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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF SOLIDS

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Application +4 | -1
Forces of 100 N each are applied in opposite directions on the upper and lower faces of a cube of side 20 cm20\,cm. The upper face is shifted parallel to itself by 0.25 cm0.25\,cm. If the side of the cube were 10 cm, then the displacement would be
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Correct option: B
0.5 cm0.5\,cm
Option B (0.5 cm0.5\,cm) is correct because the displacement is inversely proportional to the side of the cube, so halving the side doubles the displacement.

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