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JEE • PHYSICS • CURRENT ELECTRICITY

Current electricity practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 457 questions

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211 Medium
211 of 457
Application +4 | -1
A capacitor is charged by a cell of emf EE and the charging battery is then removed. If an identical capacitor is now inserted in the circuit in parallel with the previous capacitor, the potential difference across the new capacitor is
View answer and explanation
Correct option: C
E/2E / 2
Option C (E/2E / 2) is correct because when an identical capacitor is added in parallel, the charge is distributed equally, halving the potential difference.
212 Medium
212 of 457
Application +4 | -1
A 10 V10 \mathrm{~V} battery of negligible internal resistance is charged by a 200 V200 \mathrm{~V} d.c. supply. If the resistance in the charging circuit is 38Ω38 \Omega, what is the value of charging current ?
View answer and explanation
Correct option: B
5 A5 \mathrm{~A}
Option B (5 A) is correct because it is the charging current calculated by considering the net emf and the resistance in the circuit.
213 Medium
213 of 457
Application +4 | -1
The current in a wire varies with time according to the relation i=4+2t2i=4+2 t^2. How many coulomb of charge pass a cross-section of wire in time interval t=5t=5 s to t=10st=10 s ?
View answer and explanation
Correct option: A
603.33 C
Option A (603.33 C) is correct because it's the charge calculated by integrating the current function over the given time interval.
214 Medium
214 of 457
Application +4 | -1
The current of 1.6 A is flowing in a conductor. The number of electrons flowing per second through the conductor is
View answer and explanation
Correct option: B
1019{10^{19}}
Option B (1019{10^{19}}) is correct because it is calculated by dividing the total charge passing through the conductor per second by the charge of a single electron.
215 Medium
215 of 457
Application +4 | -1
Two bulbs marked 200  V−  100  W\mathrm{200}\,\,\mathrm{V - }\,\,\mathrm{100}\,\,\mathrm{W} and 200  V − 200  W\mathrm{200}\,\,\mathrm{V}\,\mathrm{ - }\,\mathrm{200}\,\,\mathrm{W} are joined in series and connected to a power supply of 200  V\mathrm{200}\,\,\mathrm{V}. The total power consumed by the two will be near to
View answer and explanation
Correct option: B
66  W\begin{array}{llllllllllllllllllll} {\mathrm{66}\,\,\mathrm{W}} \end{array}
Option B (66  W\begin{array}{llllllllllllllllllll} \mathrm{66}\,\,\mathrm{W} \end{array}) is correct because it's calculated by finding the equivalent resistance of the bulbs in series and then using the power formula.
216 Medium
216 of 457
Application +4 | -1
We are given nn resistors, each of resistance rr they are first combined to get maximum possible resistance then to get minimum possible resistance then ratio between maximum and minimum resistance is
View answer and explanation
Correct option: C
n2n^2
Option C (n2n^2) is correct because the maximum resistance is nrnr and the minimum resistance is r/nr/n, so their ratio is n2n^2.
217 Medium
217 of 457
Understanding +4 | -1
A student measures the terminal potential difference (V)\left( V \right) of a cell (of emfEemf\mathrm{ }E and internal resistance rr) as a function of the current (I)\left( I \right) flowing through it. The slope, and intercept, of the graph between VV and II, then, respectively, equal
View answer and explanation
Correct option: B
−r- r and EE
Option B ( −r- r and EE) is correct because the equation V = E - Ir represents a straight line with slope -r and y-intercept E.
218 Medium
218 of 457
Application +4 | -1
When a 40 watt lamp is connected in series with a 100 watt lamp across a 210 volt supply, which one glows brighter?
View answer and explanation
Correct option: B
40 watt lamp
Option B (40 watt lamp) is correct because in a series circuit, the lamp with higher resistance (lower power rating) glows brighter due to higher power dissipation.
219 Medium
219 of 457
Application +4 | -1
The resistance of a wire is ′R′'R' ohm. If it is melted and stretched to ′n′'n' times its original length, its new resistance will be
View answer and explanation
Correct option: D
n2R{n^2}R
Intensity at y=0.4 mmy=0.4 \mathrm{~mm} is zero. This is because at y=0.4y=0.4 mm, the path difference corresponds to an odd multiple of λ/2\lambda/2, resulting in destructive interference.
220 Medium
220 of 457
Analyzing +4 | -1
The resistance of the filament of a lamp increases with the increase in temperature. A lamp rated 100W\mathrm{100 W} and 200V\mathrm{200 V} is connected across 200V\mathrm{200 V} power supply. If the voltage drops by 10  %\mathrm{10}\,\,\mathrm{\% }, then the power of the lamp will be
View answer and explanation
Correct option: D
Between 81  and  90  W\mathrm{81}\,\,\mathrm{and}\,\,\mathrm{90}\,\,\mathrm{W}
Option D (Between 81  and  90  W\mathrm{81}\,\,\mathrm{and}\,\,\mathrm{90}\,\,\mathrm{W}) is correct because the resistance decreases with lower temperature, leading to a power output greater than 81W but less than 90W.
221 Medium
221 of 457
Understanding +4 | -1
Electrical resistance of a piece of a material sharply decreases on increasing the temperature of the piece. The material of the piece is a :
View answer and explanation
Correct option: C
Semi-conductor
Option C (Semi-conductor) is correct because semiconductors exhibit a sharp decrease in electrical resistance with increasing temperature due to increased carrier concentration.
222 Medium
222 of 457
Understanding +4 | -1
1 ampere current is equivalent to
View answer and explanation
Correct option: A
6.25×10186.25 \times 10^{18} electrons s−1\mathrm{s}^{-1}
Option A (6.25×10186.25 \times 10^{18}) is correct because 1 Ampere is equivalent to 6.25×10186.25 \times 10^{18} electrons per second based on the charge of an electron.
223 Medium
223 of 457
Application +4 | -1
The Earth's surface has a negative surface charge density of 135×10−9π(6.4)2C/m2\frac{135 \times 10^{-9}}{\pi(6.4)^2} \mathrm{C} / \mathrm{m}^2. The potential difference of 400kV400 \mathrm{kV} between the top of the atmosphere and the surface, results (due to low conductivity of the lower atmosphere) in a current of only 1800 A1800 \mathrm{~A} over the entire globe. If there is no mechanism of sustaining atmospheric electric field, how much time (in sec) would be required to neutralize the Earth's surface?(\left(\right. Radius of earth =6.4×106 m)\left.=6.4 \times 10^6 \mathrm{~m}\right)
View answer and explanation
Correct option: D
283
Option B (4225\sqrt{\frac{42}{25}}) is correct because it is calculated by using the formula for the velocity of sound in a gas and taking the ratio for hydrogen and helium.
224 Medium
224 of 457
Application +4 | -1
The current in a conductor varies with time tt as I=2t+  3t2I = 2t + \,\,3{t^2} where II is in ampere and tt in seconds. Electric charge flowing through a section of the conductor during t=2  sec⁡t = 2\,\,\sec to t=3  sec⁡t = 3\,\,\sec is
View answer and explanation
Correct option: B
24  C24\,\,C
Option B (24 C24 \mathrm{~C}) is correct because the total charge is the integral of the current with respect to time from t=2 to t=3.
225 Medium
225 of 457
Understanding +4 | -1
A thermocouple is made from two metals, Antimony and Bismuth. If one junction of the couple is kept hot and the other is kept cold, then, an electric current will
View answer and explanation
Correct option: D
Flow from Antimony to Bismuth at the cold junction
Option D is correct because in a thermocouple made of Antimony and Bismuth, current flows from Antimony to Bismuth at the cold junction, according to the thermoelectric series.
226 Medium
226 of 457
Application +4 | -1
A parallel combination of three resistors takes a current of 7.5 A7.5 \mathrm{~A} from a 30 V30 \mathrm{~V} supply. If the two resistors are 10Ω10 \Omega and 12Ω12 \Omega, find the third one.
View answer and explanation
Correct option: A
15 Ω15 ~\Omega
Option A (15 Ω15 ~\Omega) is correct because it is the value of the third resistor that satisfies the parallel resistance equation given the total current and voltage.
227 Medium
227 of 457
Remembering +4 | -1
Kirchhoff’s first law i.e.  ∑i=0i.e.\,\,\sum i = 0 at a junction is based on the law of conservation of
View answer and explanation
Correct option: A
Charge
Option A (Charge) is correct because Kirchhoff's Current Law (KCL) is a statement of the conservation of electric charge.
228 Medium
228 of 457
Understanding +4 | -1
A lead acid accumulatory (storage battery) is connected to a battery charge for over night charging. Which of the following observations will indicate that the battery was partly charged during the next morning
View answer and explanation
Correct option: B
The density of acid has increased
Option B is correct because during the charging process of a lead-acid battery, sulfuric acid is regenerated, increasing the density of the electrolyte.
229 Medium
229 of 457
Remembering +4 | -1
The mass of ions deposited during a given interval of time in the process of electrolysis depends on
View answer and explanation
Correct option: A
The current
Option A (The current) is correct because, according to Faraday's laws of electrolysis, the mass of ions deposited is directly proportional to the quantity of electricity (current x time) passed through the electrolyte.
230 Medium
230 of 457
Application +4 | -1
The lengths of the three wires of copper are in the ratio of 1:4:81: 4: 8 and their masses are in the ratio of 5:3:15: 3: 1. The ratio of their electrical resistance is
View answer and explanation
Correct option: B
3:80:9603: 80: 960
Option B (3:80:9603: 80: 960) is correct because it is the ratio of the electrical resistances calculated using the relationship between resistance, length, and mass of the wires.
231 Medium
231 of 457
Understanding +4 | -1
The electric current passing through a metallic wire produces heat because of
View answer and explanation
Correct option: D
Collisions of the conduction electrons with the atoms of the metallic wires
Option D (Collisions of the conduction electrons with the atoms of the metallic wires) is correct because the heat generated in a metallic wire is due to the resistance caused by electrons colliding with the atoms.
232 Medium
232 of 457
Application +4 | -1
The tungsten filaments of two electric bulbs are of the same length. If one of them gives 25 W25 {~W} power and the other 60 W60 {~W} power. Then
View answer and explanation
Correct option: C
60 W60 {~W} bulb has thicker filament
Option C (60 W60 {~W} bulb has thicker filament) is correct because for a given voltage, higher power implies lower resistance, which means a thicker filament.
233 Medium
233 of 457
Understanding +4 | -1
In which of the following cases ohm's law is not valid?
View answer and explanation
Correct option: C
Junction diode
Option C (Junction diode) is correct because Ohm's law is not valid for non-linear devices like junction diodes.
234 Medium
234 of 457
Understanding +4 | -1
In the above question if potential difference is applied, the drift velocity at temperature TT is
View answer and explanation
Correct option: A
Inversely proportional to TT
Option A (Inversely proportional to TT) is correct because drift velocity is inversely proportional to temperature due to increased collisions at higher temperatures.
235 Medium
235 of 457
Understanding +4 | -1
Show that one ampere is equivalent to a flow of 6.25×10186.25 \times 10^{18} elementary charges per second.
View answer and explanation
Correct option: B
6.25×10186.25 \times 10^{18}
Option B (6.25×10186.25 \times 10^{18}) is correct because it is the number of elementary charges that flow per second for a current of 1 Ampere.
236 Medium
236 of 457
Understanding +4 | -1
Wires P{P} and Q{Q} are having same resistance at room temperature. When heated, resistance of ' PP ' increases, and that of ' QQ ' decreases, we conclude that
View answer and explanation
Correct option: C
P{P} is semiconductor and Q{Q} is metal
Option B (P{P} is metal and Q{Q} is semiconductor) is correct because metals typically have a positive temperature coefficient of resistance, while semiconductors have a negative temperature coefficient.
237 Medium
237 of 457
Understanding +4 | -1
Which of the following statements are incorrect?

I. The order of magnitude of current flowing in household appliances is one ampere.

II. The order of magnitude of current in lightening is about one ampere.

III. The order of magnitude of current in nerves in human body is one ampere.
View answer and explanation
Correct option: A
II and III
Option A (II and III) is correct because the order of magnitude of current in lightning and nerves in the human body is not one ampere.
238 Medium
238 of 457
Understanding +4 | -1
When the temperature of a metallic resistor is increased, the product of its resistivity and conductivity
View answer and explanation
Correct option: C
Remains constant
Option C (Remains constant) is correct because resistivity and conductivity are inversely proportional, and their product is always 1.
239 Medium
239 of 457
Application +4 | -1
The current density of a solid cylindrical wire of radius R{R}, as a function of radial distance r{r} is given by J(r)=J0(1−rR)J(r)=J_0\left(1-\frac{r}{R}\right). The total current in the radial region r=0{r}=0 to r=R4r=\frac{R}{4} will be:
View answer and explanation
Correct option: B
5J0πR296\frac{5 J_0 \pi R^2}{96}
Option B (5J0πR296\frac{5 J_0 \pi R^2}{96}) is correct because it is the result of integrating the current density function over the specified radial region.
240 Medium
240 of 457
Understanding +4 | -1
Assertion: Potentiometer measures the correct value of emf of a cell.
Reason: No current flows through the cell being balanced at the null point of potentiometer.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because a potentiometer measures EMF at a null point where no current flows, thus providing an accurate reading without drawing current from the cell.
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