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JEE PHYSICS MCQ: RAY OPTICS

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Application +4 | -1
Two transparent slabs having equal thickness but different refractive indices μ1\mu_1 and μ2\mu_2 are pasted side by side to form a composite slab. This slab is placed just after the double slit in a Young's experiment so that the light from one slit goes through one material and the light from the other slit goes through the other material. What should be the minimum thickness of the slab so that there is a minimum at the point P0P_0 which is equidistant from the slits?
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Correct option: A
λ2(μ1−μ2)\frac{\lambda}{2\left(\mu_1-\mu_2\right)}
Option A (λ2(μ1−μ2)\frac{\lambda}{2(\mu_1-\mu_2)}) is correct because the minimum thickness is found by equating the path difference to λ/2\lambda/2 for a minimum at P0.

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