JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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The dimensional formula of modulus of rigidity is

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Correct option: D

\left[ {\mathrm{M}{\mathrm{L}^{ - 1}}{\mathrm{T}^{ - 2}}} \right]

Option D (

\left[ {\mathrm{M}{\mathrm{L}^{ - 1}}{\mathrm{T}^{ - 2}}} \right]

) is correct because modulus of rigidity is defined as shear stress divided by shear strain, and its dimensional formula is derived accordingly.

More Questions from UNITS & MEASUREMENTS

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\sqrt{\frac{\text { Modulus of elasticity }}{\text { Density }}}

\mathrm{ms}^{-1} \text {. }

\frac{1}{\left(\sqrt{\varepsilon_0 \mu_0}\right) t} \text {. }

\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{A}^2}{T^3}} \right]

{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

{\varepsilon _0}

{\Delta V}

{\Delta t}