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JEE • PHYSICS • MOTION IN PLANE

Motion in plane practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 301-330 of 489 questions

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301 Hard
301 of 489
Analyzing +4 | -1
If a=3i^−j^+5k^\mathbf{a}=3 \hat{\mathbf{i}}-\hat{\mathbf{j}}+5 \hat{\mathbf{k}} and b=i^+2j^−3k^\mathbf{b}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-3 \hat{\mathbf{k}} are given vector. A vector c\mathbf{c} which is perpendicular to ZZ-axis satisfying c⋅a=9\mathbf{c} \cdot \mathbf{a}=9 and c⋅b=−4\mathbf{c} \cdot \mathbf{b}=-4. If inclination of c\mathbf{c} with XX-axis and γ\gamma-axis is α\alpha and β\beta respectively, then which of the following is not true?
View answer and explanation
Correct option: C
α>π2\alpha>\frac{\pi}{2}
Option C is correct because the calculated value of alpha (α\alpha) is less than π2\frac{{\pi}}{{2}}, making the statement α>π2\alpha > \frac{{\pi}}{{2}} false.
302 Easy
302 of 489
Understanding +4 | -1
A scalar quantity is one that
View answer and explanation
Correct option: D
has the same value for observers with different orientations of axes.
The correct answer is D (has the same value for observers with different orientations of axes) because a scalar quantity is defined by its magnitude and is independent of coordinate system orientation.
303 Medium
303 of 489
Understanding +4 | -1
Three bodies A, B and C projected with the same initial speed with angles of projections 30∘,45∘30^{\circ}, 45^{\circ} and 60∘60^{\circ} respectively. The body/bodies having maximum range
View answer and explanation
Correct option: B
B
Option B is correct because the maximum range in projectile motion is achieved at a projection angle of 45 degrees.
304 Medium
304 of 489
Analyzing +4 | -1
Two balls are projected simultaneously in the same vertical plane from the same point with velocities V1V_1 and V2V_2 with angles θ1\theta_1 and θ2\theta_2 respectively with the horizontal. If V1cos⁡θ1=V_1 \cos \theta_1= V2cos⁡θ2V_2 \cos \theta_2, the path of one ball as seen from the position of other ball is:
View answer and explanation
Correct option: C
Vertical straight line
Option C (Vertical straight line) is correct because the horizontal components of velocities are equal, resulting in zero relative horizontal velocity, and thus a vertical path.
305 Easy
305 of 489
Analyzing +4 | -1
Assertion(A): When θ=45∘\theta=45^{\circ} or 135∘135^{\circ}, the value of RR remains the same, only the sign changes.

Reason(R): R=u2sin⁡2θgR=\frac{u^2 \sin 2 \theta}{g}
View answer and explanation
Correct option: A
Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
Option A (Both Assertion and Reason are correct and Reason is the correct explanation of Assertion) is correct because the range is the same for complementary angles, and the reason correctly states the formula for the range.
306 Medium
306 of 489
Understanding +4 | -1
The number of components in which a vector can be resolved into is
View answer and explanation
Correct option: D
Infinite
Option D is correct because a vector can be resolved into an infinite number of components, as the choice of coordinate system is arbitrary.
307 Medium
307 of 489
Understanding +4 | -1
Assertion: Time of flight of a projectile is equal to twice the time taken to attain the maximum height.

Reason: At the highest point of the trajectory, the projectile comes to rest and then begins to fall vertically downward under the effect of gravity.
View answer and explanation
Correct option: C
If assertion is true, but reason is false.
Option C (If assertion is true, but reason is false) is correct because the time of flight is twice the time to reach maximum height, but the projectile doesn't come to rest at the highest point.
308 Hard
308 of 489
Application +4 | -1
A man can swim with a speed of 4  kmh−14\,\,km{h^{ - 1}} in still water. He crosses a river 1 km wider that flows steadily at 3  kmh−13\,\,km{h^{ - 1}} If he makes his strokes normal to the river current how far down the river does he go when he reaches the other bank?
View answer and explanation
Correct option: C
750 m
Option A (0.577) is correct because it is the ratio of the efficiencies of the Carnot engine under the two given temperature conditions, calculated using the Carnot efficiency formula.
309 Hard
309 of 489
Analyzing +4 | -1
If OABCO A B C is a tetrahedron such that OA2+BC2\mathrm{OA}^2+\mathrm{BC}^2 =OB2+CA2=OC2+AB2=\mathrm{OB}^2+\mathrm{CA}^2=\mathrm{OC}^2+\mathrm{AB}^2, then which of the following is not true?
View answer and explanation
Correct option: D
AB⊥ACA B \perp A C
Option D (AB⊥ACA B \perp A C) is correct because the given condition implies that OA⊥BCO A \perp B C, OB⊥ACO B \perp A C, and OC⊥ABO C \perp A B, but it does not necessarily imply that AB⊥ACA B \perp A C.
310 Medium
310 of 489
Analyzing +4 | -1
What should be the angle between ΔA⃗\Delta \vec{A} and A⃗\vec{A} so that ∣ΔA⃗∣=Δ∣A⃗∣|\Delta \vec{A}|=\Delta|\vec{A}| ?
View answer and explanation
Correct option: A
0∘0^{\circ}
Option A (0∘0^{\circ}) is correct because for the magnitude of the change in a vector to equal the change in its magnitude, the vector must only change in magnitude, not direction, implying the angle between them is 0.
311 Hard
311 of 489
Analyzing +4 | -1
If a,b,c\mathbf{a}, \mathbf{b}, \mathbf{c} be non-zero vectors such that a\mathbf{a} is perpendicular to b\mathbf{b} and c\mathbf{c} and ∣a∣=1,∣b∣=2,∣c∣=1,b⋅c=1|\mathbf{a}|=1,|\mathbf{b}|=2,|\mathbf{c}|=1, \mathbf{b} \cdot \mathbf{c}=1 and there is a non-zero vector d\mathrm{d} coplanar with a+b\mathbf{a}+\mathbf{b} and 2b−c2 \mathbf{b}-\mathbf{c} and d⋅a=1\mathbf{d} \cdot \mathbf{a}=1, then minimum value of ∣d∣|\mathbf{d}| is
View answer and explanation
Correct option: D
413\frac{4}{\sqrt{13}}
Option D (413\frac{4}{\sqrt{13}}) is correct because it represents the minimum magnitude of vector d\mathbf{d} calculated using vector algebra and minimization techniques.
312 Medium
312 of 489
Application +4 | -1
Two forces F⃗1=500 N\vec{F}_1=500 \mathrm{~N} due east and F⃗2=250 N\vec{F}_2=250 \mathrm{~N} due north have their common initial point. F⃗2−F⃗1\vec{F}_2-\vec{F}_1 is
View answer and explanation
Correct option: A
2505 N,tan⁡−1(2)W250 \sqrt{5} \mathrm{~N}, \tan ^{-1}(2) \mathrm{W} of N\mathrm{N}
Option A (2505 N,tan⁡−1(2)W250 \sqrt{5} \mathrm{~N}, \tan ^{-1}(2) \mathrm{W} of N\mathrm{N}) is correct because it accurately calculates the magnitude and direction of the resultant vector F⃗2−F⃗1\vec{F}_2 - \vec{F}_1.
313 Medium
313 of 489
Understanding +4 | -1
Statement-I: In Δabc,ab→+bc→+ca→=0\Delta \mathrm{abc}, \overrightarrow{\mathrm{ab}}+\overrightarrow{\mathrm{bc}}+\overrightarrow{\mathrm{ca}}=0
Statements-II: If oa→=a→,ob→=b→\overrightarrow{\mathrm{oa}}=\overrightarrow{\mathrm{a}}, \overrightarrow{\mathrm{ob}}=\overrightarrow{\mathrm{b}}, then ab→=a→+b→\overrightarrow{\mathrm{ab}}=\overrightarrow{\mathrm{a}}+\overrightarrow{\mathrm{b}} (triangle law of addition)
View answer and explanation
Correct option: B
Statement-I is true and statement-II is false
Option B (Statement-I is true and statement-II is false) is correct because the vector addition in a triangle results in zero, and the triangle law of addition is stated incorrectly.
314 Medium
314 of 489
Understanding +4 | -1
In the projectile motion, if air resistance is ignored, the horizontal motion is at
View answer and explanation
Correct option: B
constant velocity
Option B is correct because in projectile motion without air resistance, there is no horizontal acceleration, resulting in constant horizontal velocity.
315 Medium
315 of 489
Application +4 | -1
If a→=3i^+j^−4k^\overrightarrow a = 3\hat i + \hat j - 4\hat k and b→=6i^+5j^−2k^,\overrightarrow b = 6\hat i + 5\hat j - 2\hat k, then ∣a→×b→∣\left| {\overrightarrow a \times \overrightarrow b } \right| is
View answer and explanation
Correct option: B
27
Option B (27) is correct because it's the magnitude of the cross product of the two vectors.
316 Medium
316 of 489
Understanding +4 | -1
For any two vectors A⃗\vec{A} and B⃗\vec{B}, then (A⃗×B⃗)2=(\vec{A} \times \vec{B})^2=
View answer and explanation
Correct option: A
A2B2−(A⃗⋅B⃗)2A^2 B^2-(\vec{A} \cdot \vec{B})^2
Option A (A2B2−(A⃗⋅B⃗)2A^2 B^2-(\vec{A} \cdot \vec{B})^2) is correct because it is the result of expanding (A⃗×B⃗)2(\vec{A} \times \vec{B})^2 using trigonometric identities.
317 Medium
317 of 489
Application +4 | -1
The linear velocity of a rotating body is given by v⃗=ω⃗×r⃗\vec v = \vec \omega \times \vec r If ω⃗=i^−2j^+2k^  and r⃗=4j^−3k^,\vec \omega = \hat i - 2\hat j + 2\hat k\,\,{\text{and }}\vec r = 4\hat j - 3\hat k, then the magnitude of v⃗\vec v is
View answer and explanation
Correct option: A
29\sqrt {29} units
Option A (29\sqrt {29} units) is correct because the magnitude of the cross product is calculated correctly.
318 Easy
318 of 489
Application +4 | -1
If a unit vector is represent by 0.5i^+0.8j^+ck^0.5 \hat{\mathbf{i}}+0.8 \hat{\mathbf{j}}+c \hat{\mathbf{k}}, then the value of cc is
View answer and explanation
Correct option: B
0.11\sqrt{0.11}
Option B (0.11\sqrt{0.11}) is correct because the magnitude of a unit vector must be 1, and this value of c satisfies that condition.
319 Medium
319 of 489
Understanding +4 | -1
Which of the following is true regarding projectile motion?
View answer and explanation
Correct option: A
Horizontal velocity of projectile is constant
Option A is correct because in projectile motion, the horizontal velocity remains constant as there is no horizontal acceleration.
320 Medium
320 of 489
Application +4 | -1
If P⃗=2i^−3j^+k^ and Q⃗=3i^−2j^, then P⃗.Q⃗\mathrm{\vec P} = 2\hat i - 3\hat j + \hat k\,and\,\mathrm{\vec Q} = 3\hat i - 2\hat j,\,then\,\mathrm{\vec P}\mathrm{.\vec Q} is
View answer and explanation
Correct option: C
12
Option C (12) is correct because the dot product of the two vectors is calculated to be 12.
321 Hard
321 of 489
Analyzing +4 | -1
A steam boat goes across a lake and comes back (1) On a quite day when the water is still and (2) On a rough day when there is uniform air current so as to help the journey onward and to impede the journey back. If the speed of the launch on both days was same, in which case it will complete the journey in lesser time
View answer and explanation
Correct option: A
Case (1)
The correct answer is A because the boat will take less time on a quiet day compared to a day with a uniform air current.
322 Medium
322 of 489
Understanding +4 | -1
Given, P=A+B{P}={A}+{B} and P=A+BP=A+B. The angle between A{A} and B{B} is
View answer and explanation
Correct option: A
0∘0^{\circ}
Option A (0∘0^{\circ}) is correct because the magnitude of the resultant vector is the sum of the magnitudes of the individual vectors, implying they are in the same direction.
323 Medium
323 of 489
Understanding +4 | -1
Select the correct statements about the football thrown in a parabolic path.
I. At the highest point the vertical component of velocity is zero
II. At the highest point, the velocity of the football, acts horizontally
III. At the highest point, the acceleration of the ball acts vertically downwards
View answer and explanation
Correct option: D
I, II and III
Option D (I, II and III) is correct because all three statements accurately describe the motion of a projectile (football) in a parabolic path.
324 Medium
324 of 489
Application +4 | -1
The diagonals of a parallelogram are given by the vectors 3i^+j^+2k^3 \hat{i}+\hat{j}+2 \hat{k} and i^−3j^+4k^\hat{i}-3 \hat{j}+4 \hat{k}. Find the area of the parallelogram.
View answer and explanation
Correct option: A
8.66 sq. units. 8.66 \text { sq. units. }
Option A (8.66 sq. units. 8.66 \text { sq. units. }) is correct because it is the area of the parallelogram calculated using the cross product of its diagonals.
325 Hard
325 of 489
Analyzing +4 | -1
If AA is 3×33 \times 3 matrix and u\mathbf{u} is a vector. If AuA \mathbf{u} and u\mathbf{u} are orthogonal for all real u\mathbf{u}, then matrix AA is aa
View answer and explanation
Correct option: A
singular
Option A (singular) is correct because if AuA \mathbf{u} and u\mathbf{u} are orthogonal for all u\mathbf{u}, then the determinant of A must be zero, implying A is singular.
326 Medium
326 of 489
Application +4 | -1
A particle is projected with an initial velocity v⃗=(2i^+4j^)m/s\vec{v}=(2 \hat{i}+4 \hat{j}) \mathrm{m} / \mathrm{s}. The equation of trajectory of the particle will be (g=10 m/s2)\left(g=10 \mathrm{~m} / \mathrm{s}^2\right) (Assume horizontal direction as xx-axis and vertically upward as positive y-axis)
View answer and explanation
Correct option: A
y=2x−5x24y=2 x-\frac{5 x^2}{4}
Option A (y=2x−5x24y=2 x-\frac{5 x^2}{4}) is correct because the equation of the trajectory is derived by eliminating time from the x and y components of motion.
327 Medium
327 of 489
Application +4 | -1
If the magnitudes of two vectors are 3 and 4 and their scalar product is 6, then find the angle between the two vectors.
View answer and explanation
Correct option: A
60∘60^{\circ}
Option A (60∘60^{\circ}) is correct because it correctly uses the dot product formula to find the angle between the two vectors.
328 Medium
328 of 489
Analyzing +4 | -1
Assertion: A projectile is thrown with an initial velocity of (ai^+bj^)m/s(a \hat{i}+b \hat{j}) \mathrm{m} / \mathrm{s}. If range of projectile is maximum then a=b{a}={b}.
Reason: In projectile motion, angle of projection is equal to 45∘45^{\circ} for maximum range condition.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because the range is maximum when the angle of projection is 45 degrees, which implies a=b, and the reason correctly explains the assertion.
329 Easy
329 of 489
Analyzing +4 | -1
Assertion If a particle is projected vertically upwards with velocity uu, the maximum height attained by the particle is h1h_1. The same particle is projected at angle 30∘30^{\circ} from horizontal with the same speed uu. Now the maximum height is h2h_2. Thus, h1=4h2h_1=4 h_2.

Reason In first case, v=0v=0 at highest point and in second case, v≠0v \neq 0 at highest point.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
Option B (If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion) is correct because both the assertion about the heights and the reason about velocities at the highest point are true, but the reason doesn't explain the assertion.
330 Easy
330 of 489
Application +4 | -1
The angle θ\theta between the vector p=i^+j^+k^\mathbf{p}=\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}} and unit vector along XX-axis is
View answer and explanation
Correct option: A
cos⁡−1(13)\cos ^{-1}\left(\frac{1}{\sqrt{3}}\right)
Option A (cos⁡−1(13)\cos ^{-1}(\frac{1}{\sqrt{3}})) is correct because the angle between the vector and the X-axis is found using the dot product formula.
Revision notes and key takeaways

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