Motion in plane practice · Hard

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Application +4 | -1

A cricket ball thrown across a field is at heights

h_1

and

h_2

from the point of projection at times

t_1

and

t_2

respectively after the throw. The ball is caught by a fielder at the same height as that of projection. The time of flight of the ball in this journey is

View answer and explanation

Correct option: C

\left(\frac{h_1 t_2^2-h_2 t_1^2}{h_1 t_2-h_2 t_1}\right)

Option C (

\left(\frac{h_1 t_2^2-h_2 t_1^2}{h_1 t_2-h_2 t_1}\right)

) is correct because it's derived from using kinematic equations and solving for the time of flight based on the given heights and times.

Revision notes and key takeaways

Review MOTION IN PLANE in your textbook or class notes, then use this set to check your understanding.

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