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JEE • PHYSICS • MAGNETIC EFFECT OF CURRENT

Magnetic effect of current practice · Medium

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Showing 211-240 of 385 questions

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211 Medium
211 of 385
Application +4 | -1
Two long straight conductors carry currents 3A3 A and 1A1 A into the plane of paper. A circular path is imagined to enclose these currents. The value of ∮B⃗⋅dl→\oint \vec{B} \cdot \overrightarrow{d l} is
View answer and explanation
Correct option: B
4μ04 \mu_0
Option B (4μ04 \mu_0) is correct because Ampere's law states that the line integral of the magnetic field around a closed loop is proportional to the enclosed current.
212 Medium
212 of 385
Application +4 | -1
A galvanometer with a coil resistance of 100  Ω100\,\,\Omega gives a full-scale deflection when a current of 1  mA1\,\,mA is passed through it. The resistance of the shunt needed in ohm to convert this galvanometer into an ammeter of range 10 A10\,A is nearly.
View answer and explanation
Correct option: A
0.01
Option D (0.099) is correct because it is calculated using the formula for shunt resistance in an ammeter.
213 Medium
213 of 385
Understanding +4 | -1
When a charged particle enters a uniform magnetic field
View answer and explanation
Correct option: C
Speed of particle will be constant
Option C (Speed of particle will be constant) is correct because the magnetic force is always perpendicular to the velocity, doing no work and thus not changing the speed.
214 Medium
214 of 385
Understanding +4 | -1
Armature current is maximum in a DC motor when the motor has
View answer and explanation
Correct option: B
just started
Option B (just started) is correct because at the moment the DC motor starts, the back EMF is zero, resulting in maximum armature current.
215 Medium
215 of 385
Application +4 | -1
A galvanometer of resistance 20  Ω\mathrm{20}\,\,\mathrm{\Omega } shows a deflection of 10\mathrm{10} divisions when a current of 1  mA\mathrm{1}\,\,\mathrm{mA} is passed through it. If a shunt of 4  Ω\mathrm{4}\,\,\mathrm{\Omega } is connected and there are 50\mathrm{50} divisions on the scale, the range of the galvanometer is
View answer and explanation
Correct option: D
30  mA\mathrm{30}\,\,\mathrm{mA}
Option D (30 mA\mathrm{30}\,\mathrm{mA}) is correct because it is the calculated range of the galvanometer after connecting the shunt resistance.
216 Medium
216 of 385
Understanding +4 | -1
A charged particle enters in a uniform
magnetic field with a certain velocity. The
power delivered to the particle by the magnetic
field depends on
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the magnetic force does no work on a charged particle, and therefore the power delivered by the magnetic field is zero.
217 Medium
217 of 385
Understanding +4 | -1
Assertion : In electric circuits, wires carrying
currents in opposite directions are often twisted
together.
Reason: If the wires are not twisted together, the
combination of the wires forms a current loop, the
magnetic field generated by the loop might affect
adjacent circuits or components
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and the
Reason is a correct explanation of the Assertion
Option A is correct because twisting wires carrying current in opposite directions minimizes the magnetic field they produce, preventing interference with nearby circuits.
218 Medium
218 of 385
Application +4 | -1
An alternating electric field, of frequency vv, is applied across the dees (radius =R=R) of a cyclotron that is being used to accelerate protons (mass = mm). The operating magnetic field (B)(B) used in the cyclotron and the kinetic energy (KK) of the proton beam, produced by it, are given by
View answer and explanation
Correct option: A
B=2πmveB=\frac{2 \pi m v}{e} and K=2mπ2v2R2K=2 m \pi^2 v^2 R^2
Option A (B=2πmveB=\frac{2 \pi m v}{e} and K=2mπ2v2R2K=2 m \pi^2 v^2 R^2) is correct because the magnetic field and kinetic energy are derived from the cyclotron frequency and radius equations.
219 Medium
219 of 385
Understanding +4 | -1
Maximum kinetic energy gained by the
charged particle in the cyclotron in
independent of
View answer and explanation
Correct option: D
frequency of revolution
Option D (frequency of revolution) is correct because the maximum kinetic energy in a cyclotron depends on the charge, magnetic field, and radius of the dees, but not directly on the frequency.
220 Medium
220 of 385
Understanding +4 | -1
The work done by an uniform magnetic field, on a moving charge is
View answer and explanation
Correct option: C
zero because F→\overrightarrow{\mathrm{F}} acts perpendicular to V→\overrightarrow{\mathrm{V}}
Option C (zero because F→\overrightarrow{\mathrm{F}} acts perpendicular to V→\overrightarrow{\mathrm{V}}) is correct because the magnetic force on a moving charge is always perpendicular to its velocity, meaning no work is done.
221 Medium
221 of 385
Analyzing +4 | -1
A straight long conductor carries current along the positive xx-axis. Identify the correct statement related to the four points A(a,a,0),B(a,0,a),C(a,−a,0)A(a, a, 0), B(a, 0, a), C(a,-a, 0) and D(a,0,−a)D(a, 0,-a).
View answer and explanation
Correct option: D
All of the above
Option D is correct because the magnetic field's magnitude is the same, fields at A and B are perpendicular, and fields at A and C are antiparallel due to the geometry around the current-carrying wire.
222 Medium
222 of 385
Understanding +4 | -1
When the number of turns of the coil is
doubled, the current sensitivity of a moving coil
galvanometer is doubled whereas the voltage
sensitivity of the galvanometer
View answer and explanation
Correct option: A
remains the same
Option A is correct because current sensitivity doubles with the number of turns, but voltage sensitivity remains the same as both N and R double, canceling each other out.
223 Medium
223 of 385
Application +4 | -1
A charged dust particle of radius 5×10−75 \times {10^{ - 7}}m is located in a horizontal electric field having an intensity of 6.28×105  Vm−16.28 \times {10^5}\;\mathrm{V}{\mathrm{m}^{ - 1}}. The surrounding medium in air with coefficient of viscosity η=1.6×10−15Nsm−2.\mathrm{\eta } = 1.6 \times {10^{ - 15}}\mathrm{Ns}{\mathrm{m}^{ - 2}}. If this particle moves with a uniform horizontal speed of 0.01 ms−1,\mathrm{m}{\mathrm{s}^{ - 1}}, the number of electrons on it will be
View answer and explanation
Correct option: B
15
Option B (15) is correct because the number of electrons is calculated by equating the electric force to the viscous force and solving for the number of electrons.
224 Medium
224 of 385
Understanding +4 | -1
A non-planar closed loop of arbitrary shape carrying a current II is placed in uniform magnetic field. The force acting on the loop
View answer and explanation
Correct option: C
is zero for all orientations
Option C (is zero for all orientations) is correct because the net force on any closed current loop in a uniform magnetic field is always zero.
225 Medium
225 of 385
Understanding +4 | -1
When a charged particle moves perpendicular
to a uniform magnetic field, there is a change in
its:
View answer and explanation
Correct option: A
momentum
Option A (momentum) is correct because the magnetic force changes the direction of the charged particle's velocity, thus changing its momentum, but not its speed or kinetic energy.
226 Medium
226 of 385
Understanding +4 | -1
Statement (A): The restoring couple in the moving coil galvanometer is due to the current in the coil

Statement(B): Wires of magnetic field around a current carrying straight conductor will be circular in a plane parallel to the conductor

Statement(C): When a charged particle enters a uniform magnetic field, its kinetic energy increases
View answer and explanation
Correct option: D
A, B, C are false
Option D is correct because all three statements (A, B, and C) are false based on the principles of moving coil galvanometers, magnetic fields, and charged particle motion in magnetic fields.
227 Medium
227 of 385
Remembering +4 | -1
The direction of the force on a current carrying
conductor held perpendicular to a uniform
magnetic field is given by
View answer and explanation
Correct option: D
Fleming's left hand rule
Option D (Fleming's left hand rule) is correct because it describes the direction of force on a current-carrying conductor in a magnetic field.
228 Medium
228 of 385
Understanding +4 | -1
A galvanometer can be converted into a voltmeter by connecting
View answer and explanation
Correct option: D
High residence in series
Option D is correct because a high resistance connected in series with a galvanometer limits the current flowing through it, allowing it to measure higher voltages without damage.
229 Medium
229 of 385
Understanding +4 | -1
Assertion: A linear solenoid carrying current is equivalent to a bar magnet.
Reason: The magnetic field lines due to current carrying solenoid resemble exactly with those of a bar magnet.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because a solenoid carrying current generates a magnetic field similar to a bar magnet, and the magnetic field lines are indeed similar.
230 Medium
230 of 385
Understanding +4 | -1
In a moving coil galvanometer, to make the
field radial
View answer and explanation
Correct option: B
magnetic poles are cylindrically cut
Option B (magnetic poles are cylindrically cut) is correct because cylindrical magnetic poles create a radial magnetic field in a moving coil galvanometer.
231 Medium
231 of 385
Application +4 | -1
A solenoid consists of 100 turns of wire and has a length of 10 cm. The magnetic field inside the solenoid when it carries a current of 0.500 A will be
View answer and explanation
Correct option: A
6.28×10−4T6.28 \times {10^{ - 4}}T
Option A (6.28×10−4T6.28 \times {10^{ - 4}}T) is correct because it is calculated using the formula for the magnetic field inside a solenoid.
232 Medium
232 of 385
Understanding +4 | -1
In moving coil galvanometer, strong horse shoe
magnet of concave shaped pole pieces is used to
View answer and explanation
Correct option: B
produce magnetic field which is parallel to plane of coil at any position
Option B (produce magnetic field which is parallel to plane of coil at any position) is correct because the concave shaped pole pieces create a radial magnetic field.
233 Medium
233 of 385
Understanding +4 | -1
The two parallel wires carry current in
opposite directions
View answer and explanation
Correct option: B
the wires repel each other
Option B (the wires repel each other) is correct because parallel wires carrying current in opposite directions experience a repulsive force.
234 Medium
234 of 385
Analyzing +4 | -1
If an electron of velocity (2i^+3j^)(2\hat{i} +3\hat{j}) is subjected to magnetic field of 4k^,4\hat{k} , then its

(a) path will change

(b) speed does not change

(c) path must be circular

(d) momentum is constant
View answer and explanation
Correct option: C
a, b, c
Option C (a, b, c) is correct because the electron's path changes, its speed remains constant, and the path is circular when velocity and magnetic field are perpendicular.
235 Medium
235 of 385
Understanding +4 | -1
A bar magnet is placed inside a uniform
magnetic field. What does it experience?
View answer and explanation
Correct option: B
A torque
Option B is correct. A bar magnet in a uniform magnetic field experiences a torque that tends to align it with the field, but no net force because the forces on the north and south poles are equal and opposite.
236 Medium
236 of 385
Application +4 | -1
A closely wound solenoid of length 1 m1 \mathrm{~m} has 5 layers of 500 turns each. If the magnitude of magnetic field inside the solenoid near its centre is 4.4mT4.4 \mathrm{mT}, the current carried is-
View answer and explanation
Correct option: A
1.4 A
Option A (1.4 A) is correct because it is the current calculated using the formula for the magnetic field inside a solenoid.
237 Medium
237 of 385
Application +4 | -1
Current i\mathrm{i} is carried in a wire of length L\mathrm{L}. If the wire is turned into a circular coil, the maximum magnitude of torque in a given magnetic field B\mathrm{B} will be:
View answer and explanation
Correct option: C
L2iB4π\frac{\mathrm{L}^2 \mathrm{iB}}{4 \pi}
Option C (L2iB4π\frac{\mathrm{L}^2 \mathrm{iB}}{4 \pi}) is correct because the maximum torque is proportional to the square of the length of the wire when formed into a circular coil.
238 Medium
238 of 385
Application +4 | -1
An electron is moving in a circle of radius rr in a uniform magnetic field B. Suddenly, the field is reduced to B2\frac{B}{2}. The radius of the circular path now becomes :
View answer and explanation
Correct option: B
2r2 \mathrm{r}
Option B (2r2 \mathrm{r}) is correct because when the magnetic field is halved, the radius of the circular path doubles, maintaining the balance of forces.
239 Medium
239 of 385
Understanding +4 | -1
Two solenoids are given- 1 st has 1 turn per unit length and 2nd has nn turns per unit length. Ratio of magnetic fields at their centers is
View answer and explanation
Correct option: B
1:n1: \mathrm{n}
Option B is correct because the magnetic field at the center of a solenoid is proportional to the number of turns per unit length. Therefore, the ratio of the magnetic fields is 1:n.
240 Medium
240 of 385
Understanding +4 | -1
Assertion (A): The coil is bound over the metallic frame in moving coil galvanometer.
Reason (R): The metallic frame helps in making steady deflection without any oscillations.
View answer and explanation
Correct option: A
Both assertion and reason are true and reason is the correct explanation of assertion
Option A is correct because the metallic frame in a moving coil galvanometer provides electromagnetic damping, which helps to make the deflection steady without oscillations.
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