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JEE • PHYSICS • MOTION IN PLANE

Motion in plane practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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301 Medium
301 of 388
Application +4 | -1
A man is swimming with speed 10 km/h in still water crosses a river of width 1 km along the shortest path in 10 minutes. The velocity of river flow is
View answer and explanation
Correct option: D
8 km/h
Option D (8 km/h) is correct because it is the velocity of the river flow calculated using the Pythagorean theorem and the given information.
302 Medium
302 of 388
Analyzing +4 | -1
If the range of oblique projectile is R{R}, then its K.E. is maximum after (from start) a displacement equal to
View answer and explanation
Correct option: B
R{R}
Option C (R2\frac{R}{2}) is correct because the kinetic energy is maximum at the start, and the horizontal displacement at half the range is R/2.
303 Medium
303 of 388
Understanding +4 | -1
There are two values of time for which a projectile is at the same height, The sum of these two times is equal to (T=T = time of fight of the projectile)
View answer and explanation
Correct option: D
TT
Option D (T) is correct because the time of flight is the total time the projectile is in the air, and the sum of the times at the same height is equal to the total time of flight.
304 Medium
304 of 388
Analyzing +4 | -1
What is the angle between P\mathbf{P} and the cross product of (P+Q)(\mathbf{P}+\mathbf{Q}) and (P−Q)(\mathbf{P}-\mathbf{Q}) ?
View answer and explanation
Correct option: A
90∘90^{\circ}
Option A is correct because the cross product of (P+Q) and (P-Q) results in a vector perpendicular to both P and Q, hence perpendicular to P.
305 Medium
305 of 388
Understanding +4 | -1
Assertion: The sum of squares of cosines of angles made by a vector with X,Y\mathrm{X}, \mathrm{Y} and Z\mathrm{Z} axes is equal to unity.
Reason: A vector making 45∘45^{\circ} with X\mathrm{X}-axis must have equal components along X\mathrm{X} and Y\mathrm{Y}-axes.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C is correct because the assertion is true (cos⁡2α+cos⁡2β+cos⁡2γ=1\cos^2\alpha + \cos^2\beta + \cos^2\gamma = 1), but the reason is false. A vector making 45° with the X-axis does not necessarily have equal components along the X and Y axes unless other angles are specified.
306 Medium
306 of 388
Analyzing +4 | -1
A particle reaches its highest point when it has covered exactly one half of its horizontal range. The corresponding point on the displacement-time graph is characterised by
View answer and explanation
Correct option: C
zero slope and positive curvature.
Option C (zero slope and positive curvature) is correct because at the highest point, the vertical velocity is zero (zero slope), and the projectile is still accelerating downwards (positive curvature).
307 Medium
307 of 388
Application +4 | -1
A boat takes two hours to travel 8 km and back in still water. If the velocity of water 4 kmh−1\mathrm{km}{\mathrm{h}^{ - 1}}, the time taken for going ups tream 8km and coming back is
View answer and explanation
Correct option: B
2 h 40 min
Option B (2 h 40 min) is correct because it accounts for the time taken to travel upstream against the current and downstream with the current.
308 Medium
308 of 388
Application +4 | -1
Some persons hire a boat for 4 hours. The river flows at a speed of 5 km/hr5 \mathrm{~km} / \mathrm{hr} and the boat moves with speed of 15 km/hr15 \mathrm{~km} / \mathrm{hr} relative to the water. How far along the flow direction, they can go if they have to return in 4 hrs?
View answer and explanation
Correct option: C
(80/3) km(80/3) \mathrm{~km}
Option C ((80/3) km(80/3) \mathrm{~km}) is correct because it accurately calculates the distance they can go along the flow direction by considering the time spent going and returning.
309 Medium
309 of 388
Understanding +4 | -1
Which of the following conditions are sufficient and essential for a quantity to be a vector?
View answer and explanation
Correct option: C
Magnitude, direction, and addition, subtraction multiplication and division by vector laws
Option C (Magnitude, direction, and addition, subtraction multiplication and division by vector laws) is correct because a vector requires magnitude, direction, and must obey vector addition laws.
310 Medium
310 of 388
Remembering +4 | -1
If uu is the initial velocity of a projectile and vv is the velocity at any instant, then the maximum horizontal range Rm\mathrm{R}_{\mathrm{m}} is equal to
View answer and explanation
Correct option: D
Rm=u2 g\mathrm{R}_{\mathrm{m}}=\frac{\mathrm{u}^2}{\mathrm{~g}}
Option D (Rₘ = u²/g) is correct because the maximum horizontal range is achieved when the launch angle is 45 degrees, resulting in sin(2θ) = 1.
311 Medium
311 of 388
Application +4 | -1
Position of a particle at any instant tt is given r⃗=3i^+2t2j^+5k^\vec{r}=3 \hat{i}+2 t^2 \hat{j}+5 \hat{k}, Its velocity at same instant will be:
View answer and explanation
Correct option: C
3i^+4tj^3\hat{i}+4 t \hat{j}
Option C (3i^+4tj^3\hat{i}+4 t \hat{j}) is correct because velocity is the derivative of the position vector with respect to time.
312 Medium
312 of 388
Application +4 | -1
A particle is projected upwards with a velocity of 100 m/sec100 \mathrm{~m} / \mathrm{sec} at an angle of 60∘60^{\circ} with the vertical. Find the time in seconds when the particle will move perpendicular to its initial direction, taking g=10 m/sec2{g}=10 \mathrm{~m} / \mathrm{sec}^2
View answer and explanation
Correct option: A
20
Option A (20) is correct because it is the time when the dot product of the initial and final velocity vectors is zero, indicating perpendicularity.
313 Medium
313 of 388
Analyzing +4 | -1
If two non-parallel vectors A⃗\vec{A} and B⃗\vec{B} are equal in magnitude, then the vectors (A⃗−B⃗)(\vec{A}-\vec{B}) and (A⃗+B⃗)(\vec{A}+\vec{B}) will be
View answer and explanation
Correct option: C
Perpendicular to each other
Option C (Perpendicular to each other) is correct because the dot product of (A+B) and (A-B) is zero when |A| = |B|.
314 Medium
314 of 388
Understanding +4 | -1
A stone is thrown with a velocity uu making an angle θ \theta \, with the horizontal. The horizontal distance covered by its fall to ground is maximum when the angle θ \theta \, is equal to
View answer and explanation
Correct option: C
45∘45^\circ
Option C (45∘45^\circ) is correct because the horizontal range is maximum when the angle of projection is 45∘45^\circ.
315 Medium
315 of 388
Understanding +4 | -1
Assertion: A man can cross river of width dd in minimum time. On increasing the river velocity, minimum time to cross the river by man will remain unchanged.
Reason: As velocity of a river is perpendicular to its width so time to cross the river is independent of velocity of river.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because the minimum time to cross a river depends only on the swimmer's velocity component perpendicular to the river flow and the width of the river.
316 Medium
316 of 388
Application +4 | -1
The maximum range of a projectile is 100 m100 \mathrm{~m} The maximum height reached by it is
View answer and explanation
Correct option: B
25 m
Option B (25 m) is correct because the maximum height is one-fourth of the maximum range when the projectile is launched at 45 degrees.
317 Medium
317 of 388
Application +4 | -1
A ball is projected horizontally from the top of a tower with a velocity v0v_0. It will be moving at an angle of 60∘60^{\circ} with the horizontal after time,
View answer and explanation
Correct option: B
3v0g\frac{\sqrt{3} v_0}{g}
Option B (3v0g\frac{\sqrt{3} v_0}{g}) is correct because it is the time at which the vertical component of velocity equals 3\sqrt{3} times the horizontal component.
318 Medium
318 of 388
Understanding +4 | -1
At the top of trajectory of a projectile, the acceleration is
View answer and explanation
Correct option: D
gg
Option D is correct because the acceleration of a projectile at the top of its trajectory is still equal to the acceleration due to gravity, *g*, acting downwards.
319 Medium
319 of 388
Application +4 | -1
The equation of trajectory of a projectile in the vertical plane is y=[10x−(59)x2]my = \left[ {10x - \left( {\frac{5}{9}} \right){x^2}} \right]m. the horizontal distance covered by the projectile when it reaches the maximum height is [g=10  ms−2]\left[ {g = 10\,\,m{s^{ - 2}}} \right]
View answer and explanation
Correct option: B
9 m
Option B (9 m) is correct because it is the x-coordinate where the projectile reaches its maximum height, found by setting the derivative of the trajectory equation to zero.
320 Medium
320 of 388
Analyzing +4 | -1
A particle has two equal accelerations in two given directions. If one of the accelerations is halved, then the angle which the resultant makes with the other is also halved. The angle between the accelerations is
View answer and explanation
Correct option: A
120∘120^{\circ}
Option A (120∘120^{\circ}) is correct because the angle between the accelerations can be found using trigonometric relationships and the given condition that halving one acceleration halves the angle of the resultant.
321 Medium
321 of 388
Understanding +4 | -1
A→\overrightarrow A is a vector quantity such that ∣A→∣= \left| {\overrightarrow A } \right| = \, non-zero constant. Which of the following expression is true for A→\overrightarrow A?
View answer and explanation
Correct option: C
A→×A→=0\overrightarrow A \times \overrightarrow A = 0
Option C (A→×A→=0\overrightarrow A \times \overrightarrow A = 0) is correct because the cross product of a vector with itself is always zero.
322 Medium
322 of 388
Analyzing +4 | -1
The lines r⃗=2k^+λ(3i^+2j^+k^)\vec{r}=2 \hat{k}+\lambda(3 \hat{i}+2 \hat{j}+\hat{k}) and r⃗=3i^+2j^+3k^\vec{r}=3 \hat{i}+2 \hat{j}+3 \hat{k} +μ(6i^+4j^+2k^)+\mu(6 \hat{i}+4 \hat{j}+2 \hat{k}) are:
View answer and explanation
Correct option: D
intersect at more than one point
Option D (intersect at more than one point) is correct because the direction vectors are proportional, indicating parallel lines, and a point on one line also lies on the other, meaning they are coincident.
323 Medium
323 of 388
Understanding +4 | -1
Given that, P+Q+R=0{P}+{Q}+{R}=0. Which of the following statement is true?
View answer and explanation
Correct option: B
∣P+Q∣=∣R∣|{P}+{Q}|=|{R}|
Option B (∣P+Q∣=∣R∣|{P}+{Q}|=|{R}|) is correct because if P+Q+R=0{P}+{Q}+{R}=0, then P+Q=−R{P}+{Q} = -{R}, and the magnitude of P+Q{P}+{Q} must equal the magnitude of R{R}.
324 Medium
324 of 388
Analyzing +4 | -1
Statement-I: Let a⃗=i^+j^\vec{a}=\hat{i}+\hat{j} and b⃗=i^−j^\vec{b}=\hat{i}-\hat{j} be two vectors. Angle between a^+b^\hat{a}+\hat{b} and a^−b^=90∘\hat{a}-\hat{b}=90^{\circ}
Statement-II: Projection of a⃗+b⃗\vec{a}+\vec{b} on a⃗−b⃗\vec{a}-\vec{b} is zero.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A is correct because both statements are true. The angle between a⃗+b⃗\vec{a}+\vec{b} and a⃗−b⃗\vec{a}-\vec{b} is 90°, and the projection of a⃗+b⃗\vec{a}+\vec{b} on a⃗−b⃗\vec{a}-\vec{b} is zero.
325 Medium
325 of 388
Application +4 | -1
Two forces whose magnitudes are in the ratio 3:5 give a resultant of 35N. If the angle between them is 60o{60^\mathrm{o}}, the magnitude of each force is
View answer and explanation
Correct option: C
15N, 25N
Option C (15N, 25N) is correct because it is found by solving the equations derived from the resultant of two forces at an angle.
326 Medium
326 of 388
Application +4 | -1
The resultant of two forces at right angle is 5N. When the angle between them is 1200{120^0}, the resultant is 13\sqrt {13}. Then the force are
View answer and explanation
Correct option: C
3 N, 4 N
Option C (3 N, 4 N) is correct because these values satisfy both the resultant force equations for right angles and 120 degrees.
327 Medium
327 of 388
Understanding +4 | -1
Assertion (A): The distance between two floating objects on a river flowing uniformly does not changes with time.

Reason (R): The floating object has the same velocity as that of the river.
View answer and explanation
Correct option: A
Both A and R are true and R is the correct explanation of A
Both A and R are true and R is the correct explanation of A because if the objects are floating, they move with the river's velocity, maintaining a constant distance.
328 Medium
328 of 388
Understanding +4 | -1
If the angle between two forces increases, the magnitude of their resultant
View answer and explanation
Correct option: A
Decreases
Option A (Decreases) is correct because the magnitude of the resultant force decreases as the angle between the two forces increases.
329 Medium
329 of 388
Analyzing +4 | -1
Two bodies are projected from roof with same speed in different directions. If air resistance is not taken into account then
View answer and explanation
Correct option: D
Both (a) and (c) are correct
Option D is correct. If air resistance is neglected, the speed at impact depends only on the initial speed and height, and if the masses are equal, the momenta will have the same magnitude.
330 Medium
330 of 388
Understanding +4 | -1
Assertion: Commutative law is followed while vector addition.
Reason: Addition of two vectors maybe done graphically using head-to-tail method or parallelogram method.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
Option B is correct because vector addition is commutative, and the head-to-tail or parallelogram method are ways to visualize this, but do not explain *why* it's commutative.
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