is calculated using conservation of energy, considering the non-Hookean restoring force.
501 Medium
501 of 535
Understanding +4 | -1
Work done by conservative forces acting on body is always equal to
View answer and explanation
Correct option: A
Negative of change in potential energy
Option A (Negative of change in potential energy) is correct because the work done by conservative forces is equal to the negative change in potential energy.
502 Medium
502 of 535
Analyzing +4 | -1
A car is negotiating a curved road of radius RR. The road is banked at an angle θ\theta. The coefficient of friction between the tyres of the car and the road is μs\mu_s. The minimum safe speed such that the car does not slip on this road is; (consider tan⁡θ<μs\tan \theta < \mu_s )
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because if tan⁡θ<μs\tan \theta < \mu_s, the car can remain at rest without slipping on the banked road.
503 Medium
503 of 535
Application +4 | -1
A 500 kg500 \mathrm{~kg} car takes a round turn of radius 50 m50 \mathrm{~m} with a velocity of 36 km h−136 \mathrm{~km} \mathrm{~h}^{-1}. The centripetal force is
View answer and explanation
Correct option: C
1000 N1000 \mathrm{~N}
Option C (1000 N1000 \mathrm{~N}) is correct because it is the result of applying the centripetal force formula with the given mass, velocity, and radius.
504 Medium
504 of 535
Understanding +4 | -1
Which of the following quantities measured from different inertial reference frames are same?
View answer and explanation
Correct option: D
Kinetic energy
Option A (Force) is incorrect. Kinetic energy is not the same in different inertial reference frames. Force is the same in different inertial reference frames.
505 Medium
505 of 535
Application +4 | -1
How much is the mass of a man if he has to do 2500 joule of work in climbing a tree 5 m5 \mathrm{~m} tall ? (g=10 m/s2)\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)
View answer and explanation
Correct option: C
50 kg50 \mathrm{~kg}
Option C (50 kg50 \mathrm{~kg}) is correct because it is calculated using the formula for work done against gravity, W = mgh.
506 Medium
506 of 535
Understanding +4 | -1
A ball hits the floor and rebounds after inelastic collision. In this case
View answer and explanation
Correct option: C
The total momentum of the ball and the earth is conserved
Option D is correct because in an inelastic collision, the total energy of the ball and the earth is conserved, although mechanical energy is not.
507 Medium
507 of 535
Understanding +4 | -1
The closed line integral of force F⃗\vec{F} taken along the closed curve is given by ∮F⃗⋅dl^\oint \vec{F} \cdot d \hat{l}. If the force F⃗\vec{F} is conservative, then the value of this integral is
View answer and explanation
Correct option: A
zero
Option A is correct because the closed line integral of a conservative force over a closed path is always zero, due to the path-independent nature of conservative forces.
508 Medium
508 of 535
Remembering +4 | -1
The total energy of the universe is
View answer and explanation
Correct option: A
Constant
Option A (Constant) is correct because the total energy of an isolated system, like the universe, remains constant according to the law of conservation of energy.
509 Medium
509 of 535
Remembering +4 | -1
The potential energy of a weight less spring compressed by a distance a is proportional to
View answer and explanation
Correct option: B
a2{a^2}
Option B (a2{a^2}) is correct because the potential energy of a spring is given by U=(1/2)ka2U = (1/2)ka^2, where 'a' is the compression distance, making it proportional to the square of the compression.
510 Medium
510 of 535
Analyzing +4 | -1
Statement-I: When a body is rotated along a vertical circle with uniform speed then the sum of its kinetic energy and potential energy is constant at all positions
Statement-II: To make a body to move along a vertical circle, its critical speed at a point is independent of mass of body
View answer and explanation
Correct option: C
Statement-I is false, Statement-II is true
Option C is correct. The total mechanical energy (KE + PE) is not constant when speed is not uniform. The critical speed at a point is independent of the mass of the body.
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