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JEE • PHYSICS • ELECTROMAGNETIC WAVES

Electromagnetic waves practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 226 questions
61 Medium
61 of 226
Understanding +4 | -1
In an electromagnetic wave, the direction of the magnetic field induction B⃗\vec{B} is
View answer and explanation
Correct option: B
Perpendicular to electric field E⃗\vec{E}
Option B (Perpendicular to electric field E⃗\vec{E}) is correct because in an electromagnetic wave, the electric and magnetic fields are perpendicular to each other and to the direction of propagation.
62 Medium
62 of 226
Remembering +4 | -1
The electromagnetic waves generally used in the purification of water are
View answer and explanation
Correct option: C
Ultra violet rays
Option C (Ultra violet rays) is correct because ultraviolet (UV) rays are commonly used for water purification due to their ability to kill bacteria and viruses.
63 Medium
63 of 226
Understanding +4 | -1
Which of the following electromagnetic wave play an important role in maintaining the earth’s warmth or average temperature through the greenhouse effect?
View answer and explanation
Correct option: B
Infrared waves
Option B (Infrared waves) is correct because infrared radiation is responsible for the greenhouse effect, trapping heat and maintaining Earth's temperature.
64 Medium
64 of 226
Application +4 | -1
Find the displacement current developed in the space between the plates of parallel plate capacitor of capacity 2μF2 \mu \mathrm{F} when voltage is changing at a rate of 106Vs−1.10^6 \mathrm{Vs}^{-1}.
View answer and explanation
Correct option: A
0.083333333
Option C (2 mA) is correct because the displacement current is calculated using the formula id=CdVdti_d = C \frac{dV}{dt}.
65 Medium
65 of 226
Remembering +4 | -1
Which rays are not part of electromagnetic spectrum?
View answer and explanation
Correct option: B
α−rays\alpha - {\text{rays}}
Option B (α−rays\alpha - {\text{rays}}) is correct because alpha rays are not part of the electromagnetic spectrum; they are particles.
66 Medium
66 of 226
Remembering +4 | -1
The part of the spectrum of the electromagnetic radiation used to cook food is
View answer and explanation
Correct option: D
Microwaves
Option D (Microwaves) is correct because microwaves are used in microwave ovens to cook food.
67 Medium
67 of 226
Application +4 | -1
The wave function (in S.I units) for an electromagnetic wave is given as −ψ(X,t)=103sin⁡π(3×106X−9×1014t)- \psi \left( {X,t} \right) = {10^3}\sin \pi \left( {3 \times {{10}^6}X - 9 \times {{10}^{14}}t} \right). The speed of wave is :
View answer and explanation
Correct option: B
3×108 m/s3 \times {10^8}\,m/s
Option B (3×108 m/s3 \times {10^8}\,m/s) is correct because the speed of the wave is calculated by dividing the angular frequency by the wave number, which results in the speed of light.
68 Medium
68 of 226
Application +4 | -1
The charge of a parallel plate capacitor is varying as q=q0sin⁡2πftq = {q_0}\sin 2\pi ft. The plates are very large and close together (area=A= A, separation=d= d). Neglecting edge effects, the displacement current through the capacitor is
View answer and explanation
Correct option: C
2πfq0cos⁡2πft2\pi f{q_0}\cos 2\pi ft
Option C (2πfq0cos⁡2πft2\pi f{q_0}\cos 2\pi ft) is correct because the displacement current is the time derivative of the charge.
69 Medium
69 of 226
Remembering +4 | -1
The electromagnetic waves travel with a velocity
View answer and explanation
Correct option: B
Equal to velocity of light
Option B (Equal to velocity of light) is correct because electromagnetic waves, by definition, travel at the speed of light in a vacuum.
70 Medium
70 of 226
Application +4 | -1
Find the values of magnetic field between plates of capacitor at distance 1 m1 \mathrm{~m} from centre where electric field varies by 101010^{10} volt /m/s/ \mathrm{m} / \mathrm{s}.
View answer and explanation
Correct option: A
5.56×10−8 T5.56 \times 10^{-8} \mathrm{~T}
Option A (5.56×10−8 T5.56 \times 10^{-8} \mathrm{~T}) is correct because it is calculated using the formula for the magnetic field between the plates of a capacitor due to the changing electric field.
71 Medium
71 of 226
Understanding +4 | -1
Assertion: During discharging there is magneticfield between plates of capacitor.

Reason : Time varying electric field produces magnetic field.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because a time-varying electric field between the capacitor plates during discharging produces a magnetic field, as described by Maxwell's equations.
72 Medium
72 of 226
Understanding +4 | -1
Which of the following statements about electromagnetic waves is/are correct?

(1) X-rays in vacuum travel faster than light waves in vacuum.

(2) The energy of X-ray photon is greater than that of a light photon

(3) Light can be polarised but X-ray cannot.
View answer and explanation
Correct option: D
2 only
Option D (2 only) is correct because X-rays and light waves travel at the same speed in a vacuum, and both can be polarized, but X-ray photons have higher energy than light photons.
73 Medium
73 of 226
Remembering +4 | -1
A radar sends the waves towards a distant object and receives the signal reflected by object. These waves are
View answer and explanation
Correct option: D
Micro waves
Option D (Micro waves) is correct because radar systems typically use microwaves to detect distant objects due to their ability to penetrate atmospheric conditions and reflect off targets.
74 Medium
74 of 226
Application +4 | -1
The maximum electric field in a plane electromagnetic wave is 600 NC−1600 \mathrm{~NC}^{-1}. The wave is going in the xx-direction and the electric field is in the yy-direction. Find the maximum magnetic field in the wave and its direction.
View answer and explanation
Correct option: A
2×10−6 T,z2 \times 10^{-6} \mathrm{~T}, z-direction
Option A (2×10−6 T,z2 \times 10^{-6} \mathrm{~T}, z-direction) is correct because it's calculated using the relationship between electric and magnetic field amplitudes in an electromagnetic wave, and the direction is determined by the wave's propagation and electric field directions.
75 Medium
75 of 226
Understanding +4 | -1
What physical quantity is the same for X\mathrm{X}-rays of wavelength 10−10 m{10^{-10}} \mathrm{~m}, red light of wavelength 6800 A∘6800 ~\mathop {\text{A}}\limits^ \circ, and radiowaves of wavelength 500 m500 \mathrm{~m}?
View answer and explanation
Correct option: A
3×108 m s−13 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1}
Option A (3×108 m s−13 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1}) is correct because the speed of all electromagnetic waves in a vacuum is constant and equal to the speed of light.
76 Medium
76 of 226
Understanding +4 | -1
An electromagnetic wave is propagating along Y\mathrm{Y}-axis. Then
View answer and explanation
Correct option: B
Oscillating electric field is along Z\mathrm{Z}-axis and oscillating magnetic field is along X\mathrm{X}-axis.
Option B is correct because in an electromagnetic wave, the electric and magnetic fields are perpendicular to each other and to the direction of propagation.
77 Medium
77 of 226
Application +4 | -1
50W/m250\mathrm{ W/}{\mathrm{m}^2} energy density of sunlight is normally incident on the surface of a solar panel. Some part of incident energy (25%) is reflected from the surface and the rest is absorbed. The force exerted on 1m2\mathrm{1 }{\mathrm{m}^\mathrm{2}} surface area will be close to (c=3×108  m/s)(c = 3 \times {10^8}{\rm\,\,{m/s)}}
View answer and explanation
Correct option: A
20×10−8N20 \times {10^{ - 8}}\mathrm{N}
Option A (20×10−8N20 \times {10^{ - 8}}\mathrm{N}) is correct because it calculates the force exerted by the sunlight considering both the absorbed and reflected portions of the incident energy.
78 Medium
78 of 226
Remembering +4 | -1
For an electromagnetic wave traveling in free space
View answer and explanation
Correct option: A
E0=cB0E_0=c B_0
Option A (E0=cB0E_0=c B_0) is correct because it represents the relationship between the electric field amplitude (E0E_0) and magnetic field amplitude (B0B_0) in an electromagnetic wave traveling in free space, where c is the speed of light.
79 Medium
79 of 226
Understanding +4 | -1
An EM wave radiates outwards from a dipole antenna with E0E_0 as the amplitude of its electric field vector. The electric field E0E_0 which transports significant energy from the source falls off as
View answer and explanation
Correct option: C
1/r1 / r
Option C (1/r1 / r) is correct because the electric field amplitude from a dipole antenna falls off inversely with distance.
80 Medium
80 of 226
Understanding +4 | -1
Assertion: A changing electric-field produces a magnetic field.

Reason: A changing magnetic field produces an electric field.
View answer and explanation
Correct option: B
Both Assertion and reason are true, but reason is not the correct explanation of Assertion.
Option B is correct because both a changing electric field produces a magnetic field, and a changing magnetic field produces an electric field, but the latter doesn't explain the former.
81 Medium
81 of 226
Application +4 | -1
Consider an electric charge oscillating with a frequency o 10MHz10 \mathrm{MHz}. The radiation emitted will have a wavelength equal to
View answer and explanation
Correct option: C
40 m40 \mathrm{~m}
Option B (30 m30 \mathrm{~m}) is correct because the wavelength of the emitted radiation is calculated using the speed of light and the given frequency.
82 Medium
82 of 226
Remembering +4 | -1
The speed of electromagnetic wave is
View answer and explanation
Correct option: C
1/(ε0μ0)1/21 /\left(\varepsilon_0 \mu_0\right)^{1 / 2}
Option C (1/(ε0μ0)1/21 /\left(\varepsilon_0 \mu_0\right)^{1 / 2}) is correct because the speed of an electromagnetic wave is inversely proportional to the square root of the product of permittivity and permeability.
83 Medium
83 of 226
Understanding +4 | -1
If ε0{\varepsilon _0} and μ0{\mu _0} represent the permittivity and permeability of vacuum and ε\varepsilon and μ\mu represent the permittivity and permeability of medium, then refractive index of the medium is given by
View answer and explanation
Correct option: B
μεμ0ε0\sqrt {\frac{{\mathrm{\mu \varepsilon }}}{{{\mathrm{\mu }_0}{\mathrm{\varepsilon }_0}}}}
Option B is correct because the refractive index is the ratio of the speed of light in vacuum to the speed of light in the medium, which is related to the permittivity and permeability of both.
84 Medium
84 of 226
Remembering +4 | -1
Which of the following is absorbed by the ozone layer?
View answer and explanation
Correct option: D
Ultraviolet rays
Option D (Ultraviolet rays) is correct because the ozone layer in the Earth's atmosphere absorbs a significant portion of the Sun's ultraviolet radiation.
85 Medium
85 of 226
Understanding +4 | -1
Which of the following is/are the property/properties of a monochromatic electromagnetic wave propagating in the free space?

I. Electric and magnetic fields will have a phase difference π2\frac{\pi}{2}.

II. The energy of the wave is distributed equally between electric and magnetic fields.

III. The pressure exerted by the wave is the product of its speed and energy density.

IV. The speed of the wave is equal to the ratio of the magnetic field to the electric field.
View answer and explanation
Correct option: B
Only II
Option B is correct because only statement II is true: the energy of an electromagnetic wave is equally distributed between electric and magnetic fields.
86 Medium
86 of 226
Remembering +4 | -1
The velocity of electromagnetic radiation in a medium of permittivity ε0{\varepsilon _0} and permeability μ0{\mu _0} is given by
View answer and explanation
Correct option: C
1μ0∈0\frac{1}{{\sqrt {{\mu _0}{ \in _0}} }}
Option C (1μ0∈0\frac{1}{{\sqrt {{\mu _0}{ \in _0}} }}) is correct because the velocity of electromagnetic radiation is inversely proportional to the square root of the product of permittivity and permeability.
87 Medium
87 of 226
Understanding +4 | -1
Assertion: MRI is an excellent method to find problem in internal tissues.

Reason : Two third of the human body is made up of hydrogen which has one electron.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because MRI relies on the abundance of hydrogen atoms in the body, which have a single electron and thus a magnetic moment.
88 Medium
88 of 226
Understanding +4 | -1
If ε0{\varepsilon _0} and μ0{\mu _0} are respectively, the electric permittivity and the magnetic permeability of free space, ε\varepsilon and μ\mu the corresponding quantities in a medium, the refractive index of the medium is
View answer and explanation
Correct option: A
μ εμ0 ε0\sqrt {\frac{{\mu \,\varepsilon }}{{{\mu _0}\,{\varepsilon _0}}}}
Option A (μ εμ0 ε0\sqrt {\frac{{\mu \,\varepsilon }}{{{\mu _0}\,{\varepsilon _0}}}}) is correct because the refractive index is the square root of the ratio of the product of permeability and permittivity of the medium to that of free space.
89 Medium
89 of 226
Understanding +4 | -1
The idea of the quantum nature of light has emerged in an attempt to explain
View answer and explanation
Correct option: C
Radiation spectrum of a black body
The correct answer is C (Radiation spectrum of a black body) because the quantum nature of light was proposed to explain the blackbody radiation spectrum.
90 Medium
90 of 226
Understanding +4 | -1
Identify the mismatched pair in electromagnetic wave spectrum
View answer and explanation
Correct option: C
Microwaves: To destroy cancer cells
Option C (Microwaves: To destroy cancer cells) is correct because microwaves are not typically used to destroy cancer cells; X-rays and gamma rays are used for that purpose.
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