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JEE • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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121 Medium
121 of 502
Understanding +4 | -1
Assertion: All derived quantities may be represented dimensionally in terms of the base quantities.
Reason : The dimensions of a base quantity in other base quantities are always zero.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B is correct because while the assertion is true, the reason is also true but does not explain the assertion.
122 Medium
122 of 502
Remembering +4 | -1
Illuminance of a surface is measured in
View answer and explanation
Correct option: C
lux
Option C (lux) is correct because illuminance, which is the measure of the amount of light falling on a surface, is measured in lux.
123 Medium
123 of 502
Analyzing +4 | -1
In the following list, the only pair which have different dimensions, is
View answer and explanation
Correct option: A
Linear momentum and moment of a force
Option A (Linear momentum and moment of a force) is correct because linear momentum has dimensions of [MLT⁻¹], while the moment of a force (torque) has dimensions of [ML²T⁻²].
124 Medium
124 of 502
Remembering +4 | -1
Dimensions of planck’s constant is:
View answer and explanation
Correct option: A
[M1L2T−1]\left[ {{M^1}{L^2}{T^{ - 1}}} \right]
Option A (M1L2T−1{{M^1}{L^2}{T^{ - 1}}}) is correct because Planck's constant has dimensions of energy multiplied by time, which is M1L2T−1{{M^1}{L^2}{T^{ - 1}}}.
125 Medium
125 of 502
Understanding +4 | -1
Consider the quantities, pressure, power, energy, impulse, gravitational potential, electrical charge, temperature, area. Out of these, the only vector quantities are
View answer and explanation
Correct option: B
Impulse and area
Option B (Impulse and area) is correct because impulse is a vector quantity and area can be treated as a vector quantity when considering surface normals.
126 Medium
126 of 502
Analyzing +4 | -1
Which of the following units denotes the dimensions [ML2/Q2],\left[ {\mathrm{M}{\mathrm{L}^2}/{\mathrm{Q}^2}} \right],, where Q denotes the electric charge?
View answer and explanation
Correct option: B
Henry (H)
Option B (Henry (H)) is correct because the dimensions of inductance (L) are [M L2 / Q2], which corresponds to Henry.
127 Medium
127 of 502
Application +4 | -1
If the percentage error in measuring length and diameter of a wire is 0.1%0.1 \% each, then the percentage error of the resistance of the wire is
View answer and explanation
Correct option: A
0.3%0.3 \%
Option A (0.3%0.3 \%) is correct because the percentage error in resistance is the sum of the percentage error in length and twice the percentage error in diameter.
128 Medium
128 of 502
Understanding +4 | -1
Which of the following quantity is NOT dimensionless?
View answer and explanation
Correct option: D
Radius of gyration
Option D (Radius of gyration) is correct because radius of gyration has dimensions of length, while the others are dimensionless.
129 Medium
129 of 502
Application +4 | -1
The radius of a uniform wire is r=0.021 cmr=0.021 \mathrm{~cm}. The value of π\pi is given to be 3.142. What is the area of cross-section of the wire up to appropriate significant figures?
View answer and explanation
Correct option: A
0.0014 cm20.0014 \mathrm{~cm}^2
Option A (0.0014 cm20.0014 \text{ cm}^2) is correct because the area is calculated using the formula for the area of a circle, and the result is rounded to the appropriate number of significant figures.
130 Medium
130 of 502
Analyzing +4 | -1
Which of the following is dimensionally correct
View answer and explanation
Correct option: B
Pressure = Energy per unit volume
Option B (Pressure = Energy per unit volume) is correct because pressure has dimensions of energy density, which is energy per unit volume.
131 Medium
131 of 502
Application +4 | -1
If the value of the resistance is 10.845Ω and the value of the current is 3.23 A, then the potential difference is 35.02935 V. its value in correct significant figures would be
View answer and explanation
Correct option: B
35.0 V
Option B (35.0 V) is correct because the result should be rounded to the least number of significant figures present in the given values, which is three.
132 Medium
132 of 502
Remembering +4 | -1
Given below are two statements.

Statement (I): Dimensional formula of planck's constant is [ML2T−1]\left[M L^2 T^{-1}\right]

Statement (II): Dimensional formula of bulk modulus is [ML−1T−2]\left[M L^{-1} T^{-2}\right]
View answer and explanation
Correct option: A
Both the statement (I) and (II) are correct
Option A (Both the statement (I) and (II) are correct) is correct because both the dimensional formula for Planck's constant and bulk modulus are stated correctly.
133 Medium
133 of 502
Remembering +4 | -1
The dimensions of surface tension are
View answer and explanation
Correct option: D
MT−2M{T^{ - 2}}
Option D (MT−2M{T^{ - 2}}) is correct because surface tension is force per unit length, and its dimensional formula is derived accordingly.
134 Medium
134 of 502
Application +4 | -1
Estimate the mean absolute error from the following data: 20.17,21.23,20.79,22.07,21.7820.17,21.23,20.79,22.07,21.78:
View answer and explanation
Correct option: B
0.58
Option B (0.58) is correct because it represents the mean of the absolute deviations from the mean value of the data.
135 Medium
135 of 502
Analyzing +4 | -1
Which of the following pair have same dimensional formula?
View answer and explanation
Correct option: B
Torque, work
Option B is correct because both torque and work have the same dimensional formula of ML2T−2ML^2T^{-2}.
136 Medium
136 of 502
Analyzing +4 | -1
Which of the following do not have the same dimensional formula as the velocity?
Given that m0=\mathrm{m}_0= permeability of free space, e0=\mathrm{e}_0= permittivity of free space, n\mathrm{n} = frequency, ll = wavelength, P=\mathrm{P}= pressure, r\mathrm{r} == density, w=\mathrm{w}= angular frequency, k=\mathrm{k}= wave number
View answer and explanation
Correct option: D
ωk\omega \mathrm{k}
Option D (ωk\omega k) is correct because its dimensional formula is [L⁻¹T⁻¹], which is different from the velocity's [LT⁻¹].
137 Medium
137 of 502
Analyzing +4 | -1
In the equation [X+aY2][Y−b]=RT, X\left[X+\frac{a}{Y^{2}}\right][Y-b]=R T, \, X is pressure, YY is volume, RR is universal gas constant TT is temperature. The physical quantity equivalent to the ratio ab\frac{a}{b} is:
View answer and explanation
Correct option: B
Energy
Option B (Energy) is correct. By equating dimensions, it is found that a/b has the same dimensions as PV, which is energy.
138 Medium
138 of 502
Analyzing +4 | -1
In the relation x=cos⁡(ωt+kx)x = \cos \left( {\omega t + kx} \right), the dimension(s) of ω\omega is/are
View answer and explanation
Correct option: C
[M0L0T−1]\left[ {{M^0}{L^0}{T^{ - 1}}} \right]
Option C ([M⁰L⁰T⁻¹]) is correct because the argument of the cosine function must be dimensionless, allowing us to determine the dimension of ω.
139 Medium
139 of 502
Understanding +4 | -1
Dimensions of specific heat are
View answer and explanation
Correct option: D
[L2 T−2 K−1]\left[\mathrm{L}^2 \mathrm{~T}^{-2} \mathrm{~K}^{-1}\right]
The correct answer is D (L2 T−2 K−1\mathrm{L}^2 \mathrm{~T}^{-2} \mathrm{~K}^{-1}) because specific heat is energy per unit mass per unit temperature change.
140 Medium
140 of 502
Application +4 | -1
Write the dimensions of aba b in the relation P=a−t2bx\mathrm{P}=\frac{\mathrm{a}-\mathrm{t}^2}{\mathrm{bx}}, where P\mathrm{P} is the pressure, x\mathrm{x} is the distance and tt is the time.
View answer and explanation
Correct option: B
ML0 T2\mathrm{ML}^0 \mathrm{~T}^2
Option B (ML0 T2\mathrm{ML}^0 \mathrm{~T}^2) is correct because it represents the dimensions of a/b, derived from the given relation by equating dimensions.
141 Medium
141 of 502
Application +4 | -1
If C is the restoring couple per unit radian twist and I is the moment of inertia, then the dimensional representation of 2πIC2\mathrm{\pi }\sqrt {\frac{I}{C}} will be
View answer and explanation
Correct option: B
[M0L0T  ]\left[ {{\mathrm{M}^0}{\mathrm{L}^0}{\mathrm{T}^\mathrm{\;}}} \right]
Option B [M0L0T  ]\left[ {{\mathrm{M}^0}{\mathrm{L}^0}{\mathrm{T}^\mathrm{\;}}} \right] is correct because it represents the dimension of time period, which is the result of the given expression.
142 Medium
142 of 502
Understanding +4 | -1
Assertion : Parallex method cannot be used for measuring distances of stars more than 100 light years away.

Reason : Because parallex angle reduces so much that it cannot be measured accurately.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and the reason is the correct explanation of the assertion) is correct because the parallax angle becomes too small to measure accurately for distant stars.
143 Medium
143 of 502
Analyzing +4 | -1
Assertion: Formula for kinetic energy is K=12mu2=ma\mathrm{K}=\frac{1}{2} \mathrm{mu}^2=\mathrm{ma}

Reason : Both the equation K=12mv2\mathrm{K}=\frac{1}{2} \mathrm{mv}^2 and k=ma\mathrm{k}=\mathrm{ma} are dimensionally incorrect.
View answer and explanation
Correct option: D
Assertion is incorrect, reason is correct
Option D is correct. The Assertion is incorrect because K = ma is dimensionally incorrect (ma represents force, not kinetic energy). The Reason is correct because both equations are dimensionally incorrect.
144 Medium
144 of 502
Analyzing +4 | -1
If electronic charge e,e, electron mass m\mathrm{m}, speed of light in vacuum c\mathrm{c} and Planck's constant h\mathrm{h} are taken as fundamental quantities, the permeability of vacuum μ0\mu_0 can be expressed in units of
View answer and explanation
Correct option: C
(hce2)\left(\frac{\mathrm{h}}{\mathrm{ce}^2}\right)
Option C (hce2)\left(\frac{\mathrm{h}}{\mathrm{ce}^2}\right) is correct because dimensional analysis confirms that the permeability of vacuum can be expressed in these units.
145 Medium
145 of 502
Application +4 | -1
Given R1=(3.0±0.1)Ω,R2=(6.0±0.2)ΩR_1=(3.0 \pm 0.1) \Omega, R_2=(6.0 \pm 0.2) \Omega, then calculated as 1RP=1R1+1R2\frac{1}{R_P}=\frac{1}{R_1}+\frac{1}{R_2} is given by
View answer and explanation
Correct option: B
(2.0±0.1)Ω(2.0 \pm 0.1) \Omega
Option A (5%5 \%) is correct because the percentage increase in time of flight is half the percentage increase in maximum height.
146 Medium
146 of 502
Understanding +4 | -1
The damping force of an oscillating particle is observed to be proportional to velocity. The constant of proportionality can be measured in
View answer and explanation
Correct option: A
Kg s−1{s^{ - 1}}
Option A is correct. The damping force is proportional to velocity (F = kv), so the constant of proportionality (k) has units of force/velocity, which is kg/s.
147 Medium
147 of 502
Analyzing +4 | -1
Which one of the following groups have quantities that do not have the same dimensions?
View answer and explanation
Correct option: C
Force, impulse
Option C (Force, impulse) is correct because force has dimensions of [MLT⁻²], while impulse has dimensions of [MLT⁻¹], which are different.
148 Medium
148 of 502
Analyzing +4 | -1
Which the following is/are correct?
I. Pressure = energy per unit area
II. Pressure = energy per unit volume
III. Pressure = force per unit volume
IV. Pressure = momentum per unit volume per unit time
View answer and explanation
Correct option: B
II only
Option B is correct because pressure is defined as energy per unit volume.
149 Medium
149 of 502
Understanding +4 | -1
Assertion : A.U. is much bigger than Ao.\mathop {\text{A}}\limits^{\text{o}} .
Reason: A.U. stands for astronomical unit and A stands for Angstrom.
View answer and explanation
Correct option: B
Assertion is correct, reason is correct; reason is not a correct explanation for assertion
Option B (Assertion is correct, reason is correct; reason is not a correct explanation for assertion) is correct because both statements are true, but the reason doesn't explain the assertion.
150 Medium
150 of 502
Application +4 | -1
The dimensions of specific resistance in terms of charge QQ is
View answer and explanation
Correct option: D
[ML3T−1Q−2]\left[M L^3 T^{-1} Q^{-2}\right]
Option D ([ML3T−1Q−2][M L^3 T^{-1} Q^{-2}]) is correct because it represents the dimensions of specific resistance derived from its formula involving resistance, area, and length.
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