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JEE • PHYSICS • MOTION IN PLANE

Motion in plane practice · Hard

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 61 questions
31 Hard
31 of 61
Understanding +4 | -1
A vector a\mathbf{a} is turned without a change in its length through a small angles dθd \theta. The value of ∣Δa∣|\Delta \mathbf{a}| and Δa\Delta a are, respectively.
View answer and explanation
Correct option: B
a⋅dθ,0a \cdot d \theta, 0
Option B (a⋅dθ,0a \cdot d \theta, 0) is correct because the magnitude of the change in the vector is adθa d\theta, while the change in the magnitude of the vector is zero.
32 Hard
32 of 61
Analyzing +4 | -1
If a,b,c\mathbf{a}, \mathbf{b}, \mathbf{c} be non-zero vectors such that a\mathbf{a} is perpendicular to b\mathbf{b} and c\mathbf{c} and ∣a∣=1,∣b∣=2,∣c∣=1,b⋅c=1|\mathbf{a}|=1,|\mathbf{b}|=2,|\mathbf{c}|=1, \mathbf{b} \cdot \mathbf{c}=1 and there is a non-zero vector d\mathrm{d} coplanar with a+b\mathbf{a}+\mathbf{b} and 2b−c2 \mathbf{b}-\mathbf{c} and d⋅a=1\mathbf{d} \cdot \mathbf{a}=1, then minimum value of ∣d∣|\mathbf{d}| is
View answer and explanation
Correct option: D
413\frac{4}{\sqrt{13}}
Option D (413\frac{4}{\sqrt{13}}) is correct because it represents the minimum magnitude of vector d\mathbf{d} found by minimizing the quadratic expression obtained from the given conditions.
33 Hard
33 of 61
Analyzing +4 | -1
If a=3i^−j^+5k^\mathbf{a}=3 \hat{\mathbf{i}}-\hat{\mathbf{j}}+5 \hat{\mathbf{k}} and b=i^+2j^−3k^\mathbf{b}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-3 \hat{\mathbf{k}} are given vector. A vector c\mathbf{c} which is perpendicular to ZZ-axis satisfying c⋅a=9\mathbf{c} \cdot \mathbf{a}=9 and c⋅b=−4\mathbf{c} \cdot \mathbf{b}=-4. If inclination of c\mathbf{c} with XX-axis and γ\gamma-axis is α\alpha and β\beta respectively, then which of the following is not true?
View answer and explanation
Correct option: C
α>π2\alpha>\frac{\pi}{2}
Option C is correct because the calculated value of alpha (α\alpha) is less than π2\frac{{\pi}}{{2}}, making the statement α>π2\alpha > \frac{{\pi}}{{2}} false.
34 Hard
34 of 61
Application +4 | -1
A man can swim with a speed of 4  kmh−14\,\,km{h^{ - 1}} in still water. He crosses a river 1 km wider that flows steadily at 3  kmh−13\,\,km{h^{ - 1}} If he makes his strokes normal to the river current how far down the river does he go when he reaches the other bank?
View answer and explanation
Correct option: C
750 m
Option A (0.577) is correct because it is the ratio of the efficiencies of the Carnot engine under the two given temperature conditions, calculated using the Carnot efficiency formula.
35 Hard
35 of 61
Analyzing +4 | -1
If OABCO A B C is a tetrahedron such that OA2+BC2\mathrm{OA}^2+\mathrm{BC}^2 =OB2+CA2=OC2+AB2=\mathrm{OB}^2+\mathrm{CA}^2=\mathrm{OC}^2+\mathrm{AB}^2, then which of the following is not true?
View answer and explanation
Correct option: D
AB⊥ACA B \perp A C
Option D (AB⊥ACA B \perp A C) is correct because the given condition implies that OA⊥BCO A \perp B C, OB⊥ACO B \perp A C, and OC⊥ABO C \perp A B, but it does not necessarily imply that AB⊥ACA B \perp A C.
36 Hard
36 of 61
Analyzing +4 | -1
If a,b,c\mathbf{a}, \mathbf{b}, \mathbf{c} be non-zero vectors such that a\mathbf{a} is perpendicular to b\mathbf{b} and c\mathbf{c} and ∣a∣=1,∣b∣=2,∣c∣=1,b⋅c=1|\mathbf{a}|=1,|\mathbf{b}|=2,|\mathbf{c}|=1, \mathbf{b} \cdot \mathbf{c}=1 and there is a non-zero vector d\mathrm{d} coplanar with a+b\mathbf{a}+\mathbf{b} and 2b−c2 \mathbf{b}-\mathbf{c} and d⋅a=1\mathbf{d} \cdot \mathbf{a}=1, then minimum value of ∣d∣|\mathbf{d}| is
View answer and explanation
Correct option: D
413\frac{4}{\sqrt{13}}
Option D (413\frac{4}{\sqrt{13}}) is correct because it represents the minimum magnitude of vector d\mathbf{d} calculated using vector algebra and minimization techniques.
37 Hard
37 of 61
Analyzing +4 | -1
A steam boat goes across a lake and comes back (1) On a quite day when the water is still and (2) On a rough day when there is uniform air current so as to help the journey onward and to impede the journey back. If the speed of the launch on both days was same, in which case it will complete the journey in lesser time
View answer and explanation
Correct option: A
Case (1)
The correct answer is A because the boat will take less time on a quiet day compared to a day with a uniform air current.
38 Hard
38 of 61
Analyzing +4 | -1
If AA is 3×33 \times 3 matrix and u\mathbf{u} is a vector. If AuA \mathbf{u} and u\mathbf{u} are orthogonal for all real u\mathbf{u}, then matrix AA is aa
View answer and explanation
Correct option: A
singular
Option A (singular) is correct because if AuA \mathbf{u} and u\mathbf{u} are orthogonal for all u\mathbf{u}, then the determinant of A must be zero, implying A is singular.
39 Hard
39 of 61
Analyzing +4 | -1
Let two non-collinear vectors a\mathbf{a} and b\mathbf{b} inclined at an angle 2π3\frac{2 \pi}{3} be such that ∣a∣=3|\mathbf{a}|=3 and ∣b∣=2|\mathbf{b}|=2. If a point PP moves so that at any time tt its position vector OP\mathbf{O P} (where OO is the origin) is given as OP=(t+1t)a+(t−1t)b\mathrm{OP}=\left(t+\frac{1}{t}\right) \mathbf{a}+\left(t-\frac{1}{t}\right) \mathbf{b}, then least distance of PP from the origin is
View answer and explanation
Correct option: B
2133+10\sqrt{2 \sqrt{133}+10}
Option B (2133+10\sqrt{2 \sqrt{133}+10}) is correct because it represents the minimum distance obtained by minimizing the squared distance function using AM-GM inequality.
40 Hard
40 of 61
Application +4 | -1
If a,b and c\mathbf{c} are three non-coplanar uni-modular vectors, each inclined with other at an angle 30∘30^{\circ}, then volume of tetrahedron whose edges are a,b\mathbf{a}, \mathbf{b} and c\mathbf{c} is
View answer and explanation
Correct option: A
33−512\frac{\sqrt{3 \sqrt{3}-5}}{12}
Option A (33−512\frac{\sqrt{3 \sqrt{3}-5}}{12}) is correct because it is the volume of the tetrahedron calculated using the scalar triple product.
41 Hard
41 of 61
Application +4 | -1
A projectile is thrown upward with a velocity v0v_0 at an angle α\alpha to the horizontal. The change in velocity of the projectile when it strikes the same horizontal plane is
View answer and explanation
Correct option: B
2v0sin⁡α2 v_0 \sin \alpha vertically downward
Option B (2v0sin⁡α2 v_0 \sin \alpha vertically downward) is correct because it represents the change in the vertical component of velocity when the projectile returns to the same horizontal plane.
42 Hard
42 of 61
Analyzing +4 | -1
Let the cosine of angle between the vectors p\mathbf{p} and q\mathbf{q} be λ\lambda such that 2p+q=i^+j^2 \mathbf{p}+\mathbf{q}=\hat{\mathbf{i}}+\hat{\mathbf{j}} and p+2q=i^−j^\mathbf{p}+2 \mathbf{q}=\hat{\mathbf{i}}-\hat{\mathbf{j}}, then λ\lambda is equal to
View answer and explanation
Correct option: B
−45-\frac{4}{5}
Option B (−45-\frac{4}{5}) is correct because by solving for vectors p\mathbf{p} and q\mathbf{q} and then using the cosine formula, we find the cosine of the angle between them.
43 Hard
43 of 61
Analyzing +4 | -1
Let two non-collinear vectors a\mathbf{a} and b\mathbf{b} inclined at an angle 2π3\frac{2 \pi}{3} be such that ∣a∣=3|\mathbf{a}|=3 and ∣b∣=2|\mathbf{b}|=2. If a point PP moves so that at any time tt its position vector OP\mathbf{O P} (where OO is the origin) is given as OP=(t+1t)a+(t−1t)b\mathrm{OP}=\left(t+\frac{1}{t}\right) \mathbf{a}+\left(t-\frac{1}{t}\right) \mathbf{b}, then least distance of PP from the origin is
View answer and explanation
Correct option: B
2133+10\sqrt{2 \sqrt{133}+10}
Option B (2133+10\sqrt{{2 \sqrt{{133}} + 10}}) is correct because it represents the minimum value of |OP| calculated using AM ≥ GM inequality after finding the expression for |OP|^2.
44 Hard
44 of 61
Application +4 | -1
A body of mass 10 kg10 \mathrm{~kg} is projected at an angle of 45∘45^{\circ} with the horizontal. The trajectory of the body is observed to pass through a point (20,10)(20,10). If TT is the time of flight, then its momentum vector, at time t=T2t=\frac{T}{\sqrt{2}}, is ______. [Take g=10 m/s2g=10 \mathrm{~m} / \mathrm{s}^2 ]
View answer and explanation
Correct option: D
1002i^+(1002−200)j^100 \sqrt{2} \hat{i}+(100 \sqrt{2}-200) \hat{j}
Option D (1002i^+(1002−200)j^100 \sqrt{2} \hat{i}+(100 \sqrt{2}-200) \hat{j}) is correct because it correctly calculates the momentum vector at the specified time using projectile motion principles.
45 Hard
45 of 61
Analyzing +4 | -1
If OABCO A B C is a tetrahedron such that OA2+BC2\mathrm{OA}^2+\mathrm{BC}^2 =OB2+CA2=OC2+AB2=\mathrm{OB}^2+\mathrm{CA}^2=\mathrm{OC}^2+\mathrm{AB}^2, then which of the following is not true?
View answer and explanation
Correct option: D
AB⊥ACA B \perp A C
Option D (AB⊥ACA B \perp A C) is correct because the given conditions imply that OA⊥BCOA \perp BC, OB⊥ACOB \perp AC, and OC⊥ABOC \perp AB, but not necessarily that AB⊥ACAB \perp AC.
46 Hard
46 of 61
Application +4 | -1
If a,b and c\mathbf{c} are three non-coplanar uni-modular vectors, each inclined with other at an angle 30∘30^{\circ}, then volume of tetrahedron whose edges are a,b\mathbf{a}, \mathbf{b} and c\mathbf{c} is
View answer and explanation
Correct option: A
33−512\frac{\sqrt{3 \sqrt{3}-5}}{12}
Option A (33−512\frac{\sqrt{3 \sqrt{3}-5}}{12}) is correct because it is the volume of the tetrahedron calculated using the scalar triple product.
47 Hard
47 of 61
Application +4 | -1
If θ\theta is the angle between the vectors a=2i^+2j^−k^\mathbf{a}=2 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}} and b=6i^−3j^+2k^\mathbf{b}=6 \hat{\mathbf{i}}-3 \hat{\mathbf{j}}+2 \hat{\mathbf{k}}, then
View answer and explanation
Correct option: A
cos⁡θ=421\cos \theta=\frac{4}{21}
Option A (cos⁡θ=421\cos \theta=\frac{4}{21}) is correct because it is the result of applying the dot product formula to find the cosine of the angle between the two vectors.
48 Hard
48 of 61
Analyzing +4 | -1
Two particles are projected from the same point on ground simultaneously with speed 20 m/s20 \mathrm{~m} / \mathrm{s} and 203 m/s\frac{20}{\sqrt{3}} \mathrm{~m} / \mathrm{s} at angles 30∘30^{\circ} and 60∘60^{\circ} respectively with the horizontal in the same direction. The maximum distance between them till both of them strike the ground is approximately (g=10 m/s2)({g}=10 \mathrm{~m} / \mathrm{s}^2)
View answer and explanation
Correct option: A
23.1 m
Option A (23.1 m) is correct because the maximum distance is the difference in their horizontal ranges, calculated using projectile motion formulas.
49 Hard
49 of 61
Analyzing +4 | -1
If a,b and c are unit vectors, then ∣a−b∣2+∣b−c∣2+∣c−a∣2|\mathbf{a}-\mathbf{b}|^2+|\mathbf{b}-\mathbf{c}|^2+|\mathbf{c}-\mathbf{a}|^2 does not exceed
View answer and explanation
Correct option: B
9
Option B (9) is correct because by expanding the expression and using the fact that the vectors are unit vectors, we can find an upper bound for the given expression.
50 Hard
50 of 61
Analyzing +4 | -1
If (a+3b)⋅(7a−5b)=0\mathrm{If}\,(\mathbf{a}+3 \mathbf{b}) \cdot(7 \mathbf{a}-5 \mathbf{b})=0 and
(a−4b)⋅(7a−2b)=0(\mathbf{a}-4 \mathbf{b}) \cdot(7 \mathbf{a}-2 \mathbf{b})=0. Then, the angle between a\mathbf{a} and b\mathbf{b} is
View answer and explanation
Correct option: A
60∘60^{\circ}
Option A (60∘60^{\circ}) is correct because solving the dot product equations leads to cos⁡θ=12\cos \theta = \frac{1}{2}, which corresponds to an angle of 60∘60^{\circ}.
51 Hard
51 of 61
Analyzing +4 | -1
Let a, b,c, be vectors of length 3, 4, 5 respectively and a\mathbf{a} be perpendicular to (b+c),b(\mathbf{b}+\mathbf{c}), \mathbf{b} to (c+a)(\mathbf{c}+\mathbf{a}) and c\mathbf{c} to (a+b)(\mathbf{a}+\mathbf{b}), then the value of (a+b+c)(\mathbf{a}+\mathbf{b}+\mathbf{c}) is
View answer and explanation
Correct option: D
525 \sqrt{2}
The correct answer is D (525 \sqrt{2}) because by using the given perpendicularity conditions and vector algebra, we find the magnitude of the sum of the vectors.
52 Hard
52 of 61
Application +4 | -1
The vectors c,a=xi^+yj^+zk^\mathbf{c}, \mathbf{a}=x \hat{\mathbf{i}}+y \hat{\mathbf{j}}+z \hat{\mathbf{k}} and b=j^\mathbf{b}=\hat{\mathbf{j}} are such that a,c\mathbf{a}, \mathbf{c} and b\mathbf{b} form a right handed system, then c\mathbf{c} is
View answer and explanation
Correct option: A
zi^−xk^z \hat{\mathbf{i}}-x \hat{\mathbf{k}}
Option A (zi^−xk^z \hat{\mathbf{i}}-x \hat{\mathbf{k}}) is correct because it satisfies the right-handed system condition with the given vectors a\mathbf{a} and b\mathbf{b}.
53 Hard
53 of 61
Application +4 | -1
The sine of the angle between the vector a=3i^+j^+k^\mathbf{a}=3 \hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}} and b=2i^−2j^+k^\mathbf{b}=2 \hat{\mathbf{i}}-2 \hat{\mathbf{j}}+\hat{\mathbf{k}} is
View answer and explanation
Correct option: A
7499\sqrt{\frac{74}{99}}
Option A (7499\sqrt{\frac{74}{99}}) is correct because it is the sine of the angle calculated using the cross product of the two vectors.
54 Hard
54 of 61
Analyzing +4 | -1
If a,b,c\mathbf{a}, \mathbf{b}, \mathbf{c} be non-zero vectors such that a\mathbf{a} is perpendicular to b\mathbf{b} and c\mathbf{c} and ∣a∣=1,∣b∣=2,∣c∣=1,b⋅c=1|\mathbf{a}|=1,|\mathbf{b}|=2,|\mathbf{c}|=1, \mathbf{b} \cdot \mathbf{c}=1 and there is a non-zero vector d\mathrm{d} coplanar with a+b\mathbf{a}+\mathbf{b} and 2b−c2 \mathbf{b}-\mathbf{c} and d⋅a=1\mathbf{d} \cdot \mathbf{a}=1, then minimum value of ∣d∣|\mathbf{d}| is
View answer and explanation
Correct option: D
413\frac{4}{\sqrt{13}}
Option D (413\frac{4}{\sqrt{13}}) is correct because it represents the minimum magnitude of vector d\mathbf{d} found by minimizing the quadratic expression obtained from the given conditions.
55 Hard
55 of 61
Analyzing +4 | -1
If a=3i^−j^+5k^\mathbf{a}=3 \hat{\mathbf{i}}-\hat{\mathbf{j}}+5 \hat{\mathbf{k}} and b=i^+2j^−3k^\mathbf{b}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-3 \hat{\mathbf{k}} are given vector. A vector c\mathbf{c} which is perpendicular to ZZ-axis satisfying c⋅a=9\mathbf{c} \cdot \mathbf{a}=9 and c⋅b=−4\mathbf{c} \cdot \mathbf{b}=-4. If inclination of c\mathbf{c} with XX-axis and γ\gamma-axis is α\alpha and β\beta respectively, then which of the following is not true?
View answer and explanation
Correct option: C
α>π2\alpha>\frac{\pi}{2}
Option C (α>π2\alpha > \frac{\pi}{2}) is correct because by finding the vector c and its components, we determine the angle it makes with the x-axis, which is less than π2\frac{\pi}{2}.
56 Hard
56 of 61
Analyzing +4 | -1
Let A, B and C\mathbf{C} be unit vectors. Suppose A⋅B=A⋅C=0\mathbf{A} \cdot \mathbf{B}=\mathbf{A} \cdot \mathbf{C}=0 and the angle between B\mathbf{B} and C\mathbf{C} is π4\frac{\pi}{4}. Then,
View answer and explanation
Correct option: B
A=±2(B×C)\mathbf{A}=\pm \sqrt{2}(\mathbf{B} \times \mathbf{C})
Option B is correct because A is perpendicular to both B and C, and the magnitude of A is related to the cross product of B and C, considering the angle between B and C.
57 Hard
57 of 61
Application +4 | -1
If a⃗\vec a and b⃗\vec b are two non collinear unit vectors and if ∣aˉ+bˉ∣=3\left| {\bar a + \bar b} \right| = \sqrt 3 then the value of (aˉ−bˉ)⋅(2aˉ+bˉ)\left( {\bar a - \bar b} \right) \cdot \left( {2\bar a + \bar b} \right) is
View answer and explanation
Correct option: D
0.5
Option D (0.5) is correct because by finding the angle between the vectors and then calculating the dot product, the result is 0.5.
58 Hard
58 of 61
Application +4 | -1
The unit vector in ZOX plane making angles 45∘45^{\circ} and 60∘60^{\circ} respectively, with a=2i^+2j^−k^a=2 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}} and b=j^−k^\mathbf{b}=\hat{\mathbf{j}}-\hat{\mathbf{k}}, is
View answer and explanation
Correct option: B
12(i^−k^)\frac{1}{\sqrt{2}}(\hat{i}-\hat{k})
Option B (12(i^−k^)\frac{1}{\sqrt{2}}(\hat{i}-\hat{k})) is correct because it satisfies the conditions of being a unit vector in the ZOX plane and making the specified angles with vectors a and b.
59 Hard
59 of 61
Analyzing +4 | -1
The vectors a=2λ2i^+4λj^+k^\mathbf{a}=2 \lambda^2 \hat{\mathbf{i}}+4 \lambda \hat{\mathbf{j}}+\hat{\mathbf{k}} and b=7i^−2j^+λk^\mathbf{b}=7 \hat{\mathbf{i}}-2 \hat{\mathbf{j}}+\lambda \hat{\mathbf{k}} make an obtuse angle whereas the angle between b\mathbf{b} and k^\hat{\mathbf{k}} is acute and less than π/6\pi / 6,
View answer and explanation
Correct option: D
null set
Option D (null set) is correct because the conditions on λ\lambda lead to contradictory inequalities, resulting in no possible values for λ\lambda.
60 Hard
60 of 61
Application +4 | -1
If aa is any vector, then (a×i^)2+(a×j^)2+(a×k^)2(\mathbf{a} \times \hat{\mathbf{i}})^2+(\mathbf{a} \times \hat{\mathbf{j}})^2+(\mathbf{a} \times \hat{\mathbf{k}})^2 is equal to
View answer and explanation
Correct option: D
2∣a∣22|\mathbf{a}|^2
Option D (2∣a∣22|\mathbf{a}|^2) is correct because it is the result of calculating the sum of squares of cross products of vector a\mathbf{a} with unit vectors along the axes.
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