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JEE • PHYSICS • CURRENT ELECTRICITY

Current electricity practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 121-150 of 475 questions

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121 Medium
121 of 475
Remembering +4 | -1
The temperature at which thermal electric power of a thermo couple becomes zero is called
View answer and explanation
Correct option: B
Neutral temperature
Option B (Neutral temperature) is correct because the thermoelectric power of a thermocouple becomes zero at the neutral temperature.
122 Medium
122 of 475
Remembering +4 | -1
Fractional increase in resistivity per unit increase in temperature is defined as
View answer and explanation
Correct option: B
Temperature coefficient of resistivity
Option B (Temperature coefficient of resistivity) is correct because the temperature coefficient of resistivity is defined as the fractional increase in resistivity per unit increase in temperature.
123 Medium
123 of 475
Application +4 | -1
When two identical batteries of internal resistance 1  Ω1\,\,\mathrm{\Omega } each are connected in series across a resistor RR, the rate of heat produced in RR is J1{J_1}. When the same batteries are connected I\mathrm{I} parallel across RR, the rate is J2{J_2}. If J1=2.25  J2{J_1} = 2.25\,\,{J_2} then the value of RR in Ω\mathrm{\Omega } is
View answer and explanation
Correct option: D
5.16
Option D (5.16) is incorrect. The correct answer is R = 4. The solution provided in the original response is incorrect. The correct answer is 4.
124 Medium
124 of 475
Application +4 | -1
If an electron revolves in the path of a circle of radius of 0.5×10−10 m0.5 \times 10^{-10} {~m} at a frequency of 5×10155 \times 10^{15} cycle/sec. The electric current in the circle is:
(Charge of an electron is 1.6×10−19C1.6 \times 10^{-19} {C} )
View answer and explanation
Correct option: B
0.8 mA0.8 {~mA}
Option B (0.8 mA0.8 {~mA}) is correct because it is calculated using the formula I = ef, where e is the electron charge and f is the frequency.
125 Medium
125 of 475
Remembering +4 | -1
The time rate of flow of charge through any cross-section of a conductor is _____
View answer and explanation
Correct option: B
Electric current
Option B (Electric current) is correct because electric current is defined as the rate of flow of charge.
126 Medium
126 of 475
Application +4 | -1
The electromotive force of a primary cell is 2  volt2\,\,volt. When it is short-circuited it gives a current of 4  ampere4\,\,ampere. Its internal resistance in ohmohm is
View answer and explanation
Correct option: A
0.5
Option A (0.5) is correct because the internal resistance is calculated using Ohm's law when the cell is short-circuited.
127 Medium
127 of 475
Understanding +4 | -1
Statement-1: When an insulated wire is bent, its resistivity increases.
Statement-2: On bending, the velocity of electron decreases.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Option D (Statement-1 is false, Statement-2 is true) is correct because resistivity is a material property and doesn't change with bending, while bending can affect electron velocity.
128 Medium
128 of 475
Understanding +4 | -1
A thermocouple is formed by two metals XX and YY, metal XX comes earlier to YY in Seebeck series. If temperature of hot junction increases beyond the temperature of inversion, then direction of current in thermocouple will be from
View answer and explanation
Correct option: D
Both (b)\left( \mathrm{b} \right) and (c)\left( \mathrm{c} \right)
Option D (Both (b) and (c)) is correct because when the temperature exceeds the inversion temperature, the current direction reverses, flowing from X to Y through the hot junction and Y to X through the cold junction.
129 Medium
129 of 475
Remembering +4 | -1
Find the correct answer.
View answer and explanation
Correct option: B
Only secondary cells can be charged
Option B (Only secondary cells can be charged) is correct because secondary cells are designed to be recharged, unlike primary cells which are disposable.
130 Medium
130 of 475
Understanding +4 | -1
For electroplating a spoon, it is placed in the voltmeter at
View answer and explanation
Correct option: B
The position of cathode
Option B (The position of cathode) is correct because in electroplating, the object to be plated (the spoon) is placed at the cathode where positive ions are reduced and deposited.
131 Medium
131 of 475
Application +4 | -1
A thermocouple of resistance 1.6  Ω1.6\,\,\mathrm{\Omega } is connected in series with a galvanometer of 8  Ω8\,\,\mathrm{\Omega } resistance. The thermocouple develops an e.e..m.f. of 10  μV10\,\,\mu V per degree temperature difference between two junctions. When one junction is kept at 0  0C0\,{\,^0}\mathrm{C} and the other in a molten metal, the galvanometer reads 8  millivolt8\,\,millivolt. The temperature of molten metal, when ee.m.f. varies linearly with temperature difference, will be
View answer and explanation
Correct option: A
960  0C960\,{\,^0}\mathrm{C}
Option A (960  0C960\,{\,^0}\mathrm{C}) is correct because it is calculated by equating the current through the galvanometer to the current produced by the thermocouple's emf, considering the total resistance of the circuit.
132 Medium
132 of 475
Application +4 | -1
The chemical equivalent of copper and zinc are 32 and 108\mathrm{32 }\,\mathrm{and }\,\mathrm{108} respectively. When copper and silver voltmeters are connected in series and electric current is passed through for sometime, 1.6  g1.6\,\,g of copper is deposited. Then, the mass of silver deposited will be
View answer and explanation
Correct option: C
5.4  g5.4\,\,g
Option C (5.4g5.4 g) is correct because it is calculated using Faraday's law, which states that the ratio of mass deposited to chemical equivalent is constant when voltmeters are connected in series.
133 Medium
133 of 475
Application +4 | -1
The thermo emf of a thermo-couple is found to depend on temperature TT (in degree Celsius) as E=4 T−T2200E = 4\,T - \frac{{{T^2}}}{{200}}, where T  0CT\,{\,^0}\mathrm{C} is the temperature of the hot junction. The neutral and inversion temperature of the thermocouple are (in degree celsius)
View answer and explanation
Correct option: D
400,800\begin{array}{llllllllllllllllllll} {\mathrm{400, 800}} \end{array}
Option D (400, 800) is correct because the neutral temperature is found by setting dEdT=0\frac{dE}{dT} = 0, and the inversion temperature is twice the neutral temperature.
134 Easy
134 of 475
Analyzing +4 | -1
Statement-1: Potential difference across the terminals of a battery can be greater than its emf.
Statement-2: When current is taken from battery, V=ε−IrV={\varepsilon}- Ir (Symbols have their usual meaning).
View answer and explanation
Correct option: B
Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1
Option B is correct. Statement-1 is true because the terminal voltage can exceed EMF during charging. Statement-2 is true but doesn't explain Statement-1.
135 Medium
135 of 475
Application +4 | -1
The equivalent resistance of two resistors connected in series is 6Ω6 \Omega and their parallel equivalent resistance is 43Ω\frac{4}{3} \Omega. What are the values of resistances?
View answer and explanation
Correct option: C
4Ω,2Ω4 \Omega, 2 \Omega
Option C (4Ω,2Ω4 \Omega, 2 \Omega) is correct because these values satisfy both the series and parallel equivalent resistance conditions.
136 Medium
136 of 475
Understanding +4 | -1
Though the electron drift velocity is small and electron charge is very small, a conductor can carry an appreciably large current because:
View answer and explanation
Correct option: A
Electron number density is very large
Option A (Electron number density is very large) is correct because the large current is due to the high number density of electrons in the conductor.
137 Medium
137 of 475
Understanding +4 | -1
Statement-I: KVA is the unit of electrical power and kWh is the unit of electrical energy.
Statement-II: Both kVA and kWh have same dimensions
View answer and explanation
Correct option: C
Statement-I is true, but Statement-II is false
Option C (Statement-I is true, but Statement-II is false) is correct because kVA is the unit of apparent power, kWh is the unit of energy, and they have different dimensions.
138 Medium
138 of 475
Analyzing +4 | -1
Assertion (A): When electric bulbs of different
powers but of same rated voltage are connected in
series, the lower power bulb glows more bright.

Reason (R): In an electric bulb most of the electrical
energy is wasted as heat energy.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason
is not the correct explanation of Assertion
Option B (If both Assertion and Reason are true but Reason is not the correct explanation of Assertion) is correct because both statements are factually correct, but the reason doesn't explain why the lower power bulb glows brighter.
139 Medium
139 of 475
Understanding +4 | -1
The specific resistance of wire
View answer and explanation
Correct option: D
is independent of length, cross section and mass of the wire
Option D is correct because specific resistance (resistivity) is a material property and independent of dimensions.
140 Medium
140 of 475
Application +4 | -1
The number of dry cells, each of e.m.f. 1.5  volt1.5\,\,volt and internal resistance 0.5  ohm0.5\,\,ohm that must be joined in series with a resistance of 20  ohm20\,\,ohm so as to send a current of 0.6  ampere0.6\,\,ampere through the circuit is
View answer and explanation
Correct option: C
10
Option C (10) is correct because it is calculated using Ohm's law for series circuits, where the total voltage equals the sum of individual cell voltages.
141 Medium
141 of 475
Remembering +4 | -1
Pick out the wrong feature about carbon resistors
View answer and explanation
Correct option: C
Relatively sensitive to temperature
Option C (Relatively sensitive to temperature) is correct because carbon resistors are relatively insensitive to temperature, making it a wrong feature.
142 Medium
142 of 475
Understanding +4 | -1
For a given temperature difference which of the following pairs will generate maximum thermo-emf?
View answer and explanation
Correct option: D
Antimony-bismuth
Option D (Antimony-bismuth) is correct because antimony and bismuth have the greatest heating contrasts, generating maximum thermo-emf.
143 Medium
143 of 475
Application +4 | -1
In a large building, there are 15 bulbs of 40 W, 5 bulbs of 100 W, 5 fans of 80 W and 1 heater of 1 kW. The voltage of the electric mains is 220 V. The minimum capacity of the main fuse of the building will be
View answer and explanation
Correct option: C
0
Option C (12 A) is correct because it is the minimum fuse capacity required based on the total power consumption.
144 Medium
144 of 475
Remembering +4 | -1
The amount of charge flowing per second per unit area normal to the flow is called
View answer and explanation
Correct option: D
current density
Option D (current density) is correct because current density is defined as the amount of charge flowing per unit time per unit area.
145 Medium
145 of 475
Application +4 | -1
A conductor wire having 1029{10^{29}} free electrons  /  m3\mathrm{electrons}\,\,/\,\,{\mathrm{m}^3} carries a current of 20 A\mathrm{20}\,\mathrm{A}. If the cross-section of the wire is 1  mm21\,\,\mathrm{m}{\mathrm{m}^2}, then the drift velocity of electrons will be
View answer and explanation
Correct option: C
1.25  ×  10−3  ms−11.25\,\, \times \,\,{10^{ - 3}}\,\,\mathrm{m}{\mathrm{s}^{ - 1}}
Option C (1.25×10−3 ms−11.25 \times {10^{ - 3}}\,\mathrm{m}{\mathrm{s}^{ - 1}}) is correct because it is the drift velocity calculated using the formula vd=InAe{v_d} = \frac{I}{{nAe}}.
146 Easy
146 of 475
Application +4 | -1
A current of 10 amp10 \mathrm{~amp} is passing through a metallic wire of cross sectional area 4×10−6 m24 \times 10^{-6} \mathrm{~m}^2. If the density of the aluminum conductor is 2.7 gm/cc2.7 \,\mathrm{gm/cc} considering aluminum gives 1 electrons per atom for conduction find the drift speed of the electrons if molecular weight of aluminum is 27 gm27 \mathrm{~gm}.
View answer and explanation
Correct option: C
2.6×10−4 m/s2.6 \times 10^{-4} \mathrm{~m} / \mathrm{s}
Option C (2.6×10−4 m/s2.6 \times 10^{-4} \mathrm{~m} / \mathrm{s}) is correct because it is calculated using the drift velocity formula, considering the number density of electrons.
147 Medium
147 of 475
Application +4 | -1
24 identical electrical cells, internal resistance of each 0.5Ω0.5 \Omega are used in mixed combination to obtain maximum current through external resistance of 3Ω3 \Omega. Calculate number of rows and number of cells in each row.
View answer and explanation
Correct option: A
12
Option C ([M0L0T0][ {{M^0}{L^0}{T^0}} ]) is correct because the quantity is dimensionless, as it represents the fine-structure constant.
148 Easy
148 of 475
Understanding +4 | -1
Statement-1: Two unequal resistances are connected in series across a cell, then potential drop across the larger resistance is more.
Statement-2: The current will be same in both unequal resistances.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1
Option A (Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1) is correct because in a series circuit, the current is the same through all resistors, and the potential drop is proportional to the resistance.
149 Medium
149 of 475
Application +4 | -1
In a metre bridge the balancing point is found to be at 39.5 cm39.5 \mathrm{~cm} from A\mathrm{A}, when the resistor Y=12.5Ω\mathrm{Y}=12.5 \Omega. The value of X\mathrm{X} is
View answer and explanation
Correct option: A
8.16Ω8.16 \Omega
Option A (8.16Ω8.16 \Omega) is correct because it is calculated using the Wheatstone bridge principle, where the ratio of resistances is equal to the ratio of lengths.
150 Medium
150 of 475
Application +4 | -1
In voltaic air cell if 5  g\mathrm{5}\,\,\mathrm{g} zinc is consumed, how many ampere hours shall we get?
View answer and explanation
Correct option: C
4.1
Option C (4.1) is correct because the ampere-hours are calculated by converting the mass of zinc consumed to charge and then to ampere-hours.
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