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JEE • PHYSICS • COMMUNICATION SYSTEMS

Communication systems practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 113 questions

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61 Medium
61 of 113
Remembering +4 | -1
The diameter of an optical fibre is
View answer and explanation
Correct option: B
10−4 cm10^{-4} {~cm}
Option B (10−4 cm10^{-4} {~cm}) is correct because the diameter of an optical fiber is typically around 125 micrometers, which is equal to 1.25×10−21.25 \times 10^{-2} mm or 1.25×10−41.25 \times 10^{-4} cm, approximately 10−410^{-4} cm.
62 Medium
62 of 113
Application +4 | -1
Sinusoidal carrier voltage of frequency 1.5 MHz and amplitude 50 V is amplitude modulated by sinusoidal voltage of frequency 10 kHz producing 50% modulation. The lower and upper side-band frequencies in kHz are
View answer and explanation
Correct option: A
1490, 1510
Option A (1490, 1510) is correct because the lower and upper sideband frequencies are calculated by subtracting and adding the modulating frequency to the carrier frequency, respectively.
63 Medium
63 of 113
Remembering +4 | -1
In pulse modulation of analog signals, common pulse system employed are
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because PAM, PPM, PDM, and PCM are all common pulse modulation systems used for analog signals.
64 Medium
64 of 113
Remembering +4 | -1
The diameter of an optical fiber is
View answer and explanation
Correct option: B
10−4m{10^{ - 4}}m
Option B is correct. The diameter of an optical fiber is typically around 10−4m{10^{-4}} m (100 micrometers).
65 Medium
65 of 113
Remembering +4 | -1
Intensity of electric field obtained at receiver antenna for a space wave propagation is
View answer and explanation
Correct option: D
Inversely proportional to the square perpendicular-distance from transmitter to antenna
Option D (Inversely proportional to the square perpendicular-distance from transmitter to antenna) is correct because the intensity of a wave decreases with the square of the distance.
66 Medium
66 of 113
Remembering +4 | -1
In satellite communication, the uplink frequency band used is:
View answer and explanation
Correct option: B
5.925−6.425GHz5.925-6.425 \mathrm{GHz}
Option B (5.925−6.425GHz5.925-6.425 \mathrm{GHz}) is correct because it is the standard uplink frequency band used in satellite communication.
67 Medium
67 of 113
Remembering +4 | -1
The number of telephonic message which are carried by a fiber at an instant with much less intensity loss are
View answer and explanation
Correct option: C
2000
Option C (2000) is correct because optical fibers can carry approximately 2000 telephonic messages at an instant with minimal intensity loss.
68 Medium
68 of 113
Understanding +4 | -1
Modulation is the phenomenon of
View answer and explanation
Correct option: A
Superimposing the audio frequency signal over a carrier wave
Option A (Superimposing the audio frequency signal over a carrier wave) is correct because modulation is the process of varying the characteristics of a carrier wave in accordance with the instantaneous amplitude of the message signal.
69 Medium
69 of 113
Understanding +4 | -1
Audio signal cannot be transmitted because
View answer and explanation
Correct option: D
The transmitting antenna length is very large and impracticable
Option D is correct because audio signals have low frequencies, requiring impractically large antenna lengths for efficient transmission.
70 Medium
70 of 113
Understanding +4 | -1
Given the electric field of a complete amplitude modulated wave as E⃗=i^Ec(1+EmEccos⁡ωmt)cos⁡ωct.\vec{E}=\hat{i} E_c\left(1+\frac{E_m}{E_c} \cos \omega_m t\right) \cos \omega_c t. Where the subscript cc stands for the carrier wave and m{m} for the modulating signal. The frequencies present in the modulated wave are
View answer and explanation
Correct option: B
ωc,ωc+ωm\omega_c, \omega_c+\omega_m and ωc−ωm\omega_c-\omega_m
Option B (ωc,ωc+ωm\omega_c, \omega_c+\omega_m and ωc−ωm\omega_c-\omega_m) is correct because amplitude modulation generates the carrier frequency and sideband frequencies.
71 Medium
71 of 113
Understanding +4 | -1
Television signals reach us only through the ground waves. The range RR related with the transmitter height hh is in Proportional to
View answer and explanation
Correct option: B
h1/2{h^{1/2}}
Option B (h1/2{h^{1/2}}) is correct because the range R is proportional to the square root of the transmitter height h, as given by the formula R=2hrR = \sqrt{2hr}.
72 Medium
72 of 113
Understanding +4 | -1
Consider telecommunication through optical fibres. Which of the following statements is no true?
View answer and explanation
Correct option: B
Optical fibres are subjected to electro-magnetic interference from outside
Option B is correct because optical fibers are not susceptible to electromagnetic interference due to the use of light for signal transmission.
73 Medium
73 of 113
Application +4 | -1
The height of transmitting antenna is 180 m180 \, \mathrm{m} and the height of the receiving antenna is 245 m245 \, \mathrm{m}. The maximum distance between them for satisfactory communication in line of sight will be:

(given R=6400 kmR=6400 \, \mathrm{km} )
View answer and explanation
Correct option: D
104 km104 \, \mathrm{km}
Option D (104 km104 \, \mathrm{km}) is correct because it is calculated using the formula for the maximum distance between antennas in line of sight.
74 Medium
74 of 113
Application +4 | -1
A carrier is simultaneously modulated by two sine waves having modulation indices of 0.3 and 0.4. The total modulation index will be
View answer and explanation
Correct option: B
0.5
Option B (0.5) is correct because the total modulation index is the square root of the sum of the squares of individual modulation indices.
75 Medium
75 of 113
Remembering +4 | -1
Basically, a communication system is a
View answer and explanation
Correct option: C
Messenger
Option C (Messenger) is correct because a communication system essentially acts as a messenger, conveying information from one point to another.
76 Medium
76 of 113
Remembering +4 | -1
Which mode of communication is/are employed for the transmission of TV signals?
View answer and explanation
Correct option: C
Space wave propagation
Option C (Space wave propagation) is correct because TV signals are transmitted using space wave propagation or line of sight communication.
77 Medium
77 of 113
Application +4 | -1
A TV tower has a height 150 m. What is the total population covered by the TV tower, if the population density around the TV tower is 103  km−2?{10^3}\mathrm{\;k}{\mathrm{m}^{ - 2}}? Radius of the earth is 6.4×106  m.6.4 \times {10^6}\;\mathrm{m}.
View answer and explanation
Correct option: A
60.288 lakhs
Option A (60.288 lakhs) is correct because it is the total population covered by the TV tower, calculated using the given height, earth's radius, and population density.
78 Medium
78 of 113
Application +4 | -1
A radar sends an electromagnetic signal of electric field (E0)=2.25  V/m\left( {{E_0}} \right) = 2.25\,\,V/m and magnetic field (B0)=1.5 ×10−8T\left( {{B_0}} \right) = 1.5\, \times {10^{ - 8}}T which strikes a target on line of sight at a distance of 3 km in a medium. After that, a part of signal (echo) reflects back towards the radar with same velocity and by same path. If the signal was transmitted at time t=0t = 0 from radar, then after how much time echo will reach to the radar?
View answer and explanation
Correct option: B
4.0×10−5s4.0 \times {10^{ - 5}}s
Option B (4.0×10−5s4.0 \times {10^{ - 5}}s) is correct because the time taken for the echo to return is calculated by considering the distance and the velocity of the electromagnetic signal in the medium.
79 Medium
79 of 113
Understanding +4 | -1
What is the reason behind the disturbing of incoming and reflected signals when a low flying aircraft passes overhead, which results in slight shaking of the picture on our TV screen?
View answer and explanation
Correct option: A
Interference
Option A (Interference) is correct because the incoming and reflected signals interfere, causing fluctuations in the received signal strength.
80 Medium
80 of 113
Remembering +4 | -1
The characteristic impedance of a coaxial cable is of the order of
View answer and explanation
Correct option: C
270  Ω
Option A (50  Ω) is the closest to the typical characteristic impedance of a coaxial cable, which is usually around 50 or 75 ohms.
81 Medium
81 of 113
Understanding +4 | -1
The space wave propagation is utilized in
View answer and explanation
Correct option: D
Cannot be reflected by any layer of earth's atmosphere
Option D (Cannot be reflected by any layer of earth's atmosphere) is correct because space waves propagate directly through the atmosphere and are not reflected by any layer.
82 Medium
82 of 113
Application +4 | -1
The velocity factor of a transmission line is x. If dielectric constant of the medium is 2.6, the value of x is
View answer and explanation
Correct option: B
0.62
Option B (0.62) is correct because the velocity factor is the inverse of the square root of the dielectric constant.
83 Medium
83 of 113
Application +4 | -1
What should be the height of transmitting antenna and the population covered, if the television telecast is to cover a radius of 150 km? The average population density around the tower is 2000/km22000/k{m^2} and the value of Re=6.5×106 m{R_e} = 6.5 \times {10^6}\,m.
View answer and explanation
Correct option: A
Height = 1731 m= \,1731\,m population covered =1413×105= 1413 \times {10^5}
Option A (Height = 1731 m= \,1731\,m population covered =1413×105= 1413 \times {10^5}) is correct because it is calculated using the formula for the height of the antenna and the area covered by the telecast.
84 Medium
84 of 113
Understanding +4 | -1
Antenna is
View answer and explanation
Correct option: D
Resistive at resonant frequency
Option D (Resistive at resonant frequency) is correct because at the resonant frequency, the inductive and capacitive reactances of the antenna cancel each other out, leaving only the resistance.
85 Medium
85 of 113
Application +4 | -1
A FM Broad cast transmitter, using modulating signal of frequency 20kHz20 \mathrm{kHz} has a deviation ratio of 10. The Bandwidth required for transmission is
View answer and explanation
Correct option: D
440 kHz
Option D (440 kHz) is correct because the bandwidth is calculated using Carson's rule: BW = 2(Δf + fm), where Δf is the frequency deviation and fm is the modulating signal frequency.
86 Medium
86 of 113
Remembering +4 | -1
Frequencies in the UHF range normally propagate by means of
View answer and explanation
Correct option: D
Space waves
Option D (Space waves) is correct because UHF frequencies typically propagate via space waves, which travel in a straight line from the transmitting antenna to the receiving antenna.
87 Medium
87 of 113
Understanding +4 | -1
A signal Acos⁡ωtA\cos \omega t is transmitted using v0sin⁡ω0t{v_0}\sin {\omega _0}t as carrier wave. The correct amplitude modulated (AM) signal is
View answer and explanation
Correct option: D
v0sin⁡ω0t+A2sin⁡(ω0−ω)t+A2sin⁡(ω0+ω)t{v_0}\sin {\omega _0}t + \frac{A}{2}\sin \left( {{\omega _0} - \omega } \right)t + \frac{A}{2}\sin \left( {{\omega _0} + \omega } \right)t
Option D is correct because it represents the amplitude modulated signal as the sum of the carrier wave and sidebands resulting from the modulation process.
88 Medium
88 of 113
Application +4 | -1
An AM wave has 1800 watt of total power content, for 100%100 \% modulation the carrier should have power content equal to
View answer and explanation
Correct option: B
1200 W1200 \mathrm{~W}
Option B (1200 W1200 \mathrm{~W}) is correct because the carrier power is calculated using the formula Pt=Pc(1+ma22)P_t = P_c(1 + \frac{m_a^2}{2}) with 100% modulation.
89 Medium
89 of 113
Remembering +4 | -1
A communication between a fixed base station and several mobile units, located on ships or aircraft utilising two way radio communication in the VHF and UHF is of frequency band
View answer and explanation
Correct option: C
30 to 470MHz470 {MHz}
Option C (30 to 470MHz470 {MHz}) is correct because VHF and UHF radio communication between a base station and mobile units typically uses frequencies in this range.
90 Medium
90 of 113
Understanding +4 | -1
Which of the following is not the frequency of frequency modulated (FM) signal?
View answer and explanation
Correct option: D
100 kHz100 \,\mathrm{kHz}
Option D (100 kHz100 \,\mathrm{kHz}) is correct because FM signals operate in the MHz range, not kHz.
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