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JEE • PHYSICS • ELECTROMAGNETIC WAVES

Electromagnetic waves practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-226 of 226 questions
211 Medium
211 of 226
Application +4 | -1
Intensity of sunlight is observed as 0.092 Wm−20.092\,W{m^{ - 2}} at a point in free space. What will be the peak value of magnetic field at that point? (ε0=8.85×10−12C−2N1m−2)({\varepsilon _0} = 8.85 \times {10^{ - 12}}{C^{ - 2}}{N^1}{m^{ - 2}})
View answer and explanation
Correct option: A
2.77×10−8T2.77 \times {10^{ - 8}}T
Option A (2.77×10−8T2.77 \times {10^{ - 8}}T) is correct because it is calculated using the relationship between intensity, electric field, and magnetic field in an electromagnetic wave.
212 Medium
212 of 226
Remembering +4 | -1
Phase difference between electric field and magnetic field associated with a plane
polarized light is
View answer and explanation
Correct option: A
zero
Option A (zero) is correct because the electric and magnetic fields in a plane polarized light wave are in phase.
213 Medium
213 of 226
Understanding +4 | -1
Assertion: Electromagnetic waves interact with matter and set up oscillations.
Reason: Interaction is independent of the wavelength of the electromagnetic waves.
View answer and explanation
Correct option: C
If the Assertion is correct but Reason is incorrect
Option C is correct because electromagnetic waves do interact with matter and set up oscillations, but the interaction is highly dependent on the wavelength of the electromagnetic waves.
214 Medium
214 of 226
Understanding +4 | -1
The magnetic field between the plates of a parallel plate capacitor is given by: B=μ0Ir2πR2B=\frac{\mu_0 I r}{2 \pi R^2}, when
View answer and explanation
Correct option: C
r<Rr< R
Option C is correct because the magnetic field inside the capacitor plates is given by the formula when r<Rr < R.
215 Medium
215 of 226
Application +4 | -1
Calculate the average energy density of an electromagnetic wave whose electric field is oscillating with amplitude 50 v/m50 \mathrm{~v} / \mathrm{m} and frequency 5×1010 Hz5 \times 10^{10} \mathrm{~Hz}.
View answer and explanation
Correct option: B
1.1×10−8 J/m31.1 \times 10^{-8} \mathrm{~J} / \mathrm{m}^3
Option B (1.1×10−8 J/m31.1 \times 10^{-8} \mathrm{~J} / \mathrm{m}^3) is correct because it is the average energy density calculated using the electric field amplitude.
216 Medium
216 of 226
Application +4 | -1
A laser gun of power 3 mW3 \mathrm{~mW} and mass 50 gm50 \mathrm{~gm} emits photons of wavelength 500 nm500 \mathrm{~nm}. It is in gravity free space and emits for one hour. Find the distance covered by gun due to recoil in this one hour (approx.) :-
View answer and explanation
Correct option: A
1.3 mm1.3 \mathrm{~mm}
Option A (1.3 mm1.3 \mathrm{~mm}) is correct because it's the distance calculated from the recoil of the laser gun due to photon emission over one hour.
217 Medium
217 of 226
Remembering +4 | -1
If an electromagnetic wave is propagation in a medium with permeability&nbsp;ε\mathrm{\varepsilon } and permittivity μ\mathrm{\mu }, then με\sqrt {\frac{\mathrm{\mu }}{\mathrm{\varepsilon }}} is the
View answer and explanation
Correct option: A
Intrinsic impedance of the medium
The correct answer is A (Intrinsic impedance of the medium) because με\sqrt {\frac{{\rm{{\mu }}}}{{\rm{{\varepsilon }}}}} represents the intrinsic impedance of a medium.
218 Medium
218 of 226
Application +4 | -1
A capacitor having a capacity of 2 pF. Electric field across the capacitor is changing with a value of 1012  Vs−1{10^{12}}\mathrm{\;V}{\mathrm{s}^{ - 1}}. The displacement current is
View answer and explanation
Correct option: A
2A2\mathrm{ }A
Option A (2A2\mathrm{ }A) is correct because the displacement current is calculated using the formula i=CdVdti = C\frac{{dV}}{{dt}}, where C is the capacitance and dVdt\frac{{dV}}{{dt}} is the rate of change of electric field.
219 Medium
219 of 226
Remembering +4 | -1
The existence of electromagnetic waves was theoretically predicted by
View answer and explanation
Correct option: B
Maxwell
Option B (Maxwell) is correct because James Clerk Maxwell theoretically predicted the existence of electromagnetic waves.
220 Medium
220 of 226
Understanding +4 | -1
A plane electromagnetic wave is incident on a material surface. If the wave delivers momentum pp and energy EE, then
View answer and explanation
Correct option: B
p≠0,E≠0p \ne 0,E \ne 0
Option B (p≠0,E≠0p \ne 0, E \ne 0) is correct because electromagnetic waves carry both momentum and energy, which they transfer upon incidence on a material surface.
221 Medium
221 of 226
Understanding +4 | -1
The frequency 1057 MHz1057 \mathrm{~MHz} of radiation arising from two close energy levels in hydrogen belongs to
View answer and explanation
Correct option: A
Radio waves
Option A is correct because a frequency of 1057 MHz corresponds to radio waves.
222 Medium
222 of 226
Application +4 | -1
A charged particle enters a uniform magnetic field with a velocity vector at an angle of 45∘45^\circ with the magnetic field. The pitch of the helical path followed by the particle is p. The radius of the helix will be
View answer and explanation
Correct option: C
p2π\frac{p}{{2\pi }}
Option C (p2π\frac{p}{{2\pi }}) is correct because it correctly relates the radius of the helix to the pitch using the given angle and the formulas for pitch and radius in a magnetic field.
223 Medium
223 of 226
Application +4 | -1
The dielectric constant of air is 1.006. The speed of electromagnetic wave travelling in air is a×108  ms−1a \times {10^8}\;m{s^{ - 1}}, where a is about
View answer and explanation
Correct option: A
3
Option A (3) is correct because the speed of electromagnetic waves in air is very close to the speed of light in a vacuum, which is approximately 3 × 108 m/s.
224 Medium
224 of 226
Understanding +4 | -1
An electromagnetic wave can be produced, when charge is
View answer and explanation
Correct option: D
Both 2 and 3
Option D is correct because an electromagnetic wave is produced when a charge is accelerated, which occurs when moving in a circular orbit or falling in an electric field.
225 Medium
225 of 226
Application +4 | -1
A plane electromagnetic wave is incident on a plane surface of area A, normally and is perfectly reflected. If energy E strikes the surface in time t then average pressure exerted on the surface is ( c=\mathrm{c}= speed of light)
View answer and explanation
Correct option: C
2E/Atc
Option C (2E/Atc) is correct because the average pressure exerted is twice the energy divided by the area, time, and speed of light, accounting for perfect reflection.
226 Medium
226 of 226
Understanding +4 | -1
A charged particle moving with constant acceleration produces
View answer and explanation
Correct option: D
electric field, magnetic field and electromagnetic wave
Option D (electric field, magnetic field and electromagnetic wave) is correct because an accelerating charged particle produces all three fields.
Revision notes and key takeaways

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