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JEE • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 502 questions

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91 Medium
91 of 502
Understanding +4 | -1
How many wavelengths of Kr86  K{r^{86}}\mathrm{\;} are there in one metre
View answer and explanation
Correct option: B
1650764
Option B (1650763.73) is correct because it is the defined number of wavelengths of Kr86Kr^{86} in one meter.
92 Medium
92 of 502
Analyzing +4 | -1
A student writes four different expressions for the displacement yy in a periodic motion as a function of time t,at, a as amplitude, TT as time period. Which of the following can be correct?
View answer and explanation
Correct option: D
y=a2[sin⁡2πtT+cos⁡2πtT]y=\frac{a}{\sqrt{2}}\left[\sin \frac{2 \pi t}{T}+\cos \frac{2 \pi t}{T}\right]
Option D is correct because it is the only expression with correct dimensions for displacement and a dimensionless argument for the trigonometric functions.
93 Medium
93 of 502
Analyzing +4 | -1
Which is wrong dimension
View answer and explanation
Correct option: B
s=vt2\mathrm{s}=\mathrm{vt}^2
Option B (s=vt²) is the wrong dimension because the dimensions on both sides of the equation do not match.
94 Medium
94 of 502
Analyzing +4 | -1
Assertion: Surface tension and surface energy have the same dimensions.

Reason: Because both have the same S.I. unit
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C (If assertion is true but reason is false) is correct because surface tension and surface energy have the same dimensions but different SI units.
95 Medium
95 of 502
Analyzing +4 | -1
In the context of accuracy of measurement and significant figures in expressing results of experiment, which of the following is/are correct
(1) Out of the two measurements 50.14 cm and 0.00025 ampere, the first one has greater accuracy
(2) If one travels 478 km by rail and 397 m by road, the total distance travelled is 478 km
View answer and explanation
Correct option: C
Both are correct
Option C is correct. 50.14 cm has greater accuracy due to more significant figures. Converting 397 m to km gives 0.397 km, so the total distance is 478 + 0.397 = 478.397 km which rounds to 478 km due to significant figures.
96 Medium
96 of 502
Remembering +4 | -1
Volt/metre is the unit of
View answer and explanation
Correct option: D
Electric intensity
Option D (Electric intensity) is correct because electric intensity (electric field) is defined as the force per unit charge, which has units of Volt/meter.
97 Medium
97 of 502
Analyzing +4 | -1
Given that y=Asin⁡(aEt−bVx){y}={A} \sin ({aEt}-{bVx}) where y{y} displacement, E{E} energy, V{V} is velocity, t{t} and x{x} are time and distance respectively then, the dimension of a/b{a / b} is:
View answer and explanation
Correct option: C
M−1L0T0{M}^{-1} {L}^0 {T}^0
Option C is correct because by equating the dimensions of the arguments of the sine function, we can find the dimensions of a/b as M⁻¹L⁰T⁰.
98 Medium
98 of 502
Understanding +4 | -1
In an expression a×10b\mathrm{a} \times 10^{\mathrm{b}} :
View answer and explanation
Correct option: B
b\mathrm{b} is order of magnitude for a≤5\mathrm{a} \leq 5
Option D (b is order of magnitude for a≥5a \geq 5) is incorrect. Option B (b is order of magnitude for a≤5a \leq 5) is correct because in scientific notation, if 'a' is less than or equal to 5, then 'b' represents the order of magnitude.
99 Medium
99 of 502
Application +4 | -1
In an experiment four quantities a,b,ca, b, c and dd are measured with percentage error 2%,3%,4%2 \%, 3 \%, 4 \% and 1%1 \% respectively. Quantity PP is calculated as follows; P=a3b2cdP=\frac{a^3 b^2}{c d}. Percentage error in PP is;
View answer and explanation
Correct option: D
17%17 \%
Option D (17%17 \%) is correct because the percentage error in P is calculated by summing the absolute values of the percentage errors in a, b, c, and d, each multiplied by its exponent in the formula for P.
100 Medium
100 of 502
Remembering +4 | -1
Consider the following statements and select the correct
statement(s).
I. 1 calorie = 4.18 joule
II. 1Ao=10−10 m1\stackrel{o}{A}=10^{-10} \mathrm{~m}
III. 1MeV=1.6×10−131 \mathrm{MeV}=1.6 \times 10^{-13} Joule
IV. 1 newton =10−5=10^{-5} dyne
View answer and explanation
Correct option: A
I, II and III
Option A (I, II and III) is correct because statements I, II, and III are all correct conversions of units.
101 Medium
101 of 502
Remembering +4 | -1
Nm2/kg2N m^2 /kg^2 is a unit of
View answer and explanation
Correct option: A
Gravitational constant
Option A (Gravitational constant) is correct because the units Nm2/kg2N m^2 /kg^2 are the units of the gravitational constant (G) in Newton's law of gravitation.
102 Medium
102 of 502
Understanding +4 | -1
The dimension of E/H\mathrm{E} / \mathrm{H} is that of
View answer and explanation
Correct option: A
Impedance
Option A (Impedance) is correct because the ratio of electric field (E) to magnetic field (H) has the dimensions of impedance.
103 Medium
103 of 502
Understanding +4 | -1
Find the number of significant digits in the value 10.05.10.05.
View answer and explanation
Correct option: A
4
Option A is correct because all non-zero digits are significant, and zeros between non-zero digits are also significant.
104 Medium
104 of 502
Remembering +4 | -1
Which of the following is not one of the seven fundamental SI units?
View answer and explanation
Correct option: A
Henry
Option A (Henry) is correct because Henry is a derived SI unit, not a fundamental one. The fundamental units are metre, kilogram, second, ampere, candela, mole, and kelvin.
105 Medium
105 of 502
Analyzing +4 | -1
If the velocity (V)(V), acceleration (A)(A), and force (F)(F) are taken as fundamental quantities instead of mass (M)(M), length (L)(L), and time (T)(T), the dimensions of Young's modulus (Y)(Y) would be
View answer and explanation
Correct option: A
FA2V−4F A^2 V^{-4}
Option A (FA2V−4F A^2 V^{-4}) is correct because the dimensions of Young's modulus can be expressed as FA2V−4F A^2 V^{-4} when velocity, acceleration, and force are fundamental quantities.
106 Medium
106 of 502
Analyzing +4 | -1
Statement-I: Linear momentum and moment of force have same dimensions.
Statement-II: Planck’s constant and angular momentum have same dimension.
View answer and explanation
Correct option: B
Statement-I is false while statement-II is correct
Option B is correct because linear momentum and moment of force have different dimensions, while Planck's constant and angular momentum have the same dimensions.
107 Medium
107 of 502
Application +4 | -1
The dimensions of farad are
View answer and explanation
Correct option: A
M−1L−2T2Q2{M^{ - 1}}{L^{ - 2}}{T^2}{Q^2}
Option A (M−1L−2T2Q2{M^{ - 1}}{L^{ - 2}}{T^2}{Q^2}) is correct because it represents the correct dimensional formula for capacitance (Farad).
108 Medium
108 of 502
Application +4 | -1
The dimensions of h/e(h=\mathrm{h} / \mathrm{e}(\mathrm{h}= Planck's constant and e=\mathrm{e}= electronic charge) are same as that of:
View answer and explanation
Correct option: A
magnetic flux
Option A (magnetic flux) is correct because the ratio h/e has the same dimensions as magnetic flux, which can be derived from the relationship between voltage and magnetic flux.
109 Medium
109 of 502
Understanding +4 | -1
In which of the following numerical values, all zeros are significant?
View answer and explanation
Correct option: B
20.2
Option B (20.2) is correct because all zeros between non-zero digits are significant.
110 Medium
110 of 502
Analyzing +4 | -1
A physical quantity P=abc2d3P=\frac{\sqrt{a b c^2}}{d^3} is determined by measuring a,b,ca, b, c, and dd separately with the percentage error of 2%,3%,2%2 \%, 3 \%, 2 \%, and 1%1 \%, respectively. Minimum amount of error is contributed by:
View answer and explanation
Correct option: B
aa
Option B (aa) is correct because the percentage error in PP depends on the error in a,b,c,a, b, c, and dd, and the contribution from aa is the smallest.
111 Medium
111 of 502
Analyzing +4 | -1
Assertion : In the equation momentum, P=massareax,P = \frac{{mass}}{{area}}x, the dimensional formula of xx is LT−2.L{T^{ - 2}}.
Reason : Quantities with different dimensions can be multiplied.
View answer and explanation
Correct option: D
Assertion is incorrect, reason is correct
Option D is correct. The assertion is incorrect because the dimensional formula of x is L3T−1L^3T^{-1}, and the reason is correct because quantities with different dimensions can be multiplied.
112 Medium
112 of 502
Application +4 | -1
If L,CL, C and RR denote the inductance, capacitance and resistance respectively, the dimensional formula for C2LRC^2 L R is
View answer and explanation
Correct option: B
[M0L0T3I0]\left[M^0 L^0 T^3 I^0\right]
Option B ([M0L0T3I0]\left[M^0 L^0 T^3 I^0\right]) is correct because the dimensional analysis of C2LRC^2 L R results in dimensions of time cubed.
113 Medium
113 of 502
Understanding +4 | -1
Assertion: μN\mu \mathrm{N} is not the same as nm\mathrm{nm}.
Reason: 1μN=10−6 N1 \mu \mathrm{N}=10^{-6} \mathrm{~N} and 1 nm=10−9 m1 \mathrm{~nm}=10^{-9} \mathrm{~m}
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of assertion
Option A is correct because μN\mu N represents micronewtons (10−610^{-6} N) and nm represents nanometers (10−910^{-9} m), which are different physical quantities with different units.
114 Medium
114 of 502
Analyzing +4 | -1
The dimensions of 1∈0e2hc\frac{1}{{{ \in _0}}}\frac{{{e^2}}}{{hc}} are
View answer and explanation
Correct option: C
M0L0T0A0{M^0}{L^0}{T^0}{A^0}
Option C is correct. The expression is dimensionless because it represents the fine-structure constant, a fundamental constant in physics.
115 Medium
115 of 502
Application +4 | -1
In the formula F=A.ehcxF=A . e^{\frac{h c}{x}}, where hh is Planck's constant, and cc is speed of light. The dimensional formula for xx is
View answer and explanation
Correct option: B
[M1L3T−2]\left[M^1 L^3 T^{-2}\right]
Option B (M1L3T−2M^1 L^3 T^{-2}) is correct because the exponent must be dimensionless, allowing us to solve for the dimensions of x.
116 Medium
116 of 502
Analyzing +4 | -1
If C,R,L and I denote capacity, resistance, inductance and electric current respectively, the quantities having the same dimensions of time are (1) CR,  (2) LR ,  (3) LC  (4) LI2\left( 1 \right)\,CR,\,\,\left( 2 \right)\,\frac{L}{R}\,,\,\,\left( 3 \right)\,\sqrt {LC} \,\,\left( 4 \right)\,L{I^2}
View answer and explanation
Correct option: D
(1), (2) and (3) only
Option D ((1), (2) and (3) only) is correct because CR, L/R, and √(LC) all have the dimensions of time.
117 Medium
117 of 502
Analyzing +4 | -1
Assertion : The error in the measurement of radius of the
sphere is 0.3%.The permissible error in its surface area is
0.6%.
Reason : The permissible error is calculated by the formula ΔAA=4Δrr\frac{{\Delta A}}{A} = \frac{{4\Delta r}}{r}
View answer and explanation
Correct option: C
Assertion is correct, reason is incorrect
Assertion is correct, reason is incorrect. The assertion is correct because the error in surface area is twice the error in radius, but the reason provides the wrong formula.
118 Medium
118 of 502
Application +4 | -1
The pitch of screw gauge is 1 mm1 \mathrm{~mm} and there are 100 divisions on circular scale. While measuring diameter of a wire, linear scale reads 1 mm1 \mathrm{~mm} and 39th39^{\text {th}} division of circular scale coincides with reference line. The zero error is −0.05 mm-0.05 \mathrm{~mm}. The correct diameter of wire is
View answer and explanation
Correct option: B
1.44 mm1.44 \mathrm{~mm}
Option B (1.44 mm1.44 \mathrm{~mm}) is correct because the correct diameter is calculated by adding the linear scale reading, circular scale reading, and the zero error.
119 Medium
119 of 502
Analyzing +4 | -1
If Planck's constant (h)(h) and speed of light in vacuum (c)(c) are taken as two fundamental quantities, which one of the following can, in addition, be taken to express length, mass and time in terms of the three chosen fundamental quantities?

(i) Mass of electron (me)\left(m_e\right)

(ii) Universal gravitational constant (G)(G)

(iii) Charge of electron (e)(e)

(iv) Mass of proton (mp)\left(m_p\right)
View answer and explanation
Correct option: A
(i), (ii) and (iii)
The correct answer is A ((i), (ii) and (iii)) because these quantities, along with Planck's constant and speed of light, can be used to express length, mass, and time in terms of fundamental quantities.
120 Medium
120 of 502
Understanding +4 | -1
Inductance L can be dimensionally represented as
View answer and explanation
Correct option: A
ML2T−2A−2M{L^2}{T^{ - 2}}{A^{ - 2}}
Option A (ML2T−2A−2M{L^2}{T^{ - 2}}{A^{ - 2}}) is correct because the energy stored in an inductor is proportional to the inductance and the square of the current.
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