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JEE • PHYSICS • GRAVITATION

Gravitation practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 450 questions

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91 Medium
91 of 450
Application +4 | -1
A chain of 125 links is 1.25 m long and has mass of 2 kg with the ends fastened together. It is set for rotating at 50 revs−1\mathrm{rev}{\mathrm{s}^{ - 1}}, centripetal force on each links is
View answer and explanation
Correct option: C
314 N
Option D (None of these) is incorrect. Option A (3.14 N) is incorrect. Option B (0.314 N) is incorrect. Option C (314 N) is correct because it is the centripetal force on each link, calculated using the formula F=mrω2F = mr\omega^2.
92 Easy
92 of 450
Understanding +4 | -1
A uniform spherical shell gradually shrinks maintaining its shape. The gravitational potential at the centre
View answer and explanation
Correct option: A
increases
Option A (increases) is correct because as the spherical shell shrinks, its radius decreases, and since the gravitational potential is inversely proportional to the radius, the potential increases (becomes less negative).
93 Easy
93 of 450
Understanding +4 | -1
Statement-1: The force of attraction due to a hollow spherical shell of uniform density, on a point mass situated inside it is zero.
Statement-2: The gravitation field due to the shell inside the shell will be zero.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true
Option A (Statement-1 is true, Statement-2 is true) is correct because the gravitational force and field inside a hollow spherical shell of uniform density are zero.
94 Medium
94 of 450
Understanding +4 | -1
If the earth stops rotating, the value of gg at the equator
View answer and explanation
Correct option: A
increases
Option A (increases) is correct because the effective gravitational acceleration at the equator is reduced due to Earth's rotation; stopping the rotation would eliminate this reduction, increasing g.
95 Medium
95 of 450
Remembering +4 | -1
According to Kepler's law of planetary motion, if TT represents time period and rr is orbital radius, then for two planets these are related as
View answer and explanation
Correct option: C
[T1T2]2=[r1r2]3\left[\frac{T_1}{T_2}\right]^2=\left[\frac{r_1}{r_2}\right]^3
Option C (T1T22=r1r23\frac{T_1}{T_2}^2=\frac{r_1}{r_2}^3) is correct because it represents Kepler's Third Law, which relates the period and orbital radius of planets.
96 Medium
96 of 450
Understanding +4 | -1
An iron ball and a wooden ball of the same radius are released from a beight hh in vacuum. The time taken by both to reach the ground is. The correct option is:
View answer and explanation
Correct option: A
Acceleration due to gravity in vacuum is same irrespective of size and mass of the body
Option A (Acceleration due to gravity in vacuum is same irrespective of size and mass of the body) is correct because in a vacuum, the only force acting on the balls is gravity, and the acceleration due to gravity is independent of mass.
97 Medium
97 of 450
Application +4 | -1
A mass ' m\mathrm{m} ' suspended from a spring stretches it by 5 cm5 \mathrm{~cm} when on the surface of the earth. The mass is then taken on to a height of 1600 km1600 \mathrm{~km} above earth's surface and again suspended from the same spring. At this altitude the extension of the spring is (Radius of earth = 6400 km6400 \mathrm{~km})
View answer and explanation
Correct option: A
3.2 cm3.2 \mathrm{~cm}
Option A (3.2 cm3.2 \mathrm{~cm}) is correct because the extension of the spring is proportional to the weight, which changes with altitude.
98 Medium
98 of 450
Understanding +4 | -1
Astronaut is in a stable orbit around the earth when he weighs a body of mass 5 kg. What is reading of spring balance?
View answer and explanation
Correct option: A
Spring will not be extended
Option A is correct because in a stable orbit, the astronaut and the body are in freefall, so the spring balance will not be extended.
99 Medium
99 of 450
Application +4 | -1
Gravitational potential of the body of mass mm at a height hh from surface of earth of radius RR is (Take g=g= acceleration due to gravity at earth's surface).
View answer and explanation
Correct option: B
−g(R−h)-g(R-h)
Option B (−g(R−h)-g(R-h)) is correct because it represents the gravitational potential at height h, derived from the potential energy formula.
100 Medium
100 of 450
Understanding +4 | -1
If the rotational motion of earth about its axis
increases, then the weight of a body on equator
would
View answer and explanation
Correct option: B
Decrease
Option B (Decrease) is correct because as the rotational speed increases, the effective weight decreases due to increased centrifugal force.
101 Medium
101 of 450
Understanding +4 | -1
A small satellite is in elliptical orbit around Earth as shown. If L denotes the magnitude of its angular momentum and K denotes kinetic energy
View answer and explanation
Correct option: D
L2=L1 and K2>K1{L_2} = {L_1}\,and\,{K_2} > {K_1}
Option D (L2=L1 and K2>K1{L_2} = {L_1}\,and\,{K_2} > {K_1}) is correct because angular momentum is conserved in an elliptical orbit, and kinetic energy is greater at the point closest to the Earth.
102 Medium
102 of 450
Application +4 | -1
A satellite of mass m is circulation around the earth with constant angular velocity. If radius of the orbit is R0{R_0} and mass of the earth M, the angular momentum about the centre of the earth is
View answer and explanation
Correct option: A
mGMR0m\sqrt {GM{R_0}}
Option A (mGMR0m\sqrt {GM{R_0}}) is correct because it is the angular momentum calculated using the orbital velocity and radius.
103 Medium
103 of 450
Application +4 | -1
Satellite A and B are revolving around the orbit of earth. The mass of A is 10 times of mass of B.The ratio of time period (TATB)\left( {\frac{{{T_A}}}{{{T_B}}}} \right) is
View answer and explanation
Correct option: B
1
Option B (1) is correct because the time period of a satellite's orbit is independent of its mass.
104 Medium
104 of 450
Analyzing +4 | -1
Assertion(A): Areal velocity of a planet around sun will become two times, if mass of planet is halved.
Reason(R): Areal velocity =L2m=\frac{L}{2 m}, where LL is angular momentum of planet about centre of sun.
View answer and explanation
Correct option: D
If Assertion is incorrect but Reason is correct.
Option D is correct because the areal velocity is independent of the mass of the planet, so halving the mass does not change the areal velocity. The reason is correct as it states the formula for areal velocity.
105 Medium
105 of 450
Understanding +4 | -1
Which of the following is/are correct.

I. An object moving the earth under the influence of Earth's gravitational force is in a state of "free-fall".

II. The dominant effect causing a slowdown in the rotation of the earth is the gravitational pull of other planets in the solar system.

III. Generally the path of a projectile from the earth is parabolic but it is elliptical for projectiles going to a very large height.

IV. The path of a projectile is independent of the gravitational force of earth.
View answer and explanation
Correct option: C
I and III
Option C is correct because an object moving under Earth's gravity is in free-fall, and projectile paths are generally parabolic but become elliptical at very large heights.
106 Medium
106 of 450
Analyzing +4 | -1
The earth is an approximate sphere. If the interior contained matter which is not of the same density everywhere, then on the surface of the earth, the acceleration due to gravity
View answer and explanation
Correct option: D
cannot be zero at any point.
The correct answer is D because even with varying densities, the acceleration due to gravity cannot be zero at any point on the Earth's surface.
107 Medium
107 of 450
Application +4 | -1
If the radius of the earth decreases by 10%, the mass remaining unchanged, then the acceleration due to gravity.
View answer and explanation
Correct option: D
increases by more than 19%
Option D (increases by more than 19%) is correct because the acceleration due to gravity increases by more than 19% when the radius decreases by 10%, keeping mass constant.
108 Medium
108 of 450
Application +4 | -1
The ratio of the radii of the planets P1 and P2{P_1}\,and\,{P_2} is a. The ratio of their acceleration due to gravity is b. The ratio of the escape velocities from them will be
View answer and explanation
Correct option: B
ab\sqrt {ab}
Option B (ab\sqrt {ab}) is correct because the escape velocity depends on both the radius and the acceleration due to gravity of the planet.
109 Medium
109 of 450
Analyzing +4 | -1
Observers on the 10th, 5th and ground floor of a tall building measure the velocity of a certain raindrop by some accurate method. Surprisingly the velocity of the raindrop measured by the three observers was found to be the same. This is because
View answer and explanation
Correct option: A
there is no gravitational force acting on the drop
Option B (gravitational force on the raindrop is balanced by the force produced by the surrounding air) is correct because the raindrop reaches terminal velocity where the net force is zero, resulting in constant velocity.
110 Medium
110 of 450
Remembering +4 | -1
The orbital velocity of a body close to the earth's surface is
View answer and explanation
Correct option: A
8 kms−18 \mathrm{~kms}^{-1}
Option A (8 kms−18 \mathrm{~kms}^{-1}) is correct because the orbital velocity close to the Earth's surface is approximately 8 km/s.
111 Medium
111 of 450
Analyzing +4 | -1
Assertion: Gravitational force between two particles is negligibly small compared to the electrical force.
Reason: The electrical force is experienced by charged particles only.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
Option B (If both assertion and reason are true but reason is not the correct explanation of assertion) is correct because gravitational force is much weaker than electrical force, and electrical force acts only on charged particles.
112 Easy
112 of 450
Understanding +4 | -1
If the speed of rotation of earth about its axis increases, then the weight of the body at the equator will
View answer and explanation
Correct option: B
decrease
Option B (decrease) is correct because the effective weight decreases with increasing rotational speed due to centrifugal force.
113 Medium
113 of 450
Understanding +4 | -1
When earth moves around the sun, the quantity which remains constant is
View answer and explanation
Correct option: D
Areal velocity
Option D (Areal velocity) is correct because according to Kepler's second law, the areal velocity of a planet orbiting the sun remains constant.
114 Medium
114 of 450
Application +4 | -1
Abody weighed 250 N250 \mathrm{~N} on the surface assuming the earth to be a sphere of uniform mass density, how much would it weigh half way down to the centre of the earth?
View answer and explanation
Correct option: C
125 N125 \mathrm{~N}
Option C (125 N125 \mathrm{~N}) is correct because the weight decreases linearly with depth inside the Earth, assuming uniform density.
115 Medium
115 of 450
Application +4 | -1
The mass of a planet that has a moon whose time period and orbital radius are TT and RR respectively can be written as
View answer and explanation
Correct option: A
4π2R3G−1T−24{\pi ^2}{R^3}{G^{ - 1}}{T^{ - 2}}
Option A (4π2R3G−1T−24{\pi ^2}{R^3}{G^{ - 1}}{T^{ - 2}}) is correct because it is derived from equating gravitational force and centripetal force.
116 Medium
116 of 450
Analyzing +4 | -1
Statement I: At height hh from ground and at depth hh below ground, where hh is approximately equal to 0.62R0.62 \mathrm{R}, the value of g\mathrm{g} acceleration due to gravity is same.

Statement II: Value of g\mathrm{g} decreases both sides, in going up and down.
View answer and explanation
Correct option: B
If both Statement - I and Statement - II are true but Statement - II is not the correct explanation of Statement - I.
Option B (If both Statement - I and Statement - II are true but Statement - II is not the correct explanation of Statement - I) is correct because both statements are true, but the general decrease of 'g' doesn't explain the specific height/depth where 'g' is the same.
117 Medium
117 of 450
Application +4 | -1
A point P(R3,0,0)P\left( {R\sqrt 3 ,0,0} \right) lies on the axis of a ring of mass MM and radius RR. The ring is located in y−zy - z plane with its centre at origin OO. A small particle of mass m starts from P and reaches OO under gravitational attraction only. Its speed at OO will be
View answer and explanation
Correct option: A
GMR\sqrt {\frac{{GM}}{R}}
Option A (GMR\sqrt {\frac{{GM}}{R}}) is correct because the speed at O is calculated using conservation of energy.
118 Medium
118 of 450
Application +4 | -1
The radius of the earth is 6.37×106 m6.37 \times 10^6 \mathrm{~m}, its mean density is 5.5×103 kg m−35.5 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3} and G=6.66×10−11 Nm2 kg−2G=6.66 \times 10^{-11}\mathrm{~Nm}^2 \mathrm{~kg}^{-2}. Determine the gravitational potential on the surface of the earth.
View answer and explanation
Correct option: A
−6.22×107 J kg−1-6.22 \times 10^7 \mathrm{~J} \mathrm{~kg}^{-1}
Option A (21\frac{2}{1}) is correct because using the ideal gas law, the ratio of the number of gas molecules in A to B is 2:1.
119 Medium
119 of 450
Application +4 | -1
The time period of a satellite of earth is 24 hours. If the separation between the earth and the satellite is decreased to one fourth of the previous value, then its new time period will become.
View answer and explanation
Correct option: C
3 hours
Option C (3 hours) is correct because the time period is proportional to R(3/2), so reducing the radius to one-fourth reduces the time period to one-eighth of the original, resulting in 3 hours.
120 Medium
120 of 450
Application +4 | -1
A body attains a height equal to the radius of the earth. The velocity of the body with which it was projected is
View answer and explanation
Correct option: A
GMR\sqrt{\frac{G M}{R}}
Option A (GMR\sqrt{\frac{G M}{R}}) is correct because it is the velocity required for a body to reach a height equal to the radius of the Earth, derived from conservation of energy.
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