Skip to main content
Back to WAVE OPTICS

Your Progress

0 / 396 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • PHYSICS • WAVE OPTICS

Wave optics practice · Medium

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 301-330 of 396 questions

Preparing practice and saved progress…

301 Medium
301 of 396
Remembering +4 | -1
The electromagnetic theory of light failed to explain
View answer and explanation
Correct option: A
Photoelectric effect
Option A (Photoelectric effect) is correct because the electromagnetic theory of light could not explain the discrete nature of energy exchange in the photoelectric effect, which required the concept of photons.
302 Medium
302 of 396
Application +4 | -1
In young's experiment find the number of maximas formed if distance between the slits is 1.5λ1.5 \lambda. Where λ\lambda is wavelength of light used:
View answer and explanation
Correct option: B
3
Option B (3) is correct because only three integer values of 'n' satisfy the condition for maxima formation in Young's experiment.
303 Medium
303 of 396
Analyzing +4 | -1
Two monochromatic coherent point sources S1S_1 and S2S_2 are separated by a distance LL. Each source emits light of wavelength λ\lambda, where L>>λL >> \lambda. The line S1S2S_1 S_2 when extended meets a screen perpendicular to it at a point A.A.
View answer and explanation
Correct option: A
The interference fringes on the screen are circular in shape
Option A (The interference fringes on the screen are circular in shape) is correct because when the screen is perpendicular to the line joining the sources, the fringes formed are circular.
304 Medium
304 of 396
Application +4 | -1
In YDSE, a thin mica sheet of thickness 2×10−6 m2 \times 10^{-6} \mathrm{~m} and refractive index (μ=1.5)(\mu=1.5) is introduced in the path of the wave in front of the slit above the central line of the screen. The wavelength of the wave used is 5000A∘5000 \mathop {\text{A}}\limits^ \circ. The central bright maximum will shift
View answer and explanation
Correct option: A
2 fringes upward
Option A (2 fringes upward) is correct because the central bright maximum shifts upward by a distance equal to 2 fringe widths when the mica sheet is introduced.
305 Medium
305 of 396
Application +4 | -1
In a double slit experiment, two parallel slits are illuminated first by light of wavelength 400 nm400 \mathrm{~nm} and then by light of unknown wavelength. The fourth order dark fringe resulting from the known wavelength of light falls in the same place on the screen as the second order bright fringe from the unknown wavelength. The value of unknown wavelength of the light is
View answer and explanation
Correct option: B
700 nm700 \mathrm{~nm}
Option B (700 nm700 \mathrm{~nm}) is correct because the condition for dark fringes in a double-slit experiment is (n+12)Dλ1d=mDλ2d(n + \frac{1}{2})\frac{{D\lambda_1}}{{d}} = m \frac{{D\lambda_2}}{{d}}, where nn and mm are integers.
306 Medium
306 of 396
Understanding +4 | -1
When a compact disc is illuminated by small source of white light, coloured bands are observed. This is due to
View answer and explanation
Correct option: B
Diffraction
Option B (Diffraction) is correct because the colored bands are formed due to the diffraction of light by the closely spaced tracks on the CD surface.
307 Medium
307 of 396
Understanding +4 | -1
Young’s double slit experiment is carried out by using green, red and blue light, one color at a time. The fringe widths recorded are βG,βR  and  βB{\beta _G},{\beta _R}\;and\;{\beta _B}, respectively. Then
View answer and explanation
Correct option: D
βR>βG>βB{\beta _R} > {\beta _G} > {\beta _B}
Option D is correct. Fringe width is directly proportional to wavelength, and red light has the longest wavelength, followed by green, and then blue, resulting in the order βR>βG>βB{\beta _R} > {\beta _G} > {\beta _B}.
308 Medium
308 of 396
Understanding +4 | -1
In Young’s double slit experiment, if one of the slits is closed fully, then in the interference pattern
View answer and explanation
Correct option: A
A bright slit will be observed, no interference pattern will exist
The correct answer is A because closing one slit eliminates the interference pattern, leaving only a single-slit diffraction pattern, which appears as a bright slit.
309 Medium
309 of 396
Understanding +4 | -1
In a Young’s double slit experiment, the central point on the screen is
View answer and explanation
Correct option: A
Bright
Option A (Bright) is correct because in Young's double-slit experiment, the central point has zero path difference, leading to constructive interference and a bright fringe.
310 Medium
310 of 396
Understanding +4 | -1
Keeping all parameter fixed if distance between two slits in Young's double slit experiment is decreased, then fringe width will
View answer and explanation
Correct option: A
Increase
Option A (Increase) is correct because the fringe width in Young's double-slit experiment is inversely proportional to the distance between the slits.
311 Medium
311 of 396
Understanding +4 | -1
If white light is used in a YDSE setup, among the following the nearest bright fringe (maxima) from the central fringe will be formed by which of the colours
View answer and explanation
Correct option: B
Violet
Option B (Violet) is correct because the fringe width in YDSE is directly proportional to the wavelength, and violet light has the shortest wavelength among the given options.
312 Medium
312 of 396
Understanding +4 | -1
Which of the following the phenomenon cannot be explained
by corpuscular theory of light
View answer and explanation
Correct option: D
all of these
The correct answer is D (all of these) because the corpuscular theory of light fails to explain phenomena like interference, diffraction, and polarization, which are wave-like properties.
313 Medium
313 of 396
Application +4 | -1
A long narrow horizontal slit is placed 1 mm1 \mathrm{~mm} above a horizontal plane mirror. The interference between the light coming directly from the slit and that after reflection is seen on a screen 1.0 m1.0 \mathrm{~m} away from the slit. Find the fringe-width if the light used has a wavelength of 700 nm700 \mathrm{~nm}.
View answer and explanation
Correct option: A
0.35 mm
The correct answer is A (0.35 mm) because the fringe width in Lloyd's mirror experiment is calculated using the formula λDd\frac{\lambda D}{d}, where d is twice the distance between the slit and the mirror.
314 Medium
314 of 396
Understanding +4 | -1
Interference may be seen using two independent
View answer and explanation
Correct option: C
Lasers
Option C (Lasers) is correct because lasers provide coherent light sources which are necessary for observing interference patterns from independent sources.
315 Medium
315 of 396
Understanding +4 | -1
Assertion: The resolving power of a telscope more if the diameter ofthe objective lens is more.

Reason: Objective lens of large diameter collects more light.
View answer and explanation
Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation of Assertion
Option A (Both Assertion and Reason are true and Reason is the correct explanation of Assertion) is correct because a larger objective lens in a telescope increases its resolving power by collecting more light, which reduces diffraction effects.
316 Medium
316 of 396
Understanding +4 | -1
If yellow light emitted by sodium lamp in Young’s double slit experiment is replaced by a monochromatic blue light of the same intensity
View answer and explanation
Correct option: A
Fringe width will decrease
Option A (Fringe width will decrease) is correct because fringe width is directly proportional to wavelength, and blue light has a shorter wavelength than yellow light.
317 Medium
317 of 396
Understanding +4 | -1
Wave nature of light is verified by
View answer and explanation
Correct option: A
Interference
The correct answer is A (Interference) because interference is a phenomenon that demonstrates the wave nature of light.
318 Medium
318 of 396
Application +4 | -1
An electric bulb, connected to a make and break power supply, switches off and on every second in its rest frame. What is the frequency of its switching off and on as seen from a spaceship travelling at a speed 0.8c?0.8 c?
View answer and explanation
Correct option: A
0.6 s−10.6 \mathrm{~s}^{-1}
Option A (0.6 s−10.6 \mathrm{~s}^{-1}) is correct because the frequency is affected by time dilation due to the spaceship's speed, as observed from a different frame of reference.
319 Medium
319 of 396
Understanding +4 | -1
If white light is used in Young’s double slit experiment
View answer and explanation
Correct option: C
Central bright fringe is white
Option C (Central bright fringe is white) is correct because all wavelengths constructively interfere at the center, resulting in white light.
320 Medium
320 of 396
Understanding +4 | -1
Statement A: Diffraction of sound waves are more easily observed as compared to light waves.

Statement B: Wavelength of sound waves is more as compared to light.
View answer and explanation
Correct option: A
A and B are correct
Option A is correct because diffraction is more easily observed when the wavelength is comparable to the size of the obstacle, and sound waves generally have larger wavelengths than light waves.
321 Medium
321 of 396
Remembering +4 | -1
By corpuscular theory of light, the phenomenon which can be explained is
View answer and explanation
Correct option: A
Refraction
Option A (Refraction) is correct because the corpuscular theory of light, proposed by Newton, could explain refraction by suggesting that light particles travel faster in denser mediums.
322 Medium
322 of 396
Application +4 | -1
Two polaroids are kept crossed to each other. Now one of them us rotated through an angle of 45∘45^\circ. The percentage of incident light now transmitted through the system is
View answer and explanation
Correct option: B
25%25\%
Option B (25%25\%) is correct because the intensity of light transmitted through two polaroids with an angle of 45 degrees between their axes is 25% of the initial unpolarized light.
323 Medium
323 of 396
Understanding +4 | -1
For constructive interference to take place between two monochromatic light waves of wavelength λ\lambda, the path difference should be
View answer and explanation
Correct option: C
nλn\lambda
Option C (nλn\lambda) is correct because constructive interference occurs when the path difference is an integer multiple of the wavelength.
324 Medium
324 of 396
Understanding +4 | -1
Assertion: The resolving power of both microscope and telescope depends on the wavelength of light used.

Reason: The resolving power of a lens is the ability to resolve the two images so they are distinctly identified.
View answer and explanation
Correct option: B
Both Assertion and Reason are true and Reason is not the correct explanation of Assertion
Option B is correct because both the assertion and reason are true, but the reason does not explain why resolving power depends on wavelength.
325 Medium
325 of 396
Understanding +4 | -1
In YDSE experiment, when two light rays make third minima, then they have (λ\lambda wave length of each light ray)
View answer and explanation
Correct option: D
Path difference of 5 λ2\frac{{5\,\lambda }}{2}
Option D (Path difference of 5λ2\frac{{5\lambda}}{{2}}) is correct because for the third minima, the path difference is given by (2n−1)λ2(2n-1)\frac{{\lambda}}{{2}} where n=3.
326 Medium
326 of 396
Remembering +4 | -1
In Huygen’s wave theory, the locus of all points in the same state of vibration is called
View answer and explanation
Correct option: C
A wave-front
Option C (A wave-front) is correct because, according to Huygens' principle, a wavefront is defined as the locus of all points in the same phase of vibration.
327 Medium
327 of 396
Understanding +4 | -1
Huygens wave theory allows us to know
View answer and explanation
Correct option: D
The propagation of wave fronts
Option D (The propagation of wave fronts) is correct because Huygens' principle primarily describes how wave fronts propagate through space.
328 Medium
328 of 396
Understanding +4 | -1
Assertion: Radio waves diffract pronouncdly around the sharp edges of the buildings than visible light waves.

Reason: Wave length of radio waves is comparable to the dimension of the edges of the builging.
View answer and explanation
Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation of Assertion
Option A is correct. Radio waves diffract more around buildings because their wavelength is comparable to the building's dimensions, which is necessary for significant diffraction.
329 Medium
329 of 396
Understanding +4 | -1
Assertion: Radio waves can be polarised.

Reason: Sound waves in air are longitudinal in nature.
View answer and explanation
Correct option: B
Both Assertion and Reason are true and Reason is not the correct explanation of Assertion
Option B (Both Assertion and Reason are true and Reason is not the correct explanation of Assertion) is correct because radio waves are transverse and can be polarized, and sound waves are longitudinal, but the latter doesn't explain the former.
330 Medium
330 of 396
Application +4 | -1
A star moves away from earth at speed 0.8 c while emitting light of frequency 6×1014Hz6 \times {10^{14}}Hz.What frequency will be observed on the earth (in units of 1014  Hz{10^{14}}\;Hz)(c=c = speed of light)
View answer and explanation
Correct option: B
1.2
Option B (1.2) is correct because the observed frequency is calculated using the Doppler effect formula for receding sources.
Revision notes and key takeaways

Review WAVE OPTICS in your textbook or class notes, then use this set to check your understanding.

Showing 301-330 of 396 questions

Your practice

0 / 396 answered · 396 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.