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JEE • PHYSICS • MOTION IN PLANE

Motion in plane practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 331-360 of 489 questions

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331 Medium
331 of 489
Understanding +4 | -1
A: Two row boats moving parallel to each other and nearby, are attracted towards each other
R: Increase of velocity of fluid flow decrease the pressure
View answer and explanation
Correct option: A
Both A and R are true and R is the correct explanation of A
The correct answer is Both A and R are true and R is the correct explanation of A because Bernoulli's principle explains the attraction between the boats.
332 Medium
332 of 489
Analyzing +4 | -1
Assertion: Three given concurrent forces may be in equilibrium which is 200 N;300 N200 \mathrm{~N} ; 300 \mathrm{~N} and 500 N\mathrm{N}

Reason: Three forces are concurrent and their summation or net force acting on a point is zero when 500 N500 \mathrm{~N} acts in one direction and both 200 N200 \mathrm{~N} and 300 N300 \mathrm{~N} act in the opposite direction.
View answer and explanation
Correct option: A
Both Assertion and Reason are true, and Reason is the correct explanation for Assertion
Option A is correct because the forces can be in equilibrium if their vector sum is zero, and the reason correctly explains this condition for the given forces.
333 Medium
333 of 489
Application +4 | -1
Two bodies are thrown from the same point with the same velocity of projection, angles of projection 30∘30^\circ and 60∘.60^\circ . If R1{R_1} and R2{R_2} are the ranges and h1{h_1} and h2{h_2} are maximum heights respectively then
View answer and explanation
Correct option: C
Both (1) and (2)
Option C (Both (1) and (2)) is correct because the ranges are equal for complementary angles of projection, and the sum of maximum heights has a specific relationship.
334 Medium
334 of 489
Analyzing +4 | -1
Given A⃗+B⃗+C⃗+D⃗=0→\vec{A}+\vec{B}+\vec{C}+\vec{D}=\overrightarrow{0}, which of the following statements is not correct?
View answer and explanation
Correct option: A
A⃗,B⃗,C⃗\vec{A}, \vec{B}, \vec{C}, and D⃗\vec{D} must each be a null vector
Option A (A⃗,B⃗,C⃗\vec{A}, \vec{B}, \vec{C}, and D⃗\vec{D} must each be a null vector) is not correct because the vectors can sum to zero without each being a null vector.
335 Medium
335 of 489
Application +4 | -1
The maximum and minimum magnitude of the resultant of two given vectors are 17 units and 7 unit respectively. If these two vectors are at right angles to each other, the magnitude of their resultant is
View answer and explanation
Correct option: D
13
Option D (13) is correct because using the maximum and minimum resultant magnitudes, we can find the individual vector magnitudes and then calculate the resultant when they are at right angles.
336 Medium
336 of 489
Analyzing +4 | -1
Two particles are projected simultaneously in the same vertical plane, from the same point, both with different speeds and at different angles with horizontal. The path followed by one, as seed by the other, is
View answer and explanation
Correct option: D
A straight line making a constant angle (≠90∘)\left( { \ne 90^\circ } \right) with the horizontal
Option D (A straight line making a constant angle (≠90∘)\left( { \ne 90^\circ } \right) with the horizontal) is correct because the relative velocity between the two particles remains constant, resulting in a straight-line path.
337 Medium
337 of 489
Analyzing +4 | -1
For a projectile if α\alpha is the angle of projection, RR is the range, hh is the maximum height, TT is the time of flight then
View answer and explanation
Correct option: C
tan⁡α=4 hR,h=gT28\tan \alpha=\frac{4 \mathrm{~h}}{\mathrm{R}}, \mathrm{h}=\frac{\mathrm{gT}^2}{8}
Option C (tan⁡α=4 hR,h=gT28\tan \alpha=\frac{4 \mathrm{~h}}{\mathrm{R}}, \mathrm{h}=\frac{\mathrm{gT}^2}{8}) is correct because it correctly relates the angle of projection, range, maximum height, and time of flight for a projectile.
338 Medium
338 of 489
Analyzing +4 | -1
Two shells are fired from a cannon with same speed at angle α\alpha and β\beta respectively with the horizontal. The time interval between the shots is T. They collide in mid-air after time ' tt ' from the first shot. Which of the following conditions must be satisfied?
View answer and explanation
Correct option: D
none of these
Option D (none of these) is correct because the condition derived from equating the x and y coordinates at the point of collision leads to contradictory requirements on the angles α\alpha and β\beta.
339 Medium
339 of 489
Application +4 | -1
A swimmer wishes to cross a 800 m800 \mathrm{~m} river flowing at 4 km/h4 \mathrm{~km} / \mathrm{h}. His speed with respect to water is 3 km/h3 \mathrm{~km} / \mathrm{h}. The shortest possible time to cross the river is
View answer and explanation
Correct option: B
16 min16 \mathrm{~min}
Option B (16 min16 \mathrm{~min}) is correct because the shortest time to cross the river is achieved when the swimmer swims perpendicular to the river flow, and the time is calculated using the swimmer's speed relative to the river.
340 Hard
340 of 489
Analyzing +4 | -1
Let two non-collinear vectors a\mathbf{a} and b\mathbf{b} inclined at an angle 2π3\frac{2 \pi}{3} be such that ∣a∣=3|\mathbf{a}|=3 and ∣b∣=2|\mathbf{b}|=2. If a point PP moves so that at any time tt its position vector OP\mathbf{O P} (where OO is the origin) is given as OP=(t+1t)a+(t−1t)b\mathrm{OP}=\left(t+\frac{1}{t}\right) \mathbf{a}+\left(t-\frac{1}{t}\right) \mathbf{b}, then least distance of PP from the origin is
View answer and explanation
Correct option: B
2133+10\sqrt{2 \sqrt{133}+10}
Option B (2133+10\sqrt{2 \sqrt{133}+10}) is correct because it represents the minimum distance obtained by minimizing the squared distance function using AM-GM inequality.
341 Medium
341 of 489
Analyzing +4 | -1
Which of the following statement(s) is/are correct?
View answer and explanation
Correct option: C
If A{A} and B{B} represent two adjacent sides of a parallelogram, then ∣A×B∣|{A} \times {B}| give the area of that parallelogram.
Option C (If A{A} and B{B} represent two adjacent sides of a parallelogram, then ∣A×B∣|{A} \times {B}| give the area of that parallelogram) is correct because the magnitude of the cross product of two adjacent sides of a parallelogram equals its area.
342 Medium
342 of 489
Understanding +4 | -1
Consider the following statements and select the correct statements from the following.
I. Addition and subtraction of scalars make sense only for quantities with same units
II. Multiplication and division of scalars with different units is possible
III. Addition, subtraction, multiplication and division of scalars with same unit is possible
View answer and explanation
Correct option: D
I, II and III
Option B is correct because a potentiometer measures potential difference without drawing current from the source, providing a more accurate measurement than a voltmeter.
343 Hard
343 of 489
Application +4 | -1
If a,b and c\mathbf{c} are three non-coplanar uni-modular vectors, each inclined with other at an angle 30∘30^{\circ}, then volume of tetrahedron whose edges are a,b\mathbf{a}, \mathbf{b} and c\mathbf{c} is
View answer and explanation
Correct option: A
33−512\frac{\sqrt{3 \sqrt{3}-5}}{12}
Option A (33−512\frac{\sqrt{3 \sqrt{3}-5}}{12}) is correct because it is the volume of the tetrahedron calculated using the scalar triple product.
344 Medium
344 of 489
Understanding +4 | -1
Pressure is a scalar quantity because
View answer and explanation
Correct option: C
it is the ratio of component of the force
normal to the area
Option A (2) is correct because the electric field on the axis of a dipole is twice the electric field on the equatorial line at the same distance.
345 Medium
345 of 489
Application +4 | -1
An aeroplane moving horizontally at a speed of 200  ms−1200\mathrm{\;m}{\mathrm{s}^{ - 1}} and at a height of 8×103m8 \times {10^3}\mathrm{m} is to drop a bomb on a target. At what horizontal distance from the target should the bomb be released? (Take g=10  ms−2\mathrm{g} = 10\mathrm{\;m}{\mathrm{s}^{ - 2}})
View answer and explanation
Correct option: C
8000 m
Option C (8000 m) is correct because it is the horizontal distance the bomb travels during the time it takes to fall from the given height.
346 Medium
346 of 489
Application +4 | -1
A body is under the action of two mutually perpendicular forces of 3 N and 4 N. The resultant force acting on the body is
View answer and explanation
Correct option: C
5 N
Option C (5 N) is correct because the resultant of two perpendicular forces is found using the Pythagorean theorem.
347 Medium
347 of 489
Application +4 | -1
A body when projected vertically up, covers a total distance ss, during its time of flight. If we neglect gravity then how much distance the particle will travel during the same time. Will it fall back?
View answer and explanation
Correct option: D
2s2 s, No
Option D (2s2 s, No) is correct because without gravity, the particle travels at a constant speed, covering twice the distance in the same time, and it will not fall back.
348 Medium
348 of 489
Analyzing +4 | -1
The angle between two vectors AA and BB is θ\theta. Vector RR is the resultant of the two vectors. If RR makes an θ2\frac{\theta}{2} with AA, then
View answer and explanation
Correct option: C
A=B\mathrm{A}=\mathrm{B}
Option C (A=B) is correct because when the resultant makes an angle θ2\frac{\theta}{2} with A, it implies that the magnitudes of A and B are equal.
349 Medium
349 of 489
Application +4 | -1
The trajectory of a projectile in a vertical plane is y=αx−βx2y = \alpha x - \beta {x^2}, where α\alpha and β\beta are constants xx and yy are respectively the horizontal and vertical distances of the projectile from the point of projection. The angle of projection θ\theta and the maximum height attained HH are respectively given by
View answer and explanation
Correct option: A
tan⁡−1α,  α24β{\tan ^{ - 1}}\alpha ,\,\,\frac{{{\alpha ^2}}}{{4\beta }}
Option A (tan⁡−1α, α24β{\tan ^{ - 1}}\alpha ,\,\frac{{{\alpha ^2}}}{{4\beta }}) is correct because it matches the angle of projection and maximum height derived from the trajectory equation.
350 Medium
350 of 489
Application +4 | -1
The position of particle is given by r⃗=2t2i^+3tj^+4k^\vec{r}=2 t^2 \hat{i}+3 t \hat{j}+4 \hat{k} where tt is in second and the coefficients have proper units for r⃗\vec{r} to be in metre. The a⃗(t)\vec{a}(t) of the particle at t=1 sect=1 \mathrm{~sec} is:
View answer and explanation
Correct option: C
4 ms−24 \mathrm{~ms}^{-2} along xx-direction
Option C (4 ms−24 \mathrm{~ms}^{-2} along xx-direction) is correct because it is the second derivative of the position vector with respect to time.
351 Easy
351 of 489
Application +4 | -1
A boat which has a speed of 5 km/hr in still water crosses a river of width 1 km along the shortest possible path in 15 minutes. The velocity of the river water (in km/hr) is
View answer and explanation
Correct option: B
3
Option B (3) is correct because the velocity of the river water is calculated using the shortest path condition and the given boat speed and time.
352 Medium
352 of 489
Understanding +4 | -1
Select the incorrect statement(s) from the following.
I. In projectile motion, the range depends on the mass. It is greater for heavier object
II. In projectile motion, the range is independent of the angle of projection.
View answer and explanation
Correct option: C
I and II
Option C (I and II) is correct because in projectile motion, the range is independent of mass and depends on the angle of projection, not independent of it.
353 Medium
353 of 489
Application +4 | -1
A person can throw a ball upto a maximum range of 100 m. How high above the ground he can throw the same ball?
View answer and explanation
Correct option: B
50 m
Option B (50 m) is correct because the maximum height is half the maximum range when the initial velocity is the same.
354 Medium
354 of 489
Understanding +4 | -1
Statement-I: Two particles of different mass, projected with same velocity at same angles. The maximum height attained by both the particle will be same.
Statement-II: The maximum height of projectile is independent of particle mass.
View answer and explanation
Correct option: A
Both statements are true
Option A (Both statements are true) is correct because the maximum height of a projectile depends on initial velocity and launch angle, but not on mass.
355 Medium
355 of 489
Application +4 | -1
If A=i^+2k^{A}=\hat{{i}}+2 \hat{{k}} and B=j^−k^{B}=\hat{{j}}-\hat{{k}}, then, A×B{A} \times {B} is equal to
View answer and explanation
Correct option: B
−2i^+j^+k^-2 \hat{{i}}+\hat{{j}}+\hat{{k}}
Option B (−2i^+j^+k^-2 \hat{{i}}+\hat{{j}}+\hat{{k}}) is correct because it is the result of the cross product of the two given vectors, calculated using the determinant method.
356 Medium
356 of 489
Understanding +4 | -1
Statement-I: The value of i^(j^×k^)+j^(k^×i^)+k^⋅(i^×j^)\hat{\mathrm{i}}(\hat{\mathrm{j}} \times \hat{\mathrm{k}})+\hat{\mathrm{j}}(\hat{\mathrm{k}} \times \hat{\mathrm{i}})+\hat{\mathrm{k}} \cdot(\hat{\mathrm{i}} \times \hat{\mathrm{j}}) is equal to 3
Statement-II: If a^,b^,c^\hat{a}, \hat{b}, \hat{c} are mutually perpendicular unit vectors, then [a^,b^,c^]=1[\hat{a}, \hat{b}, \hat{c}]=1
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A is correct because both statements are true: the scalar triple product of mutually perpendicular unit vectors is 1, and the given expression simplifies to 3.
357 Medium
357 of 489
Understanding +4 | -1
Assertion: A physical quantity can be a vector, if magnitude as well as direction is associated with it.
Reason: A physical quantity can be a scalar quantity, if it is associated with magnitude only.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because the assertion is incomplete (direction is not sufficient for a vector) and the reason is correct (magnitude is sufficient for a scalar).
358 Medium
358 of 489
Understanding +4 | -1
Assertion: Two vectors A⃗\vec{A} and B⃗\vec{B} are said to be equal if they have the same magnitude and direction.
Reason: Addition and subtraction of scalars is possible only for quantities having same units.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of assertion
Option C is correct because the assertion is true (vectors are equal if they have the same magnitude and direction), but the reason is false (addition and subtraction of scalars is possible only for quantities having the same units).
359 Medium
359 of 489
Application +4 | -1
The angle between the two vectors −2i^+3j^−k^- 2\hat i + 3\hat j - \hat k and i^+2j^+4k^\hat i + 2\hat j + 4\hat k is
View answer and explanation
Correct option: B
90∘{90^ \circ }
Option B (90∘{90^ \circ }) is correct because the dot product of the two vectors is zero, indicating they are perpendicular.
360 Medium
360 of 489
Analyzing +4 | -1
If A⋅B=0{A} \cdot {B}=0 and A×B=1{A} \times {B}=1, then A{A} and B{B} are
View answer and explanation
Correct option: A
Perpendicular unit vectors
Option A (Perpendicular unit vectors) is correct because the dot product being zero implies perpendicularity, and the magnitude of the cross product being 1 implies that both vectors are unit vectors.
Revision notes and key takeaways

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