Skip to main content
Back to MOTION IN PLANE

Your Progress

0 / 388 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • PHYSICS • MOTION IN PLANE

Motion in plane practice · Medium

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 331-360 of 388 questions
331 Medium
331 of 388
Application +4 | -1
A projectile is fired at an angle of 30∘30^{\circ} to the horizontal such that the vertical component of its initial velocity is 80 ms−180 {~ms}^{-1}. Its time of flight is TT. Its velocity at t=T4t=\frac{T}{4} has a magnitude of nearly
View answer and explanation
Correct option: C
140 ms−1140 {~ms}^{-1}
Option C (140 ms⁻¹) is correct because it involves calculating the horizontal and vertical components of velocity at t=T/4 and then finding the magnitude of the resultant velocity.
332 Medium
332 of 388
Application +4 | -1
The trajectory of a projectile is represented by y=3x−gx2/2y=\sqrt{3} x-g x^2 / 2. The angle of projection is
View answer and explanation
Correct option: C
60∘60^{\circ}
Option C (60∘60^{\circ}) is correct because it is derived by comparing the given trajectory equation with the standard projectile motion equation.
333 Medium
333 of 388
Application +4 | -1
If A^=3i^+4j^\hat{A}=3 \hat{i}+4 \hat{j} and B=7i^+24j^B=7 \hat{i}+24 \hat{j} then a vector having same magnitude as B⃗\vec{B} and parallel to vector A⃗\vec{A} will be
View answer and explanation
Correct option: B
15i^+20j^15 \hat{i}+20 \hat{j}
Option B (15i^+20j^15 \hat{i}+20 \hat{j}) is correct because it has the same magnitude as B⃗\vec{B} and is parallel to A⃗\vec{A}.
334 Medium
334 of 388
Application +4 | -1
The angle between A=i+jA = i + j and B=i−jB = i - j is
View answer and explanation
Correct option: B
90∘90^\circ
Option B (90∘90^\circ) is correct because the dot product of the two vectors is zero, indicating they are perpendicular.
335 Medium
335 of 388
Understanding +4 | -1
Assertion: The magnitude of the resultant of two vectors P⃗\vec{P} and Q⃗\vec{Q} is maximum (P+Q)(P+Q), when the two vectors act in the same direction and minimum (P−Q)(P-Q), when they act in opposite directions.

Reason: The resultant of two vectors can be found by using the relation

R=P2+Q2+2PQcos⁡θR=\sqrt{P^2+Q^2+2 P Q \cos \theta}
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not
correct explanation of the assertion.
Option B is correct because both the assertion and the reason are true, but the reason doesn't directly explain why the resultant is maximum or minimum in the specified directions.
336 Medium
336 of 388
Application +4 | -1
Among the following the set that cannot represent the three sides of a triangle is
View answer and explanation
Correct option: B
5,7,13
Option B (5,7,13) is correct because the sum of the two smaller sides (5+7=12) is not greater than the longest side (13), violating the triangle inequality theorem.
337 Medium
337 of 388
Analyzing +4 | -1
Statement-I: a⃗=i^+pj^+2k^\vec{a}=\hat{i}+p \hat{j}+2 \hat{k} and b⃗=2i^+3j^+qk^\vec{b}=2 \hat{i}+3 \hat{j}+q \hat{k} are parallel vectors if p=32,q=4p=\frac{3}{2}, q=4.
Statement-II: If a⃗=a1i^+a2j^+a3k^\vec{a}=a_1 \hat{i}+a_2 \hat{j}+a_3 \hat{k} and b⃗=b1i^+b2j^+b3k^\vec{b}=b_1 \hat{i}+b_2 \hat{j}+b_3 \hat{k} are parallel, then a1b1=a2b2−a3b3\frac{a_1}{b_1}=\frac{a_2}{b_2}-\frac{a_3}{b_3}
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option D (Statement-I is true and statement-II is true) is correct because both the given statements are correct about parallel vectors.
338 Medium
338 of 388
Understanding +4 | -1
Which of the following statements are correct ?
I. Centripetal acceleration is always directed towards the centre.
II. Magnitude of the centripetal acceleration is v2R\frac{{{v^2}}}{R}.
III. Direction of centripetal acceleration changes pointing always towards the centre.
View answer and explanation
Correct option: D
I, II and III
Option D (I, II and III) is correct because all three statements about centripetal acceleration are accurate.
339 Medium
339 of 388
Analyzing +4 | -1
The resultant of the two vectors A⃗\vec{A} and B⃗\vec{B} makes angle α\alpha with A⃗\vec{A} and β\beta with B⃗\vec{B}.

Statement (A) : α<β\alpha<\beta if ∣A⃗∣<∣B⃗∣|\vec{A}|<|\vec{B}|

Statement (B) : α<β\alpha<\boldsymbol{\beta} if ∣A→∣>∣B⃗∣|\overrightarrow{{A}}|>|\vec{B}|

Statement (C) : α=β\alpha=\beta if ∣A⃗∣=∣B⃗∣|\vec{A}|=|\vec{B}|
View answer and explanation
Correct option: C
(B) and (C) are true
Option C is correct because the angle a vector makes with the resultant depends on the magnitudes of the vectors; if |A| > |B|, then α < β, and if |A| = |B|, then α = β.
340 Medium
340 of 388
Application +4 | -1
Two vectors are given by A⃗=i^+2j^+2k^\vec{A}=\hat{i}+2 \hat{j}+2 \hat{k} and B⃗=3i^+6j^+2k^\vec{B}=3 \hat{i}+6 \hat{j}+2 \hat{k}. Another vector C⃗\vec{C} has the same magnitude as B⃗\vec{B} but has the same direction as A⃗\vec{A}. Then which of the following vectors represent C⃗\vec{C}
View answer and explanation
Correct option: A
73(i^+2j^+2k^)\frac{7}{3}(\hat{i}+2 \hat{j}+2 \hat{k})
Option A (73(i^+2j^+2k^)\frac{7}{3}(\hat{i}+2 \hat{j}+2 \hat{k})) is correct because it represents a vector with the same magnitude as B⃗\vec{B} but in the direction of A⃗\vec{A}.
341 Medium
341 of 388
Application +4 | -1
The angle between two vectors of magnitude 12 and 18 units when their resultant is 24 units, will be:
View answer and explanation
Correct option: C
75.52∘75.52^{\circ}
Option C (75.52∘75.52^{\circ}) is correct because it is the angle calculated using the law of cosines with the given magnitudes of the two vectors and their resultant.
342 Medium
342 of 388
Application +4 | -1
The vectors from origin to the points AA and BB are A=3i^−6j^+2k^{A}=3 \hat{{i}}-6 \hat{{j}}+2 \hat{{k}} and B=2i^+j^−2k^{B}=2 \hat{{i}}+\hat{{j}}-2 \hat{{k}}, respectively. The area of the △OAB\triangle O A B be
View answer and explanation
Correct option: A
5217\frac{5}{2} \sqrt{17} sq units
Option A (5217\frac{5}{2} \sqrt{17} sq units) is correct because it is the result of calculating half the magnitude of the cross product of the position vectors.
343 Medium
343 of 388
Analyzing +4 | -1
There are NN coplanar vectors each of magnitude VV. Each vector is inclined to the preceding vector at angle 2πN\frac{2 \pi}{N}. What is the magnitude of their resultant?
View answer and explanation
Correct option: C
Zero
Option C (Zero) is correct because the vectors form a closed polygon, resulting in a net resultant of zero.
344 Medium
344 of 388
Analyzing +4 | -1
Assertion: Vector (i^+j^+k^)(\hat{i}+\hat{j}+\hat{k}) is perpendicular to (i^−2j^+k^)(\hat{i}-2 \hat{j}+\hat{k})
Reason: Two non-zero vectors are perpendicular if their dot product is zero.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Assertion & Reason are True & the Reason is a correct explanation of the Assertion because the dot product of the two vectors is zero, indicating they are perpendicular, and the reason correctly states the condition for perpendicularity.
345 Medium
345 of 388
Application +4 | -1
The friction of the air causes a vertical retardation equal to 10%10 \% of the acceleration due to gravity. (Take g=10 ms−2\mathrm{g}=10 \mathrm{~ms}^{-2} ). The maximum height will be decreased by in projectile motion -
View answer and explanation
Correct option: C
9%9 \%
Option C (9%9 \%) is correct because the percentage decrease in maximum height is calculated by considering the vertical retardation due to air friction.
346 Medium
346 of 388
Application +4 | -1
Statement I : Rain is falling vertically downwards with a velocity of 3 kmh−13 \mathrm{~kmh}^{-1}. A man walks with a velocity of 4kmh−14 \mathrm{kmh}^{-1}. Relative velocity of rain w.r.t. man is 5 kmh−15 \mathrm{~kmh}^{-1}.

Statement II : Relative velocity of rain w.r.t. man is given by vmm=vr−vm\quad \mathbf{v}_{m m}=\mathbf{v}_r-\mathbf{v}_m
View answer and explanation
Correct option: A
Statement I is true, Statement II is true; Statement II is the correct explanation for Statement I
Option A (Statement I is true, Statement II is true; Statement II is the correct explanation for Statement I) is correct because the relative velocity calculation and its magnitude are accurate, and the formula used is correct.
347 Medium
347 of 388
Application +4 | -1
What is the component of 3i^+4j^3 \hat{i}+4 \hat{j} along i^+j^\hat{i}+\hat{j} ?
View answer and explanation
Correct option: D
72(i^+j^)\frac{7}{2}(\hat{i}+\hat{j})
Option D (72(i^+j^)\frac{7}{2}(\hat{i}+\hat{j})) is correct because it is the projection of the vector 3i^+4j^3\hat{i}+4\hat{j} onto the vector i^+j^\hat{i}+\hat{j}.
348 Medium
348 of 388
Understanding +4 | -1
Statement-I: The vector product of a force F⃗\vec{F} and displacement r⃗\vec{r} is equal to the work done.
Statement-II: Work done is not a vector.
View answer and explanation
Correct option: C
Statement-I is false and statement-II is true
Option C is correct because work done is a scalar quantity, and it is calculated as the dot product (scalar product) of force and displacement, not the vector product.
349 Medium
349 of 388
Understanding +4 | -1
Statement-I: If θ\theta be the angle between a⃗\vec{a} and b→\overrightarrow{\mathrm{b}}, then tan⁡θ=∣a⃗×b⃗∣a⃗⋅b⃗\tan \theta=\frac{|\vec{a} \times \vec{b}|}{\vec{a} \cdot \vec{b}}
Statement-II: a⃗×b⃗\vec{a} \times \vec{b} is perpendicular to a⃗.b⃗\vec{a} . \vec{b}
View answer and explanation
Correct option: B
Statement-I is true and statement-II is false
Option B is correct because the magnitude of the cross product divided by the dot product equals the tangent of the angle between the vectors, but the cross product is a vector while the dot product is a scalar.
350 Medium
350 of 388
Understanding +4 | -1
Which of the following is not the vector quantity?
View answer and explanation
Correct option: D
Electric flux
Option D (Electric flux) is correct because electric flux is a scalar quantity, while torque, displacement, and dipole moment are vector quantities.
351 Medium
351 of 388
Analyzing +4 | -1
Two projectiles are thrown with different velocities and at different angles so as to cover the same maximum height. Show that the sum of the times taken by each to reach the highest point is equal to the total time taken by either of the projectiles.
View answer and explanation
Correct option: A
2u1sin⁡θ1g or 2u2sin⁡θ2g\frac{2 u_1 \sin \theta_1}{g} \text { or } \frac{2 u_2 \sin \theta_2}{g}
The correct answer is A (2u1sin⁡θ1g or 2u2sin⁡θ2g\frac{{2 u_1 \sin \theta_1}}{{g}} \text {{ or }} \frac{{2 u_2 \sin \theta_2}}{{g}}) because the sum of the times to reach the highest point equals the time of flight for either projectile, given equal maximum heights.
352 Medium
352 of 388
Understanding +4 | -1
Which of the following is not true about vectors A⃗,B⃗\vec{A}, \vec{B} and C⃗\vec{C} ?
View answer and explanation
Correct option: C
(A→×C→)×(B→×C→)(\overrightarrow{\mathrm{A}} \times \overrightarrow{\mathrm{C}}) \times(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{C}}) is a scalar value.
Option C is the correct answer because (A→×C→)×(B→×C→)(\overrightarrow{\mathrm{A}} \times \overrightarrow{\mathrm{C}}) \times(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{C}}) results in a vector, not a scalar, due to the cross product operation.
353 Medium
353 of 388
Application +4 | -1
A stone is thrown vertically at a speed of 30 ms−130 \mathrm{~ms}^{-1} taking an angle of 45∘45^{\circ} with the horizontal. What is the maximum height reached by the stone? Take g=10 ms−2\mathrm{g}=10 \mathrm{~ms}^{-2}.
View answer and explanation
Correct option: B
22.5 m22.5 \mathrm{~m}
Option B (22.5 m22.5 \mathrm{~m}) is correct because it is the maximum height calculated using the projectile motion formula, considering the initial velocity and launch angle.
354 Medium
354 of 388
Analyzing +4 | -1
Following forces start acting on a particle at rest at the origin of the co-ordinate system simultaneously F⃗1=5i^−5j^+5k^,      F2=2i^+8j^+6k^,F3=−6i^+4j^−7k^,F4=−i^−3j^−2k^.{\mathrm{\vec F}_1} = 5\hat i - 5\hat j + 5\hat k,\mathrm{\;\;\;}{\mathrm{F}_2} = 2\hat i + 8\hat j + 6\hat k,{\mathrm{F}_3} = - 6\hat i + 4\hat j - 7\hat k,{\mathrm{F}_4} = - \hat i - 3\hat j - 2\hat k. The particle will move
View answer and explanation
Correct option: B
in y-z plane
Option B (in y-z plane) is correct because the resultant force vector has no component along the y-axis, indicating motion in the y-z plane.
355 Medium
355 of 388
Understanding +4 | -1
A projectile is projected at an angle of 47∘47^{\circ} relative to the horizontal. The range of the projectile could be increased by
View answer and explanation
Correct option: B
increasing the initial speed
Option B is correct because increasing the initial speed will increase the range of the projectile, given the fixed angle.
356 Medium
356 of 388
Application +4 | -1
A bullet is fired from a cannon with velocity 500 m/s . If the angle of projection is 15∘15^\circ and g=10  m/s2g = 10\;m/{s^2}. Then the range is
View answer and explanation
Correct option: B
12.5×103  m12.5 \times {10^3}\;m
Option B (12.5×103;m12.5 \times {10^3}\\;m) is correct because it is calculated using the range formula for projectile motion.
357 Medium
357 of 388
Application +4 | -1
The vectors A⃗=i^+2j^+3k^\vec{A}=\hat{i}+2 \hat{j}+3 \hat{k} and B⃗=2i^−j^\vec{B}=2 \hat{i}-\hat{j} are ___ to each other.
View answer and explanation
Correct option: A
A⃗⊥B⃗\vec{A} \perp \vec{B}
Option A (A⃗⊥B⃗\vec{A} \perp \vec{B}) is correct because the dot product of the two vectors is zero, indicating they are perpendicular.
358 Medium
358 of 388
Understanding +4 | -1
The shape of trajectory of the motion of an object is determined by
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because the trajectory of an object's motion depends on its initial position, initial velocity, and acceleration.
359 Medium
359 of 388
Application +4 | -1
A particle moves with velocity 3i^−2j^+3k^   m/s3\hat i - 2\hat j + 3\hat k\,\,\,{\text{m}}/{\text{s}} under the influence of a constant force F→=20i^+15j^−5k^   N.\overrightarrow F = 20\hat i + 15\hat j - 5\hat k\,\,\,{\text{N}}. The instantaneous power applied to the particle is (in J/s)
View answer and explanation
Correct option: A
15
Option A (15) is correct because the instantaneous power is calculated by taking the dot product of the force and velocity vectors: P=F→⋅V→P = \overrightarrow{F} \cdot \overrightarrow{V}.
360 Medium
360 of 388
Understanding +4 | -1
Assertion: In order to hit a target, a man should point his rifle at a point higher than the target.
Reason: The bullet suffers a vertically downward deflection due to gravity.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because to compensate for gravity's downward pull, a rifle must be aimed slightly higher than the target.
Revision notes and key takeaways

Review MOTION IN PLANE in your textbook or class notes, then use this set to check your understanding.

Showing 331-360 of 388 questions
0 /388
0✓ 0✗
0% Accuracy
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.