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JEE • PHYSICS • ELECTROMAGNETIC WAVES

Electromagnetic waves practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 226 questions

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91 Medium
91 of 226
Understanding +4 | -1
An electromagnetic wave travels along zz-axis. Which of the following pairs of space and time varying fields would generate such a wave
View answer and explanation
Correct option: A
Ex,By{E_x},{B_y}
Option A (Ex,By{E_x},{B_y}) is correct because in an electromagnetic wave, the electric and magnetic fields are perpendicular to each other and to the direction of propagation.
92 Medium
92 of 226
Understanding +4 | -1
The electromagnetic waves do not transport
View answer and explanation
Correct option: B
Charge
Option B is correct because electromagnetic waves transport energy, momentum, and information, but they do not transport electric charge.
93 Medium
93 of 226
Understanding +4 | -1
The intensity contribution of electric field in the net intensity of EM wave is I. The value of half of intensity contribution due to magnetic field will be
View answer and explanation
Correct option: A
I2\frac{I}{2}
Option A (I2\frac{I}{2}) is correct because the intensity of the electric field and magnetic field are equal, and half of the magnetic field intensity is half of the total intensity.
94 Medium
94 of 226
Application +4 | -1
The reative permeability of glass is 3/8 and the dielectric constant of glass is 8. The refractive index of glass is
View answer and explanation
Correct option: B
1.732
Option B (1.732) is correct because the refractive index is calculated as the square root of the product of relative permeability and dielectric constant.
95 Medium
95 of 226
Understanding +4 | -1
Assertion: The average magnitude of Pointing vectors S→\overrightarrow{\mathrm{S}} is the intensity of electromagnetic wave.

Reason: Poynting vector is given by S→=E→×B→2μ0\overrightarrow{\mathrm{S}}=\frac{\overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{B}}}{2 \mu_0}.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C is correct because while the assertion is true, the reason provides an incorrect formula for the Poynting vector (missing the factor of 2).
96 Medium
96 of 226
Application +4 | -1
The intensity of sunlight (in W/m2\mathrm{W} / \mathrm{m}^2) at the solar surface will be
View answer and explanation
Correct option: B
5.6×1075.6 \times 10^7
Option B (5.6×1075.6 \times 10^7) is correct because it is the intensity calculated using the power of the sun and its surface area.
97 Medium
97 of 226
Understanding +4 | -1
Laser beams are used to measure long distance because
View answer and explanation
Correct option: D
They have high degree of parallelism
Option D (They have high degree of parallelism) is correct because laser beams maintain a narrow width over long distances due to their parallelism.
98 Medium
98 of 226
Understanding +4 | -1
Identify the correct statements from the following descriptions of various properties of electromagnetic waves.
(A) In a plane electromagnetic wave electric field and magnetic field must be perpendicular to each other and direction of propagation of wave should be along electric field or magnetic field.
(B) The energy in electromagnetic wave is divided equally between electric and magnetic fields.
(C) Both electric field and magnetic field are parallel to each other and perpendicular to the direction of propagation of wave.
(D) The electric field, magnetic field and direction of propagation of wave must be perpendicular to each other.
(E) The ratio of amplitude of magnetic field to the amplitude of electric field is equal to speed of light.
Choose the most appropriate answer from the options given below
View answer and explanation
Correct option: B
(B) and (D) only
Option B ((B) and (D) only) is correct because electromagnetic waves have perpendicular electric and magnetic fields, and energy is equally divided between them.
99 Medium
99 of 226
Remembering +4 | -1
The wavelength of infrared rays is of the order of
View answer and explanation
Correct option: C
Diverge more
Option B (10−3m{10^{ - 3}}\mathrm{m}) is correct because the wavelength of infrared rays falls in the range of approximately $700 nm$ to $1 mm$, which includes 10−3m10^{-3} m.
100 Medium
100 of 226
Application +4 | -1
In a uniform magnetic field of 10−5T{10^{ - 5}}T in free space, the energy density is u. The electric field which will produce the same energy density in free space is
View answer and explanation
Correct option: B
3×103V/m3 \times {10^3}V/m
Option B (3×103V/m3 \times {10^3}V/m) is correct because it correctly equates the energy density of the magnetic field to the energy density of the electric field and solves for the electric field strength.
101 Medium
101 of 226
Application +4 | -1
To establish an instantaneous displacement current of 2 A in the space between two parallel plates of 1 μF1\,\mu F plates will have to be changed at the rate of
View answer and explanation
Correct option: D
2×106Vs2 \times {10^6}\frac{V}{s}
Option D (2×106Vs2 \times {10^6}\frac{V}{s}) is correct because it is calculated using the formula relating displacement current, capacitance, and the rate of change of voltage.
102 Medium
102 of 226
Understanding +4 | -1
Maxwell’s set of equation encapsulated basic laws such as
View answer and explanation
Correct option: D
Both (1) and (2)
Option D (Both (1) and (2)) is correct because Maxwell's equations encapsulate Coulomb's law, Oersted's law, Ampere's law, and Faraday's law.
103 Medium
103 of 226
Understanding +4 | -1
The average value of electric energy density in an Electromagnetic Waves is (E0{E_0} is peak value)
View answer and explanation
Correct option: D
14ε0E02\frac{1}{4}{\varepsilon _0}E_0^2
Option D (14ε0E02\frac{1}{4}{\varepsilon _0}E_0^2) is correct because the average electric energy density in an electromagnetic wave is half of the product of the permittivity of free space and the square of the RMS electric field, which is 14ε0E02\frac{1}{4}{\varepsilon _0}E_0^2.
104 Medium
104 of 226
Remembering +4 | -1
Which of the following shows green house effect
View answer and explanation
Correct option: B
Infrared rays
Option B (Infrared rays) is correct because infrared rays are absorbed by greenhouse gases in the atmosphere, trapping heat and causing the greenhouse effect.
105 Medium
105 of 226
Application +4 | -1
The magnetic field between the plate of a capacitor where r>Rr > R is given by (where rr is the distance from the axis of plates and RR is the radius of each plate of capacitor)
View answer and explanation
Correct option: C
μ0iD2πr\frac{{{\mathrm{\mu }_0}{i_D}}}{{2\mathrm{\pi }r}}
Option B (16B016 B_0) is correct because the magnetic field at the center of the coil increases by a factor of n2n^2 when the number of turns is increased to n, while keeping the current constant.
106 Medium
106 of 226
Application +4 | -1
A point source of electromagnetic radiation has an average power output of 1500 W1500 \mathrm{~W}. The maximum value of electric field at a distance of 3 m3 \mathrm{~m} from this sources in Vm−1\mathrm{Vm}^{-1} is
View answer and explanation
Correct option: B
100
Option B (100) is correct because it is the maximum electric field calculated from the average power output at a given distance.
107 Medium
107 of 226
Understanding +4 | -1
Which of the following statement is false for the properties of electromagnetic waves?
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Correct option: D
Both electric and magnetic field vectors are parallel to each other and perpendicular to the direction of propagation of wave
Option D (Both electric and magnetic field vectors are parallel to each other and perpendicular to the direction of propagation of wave) is false because electric and magnetic fields in an EM wave are perpendicular to each other.
108 Medium
108 of 226
Remembering +4 | -1
The decreasing order of wavelength of infrared, microwave, ultraviolet and gamma rays is
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Correct option: A
microwave, infrared, ultraviolet, gamma rays
Option A (microwave, infrared, ultraviolet, gamma rays) is correct because it represents the electromagnetic spectrum in decreasing order of wavelength.
109 Medium
109 of 226
Application +4 | -1
Dimensions of ε0 dϕ/dt\varepsilon_0 \mathrm{~d} \phi / \mathrm{dt} is
View answer and explanation
Correct option: A
Ampere
Option A (Ampere) is correct because the dimensions of ε0dϕ/dt\varepsilon_0 d\phi / dt represent displacement current, which has the same units as current (Ampere).
110 Medium
110 of 226
Remembering +4 | -1
The infra-red spectrum lies between
View answer and explanation
Correct option: B
the micro-wave and visible region
Option B (the micro-wave and visible region) is correct because the infrared spectrum lies between the microwave and visible regions of the electromagnetic spectrum.
111 Medium
111 of 226
Understanding +4 | -1
If a free electron is placed in the path of a plane electromagnetic wave, it will start moving along
View answer and explanation
Correct option: D
Electric field
Option D (Electric field) is correct because a free electron experiences a force due to the electric field component of an electromagnetic wave.
112 Medium
112 of 226
Remembering +4 | -1
Which of the following electromagnetic waves have minimum frequency
View answer and explanation
Correct option: B
Audible waves
Option D (Radiowaves) is correct because radiowaves have the lowest frequency among the given electromagnetic waves.
113 Medium
113 of 226
Application +4 | -1
A plane EM wave is propagating along xx direction. It has a wavelength of 4 mm4 \mathrm{~mm}. If electric field is in yy direction with the maximum magnitude of 60 Vm−160 \mathrm{~Vm}^{-1}, the equation for magnetic field is:
View answer and explanation
Correct option: B
BZ=2×10−7sin⁡[π2×103(x−3×108t)]k^ T{B}_Z=2 \times 10^{-7} \sin \left[\frac{\pi}{2} \times 10^3\left(x-3 \times 10^8 t\right)\right] \hat{k} \mathrm{~T}
Option B (BZ=2×10−7sin⁡[π2×103(x−3×108t)]k^ T{B}_Z=2 \times 10^{-7} \sin \left[\frac{\pi}{2} \times 10^3\left(x-3 \times 10^8 t\right)\right] \hat{k} \mathrm{~T}) is correct because it represents the magnetic field component of the EM wave, calculated using the relationship between electric and magnetic field amplitudes and the wave's propagation characteristics.
114 Medium
114 of 226
Understanding +4 | -1
Statement I: Microwaves have more energy than the radio waves

Statement II: Microwaves have greater wavelength than the radiowaves
View answer and explanation
Correct option: B
Statement I is true; statement II is false
Option B is correct because microwaves have higher frequency and therefore more energy than radio waves, and wavelength is inversely proportional to frequency.
115 Medium
115 of 226
Remembering +4 | -1
Which of the following rays is emitted by a human body?
View answer and explanation
Correct option: D
IR rays
Option D (IR rays) is correct because the human body emits infrared radiation due to its temperature.
116 Medium
116 of 226
Application +4 | -1
A point source is placed at origin. Its intensity at distance of 2 cm2 \mathrm{~cm} from source is II then intensity at distance 4 cm4 \mathrm{~cm} from the source shall be.
View answer and explanation
Correct option: C
I4\frac{I}{4}
Option C (I4\frac{I}{4}) is correct because the intensity of a point source decreases with the square of the distance from the source.
117 Medium
117 of 226
Remembering +4 | -1
Ozone layer blocks the radiations of wavelength
View answer and explanation
Correct option: B
Equal to 3×10−73 \times {10^{ - 7}}m
Option A (Less than 3×10−73 \times {10^{ - 7}}m) is incorrect. Ozone layer blocks the radiations of wavelength less than 3×10−73 \times {10^{ - 7}}m.
118 Medium
118 of 226
Analyzing +4 | -1
An EM wave from air enters a medium. The electric fields are E1=E01x^cos⁡[2πv(zc−t)]{E_1} = {E_{01}}\hat x\cos \left[ {2\pi v\left( {\frac{z}{c} - t} \right)} \right] in air and E2=E02x^cos⁡[k(2z−ct)]{E_2} = {E_{02}}\hat x\cos \left[ {k\left( {2z - ct} \right)} \right] in medium, where the wave number k and frequency ν refer to their values in air. The medium is non-magnetic.
If εr1{\varepsilon _{{r_1}}} and εr2{\varepsilon _{{r_2}}} refer to relative permittivities of air and medium respectively, which of the following options is correct?
View answer and explanation
Correct option: C
εr1εr2=14\frac{{{\varepsilon _{{r_1}}}}}{{{\varepsilon _{{r_2}}}}} = \frac{1}{4}
Option C (εr1εr2=14\frac{{\varepsilon _{{r_1}}}}{{\varepsilon _{{r_2}}}} = \frac{1}{4}) is correct because the ratio of relative permittivities is inversely proportional to the square of the ratio of speeds.
119 Medium
119 of 226
Understanding +4 | -1
Radio waves and visible light in vacuum have
View answer and explanation
Correct option: A
Same velocity but different wavelength
Option A (Same velocity but different wavelength) is correct because all electromagnetic waves travel at the speed of light in a vacuum, but have different wavelengths and frequencies.
120 Medium
120 of 226
Application +4 | -1
The magnetic field of a beam emerging from a filter facing a floodlight is given by

B0=12×10−8sin⁡(1.20×107z−3.60×1015t)T\mathrm{B}_0=12 \times 10^{-8} \sin ( 1.20 \times 10^7 \mathrm{z} \left.-3.60 \times 10^{15} \mathrm{t}\right) \mathrm{T}.

What is the average intensity of the beam?
View answer and explanation
Correct option: A
1.71
Option A (1.71) is correct because it is calculated using the formula for the average intensity of an electromagnetic wave.
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