Question

A plane EM wave is propagating along $x$ direction. It has a wavelength of $4 \mathrm{~mm}$. If electric field is in $y$ direction with the maximum magnitude of $60 \mathrm{~Vm}^{-1}$, the equation for magnetic field is:

Accepted Answer

${B}_Z=2 	imes 10^{-7} \sin \left[\frac{\pi}{2} 	imes 10^3\left(x-3 	imes 10^8 tight)ight] \hat{k} \mathrm{~T}$

Answer

${B_Z}=60 \sin \left[\frac{\pi}{2}\left(x-3 	imes 10^8 tight)ight] \hat{{k}} \mathrm{~T}$

Answer

$B_X=60 \sin \left[\frac{\pi}{2}\left(x-3 	imes 10^8 tight)ight] \hat{i} \mathrm{~T}$

Answer

${B}_Z=2 	imes 10^{-7} \sin \left[\frac{\pi}{2}\left({x}-3 	imes 10^8 {t}ight)ight] \hat{{k}}\mathrm{~T}$

JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

More Questions from ELECTROMAGNETIC WAVES