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JEE • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 481-502 of 502 questions
481 Medium
481 of 502
Application +4 | -1
A screw gauge with a pitch of 0.5 mm and a circular scale with 50 divisions is used to measure the thickness of a thin sheet of aluminium. Before starting the measurement, it is found that when the two jaws of the screw gauge are brought in contact, the 45th division coincides with the main scale line and that the zero of the main scale is barely visible. What is the thickness of the sheet, if the main scale reading is 0.5 mm and the 25th division coincides with the main scale line?
View answer and explanation
Correct option: A
0.75 mm
Option A (0.75 mm) is correct because it accurately calculates the thickness by considering the main scale reading, circular scale reading, and zero error of the screw gauge.
482 Medium
482 of 502
Analyzing +4 | -1
Assertion: The dimensional formula for product of resistance and conductance is same as for dielectric constant.

Reason: Both have dimensions of time constant.
View answer and explanation
Correct option: C
If assertion is true, but reason is false.
Option C (If assertion is true, but reason is false) is correct because both resistance times conductance and the dielectric constant are dimensionless, but they don't represent time constants.
483 Medium
483 of 502
Application +4 | -1
Age of the universe is about 1010yr10^{10} \mathrm{yr}, whereas the mankind has existed for 106yr10^6 \mathrm{yr}. For how many seconds would the man have existed, if age of universe were 1 day?
View answer and explanation
Correct option: C
8.6 s8.6 \mathrm{~s}
Option C (8.6 s8.6 \mathrm{~s}) is correct because the apparent age of mankind is calculated by scaling the age of the universe to one day.
484 Medium
484 of 502
Understanding +4 | -1
In the expression for Boyle's law, the product 'PVP V' has dimensions of
View answer and explanation
Correct option: C
Energy
Option C is correct because the product of pressure and volume (PV) has the dimensions of energy.
485 Medium
485 of 502
Understanding +4 | -1
Dimension of R is
View answer and explanation
Correct option: B
ML2T−3A−2M{L^2}{T^{ - 3}}{A^{ - 2}}
Option B (ML2T−3A−2M{L^2}{T^{ - 3}}{A^{ - 2}}) is correct because resistance is voltage divided by current, and substituting the dimensions of voltage and current gives the result.
486 Medium
486 of 502
Application +4 | -1
The volume of a cube in m3{m}^3 is equal to the surface area of the cube in m2{m}^2. The volume of the cube is
View answer and explanation
Correct option: B
216 m3216{~m}^3
Option B (216 m3216{~m}^3) is correct because the volume of the cube equals its surface area only when the side length is 6, resulting in a volume of 216.
487 Medium
487 of 502
Understanding +4 | -1
Assertion: One radian is the angle subtended at the centre of circle by an arc equal in length to the radius fo the circle.
Reason: Radian is the unit of distance
View answer and explanation
Correct option: C
If assertion is true reason is false
The correct answer is If assertion is true reason is false because radian is a unit of angle, not distance.
488 Medium
488 of 502
Analyzing +4 | -1
Assertion: Force can be subtracted from momentum.
Reason : Physical quantities with different nature and dimensions can be subtracted.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because force and momentum have different dimensions and cannot be subtracted, and physical quantities with different dimensions cannot be subtracted.
489 Medium
489 of 502
Analyzing +4 | -1
The position of a particle at time t is given by the relation x(t)=(v0α)(1−c−αt)x\left( t \right) = \left( {\frac{{{v_0}}}{\alpha }} \right)\left( {1 - {c^{ - \alpha t}}} \right), where v0{v_0} is a constant and α>0\alpha > 0. The diemensions of v0{v_0} and α\alpha are respectively
View answer and explanation
Correct option: A
M0L1T−1 and T−1{M^0}{L^1}{T^{ - 1}}\,{\text{and}}\,{T^{ - 1}}
Option A (M0L1T−1 and T−1{M^0}{L^1}{T^{ - 1}}\,{\text{and}}\,{T^{ - 1}}) is correct because it correctly identifies the dimensions of velocity and inverse time respectively.
490 Medium
490 of 502
Understanding +4 | -1
The expression [ML−1T−1]\left[ {\mathrm{M}{\mathrm{L}^{ - 1}}{\mathrm{T}^{ - 1}}} \right] represents
View answer and explanation
Correct option: D
Coefficient of viscosity
Option D (Coefficient of viscosity) is correct because the dimensional formula for the coefficient of viscosity is [ML⁻¹T⁻¹].
491 Medium
491 of 502
Application +4 | -1
A stone weighs (10.0±0.1)kg(10.0 \pm 0.1) \mathrm{kg} in air. The weight of the stone in water is (5.0±0.1)kg(5.0 \pm 0.1) \mathrm{kg}. Find the maximum percentage error in the measurement of specific gravity.
View answer and explanation
Correct option: A
5%5 \%
Option A (5%5 \%) is correct because the maximum percentage error in specific gravity is calculated by adding the percentage errors in weight in air and loss of weight in water.
492 Medium
492 of 502
Application +4 | -1
A screw gauge of pitch 0.5 mm0.5 \mathrm{~mm} is used to measure the diameter of uniform wire of length 6.8 cm6.8 \mathrm{~cm}, the main scale reading is 1.5 mm1.5 \mathrm{~mm} and circular scale reading is 7 . The calculated curved surface area of wire to appropriate significant figures is :
[Screw gauge has 50 divisions on its circular scale]
View answer and explanation
Correct option: B
3.4 cm23.4 \mathrm{~cm}^2
Option B (3.4 cm23.4 \mathrm{~cm}^2) is correct because it calculates the diameter using the screw gauge readings and then calculates the curved surface area of the wire.
493 Medium
493 of 502
Application +4 | -1
If the units of M,LM, L are doubled then the unit of kinetic energy will become:
View answer and explanation
Correct option: D
8 times
Option D (8 times) is correct because the kinetic energy is proportional to mass and the square of length, so doubling both results in an 8-fold increase.
494 Medium
494 of 502
Remembering +4 | -1
The ratio between pico and giga is
View answer and explanation
Correct option: B
10−2110^{-21}
Option B (10−2110^{-21}) is correct because pico is 10−1210^{-12} and giga is 10910^9, so the ratio is 10−12/109=10−2110^{-12} / 10^9 = 10^{-21}.
495 Medium
495 of 502
Application +4 | -1
In SI units, the dimensions of ∈0μ0\sqrt {\frac{{{ \in _0}}}{{{\mu _0}}}} is
View answer and explanation
Correct option: D
A2T3M−1L−2A{}^2{T^3}{M^{ - 1}}{L^{ - 2}}
The correct answer is D (A2T3M−1L−2A{}^2{T^3}{M^{ - 1}}{L^{ - 2}}) because it correctly represents the dimensions of the given expression in SI units.
496 Medium
496 of 502
Analyzing +4 | -1
Which of the following sets have different dimensions?
View answer and explanation
Correct option: D
Dipole moment, Electric flux, Electric field
Option D (Dipole moment, Electric flux, Electric field) is correct because these quantities have different dimensions, unlike the other options where the quantities have the same dimensions.
497 Medium
497 of 502
Application +4 | -1
If the length of rod A is (3.25  ±0.01)  cm\left( {3.25\; \pm 0.01} \right)\;\mathrm{cm} and that of B is (4.19  ±0.01)  cm,\left( {4.19\; \pm 0.01} \right)\mathrm{\;cm},, then the rod B is longer than rod A by
View answer and explanation
Correct option: C
(0.94  ±0.02)  cm\left( {0.94\mathrm{\;} \pm 0.02} \right)\mathrm{\;cm}
Option C (0.94  ±0.02)  cm\left( {0.94\mathrm{\;} \pm 0.02} \right)\mathrm{\;cm} is correct because the difference in lengths is calculated by subtracting the lengths and adding the uncertainties.
498 Medium
498 of 502
Analyzing +4 | -1
From the dimensional consideration, which of the following equation is correct
View answer and explanation
Correct option: A
T=2πrR3GM  T = 2\pi r\sqrt {\begin{array}{cccccccccccccccccccc} {\frac{{{R^3}}}{{GM}}}\\ \; \end{array}}
Option A (T=2πrR3GM;T = 2\pi r\sqrt {\begin{array}{cccccccccccccccccccc}{\frac{{{R^3}}}{{GM}}}\\;\end{array}}) is correct because dimensional analysis confirms that the dimensions on both sides of the equation match.
499 Medium
499 of 502
Understanding +4 | -1
Assertion: The number 1.202 has four significant figures and the number 0.0024 has two significant figures.
Reason: All the non-zero digits are significant.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
Option B (If both assertion and reason are true but reason is not the correct explanation of assertion) is correct because both statements are true, but the reason does not fully explain the assertion as embedded zeros are also significant.
500 Medium
500 of 502
Application +4 | -1
If x=at+12bt2x = at + \frac{1}{2}b{t^2}, where ‘x’ is in metre and ‘t’ in second. Then unit of ‘b’ is?
View answer and explanation
Correct option: D
ms−2m{s^{ - 2}}
Option D (ms−2m{s^{ - 2}}) is correct because the unit of 'b' is determined by dimensional analysis, ensuring the equation is dimensionally consistent.
501 Medium
501 of 502
Understanding +4 | -1
Given below are two statement :

Statements I : Astronomical unit (Au), Parsec (Pc) and Light year (ly) are units for measuring astronomical distances.

Statements II : Au < Parsec (Pc) < ly

In the light of the above statements, choose the most appropriate answer from the options given below:
View answer and explanation
Correct option: B
Statements I is correct but Statements II is
incorrect
Option B is correct because Astronomical Unit (AU), Parsec (Pc), and Light Year (ly) are indeed units for measuring astronomical distances, but the correct order is AU < ly < Parsec.
502 Medium
502 of 502
Application +4 | -1
A force ‘F’ is applied onto a square plate of side L. If the percentage error in determining L is 2% and that in F is 4%, then the percentage error in pressure is
View answer and explanation
Correct option: D
0.08
Option D (8%) is correct because the percentage error in pressure is the sum of the percentage error in force and twice the percentage error in length.
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