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JEE • PHYSICS • CURRENT ELECTRICITY

Current electricity practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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271 Medium
271 of 457
Application +4 | -1
A,  B, CA,\,\,B,\,C and DD are four resistances of 2  Ω,  2  Ω,  2  Ω  and  3  Ω2\,\,\mathrm{\Omega },\,\,2\,\,\mathrm{\Omega },\,\,2\,\,\mathrm{\Omega }\,\,\mathrm{and}\,\,3\,\,\mathrm{\Omega } respectively. They are used to form a Wheatstone bridge. The resistance DD is short circuted with a resistances R\mathrm{R} in order to get the bridge balanced. The value of RR will be
View answer and explanation
Correct option: B
6  Ω6\,\,\mathrm{\Omega }
Option B (6 Ω) is correct because it satisfies the Wheatstone bridge balance condition after short-circuiting resistance D with R.
272 Medium
272 of 457
Understanding +4 | -1
For a metallic wire, the ratio of voltage to corresponding current is
View answer and explanation
Correct option: D
increases with rise in temperature
Option D (increases with rise in temperature) is correct because the resistance of a metallic wire increases with temperature.
273 Medium
273 of 457
Remembering +4 | -1
The resistivity of a wire depends on its
View answer and explanation
Correct option: D
Material
Option D (Material) is correct because resistivity is an intrinsic property of the material.
274 Medium
274 of 457
Application +4 | -1
If R1  and  R2{R_1}\,\,\mathrm{and}\,\,{R_2} be the resistances of the filaments of 200  W\mathrm{200}\,\,\mathrm{W} and 100  W\mathrm{100}\,\,\mathrm{W} electric bulbs operation at 220  V\mathrm{220}\,\,\mathrm{V}, then (R1R2)\left( {\frac{{{R_1}}}{{{R_2}}}} \right) is
View answer and explanation
Correct option: C
0.5\mathrm{0}\mathrm{.5}
Option C (0.5) is correct because the ratio of resistances is inversely proportional to the ratio of power, given the voltage is constant.
275 Medium
275 of 457
Application +4 | -1
If 2  A\mathrm{2}\,\,\mathrm{A} of current is passed through C u S O4\mathrm{C}\,\mathrm{u}\,\mathrm{S}\,{\mathrm{O}_4} solution for 32  s\mathrm{32}\,\,\mathrm{s}, then the number of copper ions deposited at the cathode will be
View answer and explanation
Correct option: B
2  ×  10202\,\, \times \,\,{10^{20}}
Option B (2×10202 \times 10^{20}) is correct because the number of copper ions is calculated using the formula q = it = n * 2e, where n is the number of ions.
276 Medium
276 of 457
Application +4 | -1
A conducting wire of cross-sectional area 1 cm21 \mathrm{~cm}^2 has 3×1023 m−33 \times 10^{23} \mathrm{~m}^{-3} charge carriers. If wire carries a current of 24 mA24 \mathrm{~mA}, the drift speed of the carrier is
View answer and explanation
Correct option: B
5×10−3 m/s5 \times 10^{-3} \mathrm{~m} / \mathrm{s}
Option B (5×10−3 m/s5 \times 10^{-3} \mathrm{~m} / \mathrm{s}) is correct because the drift speed is calculated using the formula vd=i/(neA)v_d = i / (n e A).
277 Medium
277 of 457
Understanding +4 | -1
On increasing the temperature of a conductor, its resistance increases because the
View answer and explanation
Correct option: D
Relaxation time decreases
Option D (Relaxation time decreases) is correct because as temperature increases, the collision frequency of electrons increases, reducing the relaxation time.
278 Medium
278 of 457
Analyzing +4 | -1
Twelve cells, each having emf E volt are connected in series and are kept in a closed box. Some of these cells are wrongly connected with positive and negative terminals reversed. This 12 cell battery is connected in series with an ammeter, an external resistance R\mathrm{R} ohm and a two-cell battery (two cells of the same type used earlier, connected perfectly in series). The current in the circuit when the 12-cell battery and 2-cell battery aid each other is 3 A3 \mathrm{~A} and is 2 A2 \mathrm{~A} when they oppose each other. Then the number of cell is 12-cell battery that are connected wrongly is:
View answer and explanation
Correct option: D
1
Option D is correct. By setting up equations for the current in both aiding and opposing configurations and solving them simultaneously, we find that one cell is connected wrongly.
279 Medium
279 of 457
Understanding +4 | -1
A small drop of water falls from rest through a large height hh in air, the final velocity is proportional to:-
View answer and explanation
Correct option: D
h∘h^\circ
h∘h^\circ is correct because after falling through a large height, the drop attains terminal velocity, which is independent of height.
280 Medium
280 of 457
Application +4 | -1
A piece of silver has a resistance of 1 Ω1 ~\Omega. What will be the resistance of a constantan wire of one-third length and one-half diameter, if the specific resistance of constantan is 30 times that of silver?
View answer and explanation
Correct option: B
40 Ω40 ~\Omega
Option B (40 Ω\Omega) is correct because it correctly uses the relationship between resistance, resistivity, length, and area to find the resistance of the constantan wire.
281 Medium
281 of 457
Understanding +4 | -1
A steady current flows in a metal wire of non-uniform cross-section. Which quantity remains constant along the length of the wire?
View answer and explanation
Correct option: D
Mobility of the free electrons
The correct answer is D (Mobility of the free electrons) because mobility depends on material properties and temperature, which are constant along the wire.
282 Medium
282 of 457
Application +4 | -1
A uniform wire of resistance RR is uniformly compressed along its length, until its radius becomes nn times the original radius. Now resistance of the wire becomes
View answer and explanation
Correct option: A
Rn4\frac{R}{{{n^4}}}
Option A (Rn4\frac{R}{{{n^4}}}) is correct because the resistance changes inversely with the fourth power of the radius when the wire is compressed.
283 Medium
283 of 457
Application +4 | -1
The number of dry cells, each of e.m.f. 1.5  volt1.5\,\,volt and internal resistance 0.5  ohm0.5\,\,ohm that must be joined in series with a resistance of 20  ohm20\,\,ohm so as to send a current of 0.6  ampere0.6\,\,ampere through the circuit is
View answer and explanation
Correct option: C
10
Option C (10) is correct because it is the number of cells required to achieve the specified current through the given resistance, calculated using Ohm's law for series circuits.
284 Medium
284 of 457
Application +4 | -1
A copper wire is stretched to make it 0.5% longer. The percentage change in its electrical resistance, if its volume remains unchanged is
View answer and explanation
Correct option: B
0.01
Option B (1.00%) is correct because the percentage change in resistance is approximately twice the percentage change in length.
285 Medium
285 of 457
Remembering +4 | -1
Kirchhoff's first law (∑i=0)\left(\sum {i}=0\right) expresses the conservation of
View answer and explanation
Correct option: B
Charge
Option B (Charge) is correct because Kirchhoff's first law, also known as the junction rule, is based on the conservation of electric charge.
286 Medium
286 of 457
Understanding +4 | -1
Thermoelectric constant of a thermocouple are α\alpha and β.\beta .. Thermoelectric power at inversion temperature is
View answer and explanation
Correct option: B
−α- \alpha
Option B (−α- \alpha) is correct because at the inversion temperature, the thermoelectric power is given by the derivative of the thermoelectric EMF with respect to temperature, evaluated at the inversion temperature, which results in −α- \alpha.
287 Medium
287 of 457
Analyzing +4 | -1
Two bulbs rates (25 W−200 V)(25 {~W}-200 {~V}) and (100 W−(100 {~W}- 220 V220 {~V} ) are connected in series to a 440 V440 {~V} line. Which one is likely to fuse?
View answer and explanation
Correct option: C
25 W25 {~W} bulb
Option C (25 W25 {~W} bulb) is correct because the 25 W25 {~W} bulb has a higher resistance and will experience a larger voltage drop, making it more likely to fuse.
288 Medium
288 of 457
Application +4 | -1
Which one of the following is the resistance that must be placed parallel with 12Ω12 \Omega resistance to obtain a combined resistance of 4Ω4 \Omega ?
View answer and explanation
Correct option: C
6Ω6 \Omega
Option C (6Ω6 \Omega) is correct because it is the resistance value that, when placed in parallel with 12Ω12 \Omega, results in a combined resistance of 4Ω4 \Omega.
289 Medium
289 of 457
Application +4 | -1
A capacitor of capacitance CC is charged by a battery of emf EE and internal resistance rr. A resistance 2r2 r is also connected in series with the capacitor. The amount of heat liberated inside the battery by the time capacitor is 50%50 \% charged is
View answer and explanation
Correct option: D
E2C24\frac{E^2 C}{24}
Option D (E2C24\frac{E^2 C}{24}) is correct because during charging, half the energy is lost, and the loss is distributed between the battery and the resistor.
290 Medium
290 of 457
Understanding +4 | -1
Ohm's law fails in which of the following cases

I. Potential VV depends on II non-linearly.

II. The relation between V{V} and I depends on the sign of V{V} for the same absolute value of V{V}.

III. VV depends on II linearly.
View answer and explanation
Correct option: D
I and II
Option D (I and II) is correct because Ohm's law fails when the relationship between voltage and current is non-linear or depends on the polarity of the voltage.
291 Medium
291 of 457
Analyzing +4 | -1
Assertion: As temperature of a metallic current carrying the wire is increased, its resistance increases.
Reason: Decrease in temperature results in a decrease of electric field strength, along the conductor so that the current reduces.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C is correct because the assertion is true (resistance increases with temperature for metals), but the reason is false (decrease in temperature does not directly cause a decrease in electric field strength).
292 Medium
292 of 457
Application +4 | -1
Value of I=∫01(2x+1)2dxI=\int\limits_{0}^1(2 x+1)^2 d x is
View answer and explanation
Correct option: D
133\frac{13}{3}
Option D (133\frac{13}{3}) is correct because it is the result of correctly evaluating the definite integral of the given function.
293 Medium
293 of 457
Understanding +4 | -1
The heat developed in a system is proportional to the current though it
View answer and explanation
Correct option: D
can be any the three heats mentioned above
Option D (can be any the three heats mentioned above) is correct because the heat developed can be Joule, Thomson, or Peltier heat, depending on the specific conditions.
294 Medium
294 of 457
Analyzing +4 | -1
40  W,220  V40 \,{~W}, 220 \,{~V} and 110  W,220  V110 \,{~W}, 220\, {~V} bulbs are connected in series with 440 volt440\, volt supply, then
View answer and explanation
Correct option: B
40  W40\, {~W} bulb will fuse
Option B is correct because the 40W bulb has higher resistance and thus lower current rating, causing it to fuse first when connected in series.
295 Medium
295 of 457
Remembering +4 | -1
The internal resistance of a cell is the resistance of :
View answer and explanation
Correct option: A
electrolyte used in cell
Option A (electrolyte used in cell) is correct because the internal resistance of a cell arises from the resistance offered by the electrolyte to the flow of ions.
296 Medium
296 of 457
Application +4 | -1
For a certain thermocouple the emf is E=aT+  bT2\begin{array}{llllllllllllllllllll} {E = aT + \,\,b{T^2}} \end{array}, where t(in  0C)t\left( {\mathrm{in}\,{\,^0}\mathrm{C}} \right) is the temperature of hot junction, the cold junction is at 0  0C0\,{\,^0}\mathrm{C}. The value of contants a  and  ba\,\,\mathrm{and}\,\,b are 10  ×  10−610\,\, \times \,\,{10^{ - 6}} and 0.02  ×  10−60.02\,\, \times \,\,{10^{ - 6}} respectively, then the temperature of inversion (in  0C)\left( {\mathrm{in}\,{\,^0}\mathrm{C}} \right) will be
View answer and explanation
Correct option: C
500\begin{array}{llllllllllllllllllll} {\mathrm{500}} \end{array}
Option C (500) is correct because the temperature of inversion is found by setting the emf to zero and solving for the temperature.
297 Medium
297 of 457
Understanding +4 | -1
Choose the wrong statement regarding the experiment to identify a diode, an LED, a resistor and a capacitor
View answer and explanation
Correct option: C
when pointer moves in one way when voltage is applied and not when reversed, the item is a resistor
Option C (when pointer moves in one way when voltage is applied and not when reversed, the item is a resistor) is the wrong statement because a resistor allows current flow in both directions.
298 Medium
298 of 457
Application +4 | -1
In a thermo-couple, one junction which is at 0 ∘C0\,^\circ C and the othe at t  ∘Ct{\mkern 1mu} {\mkern 1mu} ^\circ C the emf is given by E=at2−bt2E = a{t^2} - b{t^2}. The neutral temperature is given by
View answer and explanation
Correct option: B
2  a/3 b2\,\,a/3\,b
Option B (2  a/3 b2\,\,a/3\,b) is correct because the neutral temperature is found by setting the derivative of the emf with respect to temperature equal to zero.
299 Medium
299 of 457
Understanding +4 | -1
Statement-1: The equivalent resistance in series combination is larger than even the largest individual resistance.
Statement-2: The equivalent resistance of the parallel combination is smaller than even the smallest resistance.
View answer and explanation
Correct option: B
Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1
Option B (Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1) is correct because both statements are true, but they are independent facts about series and parallel resistances.
300 Medium
300 of 457
Application +4 | -1
A bulb of 220V\mathrm{220 V} and 300W\mathrm{300 W} is connected across 110V\mathrm{110 V} circuit, the percentage reduction in power is
View answer and explanation
Correct option: D
75  %\begin{array}{llllllllllllllllllll} {\mathrm{75}\,\,\mathrm{\% }} \end{array}
Option D (75 %) is correct because the power is proportional to the square of the voltage, so reducing the voltage by half reduces the power to one-fourth.
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