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JEE • PHYSICS • MECHANICAL PROPERTIES OF SOLIDS

Mechanical properties of solids practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 251 questions

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31 Medium
31 of 251
Remembering +4 | -1
Dimensions of stress are
View answer and explanation
Correct option: D
[ M L−1 T−2 ]\mathrm{[}\,\mathrm{M}\,{\mathrm{L}^{ - 1}}\,{\mathrm{T}^{ - 2}}\,]
Option D ([ M L−1 T−2 ]\mathrm{[}\,\mathrm{M}\,{\mathrm{L}^{ - 1}}\,{\mathrm{T}^{ - 2}}\,\mathrm{]}) is correct because stress is force per unit area, and its dimensions are derived accordingly.
32 Medium
32 of 251
Analyzing +4 | -1
Statement I: A steel wire of natural length 'ℓ\ell' breaks, when clongated by length 'xx'. If original length is halved and elongated by x/2x / 2 it breaks.
Statement II: Breaking force is directly proportional to the length of the wire.
View answer and explanation
Correct option: B
Statement I is true and statement II is false
Option D (Statement I is true and statement II is false) is correct because breaking force depends on the area of cross-section, not the length of the wire.
33 Medium
33 of 251
Application +4 | -1
A uniform wire, fixed at its upper end, hangs vertically and supports a weight at its lower end. If its radius is rr, its length LL and the Young’s modulus for the material of the wire is EE, the extension is
1. directly proportional to EE

2. inversely proportional to rr

3. directly proportional to LL
View answer and explanation
Correct option: A
If only 33 is correct
Option A (If only 33 is correct) is correct because the extension is directly proportional to the length of the wire, as shown by the formula.
34 Medium
34 of 251
Understanding +4 | -1
Assertion: Steel is more elastic than rubber.
Reason: Under given deforming force, steel is deformed less than rubber.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because steel's higher elasticity means it deforms less under the same force, making both the assertion and reason true and linked.
35 Medium
35 of 251
Understanding +4 | -1
Assertion: Rise in temperature of a material causes decrease in the elasticity of the material.
Reason: The presence of impurities always increases the elasticity of the material.
View answer and explanation
Correct option: D
If both assertion and reason are false
Option D is correct because both the assertion and the reason are false. Temperature increase usually decreases elasticity, but not always, and impurities can increase or decrease elasticity.
36 Medium
36 of 251
Application +4 | -1
A stress of 3.18  ×108Nm−23.18\,\, \times {10^8}N{m^{ - 2}} is applied to a steel rod of length 1  m1\,\,m along its length. Its Young’s modulus is 2  ×  1011Nm−22\,\, \times \,\,{10^{11}}N{m^{ - 2}}. Then the elongation produced in the rod in mmmm is
View answer and explanation
Correct option: D
1.59
Option D (1.59) is correct because it is the elongation calculated using Young's modulus formula with the given stress and length.
37 Medium
37 of 251
Application +4 | -1
An elevator cable is to have a maximum stress of 7×107Nm−27 \times 10^7 \mathrm{Nm}^{-2} to allow for appropriate safety factors. Its maximum upward acceleration is 1.5 ms−21.5 \mathrm{~ms}^{-2}. If the cable has to support the total weight of 2000 kg2000 \mathrm{~kg} of a loaded elevator, the area of cross-section of the cable should be
View answer and explanation
Correct option: A
3.23 cm23.23 \mathrm{~cm}^2
Option A (3.23 cm²) is correct because it is the minimum area required to support the load with the given maximum stress and acceleration.
38 Medium
38 of 251
Understanding +4 | -1
If the load is increased beyond the _____ point, the strain increases rapidly for even a small change in the stress.
View answer and explanation
Correct option: B
Yield point
Option B (Yield point) is correct because beyond the yield point, a small change in stress leads to a large increase in strain.
39 Medium
39 of 251
Understanding +4 | -1
A: Lateral strain is directly proportional to the longitudinal strain within the elastic limit.
R: Poisson's ratio for a given material at a constant temperature is constant.
View answer and explanation
Correct option: A
If both A &\& R are true and the R is the correct explanation of the A
Option A (If both A &R\& R are true and the R is the correct explanation of the A) is correct because Poisson's ratio defines the relationship between lateral and longitudinal strain, making the reason a correct explanation for the assertion.
40 Medium
40 of 251
Understanding +4 | -1
In a wire stretched by hanging a weight from its end, the elastic potential energy per unit volume in terms of longitudinal strain σ\sigma and modulus of elasticity YY is
View answer and explanation
Correct option: A
Yσ22\frac{{Y{\sigma ^2}}}{2}
Option A (Yσ22\frac{{Y{\sigma ^2}}}{2}) is correct because the elastic potential energy per unit volume is given by half the product of stress and strain, which simplifies to the given expression.
41 Medium
41 of 251
Remembering +4 | -1
Which of the following relation is true?
View answer and explanation
Correct option: D
(1+σ)2η=Y\left( {1 + \sigma } \right)2\eta = Y
Option D ((1 + σ)2η = Y) is correct because it represents the correct relationship between Young's modulus (Y), shear modulus (η), and Poisson's ratio (σ).
42 Medium
42 of 251
Application +4 | -1
A solid sphere of radius 10 cm10 \mathrm{~cm} is subjected to a uniform pressure =5×108 Nm−2=5 \times 10^8 \mathrm{~Nm}^{-2}. Determine the consequent change in volume. Bulk modulus of the material of the sphere is equal to 3.14×1011 Nm−23.14 \times 10^{11} \mathrm{~Nm}^{-2}.
View answer and explanation
Correct option: A
6.67×10−6 m36.67 \times 10^{-6} \mathrm{~m}^3
Option A (6.67×10−6 m36.67 \times 10^{-6} \mathrm{~m}^3) is correct because it is the change in volume calculated using the bulk modulus formula.
43 Medium
43 of 251
Remembering +4 | -1
In which year Robert Hooke presented his law of elasticity?
View answer and explanation
Correct option: C
1676
Option C (1676) is correct because Robert Hooke presented his law of elasticity in 1676.
44 Medium
44 of 251
Understanding +4 | -1
Shape is related to:
View answer and explanation
Correct option: A
Shear stress
Option A is correct because shear stress is the force acting tangentially on a surface, causing deformation in shape.
45 Medium
45 of 251
Understanding +4 | -1
Assertion: Rigid body can be elastic.
Reason: If a force is applied on the rigid body, its dimension may change.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because a rigid body, by definition, cannot be elastic, and its dimensions do not change under the application of force.
46 Medium
46 of 251
Application +4 | -1
The elastic limit of brass is 379MPa379MPa. What should be the minimum diameter of a brass rod, if it is to support a 400N400N load without exceeding its elastic limit
View answer and explanation
Correct option: C
1.16  mm1.16\,\,mm
Option C (1.16 mm) is correct because it calculates the minimum diameter required to support the load without exceeding the elastic limit.
47 Medium
47 of 251
Understanding +4 | -1
Statement-I: Young's modulus, bulk modulus and shear modulus have the units of pressure.
Statement-II: The value of Young's modulus depends area of body.
View answer and explanation
Correct option: B
Statement I is true and statement II is false
Option B is correct because Young's modulus, bulk modulus, and shear modulus all have units of pressure, but Young's modulus is a material property and does not depend on the area of the body.
48 Medium
48 of 251
Remembering +4 | -1
Within proportional limit, the slope of the stress stain curve yields,
View answer and explanation
Correct option: B
Modulus of elasticity
Option B (Modulus of elasticity) is correct because the slope of the stress-strain curve within the proportional limit defines the modulus of elasticity.
49 Medium
49 of 251
Understanding +4 | -1
The Young’s modulus of a wire of length LL and radius rr is YN/m2Y\mathrm{ }N/{m^2}. If the length and radius are reduced to L/2L/2 and r/2r/2, then its Young’s modulus will be
View answer and explanation
Correct option: B
YY
Option B (YY) is correct because Young's modulus is a material property and is independent of the dimensions of the wire.
50 Medium
50 of 251
Remembering +4 | -1
Which of the following substances has the highest elasticity?
View answer and explanation
Correct option: B
Steel
Option B (Steel) is correct because steel has the highest Young's modulus among the given materials, indicating greater resistance to deformation and thus higher elasticity.
51 Medium
51 of 251
Analyzing +4 | -1
Statement I: Two identical solid balls, one of ivory and the other of wet-clay are dropped from the same height on the floor. Both the balls will rise to same height after bouncing.
Statement II: Ivory and wet-clay have same elasticity.
View answer and explanation
Correct option: D
Statement I is false and statement II is false
Option D (Statement I is false and statement II is false) is correct because wet-clay is nearly inelastic and will not rebound to the same height, and ivory and wet-clay do not have the same elasticity.
52 Medium
52 of 251
Understanding +4 | -1
A stretched rubber has
View answer and explanation
Correct option: B
Increased potential energy
Option B (Increased potential energy) is correct because stretching a rubber band stores potential energy within it due to the elastic deformation.
53 Medium
53 of 251
Understanding +4 | -1
Statement I: Silver is a ductile material,
Statement II: For a ductile material yield point and breaking point are separated by larger distance than for brittle materials on the stress-strain curve.
View answer and explanation
Correct option: A
Statement I is true and statement II is true
Option A is correct because silver is indeed ductile, and ductile materials have a larger separation between their yield and breaking points on the stress-strain curve compared to brittle materials.
54 Medium
54 of 251
Understanding +4 | -1
Bulk modulus of a material, whose Poison's ratio equal to 0.5 is
View answer and explanation
Correct option: B
Infinity
Option B (Infinity) is correct because a Poisson's ratio of 0.5 indicates a perfectly incompressible material, which has an infinite bulk modulus.
55 Medium
55 of 251
Application +4 | -1
Copper of fixed volume ' V\mathrm{V}; is drawn into wire of length ' ll '. When this wire is subjected to a constant force ' F\mathrm{F} ', the extension produced in the wire is ' Δl\Delta l '. Which of the following graphs is a straight line?
View answer and explanation
Correct option: B
Δl\Delta l versus l2l^2
Option B (Δl\Delta l versus l2l^2) is correct because the extension produced in the wire is directly proportional to l2l^2, as derived from Young's modulus and the constant volume condition.
56 Medium
56 of 251
Understanding +4 | -1
A: Spring balances show wrong readings after they have been used for a long time.
R: Spring in spring balance temporary losses elasticity due to repeated alternating deforming force.
View answer and explanation
Correct option: A
If both A &\& R are true and the R is the correct explanation of the A
Option A (If both A & R are true and the R is the correct explanation of the A) is correct because spring balances can show wrong readings after prolonged use due to the spring losing its elasticity, which is accurately described by the reason.
57 Medium
57 of 251
Application +4 | -1
Two bars AA and BB of circular cross-section and of same volume and made of the same material are subjected to tension. If the diameter of AA is half that of BB and if the force applied to both the rods is the same and it is in the elastic limit, the ratio of extension of AA to that of BB will be
View answer and explanation
Correct option: A
16
Option A (16) is correct because the extension is inversely proportional to the fourth power of the diameter, given the same volume and material.
58 Medium
58 of 251
Understanding +4 | -1
If the length of a wire is reduced to half, then it can hold the Load
View answer and explanation
Correct option: B
Same
Option B is correct because the breaking load a wire can hold depends on its cross-sectional area, not its length.
59 Medium
59 of 251
Analyzing +4 | -1
A: Bulk modulus for a perfectly plastic body is zero.
R: For perfect plastic material, there is no restoring force.
View answer and explanation
Correct option: A
If both A &\& R are true and the R is the correct explanation of the A
Option A is correct. A perfectly plastic body does not have restoring forces, which is why its bulk modulus is zero.
60 Medium
60 of 251
Remembering +4 | -1
The expression of force constant for a spring following Hooke's law is given by:
View answer and explanation
Correct option: A
k=YAlk=\frac{Y A}{l}
Option A (k=YAlk=\frac{Y A}{l}) is correct because it represents the force constant derived from Young's modulus and Hooke's law.
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