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JEE • PHYSICS • ELECTRO MAGNETIC INDUCTION

Electro magnetic induction practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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91 Medium
91 of 295
Application +4 | -1
A coil of cross-sectional area A having n turns is placed in a uniform magnetic field B. When it is rotated with an angular velocity ω\omega, the maximum e.m.f. induced in the coil will be
View answer and explanation
Correct option: A
nBAωnBA\omega
Option A (nBAωnBA\omega) is correct because it is the formula for the maximum induced emf in a rotating coil in a magnetic field.
92 Hard
92 of 295
Analyzing +4 | -1
A wire of given length is bent in the form of a ring of diameter 2 a having self inductance (L)(L), then LL will depend upon following
View answer and explanation
Correct option: A
L∝a−1L \propto a^{-1}
Option A is correct because the self-inductance L of a ring depends inversely on its radius (or diameter), hence L∝a−1L \propto a^{-1}.
93 Medium
93 of 295
Understanding +4 | -1
The expression for the induced emf contains negative sign (E=−dϕdt)\left(\mathrm{E}=\frac{-\mathrm{d} \phi}{\text {dt}}\right). What is the significance of negative sign?
View answer and explanation
Correct option: B
The induced emf opposes the change in the magnetic flux
Option B (The induced emf opposes the change in the magnetic flux) is correct because Lenz's law states that the induced emf opposes the change in magnetic flux that produces it.
94 Medium
94 of 295
Application +4 | -1
A loop of area 1 m21 \mathrm{~m}^2 is placed in a magnetic field B=2 TB=2 \mathrm{~T}, such that plane of the loop is parallel to the magnetic field. If the loop is rotated by 180∘180^{\circ}, the amount of net charge passing through any point of loop, if its resistance is 10Ω10 \Omega, is
View answer and explanation
Correct option: A
0.4 C0.4 \mathrm{~C}
Option A (0.4 C) is correct because the net charge passing through the loop is calculated using the change in magnetic flux and the resistance of the loop.
95 Medium
95 of 295
Application +4 | -1
A planar loop of wire rotates in a uniform magnetic field. Initially at t=0t = 0, the plane of the loop is perpendicular to the magnetic field. If it rotates with a period of 10 s about an axis in its plane, then the magnitude of induced emf will be maximum and minimum respectively at
View answer and explanation
Correct option: D
2.5 s and 5.0 s
Option D (2.5 s and 5.0 s) is correct because the induced emf is maximum when the plane of the loop is parallel to the magnetic field (t=2.5s) and minimum when it is perpendicular (t=5.0s).
96 Medium
96 of 295
Understanding +4 | -1
The inductance L\mathrm{L} of a solenoid depends upon its radius R\mathrm{R} as
View answer and explanation
Correct option: C
L∝R2\mathrm{L} \propto \mathrm{R}^2
Option C is correct because the inductance of a solenoid is proportional to the square of its radius, as shown in the formula L=μ0N2Al=μ0N2πR2lL = \frac{{\mu_0 N^2 A}}{l} = \frac{{\mu_0 N^2 \pi R^2}}{l}.
97 Medium
97 of 295
Application +4 | -1
In an inductor, the current I\mathrm{I} varies with time t as I=4+4t\mathrm{I=4+4 t}. If the emf induced in the inductor is 8 mV8 \mathrm{~mV}, what is self inductance? (Here current is in ampere and time is in second)
View answer and explanation
Correct option: D
2×10−3 H2 \times 10^{-3} \mathrm{~H}
Option D (2×10−3 H2 \times 10^{-3} \mathrm{~H}) is correct because it is the self-inductance calculated using the formula ∣e∣=LdIdt|e| = L \frac{dI}{dt}.
98 Medium
98 of 295
Remembering +4 | -1
Weber/m2Weber/{m^2} is equal to
View answer and explanation
Correct option: C
TeslaTesla
Option C (Tesla) is correct because Tesla is the SI unit of magnetic flux density (magnetic field strength), which is equivalent to Weber per square meter (Weber/m2Weber/{m^2}).
99 Medium
99 of 295
Application +4 | -1
If the magnetic flux through a coil at any time t\mathrm{t} is given by ϕ=(4t2+5t−3)\phi=\left(4 \mathrm{t^2+5 t}-3\right), then the increase in induced emf (in volt) 2 second after t=0\mathrm{t}=0 is
View answer and explanation
Correct option: B
16
Option B (16) is correct because it represents the difference in induced EMF calculated at t=2s and t=0s, based on the given flux equation.
100 Medium
100 of 295
Understanding +4 | -1
The magnetic flux linked with a coil of N turns of area of cross section A held with its plane parallel to the field B is
View answer and explanation
Correct option: D
0
Option D (0) is correct because the magnetic flux is zero when the plane of the coil is parallel to the magnetic field.
101 Easy
101 of 295
Understanding +4 | -1
Eddy current are produced when
View answer and explanation
Correct option: A
metal is kept in varying magnetic field
Option A (metal is kept in varying magnetic field) is correct because eddy currents are induced in a conductor when it experiences a changing magnetic field.
102 Medium
102 of 295
Understanding +4 | -1
The coil of dynamo is rotating in a magnetic field. The developed induced e.m.f. changes and the number of magnetic lines of force also changes. Which of the following conditions is correct
View answer and explanation
Correct option: B
Lines of force maximum but induced e.m.f. is zero
Option B (Lines of force maximum but induced e.m.f. is zero) is correct because the induced EMF is proportional to the rate of change of magnetic flux, which is zero when the flux is at its maximum.
103 Medium
103 of 295
Understanding +4 | -1
The total charge, induced in a conducting loop, when it is moved in a magnetic field depends on
View answer and explanation
Correct option: C
Total change in magnetic flux and resistance
Option C (Total change in magnetic flux and resistance) is correct because the induced charge depends on the total change in magnetic flux and the resistance of the loop, as given by Q=ΔΦRQ = \frac{{\Delta \Phi}}{R}.
104 Medium
104 of 295
Understanding +4 | -1
When a bar magnet falls through a long hollow metal cylinder fixed with its axis vertical, the final acceleration of the magnet is
View answer and explanation
Correct option: A
Equal to zero
Option A (Equal to zero) is correct because as the bar magnet falls, eddy currents are induced in the metal cylinder, creating a retarding force that eventually balances the weight of the magnet, resulting in zero net acceleration.
105 Medium
105 of 295
Application +4 | -1
Self inductance of primary and secondary of a perfectly coupled coils are 4 mH4 \mathrm{~mH} and 9 mH9 \mathrm{~mH} respectively. The coefficient of mutual inductance between them is
View answer and explanation
Correct option: D
6 mH6 \mathrm{~mH}
Option D (6 mH) is correct because the mutual inductance between perfectly coupled coils is given by the square root of the product of their self-inductances.
106 Medium
106 of 295
Remembering +4 | -1
The direction of magnetic lines of force produced by passing a direct current in a conductor is given by
View answer and explanation
Correct option: C
Right hand palm rule
The correct answer is C (Right hand palm rule) because the right-hand palm rule is used to determine the direction of the magnetic field around a current-carrying conductor.
107 Medium
107 of 295
Application +4 | -1
Two concentric circular coils, one of small radius r\mathrm{r} and the other of large radius R\mathrm{R} are placed co-axially with centers coinciding. If the radius r\mathrm{r} is changed by 2%2 \%, then the change in mutual inductance of the arrangement is (Assume, r<<R\mathrm{r} << \mathrm{R})
View answer and explanation
Correct option: C
4%4 \%
Option C (4%) is correct because the mutual inductance is proportional to the square of the radius, so a 2% change in radius results in a 4% change in mutual inductance.
108 Medium
108 of 295
Understanding +4 | -1
Assertion: Induced electric field lines form closed loops in space.

Reason : Induced electric field lines do not originate & terminate at charged particle.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
Option A is correct because induced electric fields are non-conservative and form closed loops, originating from changing magnetic fields, not charges.
109 Hard
109 of 295
Application +4 | -1
A uniformly wound solenoid coil of self-inductance 1.8×  10−4 H1.8 \times \,\,{10^{ - 4}}\,\mathrm{H} and resistance 6  Ω\mathrm{6}\,\,\mathrm{\Omega } is broken up into two identical coils. These identical coils are then connected in parallel across a 12  V\mathrm{12}\,\,\mathrm{V} battery of negligible resistance. The time constant for the current in the circuit is
View answer and explanation
Correct option: C
0.3  ×10−4 s0.3\,\, \times {10^{ - 4}}\,\mathrm{s}
Option C (0.3 ×10−4 s0.3\, \times {10^{ - 4}}\,\mathrm{s}) is correct because it is the time constant calculated after breaking the coil and connecting them in parallel.
110 Medium
110 of 295
Remembering +4 | -1
Which of the following is constructed on the principle of electromagnetic induction
View answer and explanation
Correct option: C
Generator
Option C (Generator) is correct because generators operate on the principle of electromagnetic induction, converting mechanical energy into electrical energy.
111 Hard
111 of 295
Application +4 | -1
A coil of 'n\mathrm{n}' turns and resistance 'R\mathrm{R}' Ω\Omega is connected in series with a resistance R2\frac{\mathrm{R}}{2}. The combination is moved for time 't\mathrm{t}' second through magnetic flux ϕ1\phi_1 to ϕ2\phi_2. The induced current in the circuit is
View answer and explanation
Correct option: D
2n(ϕ1−ϕ2)3Rt\frac{2 \mathrm{n}\left(\phi_1-\phi_2\right)}{3 \mathrm{Rt}}
Option D (2n(ϕ1−ϕ2)3Rt\frac{{2 \mathrm{n}(\phi_1-\phi_2)}}{{3 \mathrm{Rt}}}) is correct because it is derived from calculating the induced emf and then dividing by the total resistance of the circuit.
112 Medium
112 of 295
Application +4 | -1
A solenoid of radius 4 cm4 \mathrm{~cm} and 1000 turns, carries a current of 8 A8 \mathrm{~A}. If it is equivalent to a magnet of same size and magnetization M⃗\vec{M} (Magnetic moment/Volume) of 2000 Am−12000 \, \mathrm{Am}^{-1}, then the length of the solenoid is
View answer and explanation
Correct option: D
40 cm40 \mathrm{~cm}
Option D (40 cm40 \mathrm{~cm}) is correct because it is the length of the solenoid calculated by equating its magnetic moment to that of an equivalent magnet.
113 Medium
113 of 295
Application +4 | -1
A conducting rod of length L\mathrm{L} is moving in a uniform magnetic field (B)(\mathrm{B}) with a velocity v\mathrm{v} without rotation. The velocity of the rod is perpendicular to the rod, and the motion of the rod is confined to a plane perpendicular to the magnetic field. What is the induced emf developed across the rod?
View answer and explanation
Correct option: A
BLv\mathrm{BLv}
The correct answer is A (BLv) because the induced emf in a moving conductor is given by the formula emf = BLv when the magnetic field, length, and velocity are mutually perpendicular.
114 Medium
114 of 295
Application +4 | -1
A wheel with ten metallic spokes each 0.5 m long is rotated with a speed of 120 rev/min in a plane normal to the earths magnetic field at the place. If the magnitude of the field is 0.4 gauss, the induced e.m.f between the axle and the rim of the wheel is equal to
View answer and explanation
Correct option: D
6.28×10−5 V6.28 \times {10^{ - 5}}\,V
Option D (6.28×10−5 V6.28 \times {10^{ - 5}}\,V) is correct because it correctly applies the formula for induced EMF in a rotating rod within a magnetic field.
115 Easy
115 of 295
Understanding +4 | -1
The relation between the charge flow ΔQ\Delta \mathrm{Q} through the circuit of resistance r\mathrm{r} and the change in the magnetic flux ΔϕB\Delta \phi_{\mathrm{B}} is
View answer and explanation
Correct option: A
ΔQ=ΔϕBr\Delta \mathrm{Q}=\frac{\Delta \phi_{\mathrm{B}}}{\mathrm{r}}
Option A (ΔQ=ΔϕBr\Delta Q=\frac{{\Delta \phi_B}}{{r}}) is correct because the charge flow is related to the change in magnetic flux and resistance by this equation, derived from Faraday's law and Ohm's law.
116 Medium
116 of 295
Application +4 | -1
A primary coil and secondary coil are placed close to each other. A current, which changes at the rate of 25 A25 \mathrm{~A} in a millisecond, is present in the primary coil. If the mutual inductance is 92×10−6 H{92}\times 10^{-6} \mathrm{~H}, then the value of induced emf in the secondary coil is
View answer and explanation
Correct option: B
2.3 V2.3 \mathrm{~V}
Option C (L/R  sec⁡L/R\,\,\sec) is correct because it represents the time constant for an LR circuit, which determines how quickly the current decays.
117 Medium
117 of 295
Application +4 | -1
A small coil of radius rr is placed at the centre of a large coil of radius RR, where R>>rR > > r. The two coils are coplanar. The mutual induction between the coils is proportional to
View answer and explanation
Correct option: B
r2/Rr^2 / R
Option B (r2/Rr^2 / R) is correct because the mutual inductance between two coplanar coils, where one is much smaller than the other, is proportional to the area of the smaller coil divided by the radius of the larger coil.
118 Easy
118 of 295
Application +4 | -1
Current in a coil changes from 5  A\mathrm{5}\,\,\mathrm{A} to 10  A\mathrm{10}\,\,\mathrm{A} in 0.2  s\mathrm{0}.\mathrm{2}\,\,\mathrm{s}. If the coefficient of self-induction is 10  H\mathrm{10}\,\,\mathrm{H}, then the induced emf is
View answer and explanation
Correct option: B
250  V\mathrm{250}\,\,\mathrm{V}
Option B (250 V\mathrm{250}\,\mathrm{V}) is correct because it's calculated directly using the formula for induced emf, e=LdIdte = L \frac{{dI}}{{dt}}.
119 Medium
119 of 295
Remembering +4 | -1
Which of the following phenomena is utilised in the construction of mouth piece of a telephone now a days?
View answer and explanation
Correct option: C
Change of resistance with pressure
Option C (Change of resistance with pressure) is correct because modern telephone mouthpieces use a carbon microphone, which relies on the change in resistance of carbon granules due to the pressure of sound waves.
120 Medium
120 of 295
Understanding +4 | -1
Two identical induction coils each of inductance LL joined in series are placed very close to each other such that the winding direction of one is exactly opposite to that of the other, what is the net inductance?
View answer and explanation
Correct option: D
Zero
Option D is correct because when two identical coils are wound in opposite directions, their magnetic fields cancel each other, resulting in zero net inductance.
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