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JEE • PHYSICS • MAGNETIC EFFECT OF CURRENT

Magnetic effect of current practice · Mixed difficulty

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Showing 331-360 of 418 questions

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331 Medium
331 of 418
Application +4 | -1
A proton projected in a magnetic field of 0.020 T travels along a helical path of radius 5.0 cm and pitch 20 cm. Find the components of the velocity of the proton along and perpendicular to the magnetic field. Take the mass of the proton =1.6×10−27 kg=1.6 \times 10^{-27} \mathrm{~kg}.
View answer and explanation
Correct option: A
1×105 m/s;  6.4×104 m/s1 \times {10^5}\,m/s;\,\,6.4 \times {10^4}\,m/s
Option A (1×105 m/s;  6.4×104 m/s1 \times {10^5}\,m/s;\,\,6.4 \times {10^4}\,m/s) is correct because the perpendicular component is found using the radius of the helix, and the parallel component is found using the pitch.
332 Medium
332 of 418
Application +4 | -1
An ammeter reads upto 1 A. Its internal resistance is 0.81  Ω0.81\,\,\Omega. To increase the range to 10 A, the value of the required shunt is-
View answer and explanation
Correct option: D
0.09  Ω0.09\,\,\Omega
Option D (0.09,Ω0.09\\,\Omega) is correct because it is calculated using the shunt resistance formula for extending ammeter range.
333 Medium
333 of 418
Understanding +4 | -1
If a charged particle is projected with a velocity ' vv ' in a magnetic field ' BB ', then power developed by the field is
View answer and explanation
Correct option: C
zero
Option C (zero) is correct because the magnetic force on a moving charge is always perpendicular to the velocity, so the work done and thus the power developed by the magnetic field is zero.
334 Medium
334 of 418
Understanding +4 | -1
Which of the following statements is not true
View answer and explanation
Correct option: A
While taking reading of tangent galvanometer, the plane of the coil must be set at right angles to the earth’s magnetic meridian
Option A (While taking reading of tangent galvanometer, the plane of the coil must be set at right angles to the earth’s magnetic meridian) is not true because the plane of the coil must be set in the magnetic meridian, not at right angles.
335 Medium
335 of 418
Understanding +4 | -1
In a current carrying long solenoid, the field produced does not depend upon
View answer and explanation
Correct option: C
Radius of solenoid
Radius of solenoid is correct because the magnetic field inside a long solenoid depends on the number of turns per unit length and the current, but not the radius.
336 Medium
336 of 418
Understanding +4 | -1
An electron flies into a homogeneous magnetic field of 10−3 T10^{-3} \mathrm{~T} perpendicular to the force lines. The velocity of the electron is v=4×107 m s−1{v}=4 \times 10^7 \mathrm{~m} \mathrm{~s}^{-1}. What is the tangential acceleration of electron in the magnetic field?
View answer and explanation
Correct option: D
Zero
Option D is correct because the magnetic force on a moving charge does not change its speed, only its direction, resulting in zero tangential acceleration.
337 Medium
337 of 418
Understanding +4 | -1
Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): In an uniform magnetic field, speed and energy remains the same for a moving charged particle.
Reason (R): Moving charged particle experiences magnetic force perpendicular to its direction of motion.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A).
Both Assertion and Reason are true, and Reason correctly explains Assertion because the magnetic force being perpendicular to the velocity does no work, thus keeping speed and energy constant.
338 Medium
338 of 418
Understanding +4 | -1
An electron with mass mm, velocity vv and charge ee describing half a revolution in a circle of radius rr in a magnetic field BB, will experience change in energy equal to
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the magnetic force is always perpendicular to the velocity, resulting in no work done and no change in energy.
339 Medium
339 of 418
Analyzing +4 | -1
Assertion (A) : A charged particle is moving in a circle with constant speed in uniform magnetic field. If we increase the speed of particle to twice, its acceleration will become four times.

Reason (R) : In circular path of radius RR with constant speed vv, acceleration is given by v2R\frac{v^2}{R}.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true.
Option D is correct because the assertion is false (acceleration becomes twice, not four times) and the reason is true (acceleration is given by v²/R).
340 Medium
340 of 418
Understanding +4 | -1
Three moving coil galvanometers
A,B  and  CA,\mathrm{ }B\,\,and\,\,C
are made of coils of three different material having torsional constant 1.8  ×  10−8,  2.8  ×  10−81.8\,\, \times \,\,{10^{ - 8}},\,\,2.8\,\, \times \,\,{10^{ - 8}}and 3.8  ×  10−83.8\,\, \times \,\,{10^{ - 8}} respectively. If the three galvanometers are identical in all other respect, then in which of the above cases sensitivity is maximum?
View answer and explanation
Correct option: A
A\begin{array}{llllllllllllllllllll} A \end{array}
Option A is correct because the current sensitivity is inversely proportional to the torsional constant, and galvanometer A has the lowest torsional constant.
341 Hard
341 of 418
Application +4 | -1
There exists a uniform and constant magnetic field B=1.67TB=1.67 T along positive zz-axis. Simultaneously a proton and an alpha particle are projected from the origin with same speed v=45×105 ms−1v=4 \sqrt{5} \times 10^5 \mathrm{~ms}^{-1} along positive and negative xx-axis respectively. Find the separation between them when their velocities become mutually perpendicular for the first time. Ignore the force of interaction between them as well as any force other than magnetic force. Mass of the proton is 1.67×10−27 kg1.67 \times 10^{-27} \mathrm{~kg}.
View answer and explanation
Correct option: B
25 mm25 \mathrm{~mm}
Option C (23×104N−m\frac{2}{3} \times {10^4}N - m) is correct because the instantaneous torque is calculated by dividing the power by the angular speed.
342 Medium
342 of 418
Understanding +4 | -1
The coil of a moving coil galvanometer is wound over a metal frame in order to
View answer and explanation
Correct option: B
Provide electromagnetic damping
Option B (Provide electromagnetic damping) is correct because winding the coil over a metal frame in a moving coil galvanometer induces eddy currents, which provide electromagnetic damping.
343 Medium
343 of 418
Application +4 | -1
A wire of length LL meter carrying a current of II ampere is bent in the form of a circle. Its magnetic moment is:
View answer and explanation
Correct option: D
IL24π A−m2\frac{{IL}^2}{4 \pi} \mathrm{~A}-\mathrm{m}^2
Option D (IL24π A−m2\frac{{IL}^2}{4 \pi} \mathrm{~A}-\mathrm{m}^2) is correct because it is derived from calculating the area of the circle formed by the wire and then multiplying by the current.
344 Medium
344 of 418
Understanding +4 | -1
A positively charged particle enters in a uniform magnetic field with uniform velocity vv. If angle between velocity and magnetic field is 180∘,180^{\circ}, the trajectory will be
View answer and explanation
Correct option: A
Straight line
Option A (Straight line) is correct because when the angle between velocity and magnetic field is 180 degrees, the magnetic force is zero, resulting in no deflection.
345 Medium
345 of 418
Understanding +4 | -1
A metal rod is moved with a constant velocity vv in a magnetic field. A potential difference appears across the two ends:
View answer and explanation
Correct option: D
none of these
Option D (none of these) is correct because a potential difference appears only when the velocity, length, and magnetic field are mutually perpendicular.
346 Medium
346 of 418
Understanding +4 | -1
Assertion (A): Out of galvanometer, ammeter and voltmeter, resistance of ammeter is lowest and resistance of voltmeter is highest.

Reason (R): An ammeter is connected in series and a voltmeter is connected in parallel, in a circuit.
View answer and explanation
Correct option: B
(A) and (R) are true and (R) is not correct explanation of (A)
Option B ((A) and (R) are true and (R) is not correct explanation of (A)) is correct because both the assertion and the reason are true, but the reason doesn't fully explain the assertion.
347 Medium
347 of 418
Application +4 | -1
A particle of charge qq and mass mm starts moving from the origin under the action of an electric field, E=E0i^E=E_0 \hat{{i}} and B=B0i^B=B_0 \hat{{i}} with a velocity, v=v0j^v=v_0 \hat{{j}}. The speed of the particle will become 52v0\frac{\sqrt{5}}{2} v_0 after a time
View answer and explanation
Correct option: B
mv02qE\frac{m v_0}{2 q E}
Option B (mv02qE\frac{m v_0}{2 q E}) is correct because it is derived from calculating the time when the particle's speed reaches the given value under the influence of electric and magnetic fields.
348 Medium
348 of 418
Application +4 | -1
A galvanometer has a resistance of 30 Ω30\,\Omega and current of 2 mA2 \mathrm{~mA} is needed to give full scale deflection. What is the resistance needed and how is it to be connected to convert the galvanometer into voltmeter of 0.2 volt range.
View answer and explanation
Correct option: A
70 Ω70\,\Omega
Option A (70 Ω70\,\Omega) is correct because it is the resistance needed to be connected in series with the galvanometer to convert it into a voltmeter of 0.2 volt range.
349 Medium
349 of 418
Application +4 | -1
A length of wire carries a steady current ii. It is bent first to form a circular plane coil of one turn. The same length is now bent more sharply to give three loops of smaller radius. The magnetic field at the centre caused by the same current is
View answer and explanation
Correct option: D
Nine times of its initial value
Option D (Nine times of its initial value) is correct because the magnetic field at the center of a coil is proportional to the square of the number of turns when the length of the wire is constant.
350 Medium
350 of 418
Understanding +4 | -1
An electron is projected along the axis of
circular conductor carrying current I. Electron
will experience
View answer and explanation
Correct option: A
no force.
Option A (no force.) is correct because the force on a moving charge in a magnetic field is given by F=qvBsin⁡θF = qvB\sin\theta, and since the electron is moving along the axis, the angle θ\theta between the velocity and the magnetic field is 0, making the force zero.
351 Medium
351 of 418
Application +4 | -1
Calculate the torque on a 100 turn rectangular coil of length 40 cm40 \mathrm{~cm} and breadth 20 cm20 \mathrm{~cm}, carrying a current of 10 A10 \mathrm{~A}, when placed making an angle of 60∘60^{\circ} with a magnetic field of 3T3 T.
View answer and explanation
Correct option: A
120 Nm
Option A (120 Nm) is correct because it is the calculated torque on the coil using the formula τ=NIBAsin⁡θ\tau = NIBA \sin \theta.
352 Medium
352 of 418
Application +4 | -1
A charged particle with specific charge ss moves undeflected through a region of space containing mutually perpendicular and uniform electric and magnetic fields EE and BB. When the electric field is switched off, the particle will move in a circular path of radius
View answer and explanation
Correct option: D
EB2s\frac{E}{B^2 s}
Option D (EB2s\frac{E}{B^2 s}) is correct because it is derived from equating the electric and magnetic forces and then using the formula for the radius of a circular path in a magnetic field.
353 Medium
353 of 418
Understanding +4 | -1
The momentum of a charged particle moving in a perpendicular magnetic field depends on
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because the momentum of a charged particle in a magnetic field depends on its charge, the field strength, and the radius of its path.
354 Easy
354 of 418
Understanding +4 | -1
The error in measuring the current with a tangent galvanometer is minimum when the deflection is about
View answer and explanation
Correct option: C
45
Option C (45) is correct because the error in a tangent galvanometer is minimized when the deflection is around 45 degrees.
355 Medium
355 of 418
Application +4 | -1
Two long Straight wires each carrying an electric Current of 5 A5 \mathrm{~A} are kept parallel to each other at a separation of 2.5 cm2.5 \mathrm{~cm}. Find the magnitude of the magnetic force experiment by 10 cm10 \mathrm{~cm} of a wire.
View answer and explanation
Correct option: B
3.5×10−6 N3.5 \times 10^{-6} \mathrm{~N}
The correct answer is C (2.0×10−5 N2.0 \times 10^{-5} \mathrm{~N}) because it is calculated using the formula for the magnetic force between two parallel current-carrying wires.
356 Medium
356 of 418
Application +4 | -1
A long straight wire with a circular cross-section having radius RR, is carrying a steady current II. The current II is uniformly distributed across this cross-section. Then the variation of magnetic field due to current II with distance r (r<R)r\,(r < R) from its centre will be
View answer and explanation
Correct option: B
B∝rB \propto r
Option B (B∝rB \propto r) is correct because, according to Ampere's law, the magnetic field inside a long straight wire with uniform current distribution is directly proportional to the distance from the center.
357 Medium
357 of 418
Analyzing +4 | -1
Assertion: Various regular polygons formed by a constant length current carrying wire, then magnetic induction at their centres are increases when their number of sides increases.
Reason: A magnetic dipole placed in non uniform magnetic field, then torque acting on it is always zero.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because both the assertion and the reason are false statements regarding magnetic induction and torque on a magnetic dipole.
358 Medium
358 of 418
Understanding +4 | -1
Magnetic moment for a solenoid and corresponding bar magnet is
View answer and explanation
Correct option: A
equal for both
Option A (equal for both) is correct because a solenoid and a corresponding bar magnet produce the same magnetic field, resulting in equal magnetic moments.
359 Easy
359 of 418
Remembering +4 | -1
A moving electric charge produces
View answer and explanation
Correct option: A
electric and magnetic fields
Option A (electric and magnetic fields) is correct because a moving electric charge creates both electric and magnetic fields due to its motion.
360 Medium
360 of 418
Application +4 | -1
A galvanometer has a resistance of 96 Ω96\,\Omega and it is desired to pass 4%4 \% of the total current through it. Calculate the value of shunt resistance.
View answer and explanation
Correct option: A
4 Ω4\,\Omega
Option A (4 Ω4\,\Omega) is correct because it is the shunt resistance value calculated using the current division rule for parallel resistors.
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