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JEE • PHYSICS • ELECTRIC FIELDS AND CHARGES

Electric fields and charges practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 420 questions

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61 Medium
61 of 420
Application +4 | -1
Two charges placed in air repel each other by a force of 10−4N.{10^{ - 4}}N. When oil is introduced between the charges, the force becomes 2.5×10−5N.2.5 \times {10^{ - 5}}N. The dielectric constant of oil is
View answer and explanation
Correct option: D
4.04.0
Option D (4.04.0) is correct because the dielectric constant is the ratio of the force in air to the force in the medium.
62 Easy
62 of 420
Understanding +4 | -1
Statement-1: Any net charge of a conductor resides on its outer surface.
Statement-2: The electrostatic energy of a conductor is minimum when charge is spread over the surface.
View answer and explanation
Correct option: B
Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1
Option B (Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1) is correct because both statements are factually correct, but the minimum energy is not the direct cause of charge residing on the surface.
63 Medium
63 of 420
Understanding +4 | -1
While taking off synthetic clothes, seeing a spark or
hearing a crackle, are due to
View answer and explanation
Correct option: C
Electric discharge
Option C is correct because the spark and crackle are due to the electric discharge caused by accumulated static electricity.
64 Medium
64 of 420
Analyzing +4 | -1
Assertion: Two identicalballs are charged by qq. They are suspended from a common point by two insulating threads ll each. In equilibrium the angle between the threads is 180∘180^{\circ}. (Ignore gravity)

Reason: In equllibrium tension in the springs is T=14πε0×q⋅ql2T=\frac{1}{4 \pi \varepsilon_0} \times \frac{q \cdot q}{l^2}
View answer and explanation
Correct option: C
Assertion is true & Reason is false
Option D (Assertion is false and Reason is true) is incorrect. The assertion is true, but the reason is false because the tension is calculated with the distance between the balls as 2l.
65 Medium
65 of 420
Analyzing +4 | -1
Assertion:- An electric charge is fixed in free space which produces an electric field around it. No work is done in displacing another charge from its position to any other position.
Reason:- Electrostatic field is non conservative.
View answer and explanation
Correct option: D
If both Assertion & Reason are False
Option D is correct because the assertion is false as work done is zero in moving a charge in an electrostatic field, and the reason is also false as the electrostatic field is conservative.
66 Medium
66 of 420
Application +4 | -1
Two charges of 5  μc5\,\,\mu c and −45  μc- 45\,\,\mu c are separated by a distance of 42 cm. Electrostatic field strength from the smaller charge is zero at a distance of
View answer and explanation
Correct option: B
21 cm
Option B (21 cm) is correct because the point where the electric field is zero lies closer to the smaller charge and can be calculated using the formula for the electric field due to point charges.
67 Medium
67 of 420
Application +4 | -1
Estimate the number of electrons in 100 g100 \mathrm{~g} of water. How much is the total negative charge on these electrons?
View answer and explanation
Correct option: B
5.34×106c5.34 \times 10^6 \mathrm{c}
Option B (5.34×106c5.34 \times 10^6 \mathrm{c}) is correct because it calculates the total negative charge by finding the number of electrons and multiplying by the charge of an electron.
68 Medium
68 of 420
Application +4 | -1
A dipole has two charges +1μC+1 \mu {C} and −1μC-1 \mu C and each have mass 1 kg1 {~kg}. The separation between the charges is 1 m1 {~m}. An electric field 20×103v/m20 \times 10^3 {v} / {m} is applied on the dipole. If the dipole is deflected through 2∘2^{\circ} from the equilibrium position, time taken by it to come to the equilibrium position again is
View answer and explanation
Correct option: A
2.5πsec2.5 \pi {sec}
Option A (2.5πsec2.5 \pi {sec}) is correct because it's calculated using the formula for the time period of a torsional pendulum.
69 Medium
69 of 420
Analyzing +4 | -1
Assertion:- Electrostatic energy does not follow superposition principle.
Reason:-Electrostatic energy density is a quadratic function.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because electrostatic energy does not follow the superposition principle, and this is because electrostatic energy density is a quadratic function.
70 Medium
70 of 420
Analyzing +4 | -1
Assertion:- When a positive point charge is placed near a neutral conductor then the Latter becomes negatively charged.
Reason:- Induction is possible in conductors only.
View answer and explanation
Correct option: D
If both Assertion & Reason are False
Option D (If both Assertion & Reason are False) is correct because both the assertion and the reason are incorrect statements about induction.
71 Medium
71 of 420
Analyzing +4 | -1
Assertion(A): If a bob of a simple pendulum is kept in a horizontal electric field, its period of oscillation will remain same.

Reason(R): If bob is charged and kept in horizontal electric field, then the time period will be decreased.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
Option B is correct because both the assertion and reason are correct statements, but the reason doesn't explain why the period remains the same when the bob is uncharged.
72 Medium
72 of 420
Understanding +4 | -1
Assertion: Electric lines of force cross each other.

Reason: Electric field at a point superimposes to give one resultant electric field.
View answer and explanation
Correct option: D
If Assertion is false but Reason is true.
Option D (If Assertion is false but Reason is true) is correct because electric field lines never cross, but the electric field at a point is the superposition of individual fields.
73 Medium
73 of 420
Understanding +4 | -1
Two equal and opposite charges are placed at points PP and Q.Q. The null point on the line joining them is
View answer and explanation
Correct option: D
Outside the line joining PP and QQ
Option D (Outside the line joining PP and QQ) is correct because the null point due to two equal and opposite charges lies outside the line joining them, closer to the charge with smaller magnitude (in this case, at infinity if the charges are equal).
74 Medium
74 of 420
Application +4 | -1
An infinite line charge produces a field of 18×104 N/C18 \times 10^4 \mathrm{~N} / \mathrm{C} at 0.02 m0.02 \mathrm{~m}. The linear charge density is
View answer and explanation
Correct option: A
2×10−7C/m2 \times 10^{-7} \mathrm{C} / \mathrm{m}
Option A (2×10−7C/m2 \times 10^{-7} \mathrm{C} / \mathrm{m}) is correct because it is calculated using the formula for the electric field due to an infinite line charge, E=λ2πϵ0rE = \frac{\lambda}{2 \pi \epsilon_0 r}.
75 Medium
75 of 420
Analyzing +4 | -1
The bob of simple pendulum is hanging vertically down from a fixed identical bob by means of string of length ll. If both bobs are charged with a charge with a charge qq each, time period of the pendulum is (ignore the radii of the bobs)
View answer and explanation
Correct option: C
2πlg2\pi \sqrt {\frac{l}{\mathrm{g}}}
Option C is correct because the electrostatic repulsion between the charged bobs does not affect the time period of the pendulum, which remains the same as for a simple pendulum.
76 Medium
76 of 420
Understanding +4 | -1
Gauss’s law of electrostatics would be invalid if
View answer and explanation
Correct option: C
The inverse square law was not exactly true
Option C (The inverse square law was not exactly true) is correct because Gauss's law is a direct consequence of the inverse square law in electrostatics.
77 Medium
77 of 420
Application +4 | -1
A force of 4N4N is acting between two charges in air if the space between them is completely filled with glass (εr=8)\left( {{\varepsilon _r} = 8} \right), then the new force will be …… NN
View answer and explanation
Correct option: B
0.5
Option B (0.5) is correct because the force between two charges is inversely proportional to the dielectric constant of the medium.
78 Medium
78 of 420
Application +4 | -1
In a region, the intensity of an electric field is given by E=8i^+8j^+k^E=8 \hat{i}+8 \hat{j}+\hat{k} in NC−1.\mathrm{NC}^{-1}. The electric flux through a surface S=10i^m2S=10 \hat{i} m^2 in the region is
View answer and explanation
Correct option: B
80 Nm2 C−180 \mathrm{~Nm}^2 \mathrm{~C}^{-1}
Option B (80 Nm2 C−180 \mathrm{~Nm}^2 \mathrm{~C}^{-1}) is correct because electric flux is the dot product of the electric field and the area vector.
79 Easy
79 of 420
Analyzing +4 | -1
Assertion: A charge particle is released from rest in magnetic field then it will move in circular path.
Reason: Work done by magnetic field is non zero.
View answer and explanation
Correct option: D
If both assertion and reason are false
Option D is correct because a charged particle released from rest in a magnetic field will not move in a circular path (it will remain at rest), and the work done by a magnetic field is always zero.
80 Medium
80 of 420
Remembering +4 | -1
Electric charges under action of electric forces is called
View answer and explanation
Correct option: A
electrostatic
The correct answer is A (electrostatic) because electrostatics deals with electric charges at rest or in slow motion under the influence of electric forces.
81 Medium
81 of 420
Understanding +4 | -1
A hollow metallic sphere of radius 10  cm10\;cm is given a charge of 3.2×10−93.2 \times {10^{ - 9}} CC.The electric intensity at a point 4  cm4\;cm from the centre is
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the electric field inside a hollow metallic sphere is always zero, regardless of the charge on the sphere.
82 Easy
82 of 420
Analyzing +4 | -1
Assertion:- For a charged shell, potential inside shell depends only on the field inside shell.
Reason:- Potential of shell may be determined only by the field outside.
View answer and explanation
Correct option: D
If both Assertion & Reason are False
Option D is correct because the potential inside a charged shell is constant and depends on the charge on the shell, not just the field inside, and the potential of the shell depends on the charge distribution both inside and outside.
83 Hard
83 of 420
Application +4 | -1
The magnitude of the average electric field normally present in the atmosphere just above the surface of the earth is about 150 N/C,150\,N/C, directed inward towards the center of the earth. This gives the total net surface charge carried by the earth to be: [Given ε0=8.85×10−12 C2/N−m2, RE=6.37×106 m]\left[ {{\text{Given}}\,{\varepsilon _0} = 8.85 \times {{10}^{ - 12}}\,{C^2}/N - {m^2},\,{R_E} = 6.37 \times {{10}^6}\,m} \right]
View answer and explanation
Correct option: C
−680 kC- 680\,kC
Option C (−680 kC- 680\,kC) is correct because the total net surface charge is calculated using Gauss's law and the given electric field, directed inward.
84 Easy
84 of 420
Remembering +4 | -1
Electric lines of force:
View answer and explanation
Correct option: A
are imaginary
Option A (are imaginary) is correct because electric lines of force are a visual representation of the electric field, not a physical entity.
85 Medium
85 of 420
Application +4 | -1
An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius r.r. The coulomb force F⃗{\vec F} between the two is 
View answer and explanation
Correct option: C
−Ke2r3r⃗- K\frac{{{e^2}}}{{{r^3}}}\vec r
Option C (−Ke2r3r⃗- K\frac{{{e^2}}}{{{r^3}}}\vec r) is correct because the Coulomb force is attractive (negative sign) and inversely proportional to the square of the distance, expressed in vector form.
86 Medium
86 of 420
Application +4 | -1
The repulsive force between two equal charges (Q)(Q) is F.F. To reduce force by 25% how much charge is transferred from first to second:-
View answer and explanation
Correct option: C
Q2\frac{Q}{2}
Option C (Q2\frac{Q}{2}) is correct because transferring Q/2 charge results in a 25% reduction in the repulsive force between the charges.
87 Medium
87 of 420
Understanding +4 | -1
Two charges +1μC+1 \mu \mathrm{C} and +4μC+4 \mu \mathrm{C} are situated at a distance in air. The ratio of the forces acting on them is
View answer and explanation
Correct option: C
1:11: 1
The correct answer is 1: 1 because, according to Newton's third law, the forces between two charges are equal and opposite.
88 Medium
88 of 420
Understanding +4 | -1
Assertion:- Net charge density inside a conductor is zero.
Reason:- Equal and opposite charges are present in conductor.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because net charge density inside a conductor is zero due to the presence of equal and opposite charges that cancel each other out.
89 Medium
89 of 420
Remembering +4 | -1
Which of the following is the correct statement of Gauss law for electrostatics in a region of charge distribution in free space?
View answer and explanation
Correct option: B
∮E.ds=ρε0\oint E.ds = \frac{\rho }{{{\varepsilon _0}}}
Option B (∮E.ds=ρε0\oint E.ds = \frac{\rho }{{\varepsilon _0}}) is the correct statement of Gauss's law, relating the electric flux through a closed surface to the enclosed charge density.
90 Medium
90 of 420
Analyzing +4 | -1
Two masses M1M_1 and M2M_2 carry positive charges Q1Q_1 and Q2Q_2, respectively. They are dropped to the floor in a laboratory setup from the same height where there is a constant electric field vertically upwards. M1M_1 hits the floor before M2M_2. Then,
View answer and explanation
Correct option: D
M1Q2>M2Q1M_1 Q_2>M_2 Q_1
Option D is correct because the condition for M1 hitting the floor before M2 leads to the inequality M1Q2 > M2Q1.
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