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JEE • PHYSICS • WAVE OPTICS

Wave optics practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 396 questions

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91 Medium
91 of 396
Understanding +4 | -1
Assertion: One of the image in double refraction doesn't obey the principles of refraction.

Reason: Extraordinary image in double refraction doesn't obey the principles of refraction because its velocity changes with direction.
View answer and explanation
Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation of Assertion
Option A (Both Assertion and Reason are true and Reason is the correct explanation of Assertion) is correct because refraction is indeed caused by the change in the speed of light, which depends on the medium.
92 Medium
92 of 396
Application +4 | -1
The intensity of gamma radiation from a given source is II. On passing through 36  mm36\;mm of lead, it is reduced to I/8{I/8}. The thickness of lead which will reduce the intensity to I/2{I/2} will be
View answer and explanation
Correct option: B
12  mm12\;mm
Option B (12  mm12\;mm) is correct because it is derived from the exponential decay law for radiation intensity.
93 Medium
93 of 396
Understanding +4 | -1
Through which character we can distinguish the light waves from sound waves
View answer and explanation
Correct option: C
Polarization
Option C is correct because polarization is a property unique to transverse waves like light, and not exhibited by longitudinal waves like sound.
94 Medium
94 of 396
Application +4 | -1
In Young’s double-slit experiment, an interference pattern is obtained on a screen by a light of wavelength 6000A∘{6000\mathop \mathrm{A}\limits^ \circ }, coming from the coherent sources S1  and  S2{S_1}\;and\;{S_2}. At certain point PP on the screen third dark fringe is formed. Then the path difference S1P−S2P{S_1}P - {S_2}P in microns is
View answer and explanation
Correct option: B
1.51.5
Option B (1.5) is correct because the path difference for the third dark fringe in Young's double-slit experiment is (2n-1)λ/2, where n=3.
95 Medium
95 of 396
Understanding +4 | -1
The fringe width in Young’s double slit experiment increases when
View answer and explanation
Correct option: D
Distance between slits plane and screen increases
Option D is correct because the fringe width in Young's double-slit experiment is directly proportional to the distance between the slits and the screen.
96 Medium
96 of 396
Application +4 | -1
In Young’s double slit experiment, the intensity of light coming from the first slit is double the intensity from the second slit. The ratio of the maximum intensity to the minimum intensity on the interference fringe pattern observed is
View answer and explanation
Correct option: A
34
Option A (34) is correct because the ratio of maximum to minimum intensity in Young's double-slit experiment depends on the intensities of the individual slits.
97 Medium
97 of 396
Application +4 | -1
The maximum intensity in the case if nn identical incoherent waves, each of intensity 2  Wm−2\mathrm{2}\;\mathrm{W}{\mathrm{m}^{ - 2}} is 32  Wm−232\;W{\mathrm{m}^{ - 2}}. The value of n is
View answer and explanation
Correct option: B
16
Option B (16) is correct because the maximum intensity of n identical incoherent waves is n times the intensity of a single wave.
98 Medium
98 of 396
Analyzing +4 | -1
Assertion: No interference pattern is detected when two coherent sources are very close to each other. (i.e. separation almost zero).

Reason: The fringe width is inversely proportional to the distance between the two slits.
View answer and explanation
Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation of Assertion
Option A (Both Assertion and Reason are true and Reason is the correct explanation of Assertion) is correct because when the sources are very close, the fringe width becomes very large, making it difficult to observe a distinct interference pattern.
99 Medium
99 of 396
Understanding +4 | -1
If the shift of wavelength of light emitted by a star is towards violet, then this shows that star is
View answer and explanation
Correct option: B
Moving towards earth
Option B (Moving towards earth) is correct because a shift towards violet (blueshift) indicates a decrease in wavelength, implying the star is moving towards the observer.
100 Medium
100 of 396
Application +4 | -1
The ratio of the intensity at the centre of a bright fringe to the intensity at a point one-quarter of the distance between two fringe from the centre is
View answer and explanation
Correct option: A
2
Option A (2) is correct because the intensity is proportional to the square of the cosine of half the phase difference, and the phase difference at one-quarter of the fringe width is π/2\pi/2.
101 Medium
101 of 396
Understanding +4 | -1
When a beam of light is used to determine the position of an object, the maximum accuracy is achieved if the light is
View answer and explanation
Correct option: C
Of shorter wavelength
Option C (Of shorter wavelength) is correct because accuracy in determining position is inversely proportional to the wavelength of light.
102 Medium
102 of 396
Understanding +4 | -1
The wavefront of distant source of unknown shape is approximately
View answer and explanation
Correct option: D
Plane
Option D (Plane) is correct because at a very large distance from a source, the wavefront appears to be a plane.
103 Medium
103 of 396
Application +4 | -1
A light has amplitude A and angle between analyser and polarizer is 60∘60^\circ. Light is reflected by analyser has amplitude
View answer and explanation
Correct option: D
A/2A/2
Option D (A/2A/2) is correct because the amplitude of light after passing through an analyzer is given by Acos⁡θA \cos \theta, where θ\theta is the angle between the polarizer and analyzer.
104 Medium
104 of 396
Application +4 | -1
What will be the angular width of central maxima in Fraunhoffer diffraction when light of wavelength 6000A∘6000\mathop \mathrm{A}\limits^ \circ is used and slit width is 12×10−5  cm12 \times {10^{ - 5}}\;cm
View answer and explanation
Correct option: C
1  rad1\;rad
Option C (1;rad1\\;rad) is correct because the angular width of the central maxima in Fraunhofer diffraction is given by 2θ=2λd2\theta = \frac{2\lambda}{d}.
105 Medium
105 of 396
Understanding +4 | -1
Assertion : If white light is used is YDSE, then central bright fringe will be white.

Reason : Because all the wavelengths produce their zero order maxima at the same position
View answer and explanation
Correct option: A
If both Assertion and Reason are true and the Reason is a correct explanation of the Assertion
Option A (If both Assertion and Reason are true and the Reason is a correct explanation of the Assertion) is correct because the central bright fringe in YDSE with white light is white because all wavelengths have their zero-order maxima at the same position.
106 Medium
106 of 396
Understanding +4 | -1
A Young’s double slit experiment uses a monochromatic source. The shape of the interference fringes formed on a screen is
View answer and explanation
Correct option: C
Straight line
Option C is correct because in Young's double-slit experiment with a monochromatic source, the interference fringes formed on the screen are straight lines.
107 Medium
107 of 396
Analyzing +4 | -1
In Young’s double slit experiment, a third slit is made in between the double slits. Then
View answer and explanation
Correct option: B
Contrast between bright and dark fringes is reduced
Option B is correct. Introducing a third slit in Young's double-slit experiment reduces the contrast between bright and dark fringes because it introduces additional interference patterns that partially fill in the dark fringes.
108 Medium
108 of 396
Understanding +4 | -1
In Fraunhofer's single slit diffraction experiment
View answer and explanation
Correct option: A
width of the central bright band is twice the width of the third bright band
Option A is correct because in Fraunhofer single-slit diffraction, the central bright fringe's width is twice that of any other bright fringe.
109 Medium
109 of 396
Application +4 | -1
The two waves having intensities in the ratio 1:91: 9 produce interference. The ratio of the maximum to the minimum intensities is equal to
View answer and explanation
Correct option: C
4:14:1
Option C (4:14:1) is correct because it is the ratio of maximum to minimum intensities calculated using the interference formula.
110 Medium
110 of 396
Application +4 | -1
In a Young’s experiment, one of the slits is covered with a transparent sheet of thickness 3.6×10−3  cm3.6 \times {10^{ - 3}}\;cm due to which position of central fringe shifts to a position originally occupied by 30th{30^{th}} fringe. The refractive index of the sheet, if λ=6000A∘\lambda = 6000\mathop \mathrm{A}\limits^ \circ, is
View answer and explanation
Correct option: A
1.5
Option A, 1.5, is correct because it is the refractive index calculated using the shift in the central fringe position due to the introduction of a transparent sheet.
111 Medium
111 of 396
Understanding +4 | -1
In Young’s double slit experiment, if the source of light changes from orange to blue, then
View answer and explanation
Correct option: B
the distance between consecutive fringes will decrease
The distance between consecutive fringes decreases because the fringe width is directly proportional to the wavelength, and blue light has a shorter wavelength than orange light.
112 Medium
112 of 396
Understanding +4 | -1
The superposition of waves can result in
View answer and explanation
Correct option: A
Interference
Option A (Interference) is correct because superposition of waves leads to interference.
113 Medium
113 of 396
Remembering +4 | -1
The resolving limit of healthy eye is about
View answer and explanation
Correct option: A
1′1' or (160)0{\left( {\frac{1}{{60}}} \right)^0}
Option A is correct because the resolving limit of a healthy human eye is approximately 1 minute of arc (1').
114 Medium
114 of 396
Understanding +4 | -1
Figure represents a glass plate placed vertically on a horizontal table with a beam of unpolarised light falling on its surface at the polarizing angle of 57∘57^\circ with the normal. The electric vector in the reflected light on screen S will vibrate with respect to the plane of incidence in a
View answer and explanation
Correct option: A
Vertical plane
Option A (Vertical plane) is correct because the reflected light is polarized perpendicular to the plane of incidence at the polarizing angle.
115 Medium
115 of 396
Application +4 | -1
nth{n^{th}} Bright fringe if red light (λ1=7500A∘)\left( {{\lambda _1} = 7500\mathop \mathrm{A}\limits^ \circ } \right) coincides with (n+1)th{\left( {n + 1} \right)^{th}} bright fringe of green light (λ2=6000A∘)\left( {{\lambda _2} = 6000\mathop \mathrm{A}\limits^ \circ } \right). The value of n=?n = ?
View answer and explanation
Correct option: A
4
Option A (4) is correct because the condition for the coincidence of bright fringes is nλ1=(n+1)λ2n\lambda_1 = (n+1)\lambda_2, which can be solved for n.
116 Medium
116 of 396
Remembering +4 | -1
Colours in thin films are due to
View answer and explanation
Correct option: C
Interference phenomenon
Option C (Interference phenomenon) is correct because colors in thin films arise from the interference of light waves reflected from the top and bottom surfaces of the film.
117 Medium
117 of 396
Understanding +4 | -1
A scientist is observing a bacteria through a compound microscope. For better analysis and to improve its resolving power he should. (Select the best option)
View answer and explanation
Correct option: C
Increase the refractive index of the medium between the object and objective lens
Option C (Increase the refractive index of the medium between the object and objective lens) is correct because the resolving power of a microscope is directly proportional to the refractive index of the medium.
118 Medium
118 of 396
Understanding +4 | -1
Assertion: Transverse wave nature of light is proved by polarisation

Reason: According to Maxwell, light is an electro-magnetic wave but not mechanical wave.
View answer and explanation
Correct option: B
Both Assertion and Reason are true and Reason is not the correct explanation of Assertion
Option B (Both Assertion and Reason are true and Reason is not the correct explanation of Assertion) is correct because polarization demonstrates the transverse nature of light, and Maxwell's theory correctly describes light as an electromagnetic wave, but the latter doesn't explain the former.
119 Medium
119 of 396
Understanding +4 | -1
In YDSE if white light is used then.
View answer and explanation
Correct option: A
Except center, there will be spectrum
Option A is correct because in YDSE with white light, each wavelength creates its own interference pattern, resulting in a spectrum everywhere except the central bright fringe.
120 Medium
120 of 396
Remembering +4 | -1
Which of the following is a dichroic crystal?
View answer and explanation
Correct option: B
Tourmaline
Option B (Tourmaline) is correct because Tourmaline is a crystal known for exhibiting dichroism, the property of absorbing light differently depending on its polarization direction.
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