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JEE • PHYSICS • RAY OPTICS

Ray optics practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 443 questions

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91 Medium
91 of 443
Understanding +4 | -1
If μ1 and μ2{\mu _1}\,and\,{\mu _2} are the refractive indices of the materials of core and cladding of an optical fibre, then the loss of light due to its leakage can be minimized by having
View answer and explanation
Correct option: A
μ1>μ2{\mu _1} > {\mu _2}
Option A (μ1>μ2{\mu _1} > {\mu _2}) is correct because the refractive index of the core must be greater than the refractive index of the cladding to minimize light loss due to total internal reflection.
92 Medium
92 of 443
Understanding +4 | -1
A parallel beam of light is incident on a converging lens parallel to its principal axis. As one moves away from the lens on the other side of the principal axis, the intensity of light
View answer and explanation
Correct option: D
First increases and then decreases
Option D is correct because the light converges to a point and then diverges, causing the intensity to first increase and then decrease.
93 Medium
93 of 443
Understanding +4 | -1
In a compound microscope cross-wires are fixed at the point
View answer and explanation
Correct option: A
Where the image is formed by the objective
Option A is correct because cross-wires in a compound microscope are placed where the objective lens forms the initial image.
94 Medium
94 of 443
Understanding +4 | -1
When the convergent nature of a convex lens will be less as compared with air
View answer and explanation
Correct option: C
In both (a)\left( \mathrm{a} \right) and (b)\left( \mathrm{b} \right)
Option C (In both (a) and (b)) is correct because the converging ability of a convex lens decreases when immersed in a medium with a refractive index closer to that of the lens.
95 Medium
95 of 443
Application +4 | -1
Angle of minimum deviation for a prism of refractive index 1.5\mathrm{1}\mathrm{.5} is equal to the angle of the prism. The angle of the prism is (given  cos⁡  41∘  −  24′−  36′′=  0.75)\left( {\mathrm{given}\,\,\cos \,\,41^\circ \mathrm{\;} - \mathrm{\;}{{24}^\mathrm{'}} - \mathrm{\;}{{36}^{\mathrm{''}}} = \mathrm{\;}0.75} \right)
View answer and explanation
Correct option: A
82∘−49′−12′′82^\circ - 49' - 12''
Option A (82∘−49′−12′′82^\circ - 49' - 12'') is correct because it is derived from using the refractive index formula and the given cosine value to find the prism angle.
96 Medium
96 of 443
Understanding +4 | -1
When a beam of white light is allowed to pass
through convex lens parallel to principal axis, the
different colours of light converge at different point
on the principle axis after refraction. This is called
View answer and explanation
Correct option: B
Chromatic aberration
Option B (Chromatic aberration) is correct because chromatic aberration is the phenomenon where different colors of light focus at different points after refraction through a lens.
97 Medium
97 of 443
Understanding +4 | -1
If the focal length of the eye piece of a
telescope is doubled, its magnifying power
(m)(m) will be
View answer and explanation
Correct option: C
m2\frac{m}{2}
Option C (m2\frac{m}{2}) is correct because magnifying power is inversely proportional to the focal length of the eyepiece.
98 Medium
98 of 443
Understanding +4 | -1
How should people wearing spectacles work with a microscope
View answer and explanation
Correct option: C
They should take off spectacles
Option C (They should take off spectacles) is correct because the microscope is designed to correct for normal vision, and spectacles would introduce an additional, unwanted correction.
99 Medium
99 of 443
Analyzing +4 | -1
A small source of light is to be suspended directly above the centre of a circular table of radius RR. What should be the height of the light source above the table so that the intensity of light is maximum at the edges of the table compared to any other height of the source
View answer and explanation
Correct option: B
R2\frac{R}{{\sqrt 2 }}
Option B (R2\frac{R}{{\sqrt 2 }}) is correct because it represents the height at which the intensity of light at the edge of the table is maximized, derived by differentiating the intensity with respect to height and setting it to zero.
100 Medium
100 of 443
Application +4 | -1
A ray of light is incident at an angle of 60∘60^\circ on one face of a prism of angle 30∘.30^\circ . The emergent ray of light makes an angle of 30∘30^\circ with incident ray. The angle made by the emergent ray with second face of prism will be
View answer and explanation
Correct option: B
90∘90^\circ
Option B (90∘90^\circ) is correct because the emergent ray grazes the second face of the prism, meaning the angle of emergence is 0 degrees.
101 Medium
101 of 443
Remembering +4 | -1
The communication using optical fibres is based on the principle of
View answer and explanation
Correct option: A
Total internal reflection
Option A (Total internal reflection) is correct because optical fibers rely on total internal reflection to guide light signals along their length.
102 Medium
102 of 443
Application +4 | -1
A plano convex lens of (f=20  cm)\left( {f = 20\,\,\mathrm{cm}} \right) is silvered at plane surface. New ff will be
View answer and explanation
Correct option: C
30  cm\mathrm{30}\,\,\mathrm{cm}
The correct answer is not among the options provided. The correct focal length should be 10 cm. Option D (10 cm\mathrm{10}\,\mathrm{cm}) is the closest to the correct answer, but the provided explanation in the original response is incorrect. The correct answer is obtained by considering the lens-mirror combination.
103 Medium
103 of 443
Understanding +4 | -1
Which of the following is not due to total internal reflection
View answer and explanation
Correct option: C
Difference between apparent and real depth of a pond
Option C (Difference between apparent and real depth of a pond) is correct because this phenomenon is due to refraction, not total internal reflection.
104 Medium
104 of 443
Analyzing +4 | -1
Assertion: A spherical mirror of focal length f{f} in air is used in a medium of refractive index 5 . Then the focal length of mirror in medium becomes octave.

Reason: The radius of curvature of a mirror is double of the focal length.
View answer and explanation
Correct option: D
If Assertion is false but Reason is true.
Option D (If Assertion is false but Reason is true) is correct because the focal length of a mirror is independent of the surrounding medium, and the radius of curvature is indeed twice the focal length.
105 Medium
105 of 443
Application +4 | -1
Four lenses are made from the same type of glass. The radius of curvature of each face is given below. What will have the greatest positive power
View answer and explanation
Correct option: B
5  cm5\,\,cm convex and 10  cm10\,\,cm concave
Option B (5  cm5\,\,cm convex and 10  cm10\,\,cm concave) is correct because it yields the highest positive power based on the lens maker's formula.
106 Medium
106 of 443
Analyzing +4 | -1
An object approaches a convergent lens from the left of the lens with a uniform speed 5 m/s5 \mathrm{~m} / \mathrm{s} and stops at the focus. The image
View answer and explanation
Correct option: C
moves away from the lens with a non-uniform acceleration
Option C (moves away from the lens with a non-uniform acceleration) is correct because the image distance changes non-linearly as the object approaches the focus.
107 Medium
107 of 443
Understanding +4 | -1
Frosted glass is widely used for translucent
windows. The region where a transparent
adhesive tape is stuck over the frosted glass
becomes transparent. The most reasonable
explanation for this is
View answer and explanation
Correct option: C
Refractive index of adhesive glue is close to
that of glass
Option C is correct because when the refractive index of the adhesive is close to that of the glass, light passes through with minimal scattering, making the area transparent.
108 Medium
108 of 443
Application +4 | -1
The wavelength of sodium light in air is 5890  A05890\,\,{\mathrm{A}^0}. The velocity of light in air is 3  ×  10−8  ms−13\,\, \times \,\,{10^{ - 8}}\,\,\mathrm{m}{\mathrm{s}^{ - 1}}. The wavelength of light in a glass of refractive index 1.6\mathrm{1}\mathrm{.6} would be close to
View answer and explanation
Correct option: B
3681  A03681\,\,{\mathrm{A}^0}
Option B (3681  A03681\,\,{\mathrm{A}^0}) is correct because the wavelength in glass is shorter than in air due to the refractive index of the glass.
109 Medium
109 of 443
Understanding +4 | -1
A convex mirror is used to form the image of an object. Then which of the following statements is wrong
View answer and explanation
Correct option: D
The image is real
Option D (The image is real) is wrong because a convex mirror always forms a virtual, erect, and diminished image.
110 Medium
110 of 443
Application +4 | -1
For a material medium, the values of refractive index for violet and red colours are given as nv=1.56\mathrm{n}_{\mathrm{v}}=1.56 and nr=1.44\mathrm{n}_{\mathrm{r}}=1.44. The dispersive power of a prism made out of this material is
View answer and explanation
Correct option: B
0.24
Option B (0.24) is correct because the dispersive power is calculated using the refractive indices for violet and red colors.
111 Medium
111 of 443
Application +4 | -1
Two thin lenses when in contact, produce a combination of power + 10  D+ \,10\,\,D. When they are 0.25  m0.25\,\,m apart, the power reduces to + 6  D+ \,6\,\,D. The focal lengths of the lenses (in mm) are
View answer and explanation
Correct option: A
0.125 and 0.5\mathrm{0}\mathrm{.125}\,\mathrm{ and }\,\mathrm{0}\mathrm{.5}
Option A (0.125 and 0.5) is correct because it satisfies the power equations for lenses in contact and separated by a distance.
112 Medium
112 of 443
Understanding +4 | -1
The light rays from an object have been reflected
towards an observer from a standard flat mirror, the
image observed by the observer are:-

A. Real

B. Erect

C. Smaller in size than object

D. Laterally inverted

Choose the most appropriate answer from the
options given below:
View answer and explanation
Correct option: A
B and D Only
Option A is correct because a flat mirror produces a virtual, erect, same-size, and laterally inverted image.
113 Medium
113 of 443
Understanding +4 | -1
A ray of light is incidenting normally on a plane mirror. The angle of reflection will be
View answer and explanation
Correct option: A
0∘0^\circ
Option A (0∘0^\circ) is correct because when a ray of light is incident normally on a plane mirror, the angle of incidence is 0 degrees, and therefore the angle of reflection is also 0 degrees.
114 Medium
114 of 443
Understanding +4 | -1
An astronomical telescope in normal adjustment receives light from a distant source S.S. The tube length is now decreased slightly, then
View answer and explanation
Correct option: A
A virtual image of SS will be formed at a finite distance
Option A is correct because decreasing the tube length slightly will cause a virtual image to be formed at a finite distance.
115 Medium
115 of 443
Understanding +4 | -1
Relation between critical angles of water and glass is
View answer and explanation
Correct option: A
Cω>Cg{C_\omega } > {C_g}
Option A (Cω>Cg{C_\omega } > {C_g}) is correct because the critical angle is inversely related to the refractive index, and water has a lower refractive index than glass.
116 Medium
116 of 443
Understanding +4 | -1
Statement-I: Different colours of light have same velocity in vacuum, but they have different velocities in in any other transparent medium.

Statement-II: ν=c/μ\nu=c / \mu, where symbols have standard meanings. For different colours, refractive index, μ\mu of transparent medium has different values. Therefore, vv is different.
View answer and explanation
Correct option: A
If both Statement-I and Statement-II are true
Option A is correct because both statements are true and Statement-II correctly explains Statement-I. The refractive index depends on color, thus affecting velocity in a medium.
117 Medium
117 of 443
Application +4 | -1
A small telescope has an objective lens of focal length 150 cm150 \mathrm{~cm} and eyepiece of focal length 5 cm5 \mathrm{~cm}. What is the magnifying power of the telescope for viewing distant objects in normal adjustment?
If this telescope is used to view a 100 m100 \mathrm{~m} tall tower 3 km3 \mathrm{~km} away, what is the height of the image of the tower formed by the objective lens?
View answer and explanation
Correct option: A
0.05 m0.05 \mathrm{~m}
Option A (0.05 m0.05 \mathrm{~m}) is correct because it is the height of the image formed by the objective lens, calculated using the angular size of the tower and the focal length of the objective lens.
118 Medium
118 of 443
Remembering +4 | -1
In which of the following optical instrument, the final image of real object is not inverted?
View answer and explanation
Correct option: B
simple microscope
Option B (simple microscope) is correct because a simple microscope produces a virtual and erect (not inverted) final image.
119 Medium
119 of 443
Understanding +4 | -1
When monochromatic red light is used instead of blue light in a convex lens, its focal length will
View answer and explanation
Correct option: B
Increase
Option B (Increase) is correct because the focal length of a convex lens increases when red light is used instead of blue light due to red light having a longer wavelength and thus a smaller refractive index.
120 Medium
120 of 443
Understanding +4 | -1
Critical angle of light passing from glass of water is minimum for
View answer and explanation
Correct option: D
Violet colour
Option D (Violet colour) is correct because violet light has the highest refractive index, leading to the smallest critical angle.
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