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JEE • PHYSICS • MECHANICAL PROPERTIES OF FLUIDS

Mechanical properties of fluids practice · Medium

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Showing 271-300 of 390 questions

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271 Medium
271 of 390
Application +4 | -1
The terminal speed of a sphere of gold (density=19.5kgm−3)\left( {\mathrm{density} = 19.5\mathrm{kg}{\mathrm{m}^{ - 3}}} \right) is 0.2ms−10.2\mathrm{m}{\mathrm{s}^{ - 1}} in a viscous liquid (density=1.5kgm−3)\left( {\mathrm{density} = 1.5\mathrm{kg}{\mathrm{m}^{ - 3}}} \right). Then the terminal speed of a sphere of silver (density=10.5kgm−3)\left( {\mathrm{density} = 10.5\mathrm{kg}{\mathrm{m}^{ - 3}}} \right) of the same size in the same liquid is
View answer and explanation
Correct option: A
0.1ms−10.1\mathrm{m}{\mathrm{s}^{ - 1}}
Option A (0.1ms−10.1\mathrm{m}{\mathrm{s}^{ - 1}}) is correct because the terminal velocity is proportional to the difference in densities between the sphere and the liquid.
272 Medium
272 of 390
Application +4 | -1
A large tank is filled with water to a height HH. A small hole is made at the base of the tank. It takes T1{T_1} time to decrease the height of water to Hη(η>1):\frac{H}{\eta }\left( {\eta > 1} \right): and it takes T2{T_2} time to take out the rest of water. If T1=T2{T_1} = {T_2}, then the value of η\eta is
View answer and explanation
Correct option: C
4
Option C (4) is correct because the time to drain the tank is proportional to the square root of the height. Setting the times equal and solving for η yields η = 4.
273 Medium
273 of 390
Application +4 | -1
10 min10 \mathrm{~min} are taken to empty a rectangular vessel of height hh through an orifice in its bottom. How much time will it take to be emptied the vessel when half filled?
View answer and explanation
Correct option: C
7 min7 \mathrm{~min}
Option C (7 min) is correct because the time taken to empty the vessel is proportional to the square root of the height.
274 Medium
274 of 390
Remembering +4 | -1
Dimensions of coefficient of viscosity are
View answer and explanation
Correct option: C
[ML−1 T−1]\left[\mathrm{ML}^{-1} \mathrm{~T}^{-1}\right]
Option C ([ML−1 T−1]\left[\mathrm{ML}^{-1} \mathrm{~T}^{-1}\right]) is correct because it represents the correct dimensional formula for the coefficient of viscosity.
275 Medium
275 of 390
Understanding +4 | -1
Why the blood pressure in humans is greater at the feet than at the brain:
View answer and explanation
Correct option: A
Liquid pressure increases downward
Option A (Liquid pressure increases downward) is correct because the pressure in a liquid increases with depth due to the weight of the liquid column above.
276 Medium
276 of 390
Application +4 | -1
An aeroplane of mass 3×104 kg3 \times 10^4 \mathrm{~kg} and total wing area 120 m2120 \mathrm{~m}^2 is in level flight at some height. The difference in pressure between upper and lower surfaces in kilopascal is (g=10 m/s2)\left(g=10 \mathrm{~m} / \mathrm{s}^2\right)
View answer and explanation
Correct option: A
2.52.5
Option A (2.5) is correct because the pressure difference is calculated using the weight of the airplane and the wing area.
277 Medium
277 of 390
Analyzing +4 | -1
Ice pieces are floating in beaker A containing water also in a beaker B containing miscible liquid of specific gravity 1.2. When ice melts, the level of
View answer and explanation
Correct option: D
liquid in B increases
Option D (liquid in B increases) is correct because the volume of liquid displaced by the ice is less than the volume occupied by the melted ice in the liquid, due to the liquid's higher density.
278 Medium
278 of 390
Understanding +4 | -1
Bernoulli’s principle is not involved in the working/explanation of
View answer and explanation
Correct option: C
Blades of a kitchen mixer
Option C (Blades of a kitchen mixer) is correct because the blades of a kitchen mixer rely on mechanical force and do not directly involve Bernoulli's principle.
279 Medium
279 of 390
Understanding +4 | -1
Water rises in plant fibres due to
View answer and explanation
Correct option: A
Capillarity
Option A (Capillarity) is correct because water rises in plant fibers due to capillary action, which is the ability of a liquid to flow in narrow spaces against the force of gravity.
280 Medium
280 of 390
Understanding +4 | -1
Assertion: A rain drop after falling through some height attains a constant velocity.
Reason: At constant velocity, the viscous drag is just equal to its weight.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because the constant velocity is achieved when the viscous drag balances the weight of the raindrop.
281 Medium
281 of 390
Understanding +4 | -1
A large ship can float but a steel needle sinks because of
View answer and explanation
Correct option: D
none of these.
Option D (none of these) is correct because the floating/sinking behavior is determined by the relationship between the object's density and the fluid's density, as described by Archimedes' principle.
282 Medium
282 of 390
Application +4 | -1
Typical silt(hard mud) particle of radius 20μm20\mathrm{\mu m} is on the top of lake water, its density is 2000kgm−32000\mathrm{kg}{\mathrm{m}^{ - 3}} and the viscosity of lake water is 1.0 mPa, density is 1000kgm−31000\mathrm{kg}{\mathrm{m}^{ - 3}}. If the lake is still(has no internal fluid motion). The terminal speed with which the particle hits the bottom of the lake is ………. mms−1\mathrm{mm}{\mathrm{s}^{ - 1}}
View answer and explanation
Correct option: C
0.87
Option C (0.87) is correct because it is the terminal speed calculated using Stokes' Law, considering the density difference and viscosity.
283 Medium
283 of 390
Application +4 | -1
A piston of cross-sectional area 100 cm2100 \mathrm{~cm}^2 is used in a hydraulic pressure to exert a force of 10710^7 dyne on the water. The cross-sectional area of the other piston which supports an object having a mass of 2000 kg2000 \mathrm{~kg} is
View answer and explanation
Correct option: D
1.96×104 cm21.96 \times 10^4 \mathrm{~cm}^2
Option D (1.96×104 cm21.96 \times 10^4 \text{ cm}^2) is correct because it is the area required on the second piston to support the given mass, calculated using Pascal's law.
284 Medium
284 of 390
Understanding +4 | -1
Why the dam of water reservoir is thick at the bottom
View answer and explanation
Correct option: C
Pressure of water increases with depth
Option C (Pressure of water increases with depth) is correct because the pressure exerted by water increases linearly with depth, requiring a thicker dam at the bottom to withstand the force.
285 Medium
285 of 390
Application +4 | -1
Work WW is required to form a bubbles of volume VV from a given solution. What amount of work is required to be done to form a bubble of volume 2V2V ?
View answer and explanation
Correct option: D
41/3W{4^{1/3}}W
Option D (41/3W{4^{1/3}}W) is correct because the work done is proportional to the surface area, and the radius scales with the cube root of the volume.
286 Medium
286 of 390
Analyzing +4 | -1
Assertion: A solid sphere placed in the fluid under high pressure is compressed uniformly on all sides.
Reason: The volume of solid sphere will decrease with change of its geometrical shape.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C is correct because the assertion is true; a solid sphere under high pressure is compressed uniformly. However, the reason is false; the volume decreases without a change in geometrical shape.
287 Medium
287 of 390
Application +4 | -1
A cubical block is floating in a liquid with half of its volume immersed in the liquid. When the whole system accelerates upwards with acceleration of g/3g / 3, the fraction of volume immersed in the liquid will be
View answer and explanation
Correct option: A
1/21 / 2
Option A (1/21 / 2) is correct because the fraction of the volume immersed depends only on the densities of the block and liquid, which remain constant despite the acceleration.
288 Medium
288 of 390
Application +4 | -1
The surface tension of soap solution is 0.03Nm−10.03\mathrm{N}{\mathrm{m}^{ - 1}}. the work done in blowing to from a soap bubble of surface area 40cm2,(inJ),is40\mathrm{c}{\mathrm{m}^2},\left( {\mathrm{in J}} \right),\mathrm{is}
View answer and explanation
Correct option: B
2.4×10−42.4 \times {10^{ - 4}}
Option B (2.4×10−42.4 \times {10^{ - 4}}) is correct because the work done in forming a soap bubble is calculated using the formula W=T×2×ΔAW = T \times 2 \times \Delta A.
289 Medium
289 of 390
Remembering +4 | -1
With the increase in temperature viscosity of a liquid -
View answer and explanation
Correct option: B
Decreases
Option B (Decreases) is correct because as temperature increases, the kinetic energy of the liquid molecules increases, reducing the intermolecular forces and thus decreasing viscosity.
290 Medium
290 of 390
Understanding +4 | -1
Assertion:- Under steady flow the velocity of the particle of fluid is not constant at a point.
Reason:- Ideal fluids are compressible.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because under steady flow, the velocity of a fluid particle at a point is constant, and ideal fluids are incompressible.
291 Medium
291 of 390
Understanding +4 | -1
If a glass rod is dipped in pure mercury and removed, then mercury does not stick to the rod. This is because
View answer and explanation
Correct option: B
Cohesive force is greater than the adhesive force
Option B (Cohesive force is greater than the adhesive force) is correct because mercury does not wet glass due to stronger cohesive forces within the mercury compared to adhesive forces between mercury and glass.
292 Medium
292 of 390
Analyzing +4 | -1
A cork is submerged in water by a spring attached to the bottom of a bowl. When the bowl is kept in an elevator moving with acceleration downwards, the length of spring
View answer and explanation
Correct option: B
decreases
Option B (decreases) is correct because the effective weight decreases in a downward accelerating elevator, reducing the buoyant force and thus the spring's extension.
293 Medium
293 of 390
Application +4 | -1
Surface tension of a soap solution is able of 2.0 cm diameter will be
View answer and explanation
Correct option: B
15.2×10−6π15.2 \times {10^{ - 6}}\pi J
Option B (15.2×10−6π15.2 \times {10^{ - 6}}\pi J) is correct because the work done is calculated by multiplying the surface tension by the increase in area.
294 Medium
294 of 390
Analyzing +4 | -1
A man is sitting in a boat which is floating in a pond. If the man drink some water from the pond, what will happen to the level of water in the pond?
View answer and explanation
Correct option: C
Remains same
Option C (Remains same) is correct because the water displaced by the man+boat system is equal to the water removed, so the water level doesn't change.
295 Medium
295 of 390
Application +4 | -1
Two narrow bores of diameter 3.0 mm3.0 \mathrm{~mm} and 6.0 mm6.0 \mathrm{~mm} are joined together to form a U-tube open at both ends. If the U-tube contains water, what is the difference in its levels in the two limbs of the tube? Surface tension of water at the temperature of the experiment is 7.3×10−2 N/m7.3 \times 10^{-2} \mathrm{~N} / \mathrm{m}. Take the angle of contact to be zero and density of water to be 1.0×103 kg/m31.0 \times 10^3 \mathrm{~kg} / \mathrm{m}^3. (take, g=9.8 m/s2g=9.8 \mathrm{~m} / \mathrm{s}^2).
View answer and explanation
Correct option: C
5 mm5 \mathrm{~mm}
Option D (5 mm5 \mathrm{~mm}) is correct because the difference in water levels is calculated using the formula involving surface tension, radii of the bores, density of water, and gravity.
296 Medium
296 of 390
Application +4 | -1
Two drops of the same radius are falling through air with a steady velocity of 5cm5cm per sec. If the two drops coalesce, the terminal velocity would be
View answer and explanation
Correct option: C
5×(4)1/3cm5 \times {\left( 4 \right)^{1/3}}cm cm per sec
Option C (5×(4)1/3cm5 \times {\left( 4 \right)^{1/3}}cm cm per sec) is correct because the terminal velocity is proportional to the square of the radius.
297 Medium
297 of 390
Understanding +4 | -1
Terminal velocity of a small sized spherical body having radius rr falling vertically in a viscous medium having coefficient of viscosity η\eta depends on radius of body and coefficient of viscosity as
View answer and explanation
Correct option: D
Both (2) &\& (3)
Option D (Both (2) &(3))iscorrectbecauseterminalvelocityisproportionalto\& (3)) is correct because terminal velocity is proportional tor2andinverselyproportionaltoand inversely proportional toη$.
298 Medium
298 of 390
Application +4 | -1
A hydraulic lift is designed such that cross sectional area of its arms are 5 cm2 & 10 m25 \mathrm{~cm}^2 \, \& \, 10 \mathrm{~m}^2. Find the force applied by mechanic on smaller area in order to lift a car of 5000 kg?5000 \mathrm{~kg}?
View answer and explanation
Correct option: B
2.5 N2.5 \mathrm{~N}
The correct answer is B (2.5 N) because it is found by applying Pascal's principle to the hydraulic lift, relating the forces and areas.
299 Medium
299 of 390
Application +4 | -1
A denotes the area to the right on the cube hh the depth of an orifice of area of cross-sectionAA, below the liquid surface. The velocity of the liquid flowing through the orifice is
View answer and explanation
Correct option: B
2gh(A2A2−a2)\sqrt {2\mathrm{g}h} \sqrt {\left( {\frac{{{A^2}}}{{{A^2} - {a^2}}}} \right)}
Option B (2gh(A2A2−a2)\sqrt {2\mathrm{g}h} \sqrt {\left( {\frac{{{A^2}}}{{{A^2} - {a^2}}}} \right)}) is correct because it is derived from Bernoulli's theorem, accounting for the velocities at both the surface and the orifice.
300 Medium
300 of 390
Understanding +4 | -1
Aerofils are so designed that the speed of air
View answer and explanation
Correct option: A
On top side is more than on lower side
Option A is correct because aerofoils are designed to have a higher air speed on the top side compared to the lower side, creating a pressure difference that generates lift.
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