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JEE • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Mixed difficulty

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Showing 121-150 of 616 questions

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121 Medium
121 of 616
Remembering +4 | -1
Volt/metre is the unit of
View answer and explanation
Correct option: D
Electric intensity
Option D (Electric intensity) is correct because electric intensity (electric field) is defined as the force per unit charge, which has units of Volt/meter.
122 Medium
122 of 616
Analyzing +4 | -1
Given that y=Asin⁡(aEt−bVx){y}={A} \sin ({aEt}-{bVx}) where y{y} displacement, E{E} energy, V{V} is velocity, t{t} and x{x} are time and distance respectively then, the dimension of a/b{a / b} is:
View answer and explanation
Correct option: C
M−1L0T0{M}^{-1} {L}^0 {T}^0
Option C is correct because by equating the dimensions of the arguments of the sine function, we can find the dimensions of a/b as M⁻¹L⁰T⁰.
123 Medium
123 of 616
Understanding +4 | -1
In an expression a×10b\mathrm{a} \times 10^{\mathrm{b}} :
View answer and explanation
Correct option: B
b\mathrm{b} is order of magnitude for a≤5\mathrm{a} \leq 5
Option D (b is order of magnitude for a≥5a \geq 5) is incorrect. Option B (b is order of magnitude for a≤5a \leq 5) is correct because in scientific notation, if 'a' is less than or equal to 5, then 'b' represents the order of magnitude.
124 Easy
124 of 616
Remembering +4 | -1
Dimension of electric current is
View answer and explanation
Correct option: A
[M0L0T−1Q]\left[ {{M^0}{L^0}{T^{ - 1}}Q} \right]
Option A ([M0L0T−1Q]\left[ {{M^0}{L^0}{T^{ - 1}}Q} \right]) is correct because electric current is defined as the rate of flow of charge, hence its dimension is charge per time.
125 Medium
125 of 616
Application +4 | -1
In an experiment four quantities a,b,ca, b, c and dd are measured with percentage error 2%,3%,4%2 \%, 3 \%, 4 \% and 1%1 \% respectively. Quantity PP is calculated as follows; P=a3b2cdP=\frac{a^3 b^2}{c d}. Percentage error in PP is;
View answer and explanation
Correct option: D
17%17 \%
Option D (17%17 \%) is correct because the percentage error in P is calculated by summing the absolute values of the percentage errors in a, b, c, and d, each multiplied by its exponent in the formula for P.
126 Medium
126 of 616
Remembering +4 | -1
Consider the following statements and select the correct
statement(s).
I. 1 calorie = 4.18 joule
II. 1Ao=10−10 m1\stackrel{o}{A}=10^{-10} \mathrm{~m}
III. 1MeV=1.6×10−131 \mathrm{MeV}=1.6 \times 10^{-13} Joule
IV. 1 newton =10−5=10^{-5} dyne
View answer and explanation
Correct option: A
I, II and III
Option A (I, II and III) is correct because statements I, II, and III are all correct conversions of units.
127 Medium
127 of 616
Remembering +4 | -1
Nm2/kg2N m^2 /kg^2 is a unit of
View answer and explanation
Correct option: A
Gravitational constant
Option A (Gravitational constant) is correct because the units Nm2/kg2N m^2 /kg^2 are the units of the gravitational constant (G) in Newton's law of gravitation.
128 Medium
128 of 616
Understanding +4 | -1
The dimension of E/H\mathrm{E} / \mathrm{H} is that of
View answer and explanation
Correct option: A
Impedance
Option A (Impedance) is correct because the ratio of electric field (E) to magnetic field (H) has the dimensions of impedance.
129 Easy
129 of 616
Remembering +4 | -1
Ampere-hour is a unit of
View answer and explanation
Correct option: A
Quantity of electricity
Option A (Quantity of electricity) is correct because Ampere-hour is the unit of electric charge, which represents the quantity of electricity.
130 Medium
130 of 616
Understanding +4 | -1
Find the number of significant digits in the value 10.05.10.05.
View answer and explanation
Correct option: A
4
Option A is correct because all non-zero digits are significant, and zeros between non-zero digits are also significant.
131 Easy
131 of 616
Remembering +4 | -1
In which of the following systems of units, a Weber is the unit of magnetic flux?
View answer and explanation
Correct option: C
SI
Option C (SI) is correct because the Weber (Wb) is the standard unit of magnetic flux in the International System of Units (SI).
132 Medium
132 of 616
Remembering +4 | -1
Which of the following is not one of the seven fundamental SI units?
View answer and explanation
Correct option: A
Henry
Option A (Henry) is correct because Henry is a derived SI unit, not a fundamental one. The fundamental units are metre, kilogram, second, ampere, candela, mole, and kelvin.
133 Medium
133 of 616
Analyzing +4 | -1
If the velocity (V)(V), acceleration (A)(A), and force (F)(F) are taken as fundamental quantities instead of mass (M)(M), length (L)(L), and time (T)(T), the dimensions of Young's modulus (Y)(Y) would be
View answer and explanation
Correct option: A
FA2V−4F A^2 V^{-4}
Option A (FA2V−4F A^2 V^{-4}) is correct because the dimensions of Young's modulus can be expressed as FA2V−4F A^2 V^{-4} when velocity, acceleration, and force are fundamental quantities.
134 Easy
134 of 616
Application +4 | -1
What is the dimensional formula of ab−1\text{ab}^{-1} in the equation (P+aV2)(V−b)=RT,\left(\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V}-\mathrm{b})=\mathrm{RT}, where letters have their usual meaning.
View answer and explanation
Correct option: B
[ML2T−2]\left[\mathrm{ML}^2 \mathrm{T}^{-2}\right]
Option A (6.5×103 Nm−2;8%6.5 \times 10^3 \mathrm{~Nm}^{-2}; 8 \%) is correct because it calculates the pressure difference using the weight of the aircraft and estimates the fractional increase in air speed using Bernoulli's principle.
135 Medium
135 of 616
Analyzing +4 | -1
Statement-I: Linear momentum and moment of force have same dimensions.
Statement-II: Planck’s constant and angular momentum have same dimension.
View answer and explanation
Correct option: B
Statement-I is false while statement-II is correct
Option B is correct because linear momentum and moment of force have different dimensions, while Planck's constant and angular momentum have the same dimensions.
136 Medium
136 of 616
Application +4 | -1
The dimensions of farad are
View answer and explanation
Correct option: A
M−1L−2T2Q2{M^{ - 1}}{L^{ - 2}}{T^2}{Q^2}
Option A (M−1L−2T2Q2{M^{ - 1}}{L^{ - 2}}{T^2}{Q^2}) is correct because it represents the correct dimensional formula for capacitance (Farad).
137 Medium
137 of 616
Application +4 | -1
The dimensions of h/e(h=\mathrm{h} / \mathrm{e}(\mathrm{h}= Planck's constant and e=\mathrm{e}= electronic charge) are same as that of:
View answer and explanation
Correct option: A
magnetic flux
Option A (magnetic flux) is correct because the ratio h/e has the same dimensions as magnetic flux, which can be derived from the relationship between voltage and magnetic flux.
138 Medium
138 of 616
Understanding +4 | -1
In which of the following numerical values, all zeros are significant?
View answer and explanation
Correct option: B
20.2
Option B (20.2) is correct because all zeros between non-zero digits are significant.
139 Medium
139 of 616
Analyzing +4 | -1
A physical quantity P=abc2d3P=\frac{\sqrt{a b c^2}}{d^3} is determined by measuring a,b,ca, b, c, and dd separately with the percentage error of 2%,3%,2%2 \%, 3 \%, 2 \%, and 1%1 \%, respectively. Minimum amount of error is contributed by:
View answer and explanation
Correct option: B
aa
Option B (aa) is correct because the percentage error in PP depends on the error in a,b,c,a, b, c, and dd, and the contribution from aa is the smallest.
140 Medium
140 of 616
Analyzing +4 | -1
Assertion : In the equation momentum, P=massareax,P = \frac{{mass}}{{area}}x, the dimensional formula of xx is LT−2.L{T^{ - 2}}.
Reason : Quantities with different dimensions can be multiplied.
View answer and explanation
Correct option: D
Assertion is incorrect, reason is correct
Option D is correct. The assertion is incorrect because the dimensional formula of x is L3T−1L^3T^{-1}, and the reason is correct because quantities with different dimensions can be multiplied.
141 Medium
141 of 616
Application +4 | -1
If L,CL, C and RR denote the inductance, capacitance and resistance respectively, the dimensional formula for C2LRC^2 L R is
View answer and explanation
Correct option: B
[M0L0T3I0]\left[M^0 L^0 T^3 I^0\right]
Option B ([M0L0T3I0]\left[M^0 L^0 T^3 I^0\right]) is correct because the dimensional analysis of C2LRC^2 L R results in dimensions of time cubed.
142 Medium
142 of 616
Understanding +4 | -1
Assertion: μN\mu \mathrm{N} is not the same as nm\mathrm{nm}.
Reason: 1μN=10−6 N1 \mu \mathrm{N}=10^{-6} \mathrm{~N} and 1 nm=10−9 m1 \mathrm{~nm}=10^{-9} \mathrm{~m}
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of assertion
Option A is correct because μN\mu N represents micronewtons (10−610^{-6} N) and nm represents nanometers (10−910^{-9} m), which are different physical quantities with different units.
143 Medium
143 of 616
Analyzing +4 | -1
The dimensions of 1∈0e2hc\frac{1}{{{ \in _0}}}\frac{{{e^2}}}{{hc}} are
View answer and explanation
Correct option: C
M0L0T0A0{M^0}{L^0}{T^0}{A^0}
Option C is correct. The expression is dimensionless because it represents the fine-structure constant, a fundamental constant in physics.
144 Medium
144 of 616
Application +4 | -1
In the formula F=A.ehcxF=A . e^{\frac{h c}{x}}, where hh is Planck's constant, and cc is speed of light. The dimensional formula for xx is
View answer and explanation
Correct option: B
[M1L3T−2]\left[M^1 L^3 T^{-2}\right]
Option B (M1L3T−2M^1 L^3 T^{-2}) is correct because the exponent must be dimensionless, allowing us to solve for the dimensions of x.
145 Medium
145 of 616
Analyzing +4 | -1
If C,R,L and I denote capacity, resistance, inductance and electric current respectively, the quantities having the same dimensions of time are (1) CR,  (2) LR ,  (3) LC  (4) LI2\left( 1 \right)\,CR,\,\,\left( 2 \right)\,\frac{L}{R}\,,\,\,\left( 3 \right)\,\sqrt {LC} \,\,\left( 4 \right)\,L{I^2}
View answer and explanation
Correct option: D
(1), (2) and (3) only
Option D ((1), (2) and (3) only) is correct because CR, L/R, and √(LC) all have the dimensions of time.
146 Easy
146 of 616
Understanding +4 | -1
Which of the following represents a volt
View answer and explanation
Correct option: B
Watt/ampere
Option B (Watt/ampere) is correct because volt is defined as the ratio of power (in watts) to current (in amperes) according to the formula V = W/A.
147 Medium
147 of 616
Analyzing +4 | -1
Assertion : The error in the measurement of radius of the
sphere is 0.3%.The permissible error in its surface area is
0.6%.
Reason : The permissible error is calculated by the formula ΔAA=4Δrr\frac{{\Delta A}}{A} = \frac{{4\Delta r}}{r}
View answer and explanation
Correct option: C
Assertion is correct, reason is incorrect
Assertion is correct, reason is incorrect. The assertion is correct because the error in surface area is twice the error in radius, but the reason provides the wrong formula.
148 Medium
148 of 616
Application +4 | -1
The pitch of screw gauge is 1 mm1 \mathrm{~mm} and there are 100 divisions on circular scale. While measuring diameter of a wire, linear scale reads 1 mm1 \mathrm{~mm} and 39th39^{\text {th}} division of circular scale coincides with reference line. The zero error is −0.05 mm-0.05 \mathrm{~mm}. The correct diameter of wire is
View answer and explanation
Correct option: B
1.44 mm1.44 \mathrm{~mm}
Option B (1.44 mm1.44 \mathrm{~mm}) is correct because the correct diameter is calculated by adding the linear scale reading, circular scale reading, and the zero error.
149 Medium
149 of 616
Analyzing +4 | -1
If Planck's constant (h)(h) and speed of light in vacuum (c)(c) are taken as two fundamental quantities, which one of the following can, in addition, be taken to express length, mass and time in terms of the three chosen fundamental quantities?

(i) Mass of electron (me)\left(m_e\right)

(ii) Universal gravitational constant (G)(G)

(iii) Charge of electron (e)(e)

(iv) Mass of proton (mp)\left(m_p\right)
View answer and explanation
Correct option: A
(i), (ii) and (iii)
The correct answer is A ((i), (ii) and (iii)) because these quantities, along with Planck's constant and speed of light, can be used to express length, mass, and time in terms of fundamental quantities.
150 Medium
150 of 616
Understanding +4 | -1
Inductance L can be dimensionally represented as
View answer and explanation
Correct option: A
ML2T−2A−2M{L^2}{T^{ - 2}}{A^{ - 2}}
Option A (ML2T−2A−2M{L^2}{T^{ - 2}}{A^{ - 2}}) is correct because the energy stored in an inductor is proportional to the inductance and the square of the current.
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