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JEE • PHYSICS • DUAL NATURE OF RADIATION AND MATTER

Dual nature of radiation and matter practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 241-270 of 316 questions

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241 Medium
241 of 316
Understanding +4 | -1
A particle with rest mass zero is moving speed cc. The de-Broglie wavelength associated with it
View answer and explanation
Correct option: A
Zero
Option A (Zero) is correct because a particle with zero rest mass moving at the speed of light has infinite momentum, resulting in a de Broglie wavelength of zero.
242 Medium
242 of 316
Application +4 | -1
An α−Particle\alpha \mathrm{ - Particle} and a deuteron are moving with velocities v and 2v respectively. What will be the ratio of their de Broglie wavelengths-?
View answer and explanation
Correct option: A
1:11:1
Option A (1:11:1) is correct because the ratio of de Broglie wavelengths depends on the mass and velocity, and the calculation simplifies to 1:1.
243 Medium
243 of 316
Understanding +4 | -1
A metal plate gets heated when cathode rays strike against it due to
View answer and explanation
Correct option: A
Kinetic energy of cathode rays
Option A (Kinetic energy of cathode rays) is correct because when cathode rays (electrons) strike a metal plate, their kinetic energy is converted into heat, causing the plate to heat up.
244 Medium
244 of 316
Application +4 | -1
The energy of a photon is E=hvE = hv and the momentum of photon p=hλ,p = \frac{h}{\lambda }, then the velocity of photon will be
View answer and explanation
Correct option: A
E/pE/p
Option A (E/pE/p) is correct because the velocity of a photon is given by the ratio of its energy to its momentum.
245 Medium
245 of 316
Remembering +4 | -1
Millikan’s oil-drop experiment established that
View answer and explanation
Correct option: D
Electric charge is quantized
Option D (Electric charge is quantized) is correct because Millikan's oil-drop experiment demonstrated that electric charge exists in discrete units, meaning it is quantized.
246 Medium
246 of 316
Application +4 | -1
The difference between kinetic energies of photoelectrons emitted from a surface by light of wavelength 2500A∘\mathop A\limits^ \circ and 5000A∘\mathop A\limits^ \circ will be
View answer and explanation
Correct option: B
2.47 eV
Option B (2.47 eV) is correct because it is the calculated difference in kinetic energies of photoelectrons using the given wavelengths.
247 Medium
247 of 316
Understanding +4 | -1
Which one of the following statements regarding photo-emission of electrons is correct?
View answer and explanation
Correct option: C
Photoelectric emission is instantaneous with the incidence of light.
Option C (Photoelectric emission is instantaneous with the incidence of light) is correct because the process occurs almost immediately when light of sufficient frequency shines on a metal surface.
248 Medium
248 of 316
Remembering +4 | -1
Which of the following is not the property of a cathode ray
View answer and explanation
Correct option: D
It does not deflect in electric field
Option D (It does not deflect in electric field) is correct because cathode rays are streams of negatively charged particles (electrons) and therefore *do* deflect in an electric field.
249 Medium
249 of 316
Analyzing +4 | -1
Assertion: The momentum of a photon is equal to p=h/λ\mathrm{p}=\mathrm{h} / \lambda.

Reason: According to Planck E=hv\mathrm{E}=\mathrm{hv}

According to Einstein E=mc2\mathrm{E}=\mathrm{mc}^2.

So that mc2=hv⇒p=mc=h/λ\mathrm{mc}^2=\mathrm{hv} \Rightarrow \mathrm{p}=\mathrm{mc}=\mathrm{h} / \lambda
View answer and explanation
Correct option: A
If both Assertion and Reason are true and the Reason is a correct explanation of the Assertion
Option A is correct because both the assertion and reason are true, and the reason provides a correct explanation of the assertion, linking momentum, energy, and wavelength of a photon.
250 Medium
250 of 316
Analyzing +4 | -1
Two electrons are moving with non-relativistic speeds perpendicular to each other. If corresponding de Broglie wavelengths are λ1\lambda_1 and λ2\lambda_2 their de Broglie wavelength in the frame of reference attached to their centre of mass is :
View answer and explanation
Correct option: B
λCM=2λ1λ2λ12+λ22\lambda_{\mathrm{CM}}=\frac{2 \lambda_1 \lambda_2}{\sqrt{\lambda_1^2+\lambda_2^2}}
Option B is correct because the de Broglie wavelength in the center of mass frame is calculated using the relative velocities of the particles, resulting in λCM=2λ1λ2λ12+λ22\lambda_{\mathrm{CM}}=\frac{2 \lambda_1 \lambda_2}{\sqrt{\lambda_1^2+\lambda_2^2}}.
251 Medium
251 of 316
Understanding +4 | -1
The slope of frequency of incident light and stopping potential graph for a given surface will be
View answer and explanation
Correct option: B
h/eh/e
Option B is correct because the slope of the stopping potential vs. frequency graph is given by h/eh/e, where h is Planck's constant and e is the elementary charge.
252 Medium
252 of 316
Application +4 | -1
A 5 W source emits monochromatic light of wavelength 5000A∘5000\mathop A\limits^ \circ. When placed 0.5 m away, it liberates photoelectrons from a photosensitive metallic surface. When the source is moved to a distance of 1.0m, the number of photoelectrons liberated will be reduced by a factor of
View answer and explanation
Correct option: A
4
Option A (4) is correct because the number of photoelectrons is inversely proportional to the square of the distance from the source.
253 Medium
253 of 316
Application +4 | -1
In Millikan’s oil drop experiment, a charged drop of mass 1.8×10−141.8 \times {10^{ - 14}} kg is stationary between the plates. The distance between the plates 0.9 cm and potential difference between the plates is 2000 V. The number of electrons on the oil drop is
View answer and explanation
Correct option: B
5
Option B (5) is correct because in Millikan's experiment, the number of electrons is calculated by equating the electric force to the gravitational force and solving for n.
254 Medium
254 of 316
Remembering +4 | -1
The time taken by a photoelectron to come out after the photon strikes is approximately
View answer and explanation
Correct option: B
10−10  s{10^{ - 10}}\mathrm{\;s}
Option B (10−10  s{10^{ - 10}}\mathrm{\;s}) is correct because the photoelectric effect is nearly instantaneous.
255 Medium
255 of 316
Understanding +4 | -1
A beam of light of wavelength λ\lambda and with illumination LL falls on a clean surface of sodium. If NN photoelectrons are emitted each with kinetic energy E,E, then
View answer and explanation
Correct option: B
N∝LN \propto L and E∝1λE \propto \frac{1}{\lambda }
Option B (N∝LN \propto L and E∝1λE \propto \frac{1}{\lambda }) is correct because the number of photoelectrons is proportional to light intensity, and kinetic energy is inversely proportional to wavelength.
256 Medium
256 of 316
Remembering +4 | -1
Colour of star is an indication of its:-
View answer and explanation
Correct option: C
temperature
Option C (temperature) is correct because the color of a star is directly related to its surface temperature, as described by Wien's displacement law.
257 Medium
257 of 316
Application +4 | -1
Moving with the same velocity. Which of the following has the longest be Broglie wavelength
View answer and explanation
Correct option: A
β\beta-particle
Option A (β\beta-particle) is correct because, among the given particles, the beta particle (electron) has the smallest mass, and de Broglie wavelength is inversely proportional to mass.
258 Medium
258 of 316
Analyzing +4 | -1
For a body moving with relativistic speed, if the velocity is doubled, then
View answer and explanation
Correct option: A
Its linear momentum is doubled
Option C (Its linear momentum will be more than double) is correct because at relativistic speeds, the momentum increases more than linearly with velocity due to the relativistic mass increase.
259 Medium
259 of 316
Understanding +4 | -1
If the frequency of light in a photoelectric
experiment is doubled, the stopping potential will:
View answer and explanation
Correct option: C
become more than double
Option C (become more than double) is correct because the stopping potential is related to the frequency by eV0=hf−ϕ0eV_0 = hf - \phi_0, so doubling the frequency more than doubles the stopping potential.
260 Medium
260 of 316
Application +4 | -1
The debroglie wavelength of an electron is λ\lambda and has energy E{E}. If the de Broglie wavelength is reduced by 25%25 \%, then how much extra kinetic energy will the electron have now
View answer and explanation
Correct option: B
79E\frac{7}{9} E
Option B (79E\frac{7}{9} E) is correct because the kinetic energy is inversely proportional to the square of the de Broglie wavelength.
261 Medium
261 of 316
Remembering +4 | -1
The special theory of relativity is based on the frame of reference which has constant?
View answer and explanation
Correct option: B
Speed
Option B (Speed) is correct because the special theory of relativity postulates that the speed of light in a vacuum is constant for all observers.
262 Medium
262 of 316
Application +4 | -1
Ultraviolet radiation of 6.2eV falls on an aluminium surface (work function 4.2eV). The kinetic energy in joule of the fastest electron emitted is approximately
View answer and explanation
Correct option: B
3.2×10−193.2 \times {10^{ - 19}}
Option B (3.2×10−193.2 \times {10^{ - 19}}) is correct because the kinetic energy of the fastest electron is calculated using the photoelectric effect equation.
263 Medium
263 of 316
Remembering +4 | -1
The colour of the positive column in a gas discharge tube depends on
View answer and explanation
Correct option: B
The gas in the tube
Option B (The gas in the tube) is correct because the color of the light emitted in a gas discharge tube is determined by the energy levels of the gas atoms.
264 Medium
264 of 316
Application +4 | -1
Doubly ionised helium atom and hydrogen ions are accelerated, from rest, through the same potential difference. The ratio of final velocities of helium and hydrogen is
View answer and explanation
Correct option: A
1  :  21\;:\;\sqrt 2
Option A (1:21:\sqrt{2}) is correct because it is derived from the relationship between kinetic energy, charge, potential difference, and mass for both helium and hydrogen ions.
265 Medium
265 of 316
Remembering +4 | -1
The de-Broglie wavelength is proportional to
View answer and explanation
Correct option: C
λ∝1p\lambda \propto \frac{1}{p}
Option C (λ∝1p\lambda \propto \frac{1}{p}) is correct because the de Broglie wavelength is inversely proportional to the momentum of the particle.
266 Medium
266 of 316
Understanding +4 | -1
In the photoeletric effect, electrons are emitted
View answer and explanation
Correct option: D
only if the frequency of the incident radiations is above a certain threshold value
Option D is correct because photoelectrons are emitted only when the incident radiation's frequency exceeds the threshold frequency.
267 Easy
267 of 316
Analyzing +4 | -1
Statement-1: If an electron has the same wavelength as a photon, they have the same energy.
Statement-2: By de-Broglie hypothesis, p=h/λp=h / \lambda for both the electron and the photon.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D is correct because while both have the same de Broglie wavelength, their energies are different due to their different mass and energy-momentum relationships.
268 Medium
268 of 316
Understanding +4 | -1
Planck’s constant has the dimensions of
View answer and explanation
Correct option: D
Angular momentum
Option D is correct because when the size of the object is much smaller than the wavelength, scattering is the dominant phenomenon.
269 Medium
269 of 316
Understanding +4 | -1
If gE{\mathrm{g}_E} and gM{\mathrm{g}_M} are the acceleration due to gravity on the surfaces of the earth and the moon respectively and it Millikan’s oil drop experiment could be performed on the two surfaces, one will find the ratio electronic  charge  on  the  moon  electronic  charge  on  the  earth  \frac{{\mathrm{electronic\;charge\;on\;the\;moon\;}}}{{\mathrm{electronic\;charge\;on\;the\;earth\;}}} to be
View answer and explanation
Correct option: A
1
Option A (1) is correct because the electronic charge is a fundamental constant and does not depend on the gravitational acceleration of the planet or moon.
270 Medium
270 of 316
Application +4 | -1
An electron is accelerated under a potential difference of 182 V. The maximum velocity of electron will be
(Charge of an electron is 1.6×10−191.6 \times {10^{ - 19}} C and its mass is 9.1×10−31  9.1 \times {10^{ - 31}}\; kg)
View answer and explanation
Correct option: C
8×1068 \times {10^6}m/s
Option C (8×1068 \times {10^6}m/s) is correct because the maximum velocity is calculated using the kinetic energy gained by the electron due to the potential difference.
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