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JEE • PHYSICS • ELECTRO MAGNETIC INDUCTION

Electro magnetic induction practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 295 questions

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31 Medium
31 of 295
Understanding +4 | -1
If a copper ring is moved quickly towards south pole of a powerful stationary bar magnet, then
View answer and explanation
Correct option: A
Current flows through the copper ring
Option A is correct because the changing magnetic flux through the copper ring induces a current according to Faraday's law of electromagnetic induction.
32 Medium
32 of 295
Analyzing +4 | -1
Assertion: In L−R\mathrm{L}-\mathrm{R} circuit, if higher value of L\mathrm{L} is taken then it will take more time to reach steady state value of current.

Reason : For higher value of L\mathrm{L}, back emf is larger.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C (If Assertion is True but the Reason is False) is correct because a higher inductance does increase the time constant, but the back emf is larger, which is why it takes longer to reach steady state.
33 Easy
33 of 295
Understanding +4 | -1
When the rate of change of current is unity, induced emf is equal to
View answer and explanation
Correct option: C
Coefficient of self-induction
Option C (Coefficient of self-induction) is correct because the induced emf is equal to the coefficient of self-induction when the rate of change of current is unity.
34 Medium
34 of 295
Application +4 | -1
A solid metal cube of edge length 2 cm is moving in a positive Y-direction at a constant speed of 6 m/s. There is a uniform magnetic field of 0.1 T in the positive Z-direction. The potential difference between the two faces of the cube perpendicular to the X-axis is
View answer and explanation
Correct option: B
12 mV
Option B (12 mV) is correct because it is the potential difference calculated using the formula V = Blv, where B is the magnetic field, l is the length, and v is the velocity.
35 Medium
35 of 295
Application +4 | -1
A metal disc of radius RR rotates with an angular velocity ω\omega about an axis perpendicular to its plane passing through its centre in a magnetic field BB acting perpendicular to the plane of the disc. Calculate the induced emf between the rim and the axis of the disc.
View answer and explanation
Correct option: D
12BR2ω\frac{1}{2} B R^2 \omega
Option D (12BR2ω\frac{1}{2} B R^2 \omega) is correct because the induced emf between the rim and the axis of the rotating disc is given by this formula, derived from Faraday's law of electromagnetic induction.
36 Medium
36 of 295
Analyzing +4 | -1
Statement I: A hanging spring is attached to a battery and switch. On closing the switch a current suddenly flows in the spring, as a result spring compresses.

Statement II: When two current carrying coils are placed close to each other in same plane, then they attract each other if sense of current is same in both.
View answer and explanation
Correct option: A
Statement I is true, Statement II is true; Statement II is
the correct explanation for Statement I
Statement I is true, Statement II is true; Statement II is the correct explanation for Statement I because the current in the spring loops creates magnetic fields that cause attraction, leading to compression.
37 Medium
37 of 295
Understanding +4 | -1
Assertion(A): The possibility of an electric bulb fusing is higher at the time of switching on and off.

Reason(R): Inductive effects produce a large current at the time of switch-on and switch-off.
View answer and explanation
Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation of Assertion
Option A (Both Assertion and Reason are true and Reason is the correct explanation of Assertion) is correct because the inductive effects during switching cause a surge in current, increasing the chance of bulb fusing.
38 Medium
38 of 295
Application +4 | -1
A coil of 1200 turns and mean area of 500  cm2500\,\,\mathrm{c}{\mathrm{m}^2} is held perpendicular to a uniform magnetic field of induction 4×10−4  T.4 \times {10^{ - 4}}\,\,\mathrm{T}. The resistance of the coil is 20 ohm. When the coil is rotated through 1800{180^0} in the magnetic field is 0.1 seconds the average electric current (in MA) induced is
View answer and explanation
Correct option: B
0.24
Option B (0.24) is correct because it is the average electric current induced calculated using Faraday's law of electromagnetic induction.
39 Medium
39 of 295
Application +4 | -1
If 0.1 J0.1 \mathrm{~J} of energy is stored for the flow of current of 0.2 A0.2 \mathrm{~A} in an inductor, then its inductance value is
View answer and explanation
Correct option: A
5 H5 \mathrm{~H}
Option A (5 H5 \mathrm{~H}) is correct because the inductance value is calculated using the formula U=12LI2U = \frac{1}{2}LI^2.
40 Medium
40 of 295
Application +4 | -1
What is the self inductance of a solenoid of length 31.4 cm\mathrm{31}\mathrm{.4 }\,\mathrm{cm}, area of cross-section 10−3 m2{10^{ - 3}}\,{\mathrm{m}^2} and total number of turns 103{10^3} ?
View answer and explanation
Correct option: A
4  mH\mathrm{4}\,\,\mathrm{mH}
Option A (4 mH\mathrm{4}\,\mathrm{mH}) is correct because it is the self-inductance calculated using the formula L=μ0n2AlL=\mu_0 n^2 A l for a solenoid.
41 Medium
41 of 295
Application +4 | -1
A solenoid of radius R\mathrm{R} has n\mathrm{n} turns per unit length, then the self-inductance of the solenoid per unit length is
View answer and explanation
Correct option: D
μ0n2πR2\mu_0 \mathrm{n}^2 \pi \mathrm{R}^2
Option D (μ0n2πR2\mu_0 \mathrm{n}^2 \pi \mathrm{R}^2) is correct because the self-inductance per unit length of a solenoid is proportional to the square of the number of turns per unit length and the area of the solenoid.
42 Medium
42 of 295
Analyzing +4 | -1
Assertion (A): Whenever the magnetic flux linked with a closed coil changes there will be an induced emf as well as an induced current.

Reason (R): According to Faraday, the induced emf is inversely proportional to the rate of change of magnetic flux linked with a coil.
View answer and explanation
Correct option: C
Assertion is true but reason is false
Option C is correct. The Assertion is true, but the Reason is false because Faraday's law states that induced emf is directly proportional to the rate of change of magnetic flux, not inversely proportional.
43 Medium
43 of 295
Analyzing +4 | -1
Assertion: Unlike charges are projected in opposite direction in transverse magnetic field, then they are deflected in same direction.

Reason: If a voltmeter connected across two peripheral points of faraday copper disc generator, its reading is zero.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
Option B is correct because both the assertion and reason are true, but the reason does not explain the assertion. The deflection direction depends on the charge sign, and the voltmeter reading is zero due to Faraday's law.
44 Medium
44 of 295
Analyzing +4 | -1
Assertion: A thin aluminum disc, spinning freely about a central pivot, is quickly brought to rest when placed between the poles of a strong UU-shaped magnet.

Reason: A current induced in a disc rotating in a magnetic field produces a torque which tends to oppose the disc's motion.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
Option B is correct because both the assertion and reason are true, but the reason is not a complete explanation of the assertion. Eddy currents are the primary cause.
45 Medium
45 of 295
Understanding +4 | -1
Which of the following is true for induced electric fields due to time varying magnetic field?
View answer and explanation
Correct option: B
Their field lines form closed loops
Option B (Their field lines form closed loops) is correct because induced electric fields due to time-varying magnetic fields are non-conservative and form closed loops.
46 Medium
46 of 295
Application +4 | -1
An a.c. generator is made up of a 1000 -turn coil with a 3m23 m^2 cross-sectional area that rotates at 60 rads−160 \mathrm{~rad} \mathrm{s}^{-1} in a uniform magnetic field of 0.04 T0.04 \mathrm{~T}. The coil has a resistance of 500. Calculate the generator's maximum current draw.
View answer and explanation
Correct option: B
1.44 A1.44 \mathrm{~A}
Option B (1.44 A1.44 \mathrm{~A}) is correct because the maximum current is calculated by dividing the maximum induced emf by the resistance of the coil.
47 Medium
47 of 295
Understanding +4 | -1
S-I: When a coil of nn turns is placed in a changing magnetic field, an e.m.f. is developed in each turn so that the total e.m.f. developed between the terminals of the coil is equal to the sum of the e.m.f. developed in individual turns.

S-II: The induced charge is always independent of the time for which the flux has changed through the coil.
View answer and explanation
Correct option: A
Both S-I and S-II are correct
Option A (Both S-I and S-II are correct) is correct because the total emf is the sum of individual emfs, and induced charge is independent of the time of flux change.
48 Medium
48 of 295
Understanding +4 | -1
The phase difference between the flux linked with a coil rotating in a uniform magnetic field and induced emfemf produce in it is
View answer and explanation
Correct option: A
π/2\pi / 2
Option A (π/2\pi / 2) is correct because the induced emf leads the magnetic flux by a phase angle of π/2\pi/2 in a rotating coil.
49 Medium
49 of 295
Analyzing +4 | -1
Assertion : If a charged particle is released from rest in a time varying magnetic field, it moves in a circle.

Reason : In a time varying magnetic field, conservative electric field is induced.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
Option A is correct because a time-varying magnetic field induces a non-conservative electric field, which can accelerate a charged particle, causing it to move in a circle.
50 Medium
50 of 295
Application +4 | -1
The number of turns of primary and secondary coils of a transformer are 5  and 10\mathrm{5}\,\,\mathrm{and}\,\mathrm{10} respectively and the mutual inductance of the transformer is 25  henry25\,\,henry. Now the number of turns in the primary and secondary of the transformer are made 10  and 5\mathrm{10}\,\,\mathrm{and}\,\mathrm{5} respectively. The mutual inductance of the transformer in henryhenry will be
View answer and explanation
Correct option: C
25
Option C (25) is correct because the mutual inductance is proportional to the product of the number of turns in the primary and secondary coils, and the ratio remains constant.
51 Medium
51 of 295
Application +4 | -1
If ϕ=t2\phi=t^2 and R=2ΩR=2 \Omega then find induced heat in 1sec1 \mathrm{sec}.
View answer and explanation
Correct option: B
23J\frac{2}{3} J
Option B (23J\frac{2}{3} J) is correct because the induced heat is calculated by integrating the square of the induced current over time.
52 Medium
52 of 295
Understanding +4 | -1
Which one of the following is not true?
View answer and explanation
Correct option: B
Faraday's law is : e=−eodϕBdt\mathrm{e}=-\mathrm{e}_{\mathrm{o}} \frac{\mathrm{d} \phi_{\mathrm{B}}}{\mathrm{dt}}
Option A (Ampere's law is : ∫B→⋅dS→=μ0ienc\int \overrightarrow{\mathrm{B}} \cdot \mathrm{d} \overrightarrow{\mathrm{S}}=\mu_0 \mathrm{i}_{\mathrm{enc}}) is incorrect. Ampere's law should be ∫B→⋅dl→=μ0ienc\int \overrightarrow{\mathrm{B}} \cdot \mathrm{d} \overrightarrow{\mathrm{l}}=\mu_0 \mathrm{i}_{\mathrm{enc}} and Gauss's law should be εo∮E→⋅dA→=q\varepsilon_{\mathrm{o}} \oint \overrightarrow{\mathrm{E}} \cdot \mathrm{d} \overrightarrow{\mathrm{A}}=\mathrm{q}
53 Medium
53 of 295
Understanding +4 | -1
Assertion: Induced electric field is non conservative.

Reason: ∮E→⋅dl⃗≠0\oint \overrightarrow{\mathrm{E}} \cdot \mathrm{d} \vec{l} \neq 0
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
Option A is correct because the induced electric field is non-conservative, and this is directly explained by the line integral of the electric field being non-zero.
54 Medium
54 of 295
Application +4 | -1
The series combination of resistance RR and inductance LL is connected to an alternating source of emf e=311 sin⁡(100πt). e = 311\,\sin (100\pi t).\, If the value of wattles current is 0.5 A and the impedance of the circuit is 311 Ω311\,\Omega, the power factor will be:-
View answer and explanation
Correct option: B
12\frac{1}{{\sqrt 2 }}
Option B (12\frac{{1}}{{\sqrt 2 }}) is correct because the power factor is the cosine of the phase angle, which can be derived from the given wattless current and impedance.
55 Medium
55 of 295
Application +4 | -1
A 50  Hz50\,\,Hz ac current of peak value 2A\mathrm{2 A} flows through one of the pair of coils. If the mutual inductance between the pair of coils is 150  mH150\,\,mH, then the peak value of voltage induced in the second coil is
View answer and explanation
Correct option: A
30  πV30\,\,\pi \mathrm{ }V
Option A (30 πV30\,\pi \mathrm{ }V) is correct because it is calculated using the formula for induced EMF, considering the mutual inductance, peak current, and angular frequency.
56 Medium
56 of 295
Analyzing +4 | -1
A current carrying ring is placed in a horizontal plane. A charged particle is dropped along the axis of the ring to fall under the influence of gravity
View answer and explanation
Correct option: C
the velocity of the particle will increase till it reaches the centre of the ring
Option C (the velocity of the particle will increase till it reaches the centre of the ring) is correct because the only force acting on the charged particle is gravity, causing it to accelerate downwards.
57 Medium
57 of 295
Understanding +4 | -1
A bar magnet is released into a copper ring directly below it. The acceleration of the magnet will be
View answer and explanation
Correct option: B
less than the acceleration due to gravity at that place
Option B (less than the acceleration due to gravity at that place) is correct because the induced current in the copper ring creates a magnetic field that opposes the motion of the magnet, reducing its acceleration.
58 Medium
58 of 295
Understanding +4 | -1
Lenz’s law of electromagnetic induction corresponds to the
View answer and explanation
Correct option: B
Law of conservation of energy
Option B (Law of conservation of energy) is correct because Lenz's law is a consequence of the conservation of energy.
59 Medium
59 of 295
Application +4 | -1
A coil of 1200 turns and mean area of 500  cm2500\,\,\mathrm{c}{\mathrm{m}^2} is held perpendicular to a uniform magnetic field of induction 4×10−4  T.4 \times {10^{ - 4}}\,\,\mathrm{T}. The resistance of the coil is 20 ohm. When the coil is rotated through 1800{180^0} in the magnetic field is 0.1 seconds the average electric current (in MA) induced is
View answer and explanation
Correct option: B
0.24
Option B (0.24) is correct because the average electric current is calculated using the formula derived from Faraday's law of electromagnetic induction.
60 Medium
60 of 295
Understanding +4 | -1
Armature current in dc motor will be maximum when
View answer and explanation
Correct option: C
Motor has just started moving
Option C (Motor has just started moving) is correct because at the start, the back EMF is zero, leading to maximum armature current.
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