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JEE • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 361-390 of 502 questions

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361 Medium
361 of 502
Application +4 | -1
The initial temperature of a liquid is (80.0±0.1)0{\left( {80.0 \pm 0.1} \right)^0}C. After it has been cooled, its temperature is (10.0±0.1)0{\left( {10.0 \pm 0.1} \right)^0}C. The fall in temperature in degree centigrade is
View answer and explanation
Correct option: C
70.0±  0.270.0 \pm \;0.2
Option C (70.0±  0.270.0 \pm \;0.2) is correct because when subtracting quantities, their absolute errors are added.
362 Medium
362 of 502
Application +4 | -1
If random error in an experiment for 10 observations is ee, then random error in experiment for 60 observations will be
View answer and explanation
Correct option: B
e/6e / 6
Option B (e/6e / 6) is correct because random error decreases as the number of observations increases.
363 Medium
363 of 502
Application +4 | -1
The radius of a sphere is 1.41 cm1.41 \mathrm{~cm}. Express its volume to an appropriate number of significant figures.
View answer and explanation
Correct option: C
11.7 cm311.7 \mathrm{~cm}^3
Option C (11.7 cm311.7 \mathrm{~cm}^3) is correct because the volume is calculated using the sphere volume formula and rounded to the correct number of significant figures (3).
364 Medium
364 of 502
Application +4 | -1
A quantity ff is given by f=hc5G,f = \sqrt {\frac{{h{c^5}}}{G}} , where cc is speed of light, GG universal gravitational constant and hh is the Planck’s constant.
Dimension of ff is that of
View answer and explanation
Correct option: D
energy
Option D (energy) is correct because the dimensions of the given quantity match the dimensions of energy.
365 Medium
365 of 502
Application +4 | -1
If error in measurement of volume of a cube is 6%6 \% then percentage error in the measurement of its surface area is
View answer and explanation
Correct option: C
4%4 \%
Option C (4%4 \%) is correct because the percentage error in surface area is 2/3 times the percentage error in volume.
366 Medium
366 of 502
Understanding +4 | -1
Assertion: Mass, length and time are fundamental physical quantities.

Reason: They are independent of each other.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A is correct because mass, length, and time are fundamental quantities and are independent of each other, which is the reason for them being fundamental.
367 Medium
367 of 502
Application +4 | -1
The area of a square is 5.29  cm25.29\mathrm{ }\,\,c{m^2}. The area of 7 such squares taking into account the significant figures is
View answer and explanation
Correct option: B
37.0  cm237.0\mathrm{ }\,\,c{m^2}
Option B (37.0 cm237.0\mathrm{ }\,c{m^2}) is correct because it is the area of 7 squares, taking into account significant figures.
368 Medium
368 of 502
Analyzing +4 | -1
If a book with many printing errors contains four different formulae for the displacement yy of a particle undergoing a certain periodic motion.
(1) y=asin⁡2πtTy=a \sin \frac{2 \pi t}{T}
(2) y=asin⁡vTy=a \sin v T
(3) y=aTsin⁡tay=\frac{a}{T} \sin \frac{t}{a}
(4) y=(a2)(sin⁡2πtT+cos⁡2πtT)y=(a \sqrt{2})\left(\sin \frac{2 \pi t}{T}+\cos \frac{2 \pi t}{T}\right)
where aa is the maximum displacement of the particle, vv is the speed of particle, TT is the time period of motion. Then dimensionally
View answer and explanation
Correct option: B
(2) and (3) are wrong
Option B is correct because formulas (2) and (3) are dimensionally incorrect. The arguments of trigonometric functions must be dimensionless, and the dimensions of y must be length.
369 Medium
369 of 502
Understanding +4 | -1
μ0\mu_0 and ε0\varepsilon_0 denote the magnetic permeability and electrical permittivity of free space, then the dimensions of 1μ0ε0\frac{1}{\sqrt{\mu_0 \varepsilon_0}} are similar to
View answer and explanation
Correct option: B
velocity
Option B (velocity) is correct because the dimensions of 1μ0ε0\frac{{1}}{{\sqrt{{\mu_0 \varepsilon_0}}}} are [LT−1][LT^{-1}], which is the dimension of velocity.
370 Medium
370 of 502
Remembering +4 | -1
Oersted is a unit of
View answer and explanation
Correct option: B
Magnetic intensity
Option B (Magnetic intensity) is correct because Oersted is a unit of magnetic field strength, also known as magnetic intensity or H-field.
371 Medium
371 of 502
Application +4 | -1
The dimensions of   ab\;\frac{a}{b} in the equation p=a  −  t2bxp = \frac{{a\; - \;{t^2}}}{{bx}} where p is pressure, x is distance and t is time, are
View answer and explanation
Correct option: B
[MT−2]\left[ {\mathrm{M}{\mathrm{T}^{ - 2}}} \right]
Option B [MT−2]\left[ {\mathrm{M}{\mathrm{T}^{ - 2}}} \right] is correct because it is derived from dimensional analysis using the principle of homogeneity.
372 Medium
372 of 502
Application +4 | -1
How many amu would make up 1 kg?1 \mathrm{~kg}?
View answer and explanation
Correct option: A
6.024×1026amu6.024 \times 10^{26} \mathrm{amu}
Option A (6.024×1026amu6.024 \times 10^{26} \mathrm{amu}) is correct because 1 amu is approximately 1.66×10−271.66 \times 10^{-27} kg, so 1 kg is approximately 6.024×10266.024 \times 10^{26} amu.
373 Medium
373 of 502
Remembering +4 | -1
Lumen is the unit of
View answer and explanation
Correct option: A
luminous flux
Option A (luminous flux) is correct because the lumen is the SI unit specifically designed to measure luminous flux, which quantifies the total amount of visible light emitted by a source.
374 Medium
374 of 502
Remembering +4 | -1
What is the dimension of Luminous flux?
View answer and explanation
Correct option: A
[cd1][\mathrm{cd^1}]
Option A ([cd¹]) is correct because luminous flux is measured in lumens, and the dimension of luminous intensity (candela) is [cd], and luminous flux is directly related to luminous intensity.
375 Medium
375 of 502
Analyzing +4 | -1
If xx and aa stand for distance, then for what value of nn is the given equation dimensionally correct? The equation is ∫dxa2−xn=sin⁡−1xa\int \frac{d x}{\sqrt{a^2-x^n}}=\sin ^{-1} \frac{x}{a}
View answer and explanation
Correct option: B
2
Option B is correct. For the equation to be dimensionally correct, the term inside the square root must have dimensions of a2a^2. Thus, xnx^n must have the same dimensions as a2a^2, implying n=2n=2.
376 Medium
376 of 502
Understanding +4 | -1
The number of significant figures in q=1.6×10−19q = 1.6 \times {10^{ - 19}} coulomb are
View answer and explanation
Correct option: B
2
Option B (2) is correct because only the digits 1 and 6 are significant in the given number; the power of 10 does not affect the number of significant figures.
377 Medium
377 of 502
Understanding +4 | -1
Which of the following is not a dimensionless quantity?
View answer and explanation
Correct option: C
Permeability of free space (μ0)({\mu _0})
Option C (Permeability of free space (μ0)({\mu _0})) is correct because it has units and dimensions, unlike the other dimensionless quantities.
378 Medium
378 of 502
Understanding +4 | -1
Which is dimensionless?
View answer and explanation
Correct option: D
Energy/work
Option D (Energy/work) is correct because energy and work have the same dimensions, making their ratio dimensionless.
379 Medium
379 of 502
Understanding +4 | -1
Statement-I: Dimensional analysis can give us the numerical value of proportionality constants that may appear in an algebraic expression.
Statement-II: Dimensional analysis make use of the fact that dimensions can be treated as algebraic quantities.
View answer and explanation
Correct option: C
Statement-I is false and statement-II is true
Option C (Statement-I is false and statement-II is true) is correct because dimensional analysis cannot determine the numerical values of dimensionless constants, but it does rely on the fact that dimensions can be treated algebraically.
380 Medium
380 of 502
Understanding +4 | -1
If e is the charge, V the potential difference, T the temperature, then the units of eVT\frac{{eV}}{T} are the same as that of
View answer and explanation
Correct option: C
Boltzmann's constant
Option C (Boltzmann's constant) is correct because eVT\frac{{eV}}{T} has the same units as energy per temperature, which is the unit of Boltzmann's constant.
381 Medium
381 of 502
Application +4 | -1
If ee is the electronic charge, cc is the speed of light in free space and hh is Planck’s constant, the quantity 14π∈0∣e∣2hc\frac{1}{{4\pi { \in _0}}}\frac{{{{\left| e \right|}^2}}}{{hc}} has dimensions of
View answer and explanation
Correct option: C
[M0L0T0]\left[ {{M^0}{L^0}{T^0}} \right]
Option A (π6\frac{\pi}{6}) is correct because the phase difference is calculated by converting both SHMs to sine functions and then subtracting their phase angles.
382 Medium
382 of 502
Remembering +4 | -1
Parsec is a unit of
View answer and explanation
Correct option: A
Distance
Option A (Distance) is correct because a parsec is a unit of length used to measure large distances to astronomical objects outside the solar system.
383 Medium
383 of 502
Analyzing +4 | -1
If E,M,L and G denote energy, mass, angular momentum and gravitational constant respectively, then the quantity (EL2/M5G2)\left( {E{L^2}/{M^5}{G^2}} \right) has the dimensions of
View answer and explanation
Correct option: A
Angle
Option A (Angle) is correct because the expression (EL2/M5G2)\left( {E{L^2}/{M^5}{G^2}} \right) is dimensionless, representing an angle.
384 Medium
384 of 502
Analyzing +4 | -1
The entropy of any system is given by S=α2β  ln[μkRJβ2 + 3]\mathrm{S = }{\mathrm{\alpha }^\mathrm{2}}\mathrm{\beta\,\, ln}\left[ {\frac{{\mathrm{\mu kR}}}{{\mathrm{J}{\mathrm{\beta }^\mathrm{2}}}}\, + \,3} \right] where, α\alpha and β\beta are the constants; μ, J, k  and  R\mu ,\,J,\,k\,\,\mathrm{and}\,\,R are number of moles, mechanical equivalent of heat, Boltzmann constant and gas constant, respectively.
[Take,  S=dQT    ]\left[ {\mathbf{Take},\,\,\mathrm{S = }\frac{{\mathrm{dQ}}}{\mathrm{T}}\;\;} \right]
Choose the incorrect option.
View answer and explanation
Correct option: D
  α  and  k\,\,\alpha \,\,\mathrm{and}\,\,k have the same dimension
Option D is correct because α\alpha and kk have different dimensions. After dimensional analysis, it's found that α\alpha is dimensionless while kk has dimensions of energy per temperature.
385 Medium
385 of 502
Understanding +4 | -1
The ratio of the volume of the atom to the volume of the nucleus is of the order of
View answer and explanation
Correct option: A
101510^{15}
Option A (101510^{15}) is correct because the ratio of the volume of the atom to the volume of the nucleus is approximately 101510^{15}, based on their respective radii.
386 Medium
386 of 502
Application +4 | -1
If force is proportional to square of velocity, then the dimensions of proportionality constant are
View answer and explanation
Correct option: B
[ML−1T0]\left[ {\mathrm{M}{\mathrm{L}^{ - 1}}{\mathrm{T}^0}} \right]
Option B ([ML−1T0]\left[ {\mathrm{M}{\mathrm{L}^{ - 1}}{\mathrm{T}^0}} \right]) is correct because the proportionality constant's dimensions are derived from the force divided by the square of velocity.
387 Medium
387 of 502
Remembering +4 | -1
Unit of Stefan's constant is
View answer and explanation
Correct option: B
Jm−2s−1K−4{Jm}^{-2} {s}^{-1} K^{-4}
Option B is correct because Stefan's constant has units of Watts per square meter per Kelvin to the fourth power, which is equivalent to J m-2 s-1 K-4.
388 Medium
388 of 502
Understanding +4 | -1
SI unit of permittivity is
View answer and explanation
Correct option: B
C2m−2N−1{\mathrm{C}^2}{\mathrm{m}^{ - 2}}{\mathrm{N}^{ - 1}}
Option B (C2m−2N−1{\mathrm{C}^2}{\mathrm{m}^{ - 2}}{\mathrm{N}^{ - 1}}) is correct because it is derived from Coulomb's law and represents the units of permittivity.
389 Medium
389 of 502
Understanding +4 | -1
Planck’s constant has the dimensions (unit) of
View answer and explanation
Correct option: D
Angular momentum
Option D (Angular momentum) is correct because Planck's constant has the dimensions of energy multiplied by time, which is equivalent to angular momentum.
390 Medium
390 of 502
Remembering +4 | -1
The quantity having the same units in all systems of units is
View answer and explanation
Correct option: B
time
Option B (time) is correct because the unit of time (seconds) is the same in all systems of units (SI, CGS, FPS).
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