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JEE • PHYSICS • LAWS OF MOTION

Laws of motion practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 426 questions

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61 Medium
61 of 426
Application +4 | -1
In an elevator moving vertically up with an acceleration g, the force exerted on the floor by a passenger of mass M is
View answer and explanation
Correct option: D
2 Mg
Option D (2 Mg) is correct because the net force exerted on the floor is the sum of the weight and the force due to the upward acceleration.
62 Medium
62 of 426
Application +4 | -1
A mass of 4 kg4 \mathrm{~kg} rests on a horizontal plane. The plane is gradually inclined until at an angle θ=15∘\theta=15^{\circ} with the horizontal, the mass just begins to slide. What is the coefficient of static friction between the block and the surface?
View answer and explanation
Correct option: A
0.27{0.27}
Option A (0.27{0.27}) is correct because the coefficient of static friction is equal to the tangent of the angle at which the mass just begins to slide.
63 Medium
63 of 426
Application +4 | -1
A machine gun fires a bullet of mas 65 g with a velocity of 1300 m/s. The man holding it can exert a maximum force of 169 N on the gun. The number of bullets he can fire per second will be
View answer and explanation
Correct option: B
2
Option B (2) is correct because the number of bullets fired per second is calculated by equating the force exerted by the man to the rate of change of momentum of the bullets.
64 Medium
64 of 426
Understanding +4 | -1
Choose the correct statement(s) from the following.
I. Recoiling of a gun is an application of principle of conservation of linear momentum.
II. Explosion of a bomb is based on second law of motion
View answer and explanation
Correct option: A
I only
Option A is correct because a divergent lens (concave lens) always forms a virtual, erect, and diminished image for real objects.
65 Medium
65 of 426
Application +4 | -1
A mass m{m} falls freely from rest. The linear momentum, after it has fallen through a height hh, is :
( g={g}= acceleration due to gravity)
View answer and explanation
Correct option: B
m2gh{m} \sqrt{2 {gh}}
Option B (m2gh{m} \sqrt{2 {gh}}) is correct because the linear momentum is the product of mass and velocity, where velocity is derived from the kinematic equation v=2ghv = \sqrt{2gh}.
66 Medium
66 of 426
Application +4 | -1
A 4 kg4 \mathrm{~kg} block is suspended from the ceiling of an elevator through a spring having a linear mass density of 19.2×10−3kgm−319.2 \times 10^{-3} \mathrm{kgm}^{-3} Find the speed with respect to spring with which a wave pulse can proceed on the Spring if the elevator accelerates up at the rate of 2.0 ms−22.0 \mathrm{~ms}^{-2} take g=10 ms−2g=10 \mathrm{~ms}^{-2}
View answer and explanation
Correct option: D
50 m/s50 \mathrm{~m} / \mathrm{s}
Option D (50 m/s50 \mathrm{~m} / \mathrm{s}) is correct because it is the wave speed calculated using the tension in the spring due to the elevator's acceleration.
67 Medium
67 of 426
Understanding +4 | -1
Statement-I: When a ball of mass mm hits normally a wall with a velocity 'vv' and rebounds with same velocity vv, impulse imparted to the wall is 2mv2 m v.
Statement-II: Impulse == change in linear momentum
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Statement-I is true and statement-II is true. The impulse imparted to the wall is indeed 2mv, and impulse is defined as the change in linear momentum.
68 Medium
68 of 426
Understanding +4 | -1
Select correct statement regarding friction
View answer and explanation
Correct option: D
Both (1) and (2)
Option D (Both (1) and (2)) is correct because static friction is self-adjusting up to a maximum value (limiting friction), and kinetic friction is generally less than the maximum static friction.
69 Medium
69 of 426
Remembering +4 | -1
Impulse equals
View answer and explanation
Correct option: B
change in momentum
Option B (change in momentum) is correct because impulse is defined as the change in momentum of an object.
70 Medium
70 of 426
Application +4 | -1
A force of 40 newton acts on a body which is initially at rest. If the velocity of the body at the end of 10 seconds is 20   ms−1,20\,\,\,{\text{m}}{{\text{s}}^{ - 1}}, then mass of the body
View answer and explanation
Correct option: C
20 kg
Option C (20 kg) is correct because the mass is calculated using the formula F = ma, where acceleration is derived from the change in velocity over time.
71 Medium
71 of 426
Analyzing +4 | -1
If two masses (M & m) are connected on a horizontal plane and a force is applied on the combination, then the tension T depends on
View answer and explanation
Correct option: B
whether force is applied on M or m
The correct answer is B (whether force is applied on M or m) because the tension in the string depends on which mass the force is applied to.
72 Medium
72 of 426
Application +4 | -1
The coefficient of friction between the tyres and the road is 0.25. The maximum speed with which a car can be driven round a curve a radius 40 m without skidding is is (assume g=10  ms−2g = 10\;m{s^{ - 2}})
View answer and explanation
Correct option: D
10 ms−1m{s^{ - 1}}
Option D (10 ms−1m{s^{ - 1}}) is correct because it is the maximum speed calculated using the formula v=μrgv = \sqrt{\mu rg} without skidding.
73 Medium
73 of 426
Analyzing +4 | -1
A cold soft drink is kept on the balance. When the cap is open, then the weight
View answer and explanation
Correct option: C
First increases then decreases
The correct answer is C because initially, the weight increases due to the escaping gas exerting a downward force, then decreases as the gas leaves.
74 Medium
74 of 426
Application +4 | -1
A frictionless inclined plane of length l having inclination &theta; is placed inside a lift which is accelerating downward with an acceleration a(<g<g) .&nbsp;If a block is allowed to move, down the inclined plane, from rest, then the time taken by the block to slide from top of the inclined plane to the bottom of the inclined plane is
View answer and explanation
Correct option: D
2l(g−a)sin⁡θ\sqrt {\frac{{2l}}{{\left( {\mathrm{g} - a} \right)\sin \mathrm{\theta }}}}
Option D (2l(g−a)sin⁡θ\sqrt {\frac{{2l}}{{\left( {\mathrm{g} - a} \right)\sin \mathrm{\theta }}}}) is correct because the acceleration down the inclined plane is reduced due to the downward acceleration of the lift.
75 Medium
75 of 426
Understanding +4 | -1
No force is required for
View answer and explanation
Correct option: A
an object moving in straight line with constant
velocity
Option A (an object moving in straight line with constant velocity) is correct because, according to Newton's first law, an object in motion stays in motion with the same speed and in the same direction unless acted upon by a force.
76 Medium
76 of 426
Application +4 | -1
An ice cart of mass 60 kg rests on a horizontal snow patch with coefficient of static friction 13\frac{1}{3}. Assuming that there is no vertical acceleration, find the magnitude of the maximum horizontal force required to move the ice cart (g=9.8  ms−2)\left( {g = 9.8\;\mathrm{m}{\mathrm{s}^{ - 2}}} \right)
View answer and explanation
Correct option: D
196 N
Option D (196 N) is correct because it is the maximum static friction force that needs to be overcome to move the ice cart.
77 Medium
77 of 426
Application +4 | -1
A shell is fired with a muzzle velocity of 20 ms−120\,m{s^{ - 1}} at an angle of 600{60^0} with the horizontal. At the top of trajectory the shell explodes into 2 fragments of equal masses. One of them comes to rest. The distance at which second fragment touches the ground from gun will be…. (g=10 m/s2)\left( {g = 10\,m/{s^2}} \right)
View answer and explanation
Correct option: C
303 m30\sqrt 3 \,m
The correct answer is C (303,m30\sqrt 3 \\,m) because it is the distance calculated using the conservation of momentum after the explosion.
78 Medium
78 of 426
Application +4 | -1
A cubical block of mass MM vibrates horizontally with amplitude of 4 cm4 \mathrm{~cm} and a frequency of 2 Hz2 \mathrm{~Hz}. A small block of mass mm is placed on the bigger block. In order that the smaller block does not slide on the bigger block, the minimum value of the coefficient of static friction between the two blocks is
View answer and explanation
Correct option: C
0.640.64
Option C (0.64) is correct because it is the minimum coefficient of static friction required to prevent the smaller block from sliding.
79 Easy
79 of 426
Application +4 | -1
A person wants to drive on the vertical surface of a large cylindrical wooden 'well' commonly known as 'death well' in a circus. The radius of the well is R\mathrm{R} and the coefficient of friction between the tyres of the motorcycle and the wall of the well is μs\mu_{\mathrm{s}}. The minimum speed the motor cyclist must have in order to prevent slipping should be
View answer and explanation
Correct option: A
gRμs\sqrt{\frac{g \mathrm{R}}{\mu_{\mathrm{s}}}}
Option A (gRμs\sqrt{\frac{g \mathrm{R}}{\mu_{\mathrm{s}}}}) is correct because it represents the minimum speed required to prevent slipping, derived from balancing the gravitational force and frictional force.
80 Medium
80 of 426
Application +4 | -1
A gun is mounted on a railroad car. The mass of the car, the gun, the shells and the operator is 50 m50 \mathrm{~m} where mm is the mass of one shell. If the velocity of the shell with respect to the gun (in its state before firing) is 200 m/s,200 \mathrm{~m} / \mathrm{s}, what is the recoil speed of the car after the second shot? Neglect friction.
View answer and explanation
Correct option: A
200(149+148)m/s200\left(\frac{1}{49}+\frac{1}{48}\right) \mathrm{m} / \mathrm{s}
Option A (200(149+148)m/s200\left(\frac{1}{49}+\frac{1}{48}\right) \mathrm{m} / \mathrm{s}) is correct because it is the recoil speed calculated using conservation of momentum after two shots.
81 Medium
81 of 426
Understanding +4 | -1
Which of the following is a self adjusting force?
View answer and explanation
Correct option: A
Static friction
Option A (Static friction) is correct because static friction adjusts its magnitude to match the applied force, up to a maximum value.
82 Easy
82 of 426
Application +4 | -1
A bullet of mass 28 gm is fired from a rifle of mass 10 kg with a velocity of 100 m/s. The velocity of recoil of the rifle is
View answer and explanation
Correct option: A
-0.28
Option A (-0.28) is correct because it is calculated using the conservation of momentum, where the total momentum before firing equals the total momentum after firing.
83 Medium
83 of 426
Understanding +4 | -1
Physical independence of force is a consequence of
View answer and explanation
Correct option: C
first law of motion
Option C (first law of motion) is correct because Newton's first law states that an object remains at rest or in uniform motion unless acted upon by an external force, implying forces are independent unless applied.
84 Medium
84 of 426
Understanding +4 | -1
The x and y components of a force are 2 N and -3N. The force is
View answer and explanation
Correct option: A
2i^−3j^2\hat i - 3\hat j
Option A (2i^−3j^2\hat i - 3\hat j) is correct because the force vector is represented as the sum of its x and y components: F⃗=Fxi^+Fyj^\vec{F} = F_x\hat i + F_y\hat j.
85 Medium
85 of 426
Analyzing +4 | -1
Assertion: A sphere cannot roll on a frictionless horizontal surface.
Reason: The tangential frictional force on the sphere exerts torque and causes it to roll.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A is correct because both the assertion and reason are true, and the reason is the correct explanation of the assertion. A sphere needs friction to roll, and the reason correctly identifies friction as the source of torque.
86 Medium
86 of 426
Analyzing +4 | -1
A man squatting on the ground gets straight up and stand. The force of reaction of ground on the man during the process is
View answer and explanation
Correct option: D
at first greater than mgm g, and later becomes equal to mgm g.
Option D is correct because the normal reaction from the ground initially exceeds the man's weight to provide upward acceleration, then equals his weight when standing still.
87 Medium
87 of 426
Understanding +4 | -1
Identify the correct statement.
View answer and explanation
Correct option: D
Coefficient of kinetic friction is less than the coefficient of static friction
Option D (Coefficient of kinetic friction is less than the coefficient of static friction) is correct because it is generally easier to keep an object moving than to start it moving.
88 Medium
88 of 426
Analyzing +4 | -1
Assertion: The acceleration of a body down a rough inclined plane is greater than the acceleration due to gravity.
Reason: A body is able to slide on an inclined plane only when its acceleration is greater than the acceleration due to gravity.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because the acceleration down a rough inclined plane is less than g, and a body can slide even if its acceleration is less than g.
89 Medium
89 of 426
Understanding +4 | -1
An object is moving at constant velocity. The total force FF acting on the object is given by
View answer and explanation
Correct option: C
F=0{F}=0
Option C is correct because, according to Newton's First Law, an object moving at a constant velocity has zero net force acting on it.
90 Medium
90 of 426
Remembering +4 | -1
Inertia of an object is directly dependent on
View answer and explanation
Correct option: C
Mass
Option C (Mass) is correct because inertia is the resistance of an object to changes in its state of motion, and it is directly proportional to the object's mass.
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